One side of this regular hexagon has been extended to form an exterior angle.
Use given information to find m Angle p.

Answer:

A

Step-by-step explanation:

the quartiles are illustrated as 55 and 59. The average is 57.5 so 58? These are the key points on this type of graph.

The correct probability distribution of the random variable tracking "yellow (Y)" color is given by: Option A:

Yellow:x    Probability

0               9/16 = 0.5625

1                6/16 = 0.375

2                1/16 = 0.0625

Probability distribution of a random variable is the collection of value and its probability pair for values of that considered random variable.

It might be a function, a table etc.

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}[/tex]

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

For this case, the experiment consists of a spinner with four color sections, and is spun twice.

The sample space is:

S = {RB, RG, RY, RR, BR, BG, BY, BB, GR, GB, GY, GG, YR, YB, YG, YY}

Let we take:

X = the number of times out of two spins the color yellow occurs in a pair of spin of the considered spinner.

Then, as there are only two spin going to happen, so the values X can take are:

Let we take:

Then, as there are four colors equally likely, so we get:
P(A) = 1/4 (yellow color can occur in 1 way in one spin, and total number of colors that can occur = 4).

Similarly, we get P(B) = 1/4

Also, as first and second spins are independent of each other's result, so both A and B are independent events.

Getting the probabilities for each value of X:

[tex]P(X = 0) = P(A' \cap B') = P(A')P(B') = (1-P(A))(1-P(B)) \\P(X = 0) = \dfrac{3}{4} \times \dfrac{3}{4}\\\\P(X = 0) = \dfrac{9}{16}[/tex]

(where A' and B' are complement of A and B, and as (A and B) are independent, so as (A' and B') and (A' and B) and (A and B') )

So either first spin had yellow color, or second, so we get:

[tex]P(X = 1) = P((A' \cap B) \cup (A \cap B'))\\ P(X=1) = P(A' \cap B) + P(A \cap B') - P((A' \cap B) \cap (A \cap B'))\\P(X=1) = P(A')P(B) + P(A)P(B') -0\\P(X=1) = \dfrac{3}{4} \times \dfrac{1}{4} + \dfrac{1}{4} \times \dfrac{3}{4} - 0\\\\P(X = 1) = \dfrac{6}{16}[/tex]

Both event A and B occured this time, so we get:

[tex]P(X = 2) = P(A \cap B) = P(A)P(B) \\P(X = 0) = \dfrac{1}{4} \times \dfrac{1}{4}\\\\P(X = 0) = \dfrac{1}{16}[/tex]

Thus, the probability distribution of X is:

X=x                P(X = x)

0               9/16 = 0.5625

1                6/16 = 0.375

2                1/16 = 0.0625

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The logo that meets the building requirement must be:

A Logo in art is a visual symbol, that an organization selects as one of the primary visual identifiers of its brand.

They are first conceptualized, then built or created after much consultation with graphic and marketing professionals.

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Answer:

8

Step-by-step explanation:

I bolded what I think is important to know.

To build a pizza, customers choose stuffed (S) or thin (T) crust, red (R) or white (W) sauce, and a topping. The choices for toppings are pepperoni (P), sausage (S), or vegetables (V).

The following list shows the possible pizzas that can be made. The first letter represents the crust, the second letter represents the sauce, and the third letter represents the topping. For example, a stuffed-crust pizza with red sauce and pepperoni is listed as SRP, and a stuffed-crust pizza with white sauce and sausage is listed as SWS.

SRP, SRS, SRV, SWP, SWS, SWV, TRP, TRS, TRV, TWP, TWS, TWV

How many outcomes include red sauce or sausage?

An equation is formed of two equal expressions. The solution of the equation is w=3.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

In order to solve the equation, we need to isolate the variable in the following manner, therefore, the solution of the equation can be written as,

[tex]6.2w=18.6[/tex]

Divide both sides of the equation by 6.2,

[tex]6.2w=18.6\\\\\dfrac{6.2w}{6.2}=\dfrac{18.6}{6.2}\\\\w = 3[/tex]

Hence, the solution of the equation is w=3.

