On (A) select one textbook, cookbooks, magazines, paperbacks poetry, notificationThe pie chart below shows the percentage of total revenue that a publisher receives from various types of publications. Use this chart to answer the questions

On (A) Select One Textbook, Cookbooks, Magazines, Paperbacks Poetry, NotificationThe Pie Chart Below

Answers

Answer 1

Step 1

[tex]Fraction\text{ of paper back+nonfiction +poetry + textbooks take}\approx\text{ }\frac{1}{2}\text{ of the chart}[/tex][tex]\frac{1}{3\text{ }}\text{ of the chart will take }\frac{1}{3}\times360=120^o[/tex]

The only category that accounts for approximately one-third of the publisher's revenue is Magazine because the area it covers is definitely above 90 degrees.

A) Answer- Magazines

Step 2

[tex]Magazines+cookbooks+textbooks\text{ take approximately }\frac{2}{3}\text{ of the chart}[/tex][tex]\begin{gathered} Poetry+nonfiction\text{ + paperbacks take approximately }\frac{1}{3}\text{ of the chart} \\ and\text{ are approxiately equal} \\ 3x=\frac{1}{3} \\ x=\frac{1}{9} \\ The\text{ percentage will be; 100}\times\frac{2}{9}=22.2 \\ \approx20\text{\%} \end{gathered}[/tex]

Step 3

[tex]\begin{gathered} cook\text{books is approximately twice of poetry} \\ If\text{ cookbok takes 16\%, then;} \\ Poetry\text{ will take; }\frac{16}{2}\approx8\text{\%} \end{gathered}[/tex]

On (A) Select One Textbook, Cookbooks, Magazines, Paperbacks Poetry, NotificationThe Pie Chart Below
On (A) Select One Textbook, Cookbooks, Magazines, Paperbacks Poetry, NotificationThe Pie Chart Below

Related Questions

The area of OW is 2897 m2. Find the circumference of OW.A. C= 177 mB. C = 347 mC. C = 687 mD. C=2897 m

Answers

The formula to find the area of a circle is

[tex]\begin{gathered} A=\pi r^2 \\ \text{Where r is the radius and A is the area of the circle} \end{gathered}[/tex]

So as you can see, if you have the area of the circle, you can see get the measure of its radius:

[tex]\begin{gathered} A=289\pi m^2 \\ A=\pi r^2 \\ 289\pi m^2=\pi r^2 \\ \text{ Divide by }\pi\text{ from both sides of the equation} \\ \frac{289\pi m^2}{\pi}=\frac{\pi r^2}{\pi} \\ 289m^2=r^2 \\ \text{ Apply square root to both sides of the equation} \\ \sqrt[]{289m^2}=\sqrt[]{r^2} \\ 17m=r \end{gathered}[/tex]

Now that you have the measure of the radius of the circle, you can obtain its circumference using this formula:

[tex]\begin{gathered} C=2\pi r \\ \text{ Where C is the circumference and} \\ \text{r is the radius of the circle} \end{gathered}[/tex]

So, you have

[tex]\begin{gathered} r=17m \\ C=2\pi r \\ C=2\pi(17m) \\ C=34\pi m \end{gathered}[/tex]

Therefore, the correct answer is option B.

400 ft 175 ft 550 ft What is the area of this trapezoid? square feet

Answers

Let's begin by listing out the information given to us:

[tex]b_1=400ft,h=175ft,b_2=550ft[/tex]

The area of this trapezoid

[tex]\begin{gathered} A=\frac{1}{2}(b_1+b_2)h \\ A=\frac{1}{2}(400+550)\cdot175=\frac{1}{2}(950)\cdot175 \\ A=83125ft^2 \end{gathered}[/tex]

What type of function is the graph?Sqaue RootPiecewiseStepLinearQuadraticExponentialCube RootAbsolute Value

Answers

Let's begin by listing out the given information:

