Nitrogen dioxide (NO2) gas and liquid water (H2O) react to form aqueous nitric acid(HNO3) and nitrogen monoxide gas. Suppose you have 2.0 mol of NO2 and 7.0 mol of H20 in a reactor. Calculate the largest amount of NHO3 that could be produced. Round your answer to the nearest 0.1 mol.

Answers

Answer 1

Answer:

1.3 moles of HNO₃ will be produced

Explanation:

Equation for the reaction:

3NO₂ + H₂O ----> 2HNO₃ + NO

From the equation of the reaction, 3 moles of NO₂ reacts with 1 mole of H₂O to produce 2 moles of HNO₃

Suppose there are 2 moles of NO₂  and 7.0 moles of H₂O in a reactor, the limiting reactant will be NO₂ and H₂O will be in excess since 3 moles of NO₂ reacts with every 1 mole of H₂O.

Since 3 moles of NO₂ reacts to produce  2 moles of HNO₃;

2 moles of NO₂ will react to produce 2/3 * 2 moles HNO₃ = 1.3 moles of HNO₃

Therefore, 1.3 moles of HNO₃ will be produced

Answer 2

The largest amount of HNO₃ produced from the reaction between 2 mole of NO₂ and 7.0 mole of H₂O in a reactor is 1.3 mole

We'll begin by determining the limiting reactant. This can be obtained as follow:

3NO₂ + H₂O —> 2HNO₃ + NO

From the balanced equation above,

3 moles of NO₂ reacted with 1 mole of H₂O.

Therefore,

2 moles of NO₂ will react with = [tex]\frac{2}{3}\\\\[/tex] = 0.67 mole of H₂O.

From the calculation made above, we can see that only 0.67 mole of H₂O out of 7 moles given, reacted completely with 2 moles of NO₂. Thus, NO₂ is the limiting reactant and H₂O is the excess reactant.

Finally, we shall determine the largest amount of HNO₃ produced from the reaction. This can be obtained by using the limiting reactant as illustrated below:

From the balanced equation above,

3 moles of NO₂ reacted to produce 2 moles of HNO₃.

Therefore,

2 moles of NO₂ will react to produce = [tex]\frac{2 *2 }{3} \\\\[/tex] = 1.3 mole of HNO₃.

Thus, the largest amount of HNO₃ produced from the reaction is 1.3 mole

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Related Questions

Which of the compounds of H3PO4, Mg(OH)2, LiOH, and HCl, behave as acids when they are dissolved in water?A. Mg(OH)2 and LiOH.B. B H3PO4 and HC.C. Only HCl.D. Only LiOH.

Answers

Answer:

B. H3PO

Explanation:

The pH, texture, reactivity, and conductivity should be seen while determining acid or base. Among given option, H₃PO₄ is the acid  when dissolved in water.

What are acid and base?

Acid is a substance that has sour taste, pH lies in the range of 0-7 and give hydronium ion when dissolved in water. Acid turns blue litmus red. Whereas base has bitter, its pH is between 7-14 and it turns red litmus blue. It give hydroxide ion when dissolved in water.

Extensive properties, such as mass and volume depend on the amount of substance present and are not useful in the identification of a substance. Measuring mass and volume is not useful While determining acid or base. Out of given compounds, H₃PO₄ is the acid  when dissolved in water.

Therefore, H₃PO₄ is the acid  when dissolved in water.

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given that the only known ionic charges of lead are pb(ii) and pb(iv), how can you explain the existence of the pb2o3 salt

Answers

Answer:

See Explanation

Explanation:

Pb2O3 is better formulated as PbO.PbO2. It is actually a mixture of the two oxides of lead, lead II oxide and lead IV oxide.

This implies that this compound Pb2O3  (sometimes called lead sesquioxide) is a mixture of the oxides of lead in its two known oxidation states +II and +IV.

Hence Pb2O3  contains PbO and PbO2 units.

If you had to choose,
Happiness or Power? (Any type of Power)

Answers

Answer:

I will choose Happiness, Happiness, Happiness, Happiness.....

☺️❤️

Explanation:

Why Happiness Matters

It's the feeling of truly enjoying your life, and the desire to make the very best of it. Happiness is the "secret sauce" that can help us be and do our best. Here's what researchers found when they studied happy people: Happy people are more successful.

Scientific evidence suggests that being happy may have major benefits for your health. For starters, being happy promotes a healthy lifestyle. It may also help combat stress, boost your immune system, protect your heart and reduce pain. What's more, it may even increase your life expectancy.

