Answer:
She bought [tex]\frac{5}{8}[/tex] pounds of tuna on Friday
Step-by-step explanation:
Franny brought pounds of tuna at fish market on Monday =[tex]\frac{1}{4}[/tex]
We are given that on Friday she bought two and a half times as much tuna bought on Monday
So, She bought pounds of tuna on Friday = [tex]2 \frac{1}{2} \times \frac{1}{4}[/tex]
She bought pounds of tuna on Friday = [tex]\frac{5}{2} \times \frac{1}{4}[/tex]
She bought pounds of tuna on Friday = [tex]\frac{5}{8}[/tex]
Hence She bought [tex]\frac{5}{8}[/tex] pounds of tuna on Friday
A student is getting ready to take an important oral examination and is concerned about the possibility of having an "on" day or an "off" day. He figures that if he has an on day, then each of his examiners will pass him, independently of one another, with probability 0.8, whereas if he has an off day, this probability will be reduced to 0.4. Suppose that the student will pass the examination if a majority of the examiners pass him. If the student believes that he is twice as likely to have an off day as he is to have an on day, should he request an examination with 3 examiners or with 5 examiners?
Answer:
The students should request an examination with 5 examiners.
Step-by-step explanation:
Let X denote the event that the student has an “on” day, and let Y denote the
denote the event that he passes the examination. Then,
[tex]P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})[/tex]
The events ([tex]Y|X[/tex]) follows a Binomial distribution with probability of success 0.80 and the events ([tex]Y|X^{c}[/tex]) follows a Binomial distribution with probability of success 0.40.
It is provided that the student believes that he is twice as likely to have an off day as he is to have an on day. Then,
[tex]P(X)=2\cdot P(X^{c})[/tex]
Then,
[tex]P(X)+P(X^{c})=1[/tex]
⇒
[tex]2P(X^{c})+P(X^{c})=1\\\\3P(X^{c})=1\\\\P(X^{c})=\frac{1}{3}[/tex]
Then,
[tex]P(X)=1-P(X^{c})\\=1-\frac{1}{3}\\=\frac{2}{3}[/tex]
Compute the probability that the students passes if request an examination with 3 examiners as follows:
[tex]P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})[/tex]
[tex]=[\sum\limits^{3}_{x=2}{{3\choose x}(0.80)^{x}(1-0.80)^{3-x}}]\times\frac{2}{3}+[\sum\limits^{3}_{x=2}{{3\choose x}(0.40)^{3}(1-0.40)^{3-x}}]\times\frac{1}{3}[/tex]
[tex]=0.715[/tex]
The probability that the students passes if request an examination with 3 examiners is 0.715.
Compute the probability that the students passes if request an examination with 5 examiners as follows:
[tex]P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})[/tex]
[tex]=[\sum\limits^{5}_{x=3}{{5\choose x}(0.80)^{x}(1-0.80)^{5-x}}]\times\frac{2}{3}+[\sum\limits^{5}_{x=3}{{5\choose x}(0.40)^{x}(1-0.40)^{5-x}}]\times\frac{1}{3}[/tex]
[tex]=0.734[/tex]
The probability that the students passes if request an examination with 5 examiners is 0.734.
As the probability of passing is more in case of 5 examiners, the students should request an examination with 5 examiners.
Consider the scatterplot above. Write a sentence explaining the meaning of the value of the slope for this linear model. The is an average of per year .
Answer:
Slope: The percent that voted falls by 0.1271 units per year.
Step-by-step explanation:
The slope of a regression line represent the average rate of change in the dependent variable (y) based upon the changes in the independent variable (x).
In this case the regression equation provided is:
y = -0.1271 x + 307.53
The slope of the line is -0.1271.
The dependent variable is the percent that voted and the independent variable is the year.
The slope of -0.1271 indicates that every year, on average, the percent that voted decreases by 0.1271 units.
Or the percent that voted falls by 0.1271 units per year.