The graph is a curve that crossed the y-intercept

It cannot be a quadratic function. The graph does not cross the x-intercept twice

It cannot be a cube root function. The graph does not cross the x-intercept thrice

It cannot be a linear function because it is not a straight line

The graph is the graph of an exponential function (the graph has the x-axis as an asymptote on the left, and increases very fast on the right)

A nonnative species of fish are taking over a lake in Florida. Each pair of fish creates 30 new fish each year. Scientists predict that there are currently 50 nonnative fish in the lake.
Create a table and graph to model this situation. How long will it take for the nonnative fish population to exceed 1,000,000?

Also please explain why you chose the multiplier you are using for your table/equations.

Answers

The table and the graph of the given model has been created and it will take 3 to 4 years for the nonnative fish population exceed 1000000

Number of nonnative fish in the lake = 50

Each pair of fish creates 30 new fish each year.

The population in one year = (50/2) ×30

= 25×30

= 750

The population in second year = (750/2) × 30

= 375 × 30

= 11250

The population in third year = (11250/2) × 30

= 5625 × 30

= 168750

The population in fourth year = (168750/2) × 30

= 84375 × 30

= 2531250

It will take 3 to 4 years for the nonnative fish population exceed 1000000

Create a table using the values and draw the graph

Hence, the table and the graph of the given model has been created and it will take 3 to 4 years for the nonnative fish population exceed 1000000

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Suppose that Jupiter rotates on its axis once every 10 hours. The equator lies on a circle with a diameter of 88,846 miles.
1
(a) Find the angular speed of a point on its equator in radians per day (24 hours).
(b) Find the linear speed of a point on the equator in miles per day.
Do not round any intermediate computations, and round your answer to the nearest whole number.

Answers

a. The angular speed is 15.08 radians per day

b. The linear speed is v = 669899 miles per day

(a) Find the angular speed of a point on its equator in radians per day (24 hours).

The angular speed is given by ω = 2π/T where T = period of rotation

Now, since Jupiter rotates on its axis once every 10 hours, its period T = 10 hours.

We now convert this to days.

10 h × 1 day/24 h = 5/12 days

Since the angular speed ω = 2π/T,

Substituting the value of the period into the equation, we have

ω = 2π/T

ω = 2π/5/12 days

ω = 2 × 12π/5 days

ω = 24π/5 days

ω = 75.4/5 days

ω = 15.08 radians per day

ω ≅ 15 radians per day

So, the angular speed is 15.08 radians per day

(b) Find the linear speed of a point on the equator in miles per day.

The linear speed v = rω where

r = radius of equator and ω = angular speed of Jupiter

Since the equator lies on a circle with a diameter of 88,846 miles, its radius, r = 88,846 mi/2 = 44423 mi

So,

r = 44423 mi andω = 15.08 rad/day

Substituting the values of the variables into the equation for the linear speed, we have

v = rω

v = 44423 mi × 15.08 rad/day

v = 669898.84 miles per day

v ≅ 669899 miles per day

So, the linear speed is v = 669899 miles per day

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4472^73+10008×273÷6382

Answers

[tex]undefined[/tex]

For a project in statistics class, a pair of students decided to invest in two companies, one that produces software and one that does biotechnology research. Kendall purchased 86 shares in the software company and 11 shares in the biotech firm, which cost a total of $2,056. At the same time, Audrey invested a total of $1,937 in 79 shares in the software company and 11 shares in the biotech firm. How much did each share cost?Each share in the software company cost $? and each share in the biotech firm cost $?

Answers

Answer:

[tex]\begin{gathered} \text{ Each share in the software company cost \$17.} \\ \text{ Each share in the biotech firm cost \$54.} \end{gathered}[/tex]

Step-by-step explanation:

Use a system of linear equations to solve the situation. If Kendall purchased 86 shares in the software company and 11 shares in the biotech firm, which cost a total of $2,056.