Suppose the Cu ions are produced by the reaction of 0.94 g of copper turnings with excess nitric acid. How many moles of Cu are produced?

Answers

Answer:

0.0148 moles

Explanation:

Solid copper is oxidized with HNO₃:

Cu + 4HNO₃ → Cu²⁺ + 2 NO₃⁻ + 2H₂O + 2NO₂

Where 1 mole of Cu produce 1 mole of Cu²⁺ when nitric acid is in excess.

Moles of Cu that react (Molar mass Cu = 63.546g/mol):

0.94g * (1mol / 63.546g) = 0.0148 moles of Cu

And moles of Cu²⁺ produced are also:

0.0148 moles

A Beer's Law Plot of sample A gives a slope equal to 1.2 M-1cm-1. Calculate molar concentration of this sample at a wavelength of 420 nm and an absorbance reading of 0.23 in a 1 cm cuvette.

Answers

Answer:

[tex]0.192\ \text{M}[/tex]

Explanation:

A = Absorbance of solution

E = Molar absorptivity

l = Length of cuvette = 1 cm

c = Concentration of solution

Beer's law is given by

[tex]A=Elc[/tex]

The equation of a straight line is given by

[tex]y=mx+c[/tex]

Comparing the above equations we get

Value on [tex]y[/tex] axis = A = Absorbance of solution = 0.23

[tex]m[/tex] = Slope of line = El = Molar absorptivity multiplied with length = [tex]1.2\times 1\ \text{M}^{-1}[/tex]

[tex]x[/tex] = Value of x axis = c = Concentration of solution

So we get

[tex]c=\dfrac{A}{El}\\\Rightarrow c=\dfrac{0.23}{1.2\times 1}\\\Rightarrow c=0.192\ \text{M}[/tex]

The molar concentration of the sample is [tex]0.192\ \text{M}[/tex]

explain what happens to temperature and energy as molecules move from gas to liquid to solid

Answers

Answer and Explanation:

As the temperature of the substances increases, the average energy of the molecules increases, and average energy of attraction between the molecules decreases consequently intermolecular spacing between the molecules increases. As a result, a substance change in succession from gas to liquid to solid.

How many grams of oxygen gas will be produced when 2.50 moles of potassium chlorate is decomposed?

Answers

Answer:

[tex]m_{O_2}=120gO_2[/tex]

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

[tex]2KClO_3\rightarrow 2KCl+3O_2[/tex]

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

[tex]m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2[/tex]

Best regards!

how many neutrons make up one of these potassium atoms?​

Answers

Answer:

20 Neutrons

Explanation:

The element of potassium has the symbol K. The nucleus of an atom of potassium contains 19 protons and 20 neutrons. I hope that answer helps xx

what is the iupac name of CH3-CH2CH(CH3)CH2-COOH​

Answers

Answer:

Butanoic acid.

Explanation:

An atom of an element has two electrons in the first energy level and five electrons in the second energy level. Write the electron configuration and name the element. How many unpaired electrons does an atom of this element have?

Answers

Answer:

electronic configuration: 1s^2,2s^2,2p^3            

name: nitrogen

unpaired electron: 3

Explanation:

The atom with 2 electrons and 5 electrons in the first and second energy level is NITROGEN. The element has 3 unpaired electron.

The electronic configuration of the atom is 1s² 2s² 2p³

Since the atom has 7 Electrons, the element which has 7 electrons is NITROGEN.

The 2p orbital has 3 unpaired electrons in it's second energy level.

Therefore, the 2p orbital has 3 unpaired electrons in it's outermost shell.

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What two options are homogeneous mixture

Answers

Answer:

vinegar and soap

Explanation:

Answer:

vinegar and soap

Explanation: just took the test

What is the hybridization state on the central N atom in the azide ion, N3−?

Answers

The sp hybridization of the central nitrogen is consistent with the linear structure of the azide ion. In A, the terminal nitrogens may both be sp2 hybridized; after all the drawing looks similar to the double bond in ethylene.

If you wanted to change the polarity of hydrogen bromide (HBr) by substituting the bromine with a different atom. Which atom would increase the polarity of the molecule?

Answers

Answer:

This question is incomplete as it lacks options, the options are:

A. chlorine (CI)

B. iodine (1)

C. sulfur (S)

D. hydrogen (H)

The answer is A. Chlorine

Explanation:

Polarity of a substance in chemistry is a function of electric charges in the atoms of the molecules involved. Polarity, however, can be increased or decreased in molecules depending on the charges of the atoms that form them.

