Gas laws show the relationship between tempertaure, pressure, volume, volume and number of moles. The new volume of the gas is 549 mL.
What is Charles law?Charles law states that, the volume of a given mass of gas is directly proportional to its temperature at constant pressure .
Given that;
V1 = 500.0 mL
T1 = 25°C or 298 K
V2 = ?
T2 = 54°C + 273 = 327 K
Since;
V1/T1 = V2/T2
V1T2 = V2T1
V2 = V1T2/T1
V2= 500.0 mL * 327 K/298 K
V2 = 549 mL
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is respiration like burning?Explain your answer.
Answer:
Yes
Explanation:
The process of respiration and burning are similar in the following ways: Both respiration and burning require oxygen. Energy is released during both respiration and burning. The products produced (carbon dioxide and water) are the same for both respiration and burning.
Answer:
Yes
Both Respiration and Burning uses oxygen. Both Respiration and Burning produces energy. Both Respiration and Burning gives out carbon dioxide as the end product. The overall chemical reactions of both Respiration and Burning are the same.
Explanation:
Please mark me brainliest if correct
I have my last 3 electrons on the third energy level.
Answer:
an energy level represents the three dimensional space surrounding nucleus where electrons are most likely to be.
Explanation:
Consider the reaction 3CH4(g)→C3H8(g)+2H2(g).
Calculate ΔG at 298 K if the reaction mixture consists of 41 atm of CH4 , 0.013 atm of C3H8 , and 2.3×10−2 atm of H2 .
Given:
ΔH for...
CH4 = -74.8 C3H8 = -103.85 H2 = 0
ΔS for...
CH4 = 0.1863 C3H8 = 0.2699 H2 = 0.13058
ΔG for...
CH4 = -50.8 C3H8 = -23.4 H2 = 0
ΔG at 298 K = 128.9 kJ
From the calculations performed, the free energy change for the reaction is 72 kJ/mol.
What is the equilibrium constant?The equilibrium constant is a value that shows the extent to which reactants have been converted to products.
Given that the equation of the reaction is;
3CH4(g)→C3H8(g)+2H2(g)
Then;
PC3H8 = 0.013 atm
PH2 = 2.3×10−2 atm
PCH4 = 41 atm
Now;
ΔG = ΔG° + RTlnQ
ΔG°reaction = ΔG°products - ΔG°reactants
ΔG°reaction = [( -23.4) +2(0)] - 3(-50.8)
ΔG°reaction = 129 kJ/mol
Q = PC3H8 * PH2^2/PCH4^3
Q = 0.013 * (2.3×10−2)^2/( 41)^3
Q = 6.877 * 10^-6/68921
Q= 9.9* 10^-11
Hence;
ΔG = 129 * 10^3 + [8.314 * 298 * (ln 9.9* 10^-11 )]
ΔG = 129 * 10^3 - 57073
ΔG = 72 kJ/mol
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The use of evaporation and condensation to separate the partsof a mixture is called _____
Answer: Evaporation Condensation is used to seperate the parts of a mixture
Explanation: This is because it is the first order of the distilation process
The use of evaporation and condensation to separate the parts of a mixture is called distillation.
What is distillation?
Separating salt water to produce pure water and salt is an example of a simple distillation mixture.
The water begins to evaporate during the distillation process, and the vapor cools down to form pure water.
A second container is used to collect the pure water.
Thus, the use of evaporation and condensation to separate the parts of a mixture is called distillation.
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Explain ferromagnetism. Include what is happening to the electron in the atoms
In Ferromagnetism, materials are changed into permanent magnets.
What is Ferromagnetism?Ferromagnetism is a process in which specific materials are turned into permanent magnets. The spins of electrons are shifted and electrons become more aligned and sequence with the direction of the field.
So we can conclude that in Ferromagnetism, materials are changed into permanent magnets.
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Periodic Table: Why are group 1A elements called alkali metals?
