On a December day, the probability of snow is .30. The probability of a "cold" day is .50. The probability of snow and a "cold" day is .15. Are snow and "cold" weather independent events?
a. no
b. yes
c. only if given that it snowed
d. only when they are also mutually exclusive

The recurrence relation for the total amount of money in the savings account at the end of n months can be expressed using a recursive formula that takes into account the monthly deposits and the compounded interest. Let A_n be the total amount of money in the account at the end of the nth month. Then, we have:

A_n = A_{n-1} + 100 + (0.06/12)*A_{n-1}

Here, A_{n-1} represents the total amount of money in the account at the end of the (n-1)th month, which includes the deposits made in the previous months and the accumulated interest. The term 100 represents the deposit made at the beginning of the nth month.

The term (0.06/12)*A_{n-1} represents the interest earned on the balance in the account at the end of the (n-1)th month, assuming a monthly interest rate of 0.06/12.

Using this recursive formula, we can calculate the total amount of money in the account at the end of each month, starting from the initial balance of $0. For example, we can calculate A_1 = 100 + (0.06/12)*0 = $100, which represents the balance at the end of the first month.

Similarly, we can calculate A_2 = A_1 + 100 + (0.06/12)*A_1 = $206, which represents the balance at the end of the second month. We can continue this process to calculate the balances at the end of each month up to the nth month.

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If A and B are mutually exclusive, then the correct answer is c. P(A ∩ B) = 0. This is because mutually exclusive events cannot occur at the same time, meaning the intersection of the events is empty. Therefore, the probability of A and B occurring together is zero.

To explain further, if A represents the event of flipping heads on a coin and B represents the event of flipping tails on the same coin, then these events are mutually exclusive because both cannot occur at the same time. The probability of flipping heads or tails on a coin is 1, but the probability of flipping heads and tails simultaneously is 0. Therefore, P(A ∩ B) = 0.

It is important to note that if A and B are mutually exclusive, then P(A) + P(B) = 1, which is answer choice d. This is because one of the events must occur, but not both. Therefore, the total probability of either A or B occurring is 1. However, this does not directly answer the question about the probability of the intersection of A and B.

Overall, when working with mutually exclusive events, it is important to recognize that they cannot occur at the same time and therefore have no intersection, which makes the probability of A and B occurring together equal to 0.

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If A and B are mutually exclusive events, this signifies that they cannot both happen simultaneously. Therefore, the probability of both events occurring, expressed as P(A ∩ B), is equal to 0.

If A and B are mutually exclusive, it means that events A and B cannot occur at the same time. In terms of probability, we express this statement as: the probability that both A and B occur, denoted by P(A ∩ B), is equal to 0. Hence the correct answer is: c. P(A ∩ B) = 0.

This is fundamental in the study of probability and is crucial for understanding more complex concepts such as conditional probability and independence of events.

It's important to note that answers a, b and d are incorrect. Answer a, P(A) + P(B) = 0, implies that neither event can happen which contradicts the definition of mutually exclusive events. Answer b, P(A ∩ B) = 1, implies that A and B must always occur together, which is the exact opposite of what mutual exclusivity means. Answer d, P(A) + P(B) = 1, would be correct if A and B were exhaustive events, which means that either event A or event B is certain to occur.

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a. the inverse function g(x) is: g(x) = (x + 2)/3

b. the inverse function g(x) is: g(x) = [tex]x^2 + 3[/tex]

What is inverse fucntion?

An inverse function is a function that "undoes" the action of another function. More specifically, if a function f takes an input x and produces an output f(x), then its inverse function, denoted f^(-1), takes an output f(x) and produces the original input x.

a. f(x) = 3x - 2

To find the inverse of f(x), we first replace f(x) with y:

y = 3x - 2

Next, we solve for x in terms of y:

y + 2 = 3x

x = (y + 2)/3

So the inverse function g(x) is:

g(x) = (x + 2)/3

To sketch f(x) and g(x) and show that they are symmetric with respect to the line y=x, we plot them on the same coordinate plane.

Graph of f(x) and g(x):

The blue line represents f(x) and the green line represents g(x). As we can see, the two lines are symmetric with respect to the line y=x, which is the dashed diagonal line passing through the origin. This means that if we reflect any point on the blue line across the line y=x, we will get the corresponding point on the green line, and vice versa.