18x-5x=13+20 what is the answer
Answer:
3.3
Step-by-step explanation:
18x-5x=13+20
13x=33
x=2.5
In a study, researchers wanted to estimate the true mean skidding distance along a new road in a European forest. The skidding distance (in meters) were measured at 20 randomly selected road sites. The 95% confidence interval constructed based on the data collected was (303.3, 413.6). A logger working on the road claims that the mean skidding distance is at least 425 meters. Does the confidence interval supports the loggers claim
Answer:
[tex] 303.3 \leq \mu \leq 413.6[/tex]
We need to remember that the confidence interval for the true mean is given by:
[tex] \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]
Since the upper limit for the confidence interval is lower than the value of 425 we don't have enough evidence to conclude that the the mean skidding distance is at least 425 meters at the 5% of signficance used so then the confidence interval not support the loggers claim
Step-by-step explanation:
We know that they use a sample size of n =20 and the confidence interval for the true mean skidding distance along a new road in a European forest is given by:
[tex] 303.3 \leq \mu \leq 413.6[/tex]
We need to remember that the confidence interval for the true mean is given by:
[tex] \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]
Since the upper limit for the confidence interval is lower than the value of 425 we don't have enough evidence to conclude that the the mean skidding distance is at least 425 meters at the 5% of signficance used so then the confidence interval not support the loggers claim
Complete the following subtraction exercises.
10 – 2 =
14 – 6 =
15 – 9 =
17 – 8 =
13 – 5 =
11 – 8 =
20 – 8 =
16 – 7 =
12 – 9 =
21 – 9 =
11 – 6 =
5 – 5 =
4 – 0 =
16 – 8 =
10 – 5 =
18 – 7 =
13 – 8 =
12 – 4 =
Answer:
Below
Step-by-step explanation:
8,8,6,9,8,3,12,9,3,12,5,0,4,8,5,11,5,8. Answers are in order from the first to the last
If your good at maths help me
Answer:
6n+1
Step-by-step explanation:
first term=13-6=7
nth term=7+(n-1)6=7+6n-6=6n+1
Answer:
aₙ= 6n +1
Step-by-step explanation:
Second term a₂= 13
Common difference d= 6
Then first term
a₁= 13 -6= 7nth term:
aₙ= a₁ + (n-1)daₙ= 7 + (n-1)*6= 7+6n -6 = 6n +1aₙ= 6n +1Minimize
z = 20x1 + 32x2 + 40x3,
subject to
3x1 + x2 + 6x3 ≥ 9
x1 + x2 ≥ 9
4x2 + x3 ≥ 12
x1 ≥ 0, x2 ≥ 0, x3 ≥ 0.
solve for x1, x2, x3 and z
Answer:
Step-by-step explanation:
1. constraints with "[tex]\geq[/tex]" we should subtract surplus variable S1, S2, S3 and add artificial variable A1, A2, A3
Hence Z = 20 x1 + 32x2 + 40x3 + 0S1 + 0S2 + 0S3 + MA1 + MA2 + MA3
subject to
[tex]3x_1 +x_2+6x_3-S_1+A_1=9[/tex]
[tex]x_1+x_2-S_2+A_2=9[/tex]
[tex]4x_2+x_3-S_3+A_3=12[/tex]
and [tex]x_1,x_2,x_3,S_1,S_2,S_3,A_1,A_2,A_3\geq 0[/tex]
Write a sine function that has a midline of 2, an amplitude of 4 and a period of 11.
Answer:
y = 4 sin(2π/11 x) + 2
Step-by-step explanation:
y = A sin(2π/T x + B) + C
where A is the amplitude,
T is the period,
B is the phase shift,
and C is the midline.
A = 4, T = 11, and C = 2. We'll assume B = 0.
y = 4 sin(2π/11 x) + 2
The sine function with the desired characteristics is given by:
[tex]y = 2\sin{\left(\frac{2\pi}{11}\right)} + 2[/tex]
The standard sine function is given by:
[tex]y = A\sin{Bx} + C[/tex]
The amplitude is 2A.The period is [tex]\frac{2\pi}{B}[/tex].The midline is C.In this problem:
Midline of 2, thus [tex]C = 2[/tex].Amplitude of 4, thus [tex]2A = 4 \rightarrow A = 2[/tex].Period of 11, thus [tex]\frac{2\pi}{B} = 11 \rightarrow B = \frac{2\pi}{11}[/tex]Then, the equation for the sine function is:
[tex]y = 2\sin{\left(\frac{2\pi}{11}\right)} + 2[/tex]
A similar problem is given at https://brainly.com/question/18055768
A national organization that conducts research on the cost and quality of health care in the U.S. reported that, in 2012, U.S. families spent an average of $9,590 on health care expenses. Suppose you decide to test whether the average in 2015 is greater than the average in 2012. After conducting the appropriate statistical test, you find a P-value of 0.022. If the level of significance is 0.05, which of the following is the best interpretation of the P-value?