Answer:
Explanation:
The elements in Group I of the periodic table are called alkali metals. They are called alkali metals because they react with water to form alkali solutions. These metals are very reactive; hence they have to be stored under oil to protect them from corrosion by air and waterwaterwater
The group 1A elements, called alkali metals because they form alkalies on reacting with water. Alkalies are strong bases.
What are the alkali metals?They are the metals that are soft, lustrous, and have a low melting point. Air and moisture react readily with alkali metals.
Special precautions must be taken when using and storing these metals due to their reactivity.
The seven alkali metals are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).
Thus, the group 1A elements, called alkali metals because they form alkalies on reacting with water. Alkalies are strong bases.
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When a solution of mgcl2 and one of agno3 are mixed, the net ionic equation is:
When a solution of MgCl₂ and a solution of AgNO₃ are mixed, the net ionic equation obtained is:
2Cl¯(aq) + 2Ag⁺(aq) —> 2AgCl(s)
What is a chemical equation?Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.
The reactants are located on the left side while the products are located on the right side.
Reactants —> Products
The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.
How to write the net ionic equationIn solution
MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)
AgNO₃(aq) —> Ag⁺(aq) + NO₃¯(aq)
The reaction proceeds as follow
MgCl₂(aq) + AgNO₃(aq) —>
Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) —> 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)
Cancel out the spectator ions (i.e Mg²⁺ and NO₃¯) to obtain the net ionic equation
2Cl¯(aq) + 2Ag⁺(aq) —> 2AgCl(s)
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When a solution of MgCl₂ and one of AgNO₃ are mixed, the net ionic equation is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).
What are net ionic reactions?Net ionic reactions are those reactions in which each species are written in their respective ions form except the spectator ions.
Given chemical reaction is:
MgCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) + Mg(NO₃)₂(aq)
Ionic form of the given reaction will be written as
Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) → 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)
Spectator ions are those which are commonly present on both side of the reaction and for this reaction they are Mg²⁺ and NO₃¯. So the net ionic reaction will be:
2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s)
Hence required net ionic reaction is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).
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During Taylor's experiment, which piece of data would be qualitative?
mass of the cars
degree of the ramp incline
time in seconds
none are qualitative
From the available options with respect to Taylor's experiment, none of the data is qualitative.
Qualitative dataThese are data that cannot be measured using any instrument or assigned a numerical value.
Qualitative data are observable data based on perception.
This is unlike quantitative data that can be measured using relevant instruments and assigned numeric figures.
Mass can be measured in grams using a weighing balance, angle of inclination can be measured using relevant instruments, and time can be measured using a stopwatch.
Thus, none of the options is qualitative.
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Answer:
None are Qualitative
Explanation: I took the test and got a 100%
abcdefghijklmnopqrstuvwxyz
Answer:
dam aye someone give this person a medal
Explanation:
How many grams of nicl2∙6h2o will be used to prepare a 0. 0350 m, 500. 0 ml of nicl2 solution?
The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g
What is molarity?This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
How to determine the mole of NiCl₂•6HO₂Molarity = 0.035 MVolume = 500 mL = 500 / 1000 = 0.5 L Mole of NiCl₂•6HO₂ =?Mole = Molarity × Volume
Mole of NiCl₂•6HO₂ = 0.035 × 0.5
Mole of NiCl₂•6HO₂ = 0.0175 mole
How to determine the mass of NiCl₂•6HO₂Mole of NiCl₂•6HO₂ = 0.0175 moleMolar mass of NiCl₂•6HO₂ = 238 g/mol Mass of NiCl₂•6HO₂ =?Mass = mole × molar mass
Mass of NiCl₂•6HO₂ = 0.0175 × 238
Mass of NiCl₂•6HO₂ = 4.165 g
Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution
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The grams of NiCl₂.6H₂O will be used to prepare a 0.0350M, 500ml of NiCl₂ solution is 2.268 grams.