Since polarity increases when an atom in the molecule has a high ability to pull electrons toward itself i.e. electronegativity, one atom that can be substituted for Bromine in the hydrogen bromide (HBr) molecule in order to increase its polarity is CHLORINE. This is because Chlorine (Cl) is more electronegative than Bromine atom, hence, will pull more electrons from hydrogen to make the HCl molecule more polar than HBr.

To increase the polarity of HBr, the bromine atom can be replaced with a hydrogen atom.

A polar molecule is one in which a dipole moment exists. There is a positive end and a negative end in a polar molecule. Conventionally, the direction of the dipole is from the positive end of the molecule towards the negative end of the molecule.

If we want to increase the polarity of the molecule then we must substitute the bromine atom with a more electronegative atom. In this case, chlorine is  the best option.

Missing parts;

If you wanted to change the polarity of hydrogen bromide (HBr) by substituting the bromine by a different atom. Which atom would increase the polarity of the  molecule?

A. chlorine (CI)

B. iodine (1)

C. sulfur (S)

D. hydrogen (H)

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Is iron man made or natural

Answers

Answer:

Iron is natural. Paper is man-made

Explanation:

Answer:

iron

Explanation:

PLZ HELP TAKING TEST NOW. WILL GIVE BRAINLIEST
Some students decided to do an experiment with a can of pop. They opened the 340 g can of pop and left it open for a day. They then measured the pop can and found it was 332 g. Does this break the law of conservation of mass? Explain why or why not.

Answers

yes, this breaks the law of conservation of mass because the mass of the reactants should be equal to the mass of the product. In this case gas was released which changed the mass of the product so it does not follow the law of conservation of mass.

Why is the following electron configuration not possible?
1-9-1

Answers

Answer: because its noy

Explanation:

I NEED HELP ASAP PLEASE I BEG

Answers

with what?..................

Examples of solutions can be:

O A. a solid dissolved in a liquid
O B. gas mixed with a liquid
O C. liquid mixed with a liquid
OD. all of the the above

Answers

Answer:

B. gas mixed with a liquid

Explanation:

because:

A. a solid can't dissolve in a liquid.

C. two liquids mixed isn't a solution

D. Not All of the above for sure.

Examples of solutions can be all of the above. The correct option is D.

What is a solution?

A solution is made when a solute is mixed with a solvent. The solution can be a liquid, solid, or gas. The solution is made when the solute is fully mixed with the solvent. The solute is the substance that gets mixed, and the solvent is the base in which the solute gets dissolved.

So, a solid dissolved in a liquid, gas mixed with a liquid, or a liquid mixed with a liquid, the energy statement is true for a solution.

Examples of a solution are sugar dissolved in water when water mix with soda and state gets mixed with water or another gas.

Thus, the correct options are D. all of the the above.

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Dinitrogen tetraoxide, a colorless gas, exists in equilibrium with nitrogen dioxide, a reddish brown gas. One way to represent this equilibrium is:

Answers

The question is incomplete, the complete question is shown in the image attached

Answer:

F

T

Explanation:

From the equilibrium equation;

N2O4(g) ⇄NO2(g)

We must have to remember that;

1) At equilibrium, the concentration of the species on both sides of the reaction equation may not necessarily be the same but must be held at a constant value because the rate of forward reaction equals the rate of reverse reaction.

2) The rate of forward reaction must equal the rate of reverse reaction.

If the rate of forward reaction is k1 and the rate of reverse reaction is k2. Then it follows that at equilibrium k1 = k2.

How do hurricanes form? How do hurricanes form?

a Hurricanes form when winds circulate about a column of cool air.

b Hurricanes form when two warm fronts meet over the ocean

c Hurricanes form when warm air over the equator mixes with cold air from the poles

d Hurricanes form as a result of rising warm air and circulating winds​

Answers

I think the answer is D

Answer:

D. Hurricanes form as a result of rising warm air and circulating winds​

Explanation:

How does one determine a percent composition from an empirical
formula?
A. Divide the atomic mass of the element by its subscript and
multiply by 100%
O B. Divide the mass of the compound by the atomic mass of
the element and multiply by 100%
O C. Divide the subscript of the element by the mass of the
element and multiply by 100%
O D. Divide the total mass of each element by the mass of the
compound and multiply by 100%

Answers

_______________THE ANSWER IS D______________

The way one determines a percent composition from an empirical formula is to divide the total mass of each element by the mass of the compound and multiply by 100%.

What is empirical formula?

Empirical formula is a notation that indicates the ratios of the various elements present in a compound, without regard to the actual numbers.