[tex]b. f(x) = \sqrt(x - 3)[/tex]

To find the inverse of f(x), we first replace f(x) with y:

[tex]y = \sqrt(x - 3)[/tex]

Next, we solve for x in terms of y:

[tex]y^2 = x - 3\\\\x = y^2 + 3[/tex]

So the inverse function g(x) is:

[tex]g(x) = x^2 + 3[/tex]

To sketch f(x) and g(x) and show that they are symmetric with respect to the line y=x, we plot them on the same coordinate plane.

Graph of f(x) and g(x):

The red curve represents f(x) and the blue curve represents g(x). As we can see, the two curves are symmetric with respect to the line y=x, which is the dashed diagonal line passing through the point (3,0). This means that if we reflect any point on the red curve across the line y=x, we will get the corresponding point on the blue curve, and vice versa.

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Since f(-1) is positive and f(5) is negative, by the IVT, there must exist at least one value c in the interval [-1, 5] where f(c) = 0. This means that the function f(x) = x² - 4x has a zero on the interval [-1, 5].

Yes, we can use the Intermediate Value Theorem (IVT) to say that there is a zero of the function f(x) = x² - 4x on the interval [-1, 5].

The IVT states that if f(x) is a continuous function on the closed interval [a, b] and if k is any number between f(a) and f(b), then there exists at least one value c in the interval [a, b] such that f(c) = k.

In this case, we can evaluate f(-1) and f(5) to determine the sign of f(x) at the endpoints of the interval:

f(-1) = (-1)² - 4(-1) = 5

f(5) = 5² - 4(5) = -5

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Answer:

Step-by-step explanation:

80%

The values of x and y are given as follows:

x = y = 5.

The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

The theorem is expressed as follows:

c² = a² + b².

In which:

The diagonal length of the rectangle is the hypotenuse of a right triangle of sides 6 and 8, hence:

d² = 6² + 8²

d² = 100

d = 10.

The segments x and y are each half the length of the diagonal, and the two diagonals have the same length for a rectangle, hence:

x = y = 5.

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The measure of the missing angle which is named ∠PQR = 84°

The first step to solving the problem is to identify the nature of the triangle.

Note that the information states that:

Side PQ and QR are equal,
This means that it is an isosceles triangle because only isosceles triangles have two equal sides.

Another property of isosceles triangles that will help determine the m∠PQR is that the angles at the base of those equal sides are always equal.

Since that is true, then,

∠PQR = 180 - (QPR x 2 )

We know ∠QPR is 48°, so


∠PQR = 180 - (48x 2 )

∠PQR = 180 - 96

Thus,

∠PQR = 84°

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Full Question:

Although part of your question is missing, you might be referring to this full question:

See attached image.

To determine the partial fraction expansion for a rational function, we need to express it as a sum of simpler fractions. However, the general process for finding the partial fraction expansion of a rational function is as follows:

1. Factor the denominator of the rational function into linear and/or quadratic factors.
2. Write the rational function as a sum of fractions, one for each factor of the denominator. For each linear factor, use a constant numerator. For each quadratic factor, use a linear numerator.
3. Solve for the constants using algebraic manipulation and equating the numerators of the partial fractions with the original numerator of the rational function.
4. Write the partial fraction expansion as the sum of the fractions found in step 2 with the constants found in step 3.

For example, if the rational function is (3x^2 + 5x + 2)/(x^2 + 4x + 3), we would first factor the denominator as (x + 3)(x + 1). Then we would write the partial fraction expansion as:

(3x^2 + 5x + 2)/(x^2 + 4x + 3) = A/(x + 3) + B/(x + 1)

To solve for A and B, we would equate the numerators:

3x^2 + 5x + 2 = A(x + 1) + B(x + 3)

Expanding and equating coefficients, we get:

3 = B + A
5 = 3B + A

Solving for A and B, we get:

A = 1
B = 2

Therefore, the partial fraction expansion of (3x^2 + 5x + 2)/(x^2 + 4x + 3) is:

(3x^2 + 5x + 2)/(x^2 + 4x + 3) = 1/(x + 3) + 2/(x + 1)

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We cannot rule out the null hypothesis that the population means the weight is equal to 100 lb based on the critical value rule at = 0.01.

A one-sample t-test can be used to evaluate whether we can rule out the null hypothesis that the population's average weight is 100 lb.