How do we calculate grams from moles?Mass in grams of any substance will be calculated by using moles as:
n = W/M, where
W = given mass
M = molar mass
Moles from molarity will be calculated by using the below formula:
M = n/V, where
M = molarity of NiCl₂ solution = 0.0350M
V = volume of solution = 500mL = 0.5L
On putting values, we get
n = (0.035)(0.5) = 0.0175 mol
Now we convert these moles into grams by using the first formula as:
W = (0.0175mol)(129.6g/mol) = 2.268g
Hence required mass of NiCl₂.6H₂O is 2.268g.
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Which of the following pH values indicates the most basic solution? A. 3 B. 7 C. 8 D. 11
What does the abreviation asa stand for chemically?.
Answer:
Acrylonitrile Styrene Acrylate
Give a difference in physical properties between the chlorine and potassium chloride
Answer:
Chlorine exists as gaseous state while potassium chloride as a solid
Physical properties between the chlorine and potassium chloride are totally different because chlorine is available in gaseous form while potassium chloride available in solid form.
What are physical properties between the chlorine and potassium chloride ?Potassium chloride crystals are composed of face-centered cubic (FCC) unit cells. KCl has a molar mass of 74.5513 grams/mol.
It has a density of 1.984 grams per cubic centimeter when it is solid and crystalline. Potassium chloride has melting and boiling temperatures of 1040 K and 1690 K.
A metal halide salt made of potassium and chlorine is known as potassium chloride. It appears as a white or colorless vitreous crystal and has no odor.
Thus, chlorine is present in gaseous state while ptassium chloride present in solid state.
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Calcium acetate reacts with sodium carbonate to produce calcium carbonate and sodium acetate
Answer:
(CH₃COO)₂Ca(aq) + Na₂CO₃(aq) = 2CH₃COONa(aq) + CaCO₃(s)
2CH₃COO⁻ + Ca²⁺ + 2Na⁺ + CO₃²⁻ = 2CH₃COO⁻ + 2Na⁺ + CaCO₃
Ca²⁺ + CO₃²⁻ = CaCO₃
If 25 milliliter of 0. 80 m hcl is used to completely neutralize 40. Milliliters of naoh solution, what is the molarity of the base?
If 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.
How to calculate molarity?The molarity of a solution can be calculated using the following expression:
M1V1 = M2V2
Where;
M1 = molarity of acidM2 = molarity of baseV1 = volume of acidV2 = volume of base25 × 0.80 = 40 × M2
20 = 40M2
M2 = 20/40
M2 = 0.5M
Therefore, if 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.
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Which of the following statements is true?
1. The molar mass of Oz is 48 g/mol
2. A 100-gram sample contains at least 2 moles of Oz
3. 48 grams of O3 contains 6. 02 x 1023 molecules of Oz
The molar mass of Oz is 48 g/mol is true.
What is the molar mass of a substance?Molar mass of a substance is the mass of 1 mole of that substance or it is the number of grams per mole of a substance. The units for molar mass is grams/mole.
Therefore,The molar mass of Oz is 48 g/mol is correct because ozone have three oxygen and the molar mass of one oxygen is 16g/mol.
Ozone= 16×3
Ozone=48g/mol.
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What is the meaning of N, E, M, and S in periodic table Need ASAP!
Answer:
Molybdenum is M, Einsteinium is E, and N is Nitrogen. Lastly, S is sulfur.
When a 21.1 mL sample of a 0.321 M aqueous hydrofluoric acid solution is titrated with a 0.309 M aqueous barium hydroxide solution, what is the pH at the midpoint in the titration?
Answer:
formula of concentration ion.
A chemical supply company sells sulfuric acid (h2so4) in a concentration of 4. 00 m. What volume of this solution would you need to make 12. 0 ml of a 0. 50 m h2so4 solution?
Answer:
H3CS06
Explanation:
A chemical supply company sells sulfuric acid (H3CS06) in a concentration of 4.00 M. What volume of this solution would you need to make 12.0 mL of a 0.50 M H2SO4 s…
Molarity is the ratio of a mole of the solute of the substance to the liter of solution. The volume of solution required to make 12.0 ml of 0.50 M solution is 1.5 mL.
