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Find the slope of each line using the rise/run formula.​

Answer:

I believe it is 14 mm, hope i helped

Answer:

Area of table with leaf = 28.56 feet²

Area of table without leaf = 16 feet²

Step-by-step explanation:

Given:

Side of square table = 4 feet

Diameter of side leaf = 4 feet

Number of semicircle leaf = 2

Find:

Area of table without leaf

Area of table with leaf

Computation:

Area of square = Side x Side

Area of table without leaf = 4 x 4

Area of table without leaf = 16 feet²

Radius of side leaf = Diameter of side leaf / 2

Radius of side leaf = 4 / 2

Radius of side leaf = 2 feet

Area of table with leaf = Area of table without leaf + 2[πr²/2]

Area of table with leaf = 16+ 2[πr²/2]

Area of table with leaf = 16+ (3.14)(2)²

Area of table with leaf = 16+ (3.14)(4)

Area of table with leaf = 16+ 12.56

Area of table with leaf = 28.56 feet²

Answer:

let the two no. be x and y.

their sum

x+y=-11

x=-11-y.....[I]

and difference

x-y=41

x=41+y......[ii]

equating equation I and ii

we get

-11-y=41+y

-11-41=y+y

-52=2y

y=-52/2

y=-26

now

substituting value of y in equation I.

we get

x=-11-(-26)=-11+26=15

The two no. is 15 and -26.

Answer:

168cm^3

Step-by-step explanation:

area of a cube is B*H*L

(6)*(7)*(4) = area

168cm^3 = area

Answer:

168 cm³

Step-by-step explanation:

V = w · h · l

4 · 6 · 7

V = 168

Answer:

-78.91  -100.553  -23.965

Step-by-step explanation:

-15.85 - 63.06 = -78.91

-15.85 -84.703 = -100.553

-15.85 -8.115 = -23.965

Answer:

138 is closest to the  Lateral surface which is 113.097

Step-by-step explanation:

Answer:

7n

Step-by-step explanation:

Let :

The number of hours of practice per day = n

The number of practice hours in 7 days can be calculated thus :

Number of hours of practice per day * number of days

(n * 7) = 7n

Answer:

A = 66×6 cm²

Step-by-step explanation:

Given that,

The width of a rectangular garden, w = (6x2) cm

The length of a rectangular garden, l = (11x2) cm

We need to find the area of Ms. Alberta’s garden. The area of a rectangular garden is given by :

A = LW

Put all the values,

A = (6x2) × (11x3)

= (11×6)(2×3)

= 66×6 cm²

Hence, the area of the Ms. Alberta’s garden is 66×6 cm².

Answer:

y = 4x - 3

Step-by-step explanation:

Find two point of the line

(0,-3) ; (1,1)

Use this formula

(y - y1)/(y2-y1) = (x-x1)/(x2-x1)

(y-(-3)/(1-(-3) = (x-0)/(1-0)

(y+3)/4 = x

y+3 = 4x

y = 4x -3

Answer:

y = 4x -3

Step-by-step explanation:

The y intercept is (0,-3)

Using another point on the line (1,1), we can find the slope

m = (y2-y1)/(x2-x1)

m = (1 - -3)/(1-0)

   = (1+3)/(1-0)

   = 4/1

The equation for a line in slope intercept for is

y = mx+b where m is the slope and b is the y intercept

y = 4x -3

Answer:

[tex](a)\ 9 * 27[/tex]

[tex](b)\ 81 * 3[/tex]

[tex](d)\ 3*3*3*3*3[/tex]

Step-by-step explanation:

Given

[tex]3^5[/tex]

Required

Select equivalent expressions

[tex](a)\ 9 * 27[/tex]

Express as exponents

[tex]9 * 27 = 3^2 * 3^3[/tex]

Apply law of indices

[tex]9 * 27 = 3^{2+3[/tex]

[tex]9 * 27 = 3^{5[/tex]

[tex](b)\ 81 * 3[/tex]