a. The P-value of 0.022 indicates that there is a 2.2% chance that the 2015 average is greater than the average amount spent in 2012.
b. The P-value of 0.022 provides weak evidence that the average in 2015 average is greater than the average amount spent in 2012.
c. The P-value of 0.022 provides strong evidence that the 2015 average is greater than the average amount spent in 2012.
d. The P-value of 0.022 indicates that there is a very low probability that the 2015 average is different than average amount spent in 2012.
Answer:
c. The P-value of 0.022 provides strong evidence that the 2015 average is greater than the average amount spent in 2012.
Step-by-step explanation:
The P-value indicates the probability of having this sample results given that the null hypothesis is true. If the P-value is low enough (smaller than the significance level), we have evidence to reject the null hypothesis, as there is little chance the null hypothesis is true and this sample result is due to chance.
What is the area of a rectangle that is 4 1/2 cm long and 2 5/9 cm wide? Solution: Answer: What is the area of a square that has a side of 4 3/5 cm?
Answer:
1) 23/2
2) 529/25
Step-by-step explanation:
Transformation:
[tex]4\frac{1}{2} = \frac{(2*4) + 1}{2} = \frac{9}{2}[/tex]
[tex]2\frac{5}{9} = \frac{(9*2) + 5}{9} = \frac{23}{9}[/tex]
A = [tex]\frac{9}{2} * \frac{23}{9} = \frac{23}{2}[/tex]
-----------------------------
Transformation:
[tex]4\frac{3}{5} = \frac{(5*4) + 3}{5} = \frac{23}{5}[/tex]
A = [tex](\frac{23}{5})^{2} = \frac{529}{25}[/tex]
A tank is full of water. Find the work required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the density of water. Assume r = 9 m and h = 3 m.)
Answer: tank has spherical shape . The distance from the centre of mass =
h+r = 12
Weight of water in tank = 9.8×π×9³×1000×4/3
= 29.926×10⁶ N
to empty the tank Work done = 12 × 29.926 × 10⁶
= 359 × 10⁶ J
= 359 MJ. hope this helps
Step-by-step explanation:
Your local school board wants to determine the proportion of people who plan on voting for the school levy in the upcoming election. They conduct a random phone poll, where they contact 150 individuals and ask them whether or not they plan on voting for the levy. Of these 150 respondents, 78 people say they plan on voting for the levy. The school board wants to determine whether or not the data supports the idea that more than 50% of people plan on voting for the levy. Conduct a hypothesis test at the 0.10 significance level to test this claim.
Answer:
There is not enough evidence to conclude that the data supports the idea that more than 50% of people plan on voting for the levy
Step-by-step explanation:
Sample size, n = 150
Number of people that plan on voting for the levy, X = 78
Proportion of people that plan on voting for the levy:
[tex]\bar{p} = X/n\\\bar{p} = 78/150\\\bar{p} = 0.52[/tex]
The study is to determine whether or not the data supports the idea that more than 50%(0.5) of people plan on voting for the levy
The null and alternative hypotheses are:
[tex]H_0: p \leq 0.5\\H_a: p > 0.5[/tex]
Calculate the test statistics:
[tex]t_s = \frac{\bar{p} - p}{\sqrt{\frac{p(1-p)}{n} } } \\t_s = \frac{0.52-0.5}{\sqrt{\frac{0.5(1-0.5)}{150} } } \\t_s = 0.49[/tex]
For a test statistic [tex]t_s = 0.49[/tex], the p-value = 0.3121
The significance value, [tex]\alpha = 0.10[/tex]
Since the p-value(0.3121) is greater than α(0.10), the null hypothesis [tex]H_0[/tex] will be accepted.