[tex]86x+11y=2056[/tex]

At the same time, Audrey invested a total of $1,937 in 79 shares in the software company and 11 shares in the biotech firm.

[tex]79x+11y=1937[/tex]

Let x be the cost of each share in the software company cost.

Let y be the cost of each share in the biotech firm cost.

Solve using the substitution method, isolate one of the variables on one of the equations and plug it into the other equation;

[tex]\begin{gathered} x=\frac{1937}{79}-\frac{11}{79}y \\ Plug\text{ it into the first one:} \\ 86(\frac{1937}{79}-\frac{11}{79}y)+11y=2056 \\ \frac{166582}{79}-\frac{946}{79}y+11y=2056 \\ -\frac{77}{79}y=-\frac{4158}{79} \\ y=\frac{4158*79}{77*79} \\ y=\text{ \$54} \end{gathered}[/tex]

Then, the cost of a share in the biotech firm cost $54. Substitute into the isolated ''x'' equation, and solve for x.

[tex]\begin{gathered} x=\frac{1937}{79}-\frac{11}{79}(54) \\ x=\text{ \$17} \end{gathered}[/tex]

solve for f 8=6+2falgebra

Answers

Given the following question:

To find the answer we need to isolate the variable.

[tex]\begin{gathered} 8=6+2f \\ 2f+6=8 \\ 6-6=0 \\ 8-6=2 \\ 2f=2 \\ \frac{2f}{2}=f \\ 2\div2=1 \\ f=1 \end{gathered}[/tex]

Your answer is f = 1.

How much will you get paid if you work 47 hours ??

Answers

SOLUTION

This question means that if you work for 40 hours, you earn $12 for each hour you work. But if you work for more than 40 hours you earn $12 multiplied by 1.5 for the extra hours after 40 hours.

So if you work for 47 hours, you earn

[tex]\begin{gathered} for\text{ the first 40 hours, we have } \\ 40\text{ hours }\times12\text{ dollars = 480 dollars } \end{gathered}[/tex]

For the extra 7 hours, we have

[tex]1.5\times7\text{ hours }\times12\text{ dollars = 126 dollars }[/tex]

Total money earned becomes

[tex]480+126=606[/tex]

Hence the answer is $606

Answer:

The answer is $606.

7. If x = 8, which equation is true? A) 4x + 6 = 42B) 52 - 6x = 4 C×/2) + 20 = 16

Answers

[tex]\begin{gathered} \text{The options B is correct.} \\ 52-6x=4 \\ \Rightarrow52-6\times8 \\ \Rightarrow52-48 \\ \Rightarrow4 \end{gathered}[/tex]

1+1 Can you help what is it

Answers

Solution:

Given:

[tex]1+1=2[/tex]

When you add 1 plus 1, the result is 2.

multi step equation -3x-2=-1

Answers

x = -1/3

Explanation:

-3x-2=-1

collect like terms by adding +2 to both sides:

-3x -2 + 2 = -1 + 2

-3x = 1

Divide both sides by the coefficient of x:

coefficient of x = -3

-3x/-3 = 1/-3

x = -1/3

If 6 cups of rice will serve 14 people, howmany people can be served with 21/2cups of rice?

Answers

Answer:

24 people

Explanations:

Number of people that can be served with 6 cups of rice = 14

Number of people that can be served with 1 cup of rice = 14/6 = 7/3

Number of people that can be served with 21/2 cups of rice = 21/2 x 7/3

Number of people that can be served with 21/2 cups of rice = 147/6

Number of people that can be served with 21/2 cups of rice = 24.5

24 people can be served with 21/2 cups of rice

what is the behavior of this polynomial ​

Answers

The end behavior of the polynomial y = -x³ + 2x² + x - 2 is described as follows:

The left tail points upward and the right tails points downward.

What is the end behavior of a polynomial?

The end behavior of a polynomial function is given by the limits of the function as x approaches infinity, meaning that only the term with the highest exponent is considered.