First, we need to calculate the test statistic t:

[tex]$t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}}$[/tex]

[tex]$t = \frac{(102 - 100)}{\frac{10}{\sqrt{25}}} = 2$[/tex]

The critical value for the t-distribution with 24 degrees of freedom and a significance level of 0.01 must then be determined. To determine this value, we can utilize a t-table or statistical software.

We establish the critical value to be 2.492 using a t-table. We are unable to reject the null hypothesis because our calculated t-value (2) is smaller than the crucial value (2.492).

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Answer:

-15 and -2

Step-by-step explanation:

Two negatives multiply to be a positive. We know -15 • -2 = +30

Combine (add) them and you get -17.

(a) 248 to decimal
Since it's already in decimal form, there's no need for conversion.
Answer: 248

(b) 2416 to decimal (assuming it's a hexadecimal number)
Step 1: Identify the place values of the hexadecimal number (from right to left): 1, 16, 256
Step 2: Multiply the digits by their place values and sum them up: (2 * 256) + (4 * 16) + (1 * 1) = 512 + 64 + 1 = 577
Answer: 577

(c) 2c16 to decimal (assuming it's a hexadecimal number)
Step 1: Identify the place values of the hexadecimal number (from right to left): 1, 16, 256
Step 2: Convert the letter "c" to its decimal equivalent: C = 12
Step 3: Multiply the digits by their place values and sum them up: (2 * 256) + (12 * 16) + (1 * 1) = 512 + 192 + 1 = 705
Answer: 705

(d) 00110011101000112 to hexadecimal
Step 1: Group the binary digits into sets of four from right to left: 0011 0011 1010 0011
Step 2: Convert each group of four binary digits into their corresponding hexadecimal values:
      0011 = 3
      0011 = 3
      1010 = A
      0011 = 3
Step 3: Combine the hexadecimal values: 33A3
Answer: 33A3

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B) Note that in the prompt above, you can use translation to map the line y= 2x -4 onto the line y = 2x + 4.

While you can use axial symmetry in the y -  axis to map the line  y = x onto the line y = -x.

Axial symmetry is symmetry around an axis; an item is axially symmetric if it retains its appearance when rotated around an axis.

A baseball bat with no brand or other design, or a plain white tea saucer, for example, looks the same when rotated by any angle around the line traveling longitudinally through its center, indicating that it is axially symmetric.

A transformation in which the coordinate system's origin is shifted but the orientation of each axis remains constant

So for B) you can use a translation to map the line y = 2x -4 onto the line y = 2x + 4 by shifting the first line 4 units upwards along the y - axis....

mathematically, that would be:

y = 2x - 4 + 4

y = 2x


For C) you can use axial symmetry on the y -  axis to achhieve the mapping of y = x onto y = -x by reflection.

The polar opoppsite of y = x  is y = -x.

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Answer: 5y^2 +3y+12

Step-by-step explanation:

6y^2+3y+1

y^2-11

equals

5y^2+3y+12

The length of the remaining piece of wooden beam after the cut out in terms of polynomial y is 5y² + 3y + 12

Length of the wooden beam = 6y² + 3y + 1

Length cut out from the wooden beam= y² - 11

Length of the remaining piece of beam = Length of the wooden beam - Length cut out from the wooden beam

= (6y² + 3y + 1) - (y² - 11)

= 6y² + 3y + 1 - y² + 11

= 5y² + 3y + 12

Hence, 5y² + 3y + 12 is the remaining length of the wooden beam.

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The value of x in the right triangle with acute angles 8x and 4x + 6 is 7

From the question, we have the following parameters that can be used in our computation:

The right triangle with acute angles 8x and 4x + 6

The sum of acute angles in a right triangle is 90

Using the above as a guide, we have the following:

8x + 4x + 6 = 90

So, we have

12x = 84

Divide by 12

x = 7

Hence, the value of x is 7

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The probability that a fruit picked at random weighs between 443 grams and 492 grams is approximately 0.3695 or 36.95%.

To find the probability that a fruit picked at random weighs between 443 grams and 492 grams, we need to standardize these values using the formula:

z = (x - μ) / σ

where x is the weight of the fruit, μ is the mean weight (438 grams), σ is the standard deviation (17 grams), and z is the standardized score.