This means that there is not enough evidence to conclude that the data supports the idea that more than 50% of people plan on voting for the levy
A game is played using one die. If the die is rolled and shows 1, the player wins $5. If the die shows any number other than 1, the player wins nothing. If there is a $1 charge to play the game, what is the game’s expected value?
Answer:
1/5
Step-by-step explanation:
i had a similar question
For each roll you start with paying 2 dollars and you only with 10 dollars one out of 6 rolls (on average).
So the cost for one play is 2 dollars and your win is 10/6.
Value is -2+10/6=-1/3 dollars
So you lose 1/3 dollars on average with each game
since you have no limited rolls u put 1/5
this from another question but both same just different numbers
Autism is a serious and lifelong disability that is characterized by a severely decreased ability to engage in communication and social interaction. In 1998 citizens in a New Jersey town were concerned about the number of children diagnosed with autism, and a study was undertaken to establish the prevalence in the community. Data from the study are reported below:
Numbers of Children Diagnosed with Autistic Disorder
Age Category (y) Diagnosed with Autistic Disorder Number of Children in Population
3-5 19 3479
6-10 17 5417
Required:
a. Calculate the prevalence rate of autism for these children for the two age categories.
b. Convert the prevalence rate to a rate per 1,000
Answer:
a. Calculate the prevalence rate of autism for these children for the two age categories.
3-5: prevalence rate = 0.55%6-10: prevalence rate = 0.31%b. Convert the prevalence rate to a rate per 1,000
3-5: prevalence rate = 5.5 per thousand6-10: prevalence rate = 3.1 pér thousandStep-by-step explanation:
Generally prevalence is calculated using the following formula:
(number of people with autism / number of people measured) x 100%
age category
3-5: prevalence rate = (19/3,479) x 100% = 0.55%
6-10: prevalence rate = (17/5,417) x 100% = 0.31%
if you want to convert to a rate per 1,000, allyou need to do is multiply by 1,000 instead of 100
3-5: prevalence rate = (19/3,479) x 1,000 = 5.5
6-10: prevalence rate = (17/5,417) x 1,000 = 3.1
Order the numbers from greatest to least.
4. 234,358; 23,208; 23,098
Answer:
23,098; 23,208 ; 234,358
Step-by-step explanation:
Hope this helps
How do you solve this problem? population proportion is to be estimated from a sample of 400 with a sample proportion of 0.1. Approximate the 95% confidence interval of the population proportion
Answer:
(0.0706, 0.1294)
Step-by-step explanation:
Confidence interval of a proportion is:
CI = p ± CV × SE
where p is the proportion,
CV is the critical value (z score or t score),
and SE is the standard error.
The sample is large enough to estimate as normal. For 95% confidence level, CV = z = 1.96.
Standard error for a proportion is:
SE = √(pq/n)
SE = √(0.1 × 0.9 / 400)
SE = 0.015
The confidence interval is:
CI = 0.1 ± (1.96)(0.015)
CI = (0.0706, 0.1294)
Round as needed.
gary mixes a solution using two types of concentration of sale: .70 gallons of 5% and .30 gallons of 22% salt. what is the concentration of the mixed solutions
Answer:
10.1%
Step-by-step explanation:
The first thing we should do is calculate the total volume of the solution when mixing them would be:
0.7 + 0.3 = 1
Now, we have that the resulting concentration (x) would be equal to the sum of the multiplications between the volumes and the concentrations to be mixed, as follows:
x * 1 = 0.7 * 0.05 + 0.3 * 0.22
x = 0.035 + 0.066
x = 0.101
That is, the concentration of the resulting mixture would be 10.1% (0.101 * 100)
please please solve for x
Answer:
Step-by-step explanation:
laura quiere cubrir con papel china una puesta como la que se muestran el dibujo cuánto centímetros cuadrados tendrá que cubrir con papeles llena
Answer:
El área a cubrir es de 4800 cm^2.
Step-by-step explanation:
La pregunta está incompleta:
Laura quiere cubrir con papel de china una puerta como la que se muestra en el dibujo cuánto es centímetros cuadrados. Las medidas son 80 cm de largo y 60 cm de ancho.