These limits are divided into two tails, as follows:

Left tail: x goes to negative infinity.Right tail: x goes to positive infinity.

The function in this problem is given as follows:

y = -x³ + 2x² + x - 2

At the left tail, the limit is given as follows:

lim x -> -∞ f(x) = -(-∞)³ = -(-∞) = ∞.

Hence it points upward.

At the right tail, the limit is given as follows:

lim x -> ∞ f(x) = -(∞)³ = -(∞) = -∞.

Hence it points downward.

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Can I get some help on this i got stuck

Answers

Given:

Given that

[tex]\tan\theta=\sqrt{5}[/tex]

Required:

To find the other five trig ratio.

Explanation:

[tex]\begin{gathered} \tan\theta=\frac{opp}{adj} \\ \\ =\frac{\sqrt{5}}{1} \end{gathered}[/tex]

Now the hypotenuse is,

[tex]\begin{gathered} hyp^2=opp^2+adj^2 \\ \\ hyp^2=5+1 \\ \\ =5+1 \\ \\ =6 \\ \\ hyp=\sqrt{6} \end{gathered}[/tex]

Now,

[tex]\begin{gathered} \sin\theta=\frac{opp}{hyp} \\ \\ =\frac{\sqrt{5}}{\sqrt{6}} \end{gathered}[/tex][tex]\begin{gathered} \cos\theta=\frac{adj}{hyp} \\ \\ =\frac{1}{\sqrt{6}} \end{gathered}[/tex][tex]\begin{gathered} cot\theta=\frac{adj}{opp} \\ \\ =\frac{1}{\sqrt{5}} \end{gathered}[/tex][tex]\begin{gathered} sec\theta=\frac{hyp}{adj} \\ \\ =\frac{\sqrt{6}}{1} \end{gathered}[/tex][tex]\begin{gathered} cosec\theta=\frac{hyp}{opp} \\ \\ =\frac{\sqrt{6}}{\sqrt{5}} \end{gathered}[/tex]

Final Answer:

The six trig ratio are

[tex]\begin{gathered} \sin\theta=\sqrt{\frac{5}{6}} \\ \cos\theta=\frac{1}{\sqrt{6}} \\ cot\theta=\frac{1}{\sqrt{5}} \\ sec\theta=\sqrt{6} \\ cosec\theta=\frac{\sqrt{6}}{\sqrt{5}} \end{gathered}[/tex]

IExample 2 Reflection A trapezoid with the vertices W (-1.4) X(4.4) Y (4,1), and Z (-3 1) is reflected over the x-axisa.) Find the coordinates of the verticesof the image.b.) Graph trapezoid WXYZ and its

Answers

a) Reflection over the x-axis tranforms the point (x,y) into (x, -y). Then:

W (-1,4) → W' (-1,-4)

X (4,4) → X' (4,-4)

Y (4,1) → Y' (4,-1)

Z (-3,1) → Z' (-3,-1)

b) The graph is:

If measure of angle P = (19x -5) degrees and x=4 find the measure of P.

Answers

Solution:

Given:

Angle P is measured in degrees.

[tex]P=19x-5[/tex]

where x = 4

Substituting the value of x in the equation,

[tex]\begin{gathered} P=19x-5 \\ P=19(4)-5 \\ P=76-5 \\ P=71^0 \end{gathered}[/tex]

Therefore, the measure of angle P is 71 degrees.