What is molar dilution?Molar dilution is the calculation of the molarity or the volume of the unknown value from the known value. It is given as,
[tex]\rm M_{1}V_{1}= \rm M_{2}V_{2}[/tex]
Given,
Initial molarity = 4.00 M
Initial volume =?
Final molarity = 0.50 M
Final volume = 12.0 mL
Substituting values in the equation:
[tex]\begin{aligned} \rm V_{1} &= \rm \dfrac{\rm M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.50 \times 12.0 }{4.00}\\\\&= 1.5 \;\rm ml\end{aligned}[/tex]
Therefore, 1.5 ml of 4.00 M sulfuric acid must be used to make 12 ml of 0.50 M solution.
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Mercury(ii) oxide (hgo) decomposes to form mercury (hg) and oxygen (o2). the balanced chemical equation is shown below. 2hgo right arrow. 2hg o2 the molar mass of o2 is 32.00 g/mol. how many moles of hgo are needed to produce 250.0 g of o2? 3.906 moles 7.813 moles 15.63 moles 73.87 moles
Decomposition reaction results in the formation of the products by splitting the reactants. Moles of mercury(ii) oxide needed are 15.63 moles.
What are moles?Moles are the ratio of mass and the molar mass of the compound or the molecule.
Moles of oxygen are calculated as:
[tex]\begin{aligned}\rm n &= \rm \dfrac {mass}{molar\; mass}\\\\&= \dfrac{250}{32}\\\\&= 7.8125 \;\rm moles\end{aligned}[/tex]
The balanced chemical reaction can be shown as,
[tex]\rm 2HgO \rightarrow 2Hg + O_{2}[/tex]
From the reaction, it can be said that 1 mole of oxygen requires 2 moles of mercury oxide.
Moles of mercury oxide are calculated as:
[tex]\begin{aligned} \rm n HgO& = (7.8125 \;\rm moles \; O_{2}) \times (\dfrac{2 \;\rm moles\; HgO}{1 \;\rm mole \; O_{2}})\\\\\rm n HgO &= 15.625 \;\rm moles \end{aligned}[/tex]
Therefore, option C. 15.63 moles of mercury (II) oxide is needed.
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6. How did humans help the bison from being hunted to extinction?
Answer:
✒️Answer:Bison were saved through the combined efforts of conservationists, scientists, ranchers and ultimately the general public. As their comeback continues, I believe that they can teach us how to be better stewards of the land and provide a future for the Plains where ecosystems and human cultures thrive.
Explanation:
#CarryOnLearning[tex]watch.some.anime[/tex]
Which equation shows conservation of both mass and charge?
(1) Cl2 + Br→ Cl- + Br,
(2) Cu + 2 Agt → Cu2+ + Ag
(3) Zn + Cr3+ → Zn2+ + Cr
(4) Ni + Pb2+ → Ni2+ + Pb
The equation that shows conservation of both mass and charge is:
(4) Ni + Pb²⁺ → Ni²⁺ + Pb
What do conservation of mass and conservation of charge stand for?Conservation of mass: there is the same mass, i.e. same number of atoms, in the reactants and in the products.Conservation of charge: there is the same electrical charge in the reactants and in the products.Which equation shows conservation of both mass and charge?
(1) Cl₂ + Br → Cl⁻ + Br
No, the equation does not show conservation of mass nor charge.
(2) Cu + 2 Ag⁺ → Cu²⁺ + Ag
No, the equation does not show conservation of mass.
(3) Zn + Cr³⁺ → Zn²⁺ + Cr
No, the equation does not show conservation of charge.
(4) Ni + Pb²⁺ → Ni²⁺ + Pb
Yes, the equation show conservation of mass and charge.
The equation that shows conservation of both mass and charge is:
(4) Ni + Pb²⁺ → Ni²⁺ + Pb
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How much energy, in kJ, is released when 27.0 grams of water is cooled from 112C to -15C?