The empirical formula of a compound is the simplest ratio that can exist between the constituent elements of a compound.

However, the percent composition of a compound can be determined by dividing the total mass of each element by the mass of the compound and multiply by 100%.

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Name something that has zero thermal energy.

Answers

Absolute zero is the point at which the fundamental particles of nature have minimal vibrational motion, retaining only quantum mechanical, zero-point energy-induced particle motion.
Hope this helped! c:

Answer:

When all molecules in a system stop moving completely, there is zero thermal energy

Explanation:

It is impossible to reach though

Arrange the following compounds in order of increasing acidity, and explain the reasons for your choice of order. Enter your answer in the answer box below. a. 4-nitrophenol b. cyclohexanol c. 2,6-difluorocyclohexanol d. 4-bromophenol

Answers

Answer:

(a) > (d) > (c) > (b)

Explanation:

Acidic character is based upon inductive effect of the functional group that are attached to parent chain.

1. Nitro is a -I group which makes phenol acidic due to increased resonance,  2. bromine is a -I group but it is weaker than nitro group

3. phenol is more acidic than cyclohexanol due to resonance stabilization of resonance and among halogen F>Cl>Br>I is the order of acidity

4. cyclohexanol will be weakest as  it is not associated with any -I groups here.

so the order of acidity will be

(a). 4-nitropheno >  (d). 4-bromophenol > (c). 2,6-difluorocyclohexanol  >               (b). cyclohexanol

Calculate the volume in milliliters of 1.57 M potassium hydroxide that contains 10.3 g of solute.

Answers

Answer:

[tex]V = 0.117 \ L[/tex]

General Formulas and Concepts:

Chem

Reading a Periodic TableWriting compounds and polyatomic ionsMolarity = moles of solute / liters of solution

Explanation:

Step 1: Define

1.57 M KOH (potassium hydroxide)

10.3 g KOH

Step 2: Define conversions

Molar Mass of K - 39.10 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of KOH - 39.10 + 16.00 + 1.01 = 56.11 g/mol

Step 3: Convert

[tex]10.3 \ g \ KOH(\frac{1 \ mol \ KOH}{56.11 \ g \ KOH} )[/tex] = 0.183568 mol KOH

Step 4: Solve for Volume

Substitute:                    [tex]1.57 \ M=\frac{0.183568 \ mol}{x \ L}[/tex]Move x:                         [tex]x1.57 \ M=0.183568 \ mol[/tex]Isolate x:                       [tex]x=\frac{0.183568 \ mol}{1.57 \ M}[/tex]Evaluate:                      [tex]x=0.116922 \ L[/tex]

Step 5: Check

We are given 3 sig figs. Follow sig fig rules.

[tex]0.116922 \ L \approx 0.117 \ L[/tex]

The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.

Answers

Answer:

1.86 M

Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

Volume of solution = 35.5 mL

Molarity of solution =?

Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)

= 144 + 22 + 176

= 342 g/mol

Mole of C12H22O11 =?

Mole = mass /Molar mass

Mole of C12H22O11 = 22.5 /342

Mole of sucrose (C12H22O11) = 0.066 mole

Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

35.5 mL = 35.5 mL × 1 L / 1000 mL

35.5 mL = 0.0355 L

Thus, 35.5 mL is equivalent to 0.0355 L.

Finally, we shall determine the molarity of the solution as follow:

Mole of sucrose (C12H22O11) = 0.066 mole

Volume of solution = 0.0355 L.

Molarity of solution =?

Molarity = mole /Volume

Molarity of solution = 0.066/0.0355

Molarity of solution = 1.86 M

Therefore, the molarity of the solution is 1.86 M.

Which elements-O2, Rb, Sb, Pt, Y, Sm, Mn, Rh, Sn, Li-will react (a) with a solution of I to generate I2; (b) with a solution of Ag' to generate Ag; and (c) with a solution of Nat to generate Na?

Answers

Answer:

a) O2, Pt, Rh

b) Rb, Y, Sm, Mn, Sn, Li

c)Rb

Explanation:

We must consider the reduction potentials of each of the species in the question.

In (a) above, all the elements whose reduction potential is higher than the redox potential for the oxidation of I^- will react with a solution of I^- to generate I2 as shown above.

In (b) above, all the strong reducing agents can donate electrons to Ag^+ and reduce it to Ag as shown above.

In (c) Rb has a more negative reduction potential than sodium hence it can react with a solution of sodium salt to generate sodium metal.