For the lower end of the range (443 grams), we have:

z = [tex]\frac{(443 - 438)}{17} = 0.29[/tex]

For the upper end of the range (492 grams), we have:

z = [tex]\frac{(492 - 438)}{17} = 3.18[/tex]

Using a standard normal distribution table or calculator, we can find the probability that a standardized score falls between these values.

The probability of a z-score between 0.29 and 3.18 is approximately 0.3695.

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The slope of the graph is 50, and it represents the rate of change of the total cost of the gym membership per month.

To write an equation for C, the total cost of the gym membership, we can use the slope-intercept form of a linear equation, which is y = mx + b. In this case, y represents the total cost, m represents the slope, x represents the number of months, and b represents the y-intercept (the initial cost of joining the gym).

From the graph, we can see that the initial cost of joining the gym is $700 (the y-intercept), and the monthly fee is $50 (the slope of the line connecting the dots). So, the equation for C is:

C = 50t + 700

where t is the number of months.

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The present age of the Father is 35 and the age of the Son is 15 years after solving the given problem.

By examining the given problem we can solve it in the following way:

Present age:

Let x = Son's present age

x + 20 = Father's present age

5 years ago:

x - 5 = Son's age 5 years ago

x + 20 -5 = father's age 5 years ago

Father's age 5 years ago = 3( Son's age 5 years ago )

x + 20 - 5 = 3 (x - 5)

x + 15 = 3x - 15

2x = 30

x = 15

x = 15, Son's present age

x + 20 = 35 = father's present age.

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If the approximate areas of Colorado and Hawaii are listed as Colorado: 2.7 x 105 square kilometers. The amount  larger is Colorado is: 2.417 x 10^5.

The first step is to divide the area of Hawaii by the area of Colorado and before we do that we must ensure that both of these figures have the same exponent.

So,

2.7 x 10^5 square km - 2.83 x 10^4 square km

2.83 x 10^4 = 0.283 x 10^5

Hence,

2.7 x 10^5 - 0.283 x 10^5

= 2.417 x 10^5

Therefore  Colorado is 2.417 x 10^5 square kilometers larger than Hawaii.

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It will take God approximately 32 days to use up all the gas in his tanker and need a refill.

If God filled his gas tanker with 19/5/9 tank of gas and uses 1 5/6 gallons of gas each day, we can calculate how many days it will take for him to need a refill.

First, we need to convert the mixed number 19/5/9 to an improper fraction:

19/5/9 = (19 * 9 + 5) / 9 = 176/9

So God has 176/9 tanks of gas in his tanker.

Next, we can calculate how much gas God uses each day:

1 5/6 = (6 * 1 + 5) / 6 = 11/6

So God uses 11/6 gallons of gas each day.

To find out how many days it will take for God to need a refill, we can divide the amount of gas in his tanker by the amount of gas he uses each day:

(176/9) / (11/6) = (176/9) * (6/11) = 32

Therefore, it will take God approximately 32 days to use up all the gas in his tanker and need a refill.

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Answer:

Sure, I can help you with that. Here are the steps on how to solve the problem:

1. Let x be the height of the balloon on the left and y be the height of the balloon on the right.

2. Using the tangent function, we can write the following equations:

```

tan(38) = x/700

tan(26) = y/1050

```

3. Solve the first equation for x:

```

x = 700tan(38)

```

4. Substitute this value of x into the second equation:

```

y/1050 = tan(26)

y = 1050tan(26)

```

5. Subtract the two equations to find the difference between the heights of the two balloons:

```

y - x = 1050tan(26) - 700tan(38)

```

6. Evaluate this expression using a calculator and round your answer to the nearest tenth:

```

y - x = 266.51 meters

```

Therefore, the balloon on the right is 266.51 meters higher than the balloon on the left.

Step-by-step explanation:

The correct expansion of (3x – 2)(2[tex]x^2[/tex]  + 5) is 3x *  2[tex]x^2[/tex] + 3x * 5 + (–2) * 2[tex]x^2[/tex]  + (–2) * 5. Thus option A is the most appropriate option as the answer the above question

The expansion of the given algebraic expression follows the distributive rule of multiplication that is (a + b)(c + d) = ac + ad + bc + bd.

Thus the first term of the first expression which is 3x is multiplied by the the second expression and we get 3x • 2[tex]x^2[/tex] + 3x • 5 + (–2)

Then the second term that is -2 is multiplied by the second expression and we get 5 + (–2) • 2[tex]x^2[/tex]  + (–2) • 5

Then we add both expressions and get the answer 3x * 2[tex]x^2[/tex] + 3x * 5 –2 * 2[tex]x^2[/tex]  –2 * 5.

