The ratio which represents the, scale of the map is 1 cm : 2 km.
Every centimeter on the map represents 2 kilometers on Earth's surface. It provides a convenient way to understand the relative distances and sizes of features on the map compared to their actual counterparts on Earth.
To determine the scale of the map, we need to find the ratio that represents how the map measurements compare to actual ones on Earth's surface. In this case, every 3 cm on the map corresponds to 6 km on Earth's surface.
We can set up a ratio using the given information:
3 cm on the map corresponds to 6 km on Earth's surface.
Let's simplify this ratio. Since 3 cm represents 6 km, we can divide both sides of the ratio by 3 to obtain:
1 cm on the map corresponds to 2 km on Earth's surface.
Therefore, the scale of the map is 1 cm : 2 km.
This means that every centimeter on the map represents 2 kilometers on Earth's surface. It provides a convenient way to understand the relative distances and sizes of features on the map compared to their actual counterparts on Earth. For example, if a road on the map measures 5 cm, its actual length on Earth would be 10 km based on the scale.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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A rocket has been fired upward to launch a stellite in its orbit name two forces acting on the rocket immediately after leaving the launching pad
Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.
1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.
This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.
2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.
The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.
Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.
However, the thrust force continues to be the dominant force propelling the rocket upward.
It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.
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Do this question by electric flux
A conducting sphere of radius 10cm has an unknown charge. If the electric field 20 cm from the centre of the sphere is [tex]1.5*10^{3}[/tex] N/C and points radially inwards what is the net charge on the sphere.
Answer:
To find the net charge on the sphere using electric flux, we can use the formula:
Φ = Q/ε0
Where Φ is the electric flux, Q is the charge, and ε0 is the permittivity of free space.
Given that the electric field 20 cm from the center of the sphere is N/C and points radially inwards, we can use the formula for electric field due to a charged sphere to find the charge on the sphere:
E = kQ/r^2
Where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the center of the sphere.
Substituting the given values, we get:
20 = (1/4πε0)(Q)/(0.2)^2
Solving for Q, we get:
Q = (20)(0.2)^2(4πε0)
Q = 0.64πε0 C
Now, substituting this value of Q in the formula for electric flux, we get: Φ = Q/ε0 = (0.64πε0)/(ε0) = 0.64π C
Therefore, the net charge on the sphere is 0.64π C.
a compound having 44 total atoms consists of 11 atoms of element x and 33 atoms of element y find the % element x in the compound
A. 11%
B. 33%
C. 25%
D. 44%
E. 22%
The % element x in the compound is option c.25%.
To find the percentage of element X in the compound, we need to calculate the ratio of the number of atoms of element X to the total number of atoms in the compound and then convert it to a percentage.
Given:
Total number of atoms = 44
Number of atoms of element X = 11
To calculate the percentage, we can use the following formula:
Percentage of element X = (Number of atoms of element X / Total number of atoms) * 100
Substituting the given values, we get:
Percentage of element X = (11 / 44) * 100
Simplifying the equation, we have:
Percentage of element X = 0.25 * 100
Percentage of element X = 25%
Therefore, the percentage of element X in the compound is 25%.
The correct answer is option C. 25%.
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Voltage
Depends on the amount of resistance
Depends on the amount of current
Is the measurement of electrical pressure
All of the above
Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.
According to the Ohm's Law, the current through a conductor between two points is directly proportional to the voltage across the two points.
Mathematically,
V ∝ I
V = IR
where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.
Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.
Hence All of the above option in the given question are true.
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