Tenemos que calcular el área que representa la puerta, cuyos lados son 80 cm y 60 cm.
El área A se calcula multiplicando ambos lados:
[tex]A=80\,cm\cdot60\,cm=4800\,cm^2[/tex]
2.In quadratic equation ax2 + bx + c = 0, if discriminant is D= b2 - 4ac, then roots of the quadratic equation are
(choose the correct alternative)
(1) Real and distinct, if D > 0
(2) Real and equal (i.e., repeated roots), if D = 0.
(3) Non-real (i.e. imaginary), if D< 0
(4) All of the above are correct
Answer:
(2) Real and equal (i.e., repeated roots), if D = 0.
Step-by-step explanation:
.In a quadratic equation ax2 + bx + c = 0, if discriminant is D= b2 - 4ac, then roots of the quadratic equation are
Real and equal (i.e., repeated roots), if D = 0.
If the D > b² - 4ac then it's real and distinct.
Question 2 of 10
2 Points
What is the sum of the rational expressions below?
2x+3/3x+x/x+1
Answer:
5x^2+5x+3/3x^2+3x
Step-by-step explanation:
Round 5 to the nearest ten.Enter your answer in the box below.
Answer:
[tex]10[/tex]
Step-by-step explanation:
[tex]05[/tex]
If the units place is higher than 5, then add 1 to the tens place.
Discover the area of a circle with a diameter of 17 feet ?
Answer: A≈226.98 ft²
Step-by-step explanation:
The formula for area of a circle is A=πr². The formula doesn't include diameter , but we can certainly find the radius from the diameter.
d=2r
17=2r
r=17/2=8.5 ft
Now that we have the radius, we can plug it in to area formula.
A=πr²
A=π(8.5ft)²
A=π72.25ft²
A≈226.98 ft²
Area of a circle: A = πr²
Get the radius by dividing the diameter by 2.
17 / 2 = 8.5
Now, solve with the given values.
A = π(8.5)²
A = 72.25π
A = 226.865
Therefore, the area is 226.865ft³
Best of Luck!
You are playing a game called cornhole and let’s assume that you are reallygood at it with the winning probability is 0.8. For the following parts, find (a) the name ofthe appropriate probability distribution and correct parameters, (b) the expected value and (c) the variance of Y.
A. Y = the number of games it takes you to lose one time.
B. Y = the number of games it takes you to lose four times.
C. Y the number of times you win out of 100 games.
Answer:
Step-by-step explanation:
Given that :
The probability of winning is 0.8
i.e P(winning) = 0.8
Then P(losing) = 0.2
a) Y ~ Geometric distribution
[tex]P = P(loose) =0.2 \\ \\ \mu_{\delta} = \dfrac{1}{P}= \dfrac{1}{0.2}\\ \\ = 5.0 \\ \\ \\ \dfrac{\sigma ^2 }{\delta } = \dfrac{1-P}{P^2} \\ \\ =\dfrac{0.8}{0.04} \\ \\ = 20[/tex]
b) Y ~ Negative Binomial Distribution
[tex]P = P (loose) =0.2 \\ \\ \delta = number \ of \ loss = 4 \\ \\ \mu_{\delta} = \dfrac{\delta}{P} \\ \\ =\dfrac{4}{0.2} \\ \\ = 20 \\ \\ \\ \sigma ^2_{\delta} = \dfrac{\delta (1-P)}{P^2} \\ \\ = \dfrac{4*0.8}{0.04}\\ \\ = 80[/tex]
c) Y ~ Binomial Distribution;
n = 100 ; P = 0.8
[tex]\mu_{\delta} = nP \\ \\ = 100*0.8 \\ \\ = 80 \\ \\ \\ \sigma_{\delta}^2 = nP(1-P) \\ \\ =80*0.2 \\ \\ = 16[/tex]
Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!
Answer:
2 is the answer
Step-by-step explanation:
area=1/2*base*height
as height = 2*base and area =4 it comes
1/2*2*base*base=4
so base *base=4
so base = 2
In an aquarium, there are 4 large fish and 16 small fish. Half of the small fish are blue. One fish is selected at random. Find the probability that it is a small, blue fish. Write your answer as a fraction in simplest form.