A tree service company put logs in the shape of a rectangular prism.However, it is supposed to snow, and the owner wants to cover the logs tokeep them dry. If the pile of logs creates a rectangular prism with thesemeasurements: 30 cm long, 12 cm wide, and 40 cm high, what is theminimum amount of material needed to cover the pile of logs? *

Answers

An example of a rectangular prism is given below

To get the minimum amount of material needed to cover the pile of logs, we will get the volume of the rectangular prism

The volume is calculated as:

[tex]\text{Volume of prism = length}\times breadth\times height[/tex]

Thus, the minimum amount of material will be

[tex]\begin{gathered} \text{Volume}=30\operatorname{cm}\times12\operatorname{cm}\times40\operatorname{cm} \\ \text{Volume}=14400\operatorname{cm}^3 \end{gathered}[/tex]

The minimum amount of material needed to cover the pile of logs will be 14400cm³

The volume of this cube is 125 cubic meters. What is the value of d?

Answers

EXPLANATION

The volume of a cube is equal to:

V= side*side*side

Let's call to the side: "d"

V = d*d*d = d^3

If the volume is equal to 125 m^3, then the value of d will be:

[tex]125=d^3[/tex]

Isolating d:

[tex]\sqrt[3]{125}=5m^3[/tex]

Answer: the value of d is 5 cubic meters.

Find the general solution of the differential equation
[tex] \frac{dy}{dx} = (1 + {x}^{2} )(1 + {y}^{2} )[/tex]

Answers

[tex]{ \pink{ \tt{ { \tan }^{ - 1} y - \frac{ {x}^{3} }{3} = c }}}[/tex]

Step-by-step explanation:

This can be written as,

[tex]{ \green{ \tt \frac{dy}{1 + {y}^{2}}}} = { \green{ \tt{(1 + {x}^{2})dx}}}[/tex]

Integeare on both sides, then

[tex]{ \blue{ \tt{ ∫  \frac{1}{1 + {y}^{2}}}}}{ \blue{ \tt{dy}}} = { \blue{ \tt{  ∫ (1 + {x}^{2} )dx}}}[/tex]

[tex]{ \blue{ \tt{ { \tan }^{ - 1} y = \frac{ {x}^{3} }{3} + c}}}[/tex]

[tex]{ \huge{ \green{ \blue{ \tt{ { \tan }^{ - 1} y - \frac{ {x}^{3} }{3} = c}}}}}[/tex]

Consider the following rational numbers.-1 1/2, -12, -43a. order the numbers from least to greatest_____b. Order the numbers' absolute values from least to greatest._____is the order of the rational numbers in part(a) different from the order of the numbers' absolute values in part (b)?c. explain why or why not

Answers

a) -43, -12, -1 1/2

b) 1 1/2. 12, 43

c) it is different

Explanation:

a) -1 1/2, -12, -43

from the least to the greatest:

The higher a negative number , the lesser the value of the number

-43, -12, -1 1/2

b) The absolute values of -1 1/2, -12, -43:

1 1/2, 12, 43

absolute values from least to greatest:

1 1/2. 12, 43

The order of the rational numbers in part (a) is different from the order of the numbers' absolute values in part (b)

c) Absolute values of a negative number gives a positive number. The higher a posititve number, the greater its value. While a higher negative number has a lower value. This makes the result in ordering the data different

Isaac Green Elimination (Level 1) Mar 17, 8:18:58 AM Find the solution of the system of equations. -10x+8y=-444x+8y=40

Answers

The given equations are:

[tex]\begin{gathered} -10x+8y=-44\ldots\ldots(1) \\ 4x+8y=40\ldots\ldots\text{.}\mathrm{}(2) \end{gathered}[/tex]

Subtract equation 1 from 2, we get,

[tex]\begin{gathered} 4x+10x+8y-8y=40+44 \\ 14x=84 \\ x=\frac{84}{14}=6 \end{gathered}[/tex]

Now, substitute the value of x in equation 2, we get

[tex]\begin{gathered} 4\times6+8y=40 \\ 8y=40-24=16 \\ y=\frac{16}{8}=2 \end{gathered}[/tex]

Thus, the solution is x = 6 and y = 2

which answer best shows that is function is only decreasing

Answers

-2 < x < 0.5

By looking at the graph, we can see that from x = -2 to x = 0.5 the function is decreasing, from 0 to -7 ( olong the y axis)

what's 2 over 5th plus 2 over 10th

Answers

The expression we need to solve is:

[tex]\frac{2}{5}+\frac{2}{10}[/tex]

To solve this problem, we need to not that we can simplify the fraction 2/10 by dividing both number by 2:

the United States Air Force has 19 women for every 81 men enlisted in a squadron has 750 member approximately how many women round your answer to the nearest whole number

Answers

the United States Air Force has 19 women for every 81 men enlisted in a squadron has 750 member approximately how many women round your answer to the nearest whole number ​

we have that

Let

x -----> the number of women

y ----> the number of men

so

x+y=750 -------> equation A

x/y=19/81--------> y/x=81/19

y=(81/19)x ------> equation B

substitute equation B in equation A

x+(81/19)x=750

solve for x

(100/19)x=750

x=(750*19)/100

x=142.5

therefore

the number of women is 143

Now, suppose gas costs $2 per gallon. Find the total distance the boys could travel.

Answers

Wehave the following:

according to the statement we have the following equation

[tex]d(p)=20\cdot(\frac{15}{p}+8)[/tex]

where d is the distance and p is gas cost

replacing when p is 2

[tex]\begin{gathered} d(2)=20\cdot(\frac{15}{2}+8) \\ d(2)=310 \end{gathered}[/tex]

Therefore he was able to travel a total of 310 miles

Express the confidence interval (32.9%, 49.1%) in the form of ˆp ± ME

Answers

ANSWER

[tex]\text{ 41\%}\pm8.1\text{ \%}[/tex]

EXPLANATION

The confidence interval is given as (32.9%, 49.19%)

Firstly, we need to find the value of P and ME

Assume, that the upper limit of the confidence interval is 49.19%, and the lower limit is 32.9%

P + ME = 49.1 ---------- 1

P - ME = 32.9 ------------2

The above equation can be solved simultaneously by using the substitution method

Isolate P in equation 1

P = 49.1 - ME

substitute the value of P = 49.19 - ME into equation 2

49.1 - ME - ME = 32.9

49.1 - 2ME = 32.9

subtract 49.1 from both sides of the equation

49.1 - 49.1 - 2ME = 32.9 - 49.1

-2ME = 32.9 - 49.1

-2ME = -16.2

Divide both sides by -2

-2ME/-2 = -16.2/-2

ME = 8.1

To find P, substitute the value of ME = 8.15 into the equation 1

P = 49.1 - 8.1

P = 41

From the above calculations, you will see that P = 41% and ME = 8.1%

Hence the confidence interval can be expressed as

[tex]\text{ 41\% }\pm\text{ 8.1\%}[/tex]

Solve the following inequality.45 < 9(x + 3) < 153

Answers

In order to solve this inequality, we can do the following steps:

[tex]\begin{gathered} 45<9(x+3)<153\\ \\ \frac{45}{9}Therefore the correct option is B.

The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).14,84,504Find the 6th term.

Answers

ANSWER

a6 = 108864

EXPLANATION

First, we have to find the rule to obtain the nth term of the sequence. For that, we have to decide if this sequence is an arithmetic sequence or a geometric sequence. Note that between the first and second term there's a difference of 70, but between the second and third terms the difference is 420. Therefore it can't be an arithmetic sequence.

Let's assume it is a geometric sequence. The formula for the nth term is:

[tex]a_n=a_1\cdot r^{n-1}[/tex]

We have a1 = 14 and using the second term we can find r. a2 = 84:

[tex]\begin{gathered} a_2=a_1\cdot r^{2-1} \\ 84=14\cdot r^1 \\ r=\frac{84}{14} \\ r=6 \end{gathered}[/tex]

The general formula for the nth term of this sequence is:

[tex]a_n=14\cdot6^{n-1}[/tex]

To be sure, let's check if it works for the third term:

[tex]\begin{gathered} a_3=14\cdot6^{3-1} \\ a_3=14\cdot6^2 \\ a_3=14\cdot36 \\ a_3=504 \end{gathered}[/tex]

Now, to find the 6th term, we just have to use this formula, with n = 6:

[tex]\begin{gathered} a_6=14\cdot6^{6-1} \\ a_6=14\cdot6^5 \\ a_6=108864 \end{gathered}[/tex]

Hence, the 6th term of this sequence is 108864.