Express as exponents

[tex]81 * 3 = 3^4 * 3[/tex]

Apply law of indices

[tex]81 * 3 = 3^{4+1[/tex]

[tex]81 * 3 = 3^5[/tex]

[tex](c)\ 3*5[/tex]

Solve

[tex]3*5 = 15[/tex]

[tex](d)\ 3*3*3*3*3[/tex]

From calculator, we have

[tex]3*3*3*3*3=243[/tex]

Express as exponents

[tex]3*3*3*3*3=3^5[/tex]

[tex](e) 9 * 9[/tex]

Express as exponents

[tex]9 * 9= 3^2 * 3^2[/tex]

Apply law of indices

[tex]9 * 9= 3^{2+2[/tex]

[tex]9 * 9= 3^4[/tex]

Hence, a, b and d are true

============================================================

Explanation:

Let's expand this out up to say n = 6 terms

I'll write the summation in such a way that each (1/(k+1) - 1/k) grouping will get its own row. Each row has the same value of k.

If we plug in k = 1 through k = 6, but not evaluate just yet, we will have this:

1/(1+1) - 1/1

1/(2+1) - 1/2

1/(3+1) - 1/3

1/(4+1) - 1/4

1/(5+1) - 1/5

1/(6+1) - 1/6

All I've done so far is replace k with 1 through 6. Again, each row represents a different k value. Each row has the general format 1/(k+1)-1/k.

Let's simplify everything in the first column.

So the (1+1) turns into 2, the (2+1) turns into 3, and so on.

Doing that leads to...

1/2 - 1/1

1/3 - 1/2

1/4 - 1/3

1/5 - 1/4

1/6 - 1/5

1/7 - 1/6

Then note how we have the cancellations shown in the diagram below. The color coding shows how the terms pair up to cancel out. By "cancel out", I mean specifically that the fractions add up to 0. Eg: 1/2 + (-1/2) = 0.

Nearly everything cancels out. The only things left after the dust settles is the -1/1 in the first row and the 1/7 in the bottom row. This evaluates to 1/7-1/1 = 1/7 - 7/7 = (1-7)/1 = -6/7

If you were to try this with n = 7, then you should find that again nearly everything cancels but the fractions -1/1 and 1/8. Then 1/8 - 1/1 = -7/8.

For n = 8, you should end up with 1/9 - 1/1 = -8/9.

You can probably see the pattern.

A conjecture is that the answer is -n/(n+1). The general proof of this isn't too tricky. Simply follow the same ideas as mentioned above. Expand out a few terms and see how things cancel out. You'll find that everything cancels except for the -1/1 in the first row and the 1/(n+1) just one term before the very end. Then we can say:

1/(n+1) - 1/1

1/(n+1) - (n+1)/(n+1)

(1-(n+1))/(n+1)

(1-n-1)/(n+1)

-n/(n+1)

If we tried n = 6, then we find,

-n/(n+1) = -6/(6+1) = -6/7

which was the result we found earlier when we added the first n = 6 terms of this series. Trying out n = 7 should lead to -n/(n+1) = -7/8, and so on.

Answer:

the area is 207

Step-by-step explanation:

The equation to solve the area of a cylinder is A=2πrh+2πr^2

The radius is the length from the outside to the center, 6 is the diameter so we could half that to get the radius, 3 and height is 8

A=2*3.14*3*8+2*3.14*3^2

A=6.28*3*8+6.28*9

A=18.84*8+56.52

A=150.72+56.52

A=207.24

207.24 rounded to the nearest whole number is 207 so your area is 207

Answer:

$3,220

Step-by-step explanation:

Add

Answer:

1. x=11

2. x=10

Answer:

Step-by-step explanation:

To answer quickly, I would assume that x in the first equation equals 11 since

4 x 11 = 44.

And for the second one, 20 x 10 = 200.

First equation x = 11

Second equation x = 10

Good luck!