Answer: Q
=
−
53
,
796.6
J
Explanation is right here instead
The equation for heat is
Q
=
m
(
t
f
−
t
i
)
C
p
Q = heat in Joules
m = mass in grams
t
f
= final temp
t
i
= initial temp
C
p
= Specific Heat Capacity
For this problem
Q
=
?
?
?
m
=
275
g
t
f
=
38.4
o
C
t
i
=
85.2
o
C
C
p
=
4.18
j
g
o
C
Q
=
275
g
(
38.4
o
C
−
85.2
o
C
)
4.18
J
g
o
C
Q
=
275
g
(
−
46.8
o
C
)
)
4.18
J
g
o
C
Q
=
−
53
,
796.6
J
The negative Joule value means heat is being lost in an exothermic reaction.
Explanation:
Why is the addition of cold distilled water to the container holding the aspirin you are trying to isolate a necessary step and why should this step be carried out carefully?.
Answer:
The aspirin is more soluble in ethanol than water - the water helps the crystals separate from solution.
Explanation:
Hope this helps!
ASAP HELP
The troposphere revives most of its heat energy from the blank
Green gram defination
For grade 7
a leguminous plant, Phaseolus aureus, whose seeds are used as food in India.
Answer:
Green Gram is a small round edible green bean which is also known as moong ki daal in the subcontinent.
Explanation:
The green gram bean which is also known as the mung, maash or moong, is a plant species in the legume family. The green gram bean is mainly cultivated in East, Southeast and South Asia. It is used as an ingredient in both savoury and sweet dishes.
Describe the process used to balance an equation?
Answer:
Explanation:
When you balance a chemical equation, you change coefficients. You never change subscripts. A coefficient is a whole number multiplier. To balance a chemical equation, you add these whole number multipliers (coefficients) to make sure that there are the same number of atoms on each side of the arrow
Determine the product(s) formed when cyclohexene is treated with the following reagents
Explanation:
Big C carbon surrounded by He helium
A chemistry teacher adds 50. 0 mL of 1. 50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution? Use M subscript i V subscript i equals M subscript f V subscript f. 0. 300 M 0. 375 M 6. 00 M 7. 50 M.
The concentration of the final solution after mixing water into the H₂SO₄ is 0.375 M.
How do we calculate the concentration?Concentration in terms of molarity will be calculated by using the below formula as:
M₁V₁ = M₂V₂, where
M₁ = molarity of H₂SO₄ = 1.50 M
V₁ = volume of H₂SO₄ = 50 mL
M₂ = molarity of water = ?
V₂ = volume of water = 200 mL
On putting all values on the above equation, we get
M₂ = (1.50)(50) / (200) = 0.375 M
Hence option (2) is correct.
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Calculate the volume of 1.5 M nitric acid required to neutralize 30.0 mL of 7.0 M sodium
hydroxide.
HNO3 (aq) + NaOH (aq) → H2O (l) + NaNO3 (aq)
Answer:
0.14 liters nitric acid
Explanation:
Molarity = moles / liter
7.0 M = x / 0.03 L
= 0.21 moles NaOH
0.21 moles NaOH x ( 1 mole HNO3 / 1 mole NaOH) = 0.21 moles HNO3
Molarity = moles / liter
1.5 M = 0.21 moles / x
x = 0.21 moles / 1.5 M
x = 0.14 Liters HNO3
Answer:
[tex]140mL[/tex]
Explanation:
[tex]M_1V_1=M_2V_2[/tex]
[tex]M_1=1.5M[/tex] molarity of nitric acid
[tex]V_1=?[/tex] volume of nitric acid
[tex]M_2=7.0M[/tex] molarity of sodium hydroxide
[tex]V_2=30.0mL[/tex] volume of sodium hydroxide
[tex](1.5M)(V_1)=(7.0M)(30.0mL)[/tex]
[tex]V_1 =\frac{(7.0M)(30.0mL)}{1.5M}=140mL[/tex]
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