Answer:
2/5
Step-by-step explanation:
There are 20 fish, 8 of which are small and blue. Therefore, the probability of randomly selecting a small blue fish is 8/20 = 2/5.
what is the next term in the geometric sequence below 3, -6, 12, -24, ____
Answer:
48
Step-by-step explanation:
Answer:
48
Step-by-step explanation:
100%
Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic readings (mmHg) are listed below.
{ 130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150 }
Answer:
[tex] Min =120, Max= 150[/tex]
The first quartile can be calculated with this data:
130, 135, 140, 120, 130, 130
And the middle value is:
[tex] Q_1 = \frac{140+120}{2}=130[/tex]
The median is the value in the 6th position from the dataset ordered and we got:
[tex] Median= 135[/tex]
The third quartile can be calculated with this data:
135 140 140 143 144 150
And the middle value is:
[tex] Q_3 = \frac{140+143}{2}=141.5[/tex]
The five number summary for this case:
Min. 1st Qu. Median Mean 3rd Qu. Max.
120.0 130.0 135.0 135.6 141.5 150.0
The boxplot is on the figure attached
Step-by-step explanation:
We have the following data given:
130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150
If we sort the values on increasing order we got:
120 130 130 130 130 135 140 140 143 144 150
The minimum and maximum are:
[tex] Min =120, Max= 150[/tex]
The first quartile can be calculated with this data:
130, 135, 140, 120, 130, 130
And the middle value is:
[tex] Q_1 = \frac{140+120}{2}=130[/tex]
The median is the value in the 6th position from the dataset ordered and we got:
[tex] Median= 135[/tex]
The third quartile can be calculated with this data:
135 140 140 143 144 150
And the middle value is:
[tex] Q_3 = \frac{140+143}{2}=141.5[/tex]
The five number summary for this case:
Min. 1st Qu. Median Mean 3rd Qu. Max.
120.0 130.0 135.0 135.6 141.5 150.0
The boxplot is on the figure attached
En una encuesta sobre preferencias entre los deportes Tenis (T), Surf (S) y Golf (G) se sabe que:
90 personas fueron encuestadas
15 personas prefieren Golf
10 no prefieren ninguno de estos deportes
ninguno de los que prefiere los deportes Tenis ó Surf prefieren Golf
30 prefieren sólo Surf
20 prefieren sólo Tenis
a) ¿Cuántas personas prefieren dos de estos deportes?
b) ¿Cuántos prefieren sólo uno de estos deportes?
Answer:
a) 15
b) 65
Step-by-step explanation:
Adjunto se encuentra el diagrama asociado a esta situación. Comenzamos por ubicar aquellas afirmaciones que relacionan todos los deportes. Sabemos que 10 personas no prefieren ningún deporte. Luego, ubicamos 10 fuera de los conjuntos mostrados. Sabemos que 30 personas prefieren sólo surf y 20 personas prefieren sólo Tenis. Es decir, hay 30 personas en el conjunto S que no intersectan a los otros dos. En este momento, hemos ubicado a 60 personas. Nos hacen falta 30 personas. La afirmación "15 personas prefieren Golf" significa que la suma de los números dentro del conjunto G es 15. La afirmación "ninguno de los que prefieren los deportes Tenis o Surf prefieren el golf. Es decir, que la intersección de G con T y con S son vacías. Es decir que las 15 personas que prefieren golf, lo prefieren únicamente. Esto nos deja con 15 personas por ubicar. El único lugar donde podemos ubicar a dichas 15 personas es en en la intersección de T y S.
a). ¿cuántas personas prefieren dos de estos deportes? Por el diagrama, son aquellas personas que prefieren Tenis o Surf. Es decir, 15.
b) ¿Cuánto prefieren sólo uno de estos deportes? Es la suma de aquellos que prefieren sólo un deporte. Es decir, sólo G, sólo T o sólo S. Es decir 15+20+30 = 65.
Simplify the expression. (-3 + 6i)(-3 + 5i)
Answer:
11i-6
Step-by-step explanation:
Answer:
11i-6
Step-by-step explanation:
(-3+6i)(-3+5i)
combine like terms (-3)+(-3)=-6
6i+5i=11i