Answer:

could you please also post what the choosing options are and then ill edit this and do it again

Step-by-step explanation:

Answer:

[tex]\cos{W} = \frac{9}{41}[/tex]

Step-by-step explanation:

Cosine of an angle:

The cosine of an angle, in a right triangle, is the length of the side adjacent to this angle divided by the hypotenuse.

Length of the largest side:

The length of the largest side is 41, that is, the hypotenuse is 41. The hypotenuse is XW.

WY = 9.

This means that the length of the adjacent side to angle W is 9.

What ratio represents the cosine of ∠W?

Adjacent side has length 9, hypotenuse has length 41. So

[tex]\cos{W} = \frac{9}{41}[/tex]

Answer:

Step-by-step explanation:

Answer:

Solution given:

l=8cm

b=8cm

h=3cm

now

total surface area=2(lb+bh+lh)

=2(8*8+8*3+8*3)=224cm²

224 cm² is a required volume.

Answer:

[tex]A = 329.7[/tex]

Step-by-step explanation:

Given

[tex]h = 15[/tex] --- height

[tex]d = 7[/tex] --- diameter

Required

Paper needed to cover the sides

To do this, we simply calculate the surface area of the cylinder (without considering the top and bottom)

This is calculated as:

[tex]A = 2\pi rh[/tex]

Where

[tex]r = \frac{d}{2}[/tex]

[tex]r = \frac{7}{2}= 3.5[/tex]

The formula becomes

[tex]A = 2 * 3.14 *3.5 *15[/tex]

This gives:

[tex]A = 329.7[/tex]

:1

i didnt understand the question because of my English sorry

:2

we all know that the total of degrees is 180 so 70+70=140

180-140=40

so the answer is 40

3:

we have a figure with 4 angle so the total of degrees is 360 so the answer is 126

4:

the answer most be 50 becuse we have a Special degree witch always equal 90 if we have recatngle so

x+40=90

X=50 the answer and if you want to try again choose the second one

2x-10=90

2x=100

X=50 same answe you see

5:

in this quastion i searched and find alot of answers any way

its should be 7 or 3 but the correct answer in my opinion its 7

its shows in the picture i sent hopefully its helpful to you i will try to translate the first quastion and sent it to you

9514 1404 393

Answer:

  y = -4x -2

Step-by-step explanation:

The slope is given by the formula ...

  m = (y2 -y1)/(x2 -x1)

  m = (-10 -10)/(2 -(-3)) = -20/5 = -4

__

The y-intercept is given by ...

  b = y1 -m(x1)

  b = 10 -(-4)(-3) = 10 -12 = -2

Then the slope-intercept equation is ...

  y = mx +b

  y = -4x -2

Answer:

Step-by-step explanation:

Answer:

2183475 dont know

Step-by-step explanation:

Answer:

15x = 58y

Step-by-step explanation:

If 2 and 5 are 3 distance apart then 12 and 15 are 3 distance apart.

the difference between 2 and 5 is 5 because 86-81 is 5. So if we subtract 63-5 we will get 58

Hope this helps! Please leave any questions or concerns in the comments byeee <3

Answer:

20 and 90

Step-by-step explanation:

Answer:

49/144

Step-by-step explanation:

Answer:

49/144

Step-by-step explanation:

Answer:

a) the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b)

- the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

- the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

- the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

Step-by-step explanation:

Given the data in the question;

proportion p = 0.6

sample size n = 10

binomial distribution

let x rep number of orders for raw materials arriving late in the sample.