After further simplification of the above expression we get, 6[tex]x^3[/tex] + 15x - [tex]4x^2[/tex] - 10.

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The probability of rolling a single six-sided die and getting a 2, 3, 4, or 5 is:
4/6 or 2/3

To determine the probability of the given outcome or event using the theoretical method, follow these steps:

1. Identify the total number of possible outcomes when rolling a single six-sided die. In this case, there are 6 possible outcomes (1, 2, 3, 4, 5, or 6).

2. Identify the number of successful outcomes, which are the outcomes that meet the criteria of the event. In this case, the successful outcomes are rolling a 2, 3, 4, or 5. There are 4 successful outcomes.

3. Calculate the probability by dividing the number of successful outcomes by the total number of possible outcomes. In this case, the probability is:

Probability = (Number of successful outcomes) / (Total number of possible outcomes)
Probability = 4/6

4. Simplify the fraction if possible. In this case, you can simplify 4/6 to 2/3.

The probability of rolling a single six-sided die and getting a 2, 3, 4, or 5 is 2/3.

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The function that has the greatest x-intercept is the function h(x)

The x-intercept of a function is the x-value of the function when the y-value is 0, which is the set of points at which the graph of the function intersects the x-axis.

The x-intercept of each function are found as follows;

f(x) = 3·x - 9 = 0

x = 9/3 = 3

g(x) = |x + 3| = 0

(x + 3) > 0 and |x + 3| = x + 3 = 0

x = 0 - 3 = -3

|x + 3| < 0 and |x + 3| = -(x + 3) = 0

x = -3

h(x) = 2·x - 16 = 0

x = 16/2 = 8

x = 8

j(x) = -5·(x - 2)² = 0

The x-intercept is x = 2

The function that has the greatest x-intercept is therefore the function h(x) = 2·x - 16

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Answer:

The answer is D.2

Step-by-step explanation:

Can Ihave brainliest bc you said it was worth 13 but it's worth 7 :l

This means that there are 3 students who scored within that range. Therefore, the correct answer is C. 3.

The histogram displays the test scores for the 19 students in the geometry class. To determine how many students scored from 110 to 119 points, we need to look at the height of the bars in that range.

A histogram is a graphical representation of data that displays the frequency or distribution of a set of continuous or discrete variables. It consists of a series of bars, where each bar represents a specific category or range of values, and the height of the bar corresponds to the frequency or count of observations falling within that category or range.

Based on the histogram, we can see that the bar representing the range from 110 to 119 points has a height of 3. This means that there are 3 students who scored within that range. Therefore, the correct answer is C. 3.

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We have shown that if b = 0(mod a) and c = 0(mod b), then c = 0(mod a).

The statement "If b = 0(mod a) and c = 0(mod b), then c = 0(mod a)" is true.

To prove this, we need to show that if b is a multiple of a and c is a multiple of b, then c is a multiple of a.

Suppose that b = ak and c = bk' for some integers k and k'. Then, we have:

c = bk' = (ak)k' = a(kk')

Since k and k' are both integers, their product kk' is also an integer. Therefore, we can write c = a(kk'), which shows that c is a multiple of a.

Hence, we have shown that if b = 0(mod a) and c = 0(mod b), then c = 0(mod a).

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The area of the trapezoid in this problem is given as follows:

C. [tex]A = 96\sqrt{3}[/tex] mm².

The area of a trapezoid is given by half the multiplication of the height by the sum of the bases, hence:

A = 0.5 x h x (b1 + b2).

The bases in this problem are given as follows:

11 mm and 15 + 6 = 21 mm.

The height of the trapezoid is obtained considering the angle of 60º, for which:

We have that the tangent of 60º is given as follows:

[tex]tan{60^\circ} = \sqrt{3}[/tex]

The tangent is the division of the opposite side by the adjacent side, hence the height is obtained as follows:

[tex]\sqrt{3} = \frac{h}{6}[/tex]

[tex]h = 6\sqrt{3}[/tex]

Thus the area of the trapezoid is obtained as follows:

[tex]A = 0.5 \times 6\sqrt{3} \times (11 + 21)[/tex]

[tex]A = 96\sqrt{3}[/tex] mm².

