one number is 8 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 480, find the numbers

Answer:

Step-by-step explanation:

Let the first number = x

Let the second number = 8x

Let the third number = x + 100

x + 8x + x + 100 = 480              Combine like terms

10x + 100 = 480                        Subtract 100

      - 100    -100

10x = 380                                   Divide by 10

x = 380/10

x = 38

First number = 38

Second number = 8*38 = 304

The third number = 38 + 100 = 138

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