What is the amount in the account after 4 yrs , rounded to the nearest dollar

Answers

We have the next formula

[tex]f(x)=350(1+0.03)^x[/tex]

where x us the number of years, in this case x= 4

[tex]f(4)=350(1+0.03)^4=393.92[/tex]

rounded to the nearest dollar is $394 is the amount in the account after 4 years.

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you roll a number cu Many types of cancer involve uncontrolled cell divisions where the telomeres do not shorten or areignored when they get to the critical point. One line of cancer research is to stop the formation of thespindle during prophase. How would this inhibit cancer growth/spread? What would some of the possible/negative side effects be? Jaylin has a scale model of a train to some centimeters in the model represents 3 feet in a real train on the scale model the two wheels of Jaylin true or 3.5 cm apart there are some old railroad tracks in the Wyoming that are 4.5 feet apart would the real train be able travel on those tracks? Which option describes reasoning is it the central argumentopinions included in a texta resource used to evaluate evidencestatements of support in an argument The posted speed limit is 45 miles per hour. Choose all the metric measures that are faster than 45 miles per hour. Customary and Metric Unit Equivalents DATA Length Weight/Mass Capacity 1 m - 3.28 ft 1 Oz - 28.35 g 1 gal - 3.79 L 1 m - 39.37 in. 1 kg - 2.20 lb 1 gt - 0.95 L 1 in. - 2.54 cm 1 metric ton (1) - 1.102 T 1 mi - 1.61 km A 45 km per hour B. 64.1 km per hour C. 86.4 km per hour D. 91 km per hour E. 112.3 km per hour State all integer values of x in the interval [-4,3] that satisfy the following inequality 5x-5> -20 farmer Washington is giving a way free produce. he starts with 12 mangoes, 17 cashew packs,13 june plums and 8 Jamaican apples . whats the probability of the first person to selecta mango or a june plum or cashew pack 200200 divided by 20 How much fencing does Susie need.Option d: x = 10 and 80 ft of fencing. the tigers scored twice as many points as the buzzers .the tigers scored. poilnts did the buzzers score? Use Example 1 as a model to evaluate the limitlim n nf(ci)xii = 1over the region bounded by the graphs of the equations. (Round your answer to three decimal places.)f(x) = x, y = 0, x = 0, x = 21Hint: Let ci = 21i2n2. Find the surface area of a rectangle solid with edges of length 2cm,5cm, and 7cm Good morning I could really use help with this question please! A pure silver lions fan throws a roll of toilet paper at 7.2 m/s from her seat at Fords field during a recent game. how fast is the 0.4 KG roll going when it strikes an opposition player 16. 1 m below? Write an equation with integer coefficients that has a zero at 3 with a multiplicity of 2,a zero at - 5/4. what is the slope of the liner function represented in the table A. -7 B. -1/7 C. 1/7 D. 7x -7 y 0 x 0 y 1 find the length of the radius if the circumference is 13.2 round to one decimal place. use 3.14 for Please help this is due in an hour. the equation is q+q+.3q=180 pls help. Translate each sentence into an equation or formula.1. Fifty-three plus four times b is the same as 21.2. The sum of five times f and twice g is equal to 23,3. Three plus the sum of the squares of w and x is 32,4. Degrees Kelvin K equals 273 plus degrees Celsius C. 23.Given:5x-18= 3x + 2Prove:x = 10Statement2. 5x = 3x + 203.Reason2.3. Subtraction Property4. Division Property