Identify the necessary parts to build a calorimeter. Select one or more:________ A. Cover. B. An interior paper cup. C. Thermometer. D. An interior styrofoam cup. E. An exterior paper cup An exterior styrofoam cup Conductivity probe.

Answers

Answer:

Explanation:

A calorimeter is an instrument used for measuring the heat of reactions and heat capacity. A calorimeter should contain an insulating cover, a thermometer, styrofoam cups (you could have that both on the inside and the outside in the case of a styrofoam calorimeter) and you could also have a conductivity probe (in the form of ignition wires and bulb).

A calorimeter is the analytical device used to measure the heat of the reaction. The construction of calorimeter requires cover, paper cup, thermometer, styrofoam cup, and conductivity probe.

How to build a calorimeter?

In a chemical reaction, the amount of heat released or absorbed by the reaction helps in the analysis of various parameters. The calorimeter measures the heat of the reaction.

The construction of a calorimeter requires:

Paper can for  the filling of water.Cover to stop the loss of heatStyrofoam cup to allow the reactionThermometer to measure the change in temperatureConductivity probe to allow the transfer of heat energy

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For the following reaction at equilibrium SO3(g) + NO(g) = SO2(g) + NO2(g)It is found that [SO2] = 0.70 M and [NO] = 1.20 M. Calculate the equilibrium constant for the readction knowing that the initial concentration were [SO3] = 2.55 M and [NO] = 1.90 M.

Answers

Answer:

[tex]K=0.14[/tex]

Explanation:

Hello!

In this case, for the undergoing chemical reaction, we can write the equilibrium expression via:

[tex]K=\frac{[SO_2][NO_2]}{[SO_3][NO]}[/tex]

Whereas the equilibrium concentration of both SO3 and NO are 2.55 M and 1.90 M respectively, it means that the extent of reaction [tex]x[/tex] is:

[tex]x=1.90M-1.20M=0.7M[/tex]

Because the equilibrium expression in terms of the reaction extent is:

[tex]K=\frac{x*x}{([SO_3]_0-x)([NO]_0-x)}[/tex]

It means that the concentration of SO3, NO, SO2 and NO2 at equilibrium are:

[tex][SO_3]=2.55M-0.70M=1.85M[/tex]

[tex][NO]=1.20M[/tex]

[tex][SO_2]=0.70M[/tex]

[tex][NO_2]=0.70M[/tex]

Thus, the equilibrium constant for such reaction is:

[tex]K=\frac{0.70*0.70}{1.85*1.90}\\\\K=0.14[/tex]

Best regards!

For a particular reaction, the change in enthalpy is â9kJmole and the activation energy is 13kJmole. The enthalpy change (ÎH) and activation energy (Ea) for the catalyzed reaction could be which of the following? a. â9kJmole,5kJmole. b. â9kJmole,19kJmole.c. â14kJmole,5kJmole.d. â14kJmole,â13kJmole.

Answers

Answer:

The answer is Option a, that is "−9kJmole,5kJmole".

Explanation:

Please find the complete question in the attached file.

In the question, it uses the catalyst inside a process, which does not modify the process eigenvalues, however, it decreases the active energy with an enthalpy of -9kJmole, and also the power for activating decreases around 13 to 5 kJ mole, that's why the choice a is correct.

7.46 - A 0.0500-mol sample of a nutrient substance is burned in a bomb calorimeter containing 2.00 x 10g H20. If the formula weight of this nutrient substance is 114 g/mol, what is the fuel value (in nutritional Cal) if the temperature of the water increased 5.70C?​

Answers

Answer:

[tex]200\frac{kcal}{g}[/tex]

Explanation:

Hello!

In this case, for this calorimetry problem, since the combustion 0.0500 mol of the nutrient increase the temperature of water by 5.70 °C, we can notice that the heat lost by the nutrient is gained by water in order to write:

[tex]Q_{nutrient}=-Q_{water}[/tex]

Which can be also written as:

[tex]Q_{nutrient}=-m_{water}C_{water}\Delta T_{water}\\\\Q_{nutrient}=-200 g*4.184\frac{J}{g\°C}*5.70\°C\\\\Q_{nutrient}=4769.8 J[/tex]

Thus, in terms of the grams of the nutrient:

[tex]m_{nutrient}=0.0500mol*\frac{114g}{1mol}=5.70g[/tex]

The fuel value in nutritional Cal (kcal/g) turns out:

[tex]Fuel \ Value=\frac{-4.7698kJ}{5.70g}*\frac{1kcal}{4.184kJ}=200\frac{kcal}{g}[/tex]

Best regards!

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