(a) probability of committing a type I error if the true proportion is  p = 0.6;

∝ = P( type I error )

= P( reject null hypothesis when p = 0.6 )

= ³∑[tex]_{x=0[/tex] b( x, n, p )

= ³∑[tex]_{x=0[/tex] b( x, 10, 0.6 )

= ³∑[tex]_{x=0[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.6)^x[/tex][tex]( 1 - 0.6 )^{10-x[/tex]

∝ = 0.0548

Therefore, the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b)

the probability of committing a type II error for the alternative hypotheses p = 0.3

β = P( type II error )

= P( accept the null hypothesis when p = 0.3 )

= ¹⁰∑[tex]_{x=4[/tex] b( x, n, p )

= ¹⁰∑[tex]_{x=4[/tex] b( x, 10, 0.3 )

= ¹⁰∑[tex]_{x=4[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.3)^x[/tex][tex]( 1 - 0.3 )^{10-x[/tex]

= 1 - ³∑[tex]_{x=0[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.3)^x[/tex][tex]( 1 - 0.3 )^{10-x[/tex]

= 1 - 0.6496

= 0.3504

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

the probability of committing a type II error for the alternative hypotheses p = 0.4

β = P( type II error )

= P( accept the null hypothesis when p = 0.4 )

= ¹⁰∑[tex]_{x=4[/tex] b( x, n, p )

= ¹⁰∑[tex]_{x=4[/tex] b( x, 10, 0.4 )

= ¹⁰∑[tex]_{x=4[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.4)^x[/tex][tex]( 1 - 0.4 )^{10-x[/tex]

= 1 - ³∑[tex]_{x=0[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.4)^x[/tex][tex]( 1 - 0.4 )^{10-x[/tex]

= 1 - 0.3823

= 0.6177

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

the probability of committing a type II error for the alternative hypotheses p = 0.5

β = P( type II error )

= P( accept the null hypothesis when p = 0.5 )

= ¹⁰∑[tex]_{x=4[/tex] b( x, n, p )

= ¹⁰∑[tex]_{x=4[/tex] b( x, 10, 0.5 )

= ¹⁰∑[tex]_{x=4[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.5)^x[/tex][tex]( 1 - 0.5 )^{10-x[/tex]

= 1 - ³∑[tex]_{x=0[/tex] [tex]\left[\begin{array}{ccc}10\\x\\\end{array}\right][/tex][tex](0.5)^x[/tex][tex]( 1 - 0.5 )^{10-x[/tex]

= 1 - 0.1719

= 0.8281

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

The probability of committing a type I is 0.0548, type II error for  p = 0.3 is 0.3504, type II error for p = 0.4 is 0.6177, type II error for s p = 0.5 is 0.8281.

The sample size n = 10

Binomial distribution summarizes the number of trials, or observations when each trial has the same probability of attaining one particular value.

[tex]\rm p= \left[\begin{array}{ccc}n\\x\\\end{array}\right] \times p^{x} \times q^{n-x}[/tex]

(a) Probability of committing a type I error if the true proportion is  p = 0.6;

∝ = P( type I error )

= P( reject null hypothesis when p = 0.6 )

[tex]\rm p= \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.6^{x} \times 0.6^{10-x}\\[/tex]

∝ = 0.0548

Therefore, the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b) The probability of committing a type II error for the alternative hypotheses p = 0.3

β = P( type II error )

= P( accept the null hypothesis when p = 0.3 ) = ¹⁰∑

[tex]\rm p= \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.3^{x} \times 0.3^{10-x}\\[/tex]

= 1 - ³∑

= 1 - 0.6496

= 0.3504

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

The probability of committing a type II error for the alternative hypotheses p = 0.4

β = P( type II error )

= P( accept the null hypothesis when p = 0.4 )

[tex]\rm \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.4^{x} \times 0.4^{10-x}\\[/tex] = ¹⁰∑

= 1 - ³∑

= 1 - 0.3823

= 0.6177

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

The probability of committing a type II error for the alternative hypotheses p = 0.5

β = P( type II error )

= P( accept the null hypothesis when p = 0.5 )

¹⁰∑ = [tex]\rm \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.5^{x} \times 0.5^{10-x}\\[/tex]

= 1 - ³∑

= 1 - 0.1719

= 0.8281

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

Learn more about Binomial distribution here:

https://brainly.com/question/12734585

Answer:

12

Step-by-step explanation:

i think that is the answer