One factor of x^2 + 5x - 24 is?

Answer:

Step-by-step explanation:

(y - 3) = -2(x - 4)

y = -2x + 8 + 3

y = -2x + 11

pls give brainliest

Answer:

The the linear equation in point-slope form is

[tex]y-3 = -2 (x-4)[/tex]

Step-by-step explanation:

Given

We know that the point-slope form of the line equation is

[tex]y-y_1=m\left(x-x_1\right)[/tex]

Here:

substituting the values m = -2 and the point (4, 3) in the point-slope form

[tex]y-y_1=m\left(x-x_1\right)[/tex]

[tex]y-3 = -2 (x-4)[/tex]

Thus, the the linear equation in point-slope form is

[tex]y-3 = -2 (x-4)[/tex]

Note: This equation could be further simplified to write it in the slope-intercept form

[tex]y=mx+b[/tex]

where m is the slope and b is the y-intercept

so writing the equation in the slope-intercept form

[tex]y-3 = -2 (x-4)[/tex]

[tex]y-3 = -2x+8[/tex]

[tex]y=-2x+8+3[/tex]

[tex]y=-2x+11[/tex]

Thus, the equation is the slope-intercept form is

Answer:

Step-by-step explanation: 3x5=7056 = x25 2016

Answer:

1.5 cookies if 2/8 is like 2 cookies out of 8, 1/16 if its like 2/8 of a cookie

Step-by-step explanation: \

1.5: 2 x 3/4 (already ate 1/4) = 1.5

1/16= 1/4 (2/8 reduced)  x 1/4

Answer:

Costs are changing at the rate of $588 per month at this production level.

Step-by-step explanation:

From the question, we have:

C = 0.3X^2 + 8,000 ........................ (1)

Differentiating equation (1) with respect to time, t, we have:

dC/dt = (0.3 * 2) X (dX/dt)....................... (2)

Where;

X = 70

dX/dt = 14

Substituting this into equation (2), we have:

dC/dt = (0.3 * 2) * 70 * 14

dC/dt = 588

This implies that costs are changing at the rate of $588 per month at this production level.

Answer:

f(2.5)=3.5

Step-by-step explanation:

f(x)=2×2-3x+7

So,

f(2.5)=2×2-3×2.5+7

=4-7.5+7

=11-7.5

=3.5

Hope it will help you

Answer:

[tex]3^{-3}\cdot \:\:8^{-3}=\frac{1}{24^3}[/tex]

Thus, the equivalent expression is:  [tex]\frac{1}{24^3}[/tex]

Step-by-step explanation:

Given the expression

[tex]3^{-3}\cdot 8^{-3}[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}[/tex]

[tex]=8^{-3}\cdot \frac{1}{3^3}[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}[/tex]

[tex]=\frac{1}{3^3}\cdot \frac{1}{8^3}[/tex]

[tex]\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}[/tex]

[tex]=\frac{1\cdot \:1}{3^3\cdot \:8^3}[/tex]

[tex]=\frac{1}{24^3}[/tex]

Thus,

[tex]3^{-3}\cdot \:\:8^{-3}=\frac{1}{24^3}[/tex]

Thus, the equivalent expression is:  [tex]\frac{1}{24^3}[/tex]

Answer:

(B). [tex]A_{y}[/tex] = [tex]\left[\begin{array}{cc}12&7\\17&-51\end{array}\right][/tex]

Step-by-step explanation:

12x - 13y = 7

17x - 22y = - 51

A = [tex]\left[\begin{array}{cc}12&-13\\17&-22\end{array}\right][/tex]

[tex]A_{x}[/tex] = [tex]\left[\begin{array}{cc}7&-13\\-51&-22\end{array}\right][/tex]

[tex]A_{y}[/tex] = [tex]\left[\begin{array}{cc}12&7\\17&-51\end{array}\right][/tex]