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The expression to calculate the length in minutes of the phone call is:

(length of call in minutes) = (total cost - fixed cost) / (cost per minute)

Where the fixed cost is $1.00 and the cost per minute is $0.15.

Mona's mobile phone plan charges a fixed cost of $1.00 for the first call of the day and an additional $0.15 per minute for the length of the call. To calculate the length of the call in minutes, we need to subtract the fixed cost of $1.00 from the total cost of the call and then divide the result by the cost per minute of $0.15. This gives us the equation:

(length of call in minutes) = (total cost - fixed cost) / (cost per minute)

Substituting the values given in the problem, we get:

Simplifying this expression, we have:

Dividing $1.95 by $0.15 gives us the answer:

Therefore, Mona's phone call lasted 13 minutes.

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The left side of Green's theorem for this vector field and rectangular path is 32.28 ay.

To evaluate the left side of Green's theorem, we need to compute the line integral of the vector field F along the boundary of the region enclosed by the rectangular path C.

First, let's parameterize the rectangular path C as follows:

r(t) = (x(t), y(t)), where 2.8 ≤ x ≤ 8 and 2.1 ≤ y ≤ 7.5.

The boundary of the rectangular path C is composed of four line segments:

From (2.8, 2.1) to (8, 2.1): r(t) = (t, 2.1), where 2.8 ≤ t ≤ 8.

From (8, 2.1) to (8, 7.5): r(t) = (8, t), where 2.1 ≤ t ≤ 7.5.

From (8, 7.5) to (2.8, 7.5): r(t) = (t, 7.5), where 8 ≤ t ≤ 2.8 (note the reverse order).

From (2.8, 7.5) to (2.8, 2.1): r(t) = (2.8, t), where 7.5 ≥ t ≥ 2.1 (note the reverse order).

We can now evaluate the line integral of F along each of these line segments using the parameterization r(t) and the definition of the line integral:

∫_C F · dr = ∫_(C1) F · dr + ∫_(C2) F · dr + ∫_(C3) F · dr + ∫_(C4) F · dr,

where the dot product F · dr is given by:

F · dr = (x dx + y dy) · (dx ax + dy ay) = x dx^2 + y dy^2.

Let's evaluate each of the line integrals separately:

∫_(C1) F · dr = ∫_(2.8)^8 (t ax + 2.1 ay) · dt = (8 - 2.8) ax + 2.1 (0) ay = 5.2 ax

∫_(C2) F · dr = ∫_(2.1)^7.5 (8 ax + t ay) · dt = 8 (7.5 - 2.1) ay + 8 (0) ax = 46 ay

∫_(C3) F · dr = ∫_(8)^2.8 (t ax + 7.5 ay) · (-dt) = (8 - 2.8) ax + 7.5 (0) ay = -5.2 ax

∫_(C4) F · dr = ∫_(7.5)^2.1 (2.8 ax + t ay) · (-dt) = 2.8 (2.1 - 7.5) ay + 2.8 (0) ax = -13.72 ay

Therefore, the line integral of F along the boundary of the rectangular path C is:

∫_C F · dr = ∫_(C1) F · dr + ∫_(C2) F · dr + ∫_(C3) F · dr + ∫_(C4) F · dr = 5.2 ax + 46 ay - 5.2 ax - 13.72 ay = 32.28 ay.

So the left side of Green's theorem for this vector field and rectangular path is 32.28 ay.

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Answer:

(3,1)

Step-by-step explanation:

The correct answer is (b) "Because vertex L' is located at (–2, 6) and vertex N' is located at (4, –2), the length of a side is 10 units."

First, we perform a translation 3 units right and 2 units down. This means we add 3 to the x-coordinates and subtract 2 from the y-coordinates of each vertex:

L' = (-1, 3)

R' = (-2, 1)

N' = (2, -1)

Next, we perform a dilation centered at the origin with a scale factor of 2. This means we multiply the coordinates of each vertex by 2:

L" = (-2, 6)

R" = (-4, 2)

N" = (4, -2)

Now, we can use the distance formula to calculate the lengths of the sides of triangle L'N'R':

L'N' = √[(4+2)² + (-2-6)²] = √[100] = 10

Therefore, the correct answer is (b) "Because vertex L' is located at (–2, 6) and vertex N' is located at (4, –2), the length of a side is 10 units."

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