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Answer:

The angle of KLM is 50°

Step-by-step explanation:

Used protractor

Answer:

∠ KLM ≈ 33.7°

Step-by-step explanation:

using Pythagoras' identity in right triangle JKM

KM²  = JK² + JM² = 7² + 4.5² = 49 + 20.25 = 69.25 ( take square root of both sides )

KM = [tex]\sqrt{69.25}[/tex] ≈ 8.322 cm

using the sine ratio in right triangle KLM

sin KLM = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{KM}{LM}[/tex] = [tex]\frac{8.322}{15}[/tex] , then

∠ KLM = [tex]sin^{-1}[/tex] ( [tex]\frac{8.322}{15}[/tex] ) ≈ 33.7° ( to 3 significant figures )

Answer:

Step-by-step explanation:

What is the value of 6(2b-4) when b =5 2.  The value of is 36. Step-by-step explanation: Given expression: To find the value of at b= 5, we need to substitute the b=5 in the expression, we get.

can i have brainly please :) thanks bro

Answer: 36

Step-by-step explanation:

The stop sign is an octagon or regular polygon.

It is given that a stop sign has 8 sides.

It is required to describe the sign using a polygon.

It is defined as the flat planner geometry in two dimensions with a closed shape there are two types of polygon one is irregular in which the angle and sides are not equal and the second one is a regular polygon in which sides and angles are equal called regular polygon.

We have a stop sign that has 8 sides.

As we know the definition of a polygon they are planner geometry and in a regular polygon, the sides and angles are equal called regular polygon.

The stop sign has 8 if we assume they are all equal sides and angles then we can say that the stop sign is an octagon(in which the number of sides is 8) or a regular polygon.

Thus, the stop sign is an octagon or regular polygon.

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Answer:

8, octagon, & regular

Step-by-step explanation:

I did it

Answer:

Here!!

Step-by-step explanation:

Here are a few ratios that are equivalent to  4 : 11  . . . . .

8 : 22

12 : 33

20 : 55

400 : 1100

308 : 847

4 billion : 11 billion

The wall can be built in 22 days by 6 workers in first 6 days and 9 workers in the rest of time.

In this question we must use the definition of inverse proportionality, in which the number of workers ([tex]n[/tex]), no unit, is inversely proportional to the building time ([tex]t[/tex]), in days.

According to the statement, 6 workers spent 6 days building a wall and there are 24 days left for completion, but 3 more workers entered to reduce building time, which can be represented by the following expression:

[tex]x = 24\,days \times \frac{6}{9}[/tex]

[tex]x = 16\,days[/tex]

In this scenario, the wall can be built in 22 days. [tex]\blacksquare[/tex]

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Answer:

x-17=56

x-17+17=56+17

x=56+17

x=73

Step-by-step explanation:

Do mark BRAINLIEST

Answer:

d

Step-by-step explanation:

Answer:

1st option

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - [tex]\frac{4}{5}[/tex] , then

y = - [tex]\frac{4}{5}[/tex] x + c

to find c substitute (5, 1 ) into the equation

1 = - 4 + c ⇒ c = 1 + 4 = 5

y = - [tex]\frac{4}{5}[/tex] x + 5 ( multiply through by 5 to clear the fraction )

5y = - 4x + 25 ( add 4x to both sides )

4x + 5y = 25 ← in standard form

The horizontal distance to the nearest hundredth of a meter, that Liola covered is 129.03 m (option A)

The following data were obtained from the question:

The horizontal distance Liola covered as she drives 130 m up the hill can be obtained as follow:

Cos θ = Adjacent / Hypotenuse

Cos 7 = Horizontal distance / 130

Cross multiply

Horizontal distance = 130 × Cos 7

= 130 × 0.9925

= 129.03 m

Thus, the horizontal distance Liola covered is 129.03 m (option A)

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Using the t-distribution, as we have the standard deviation for the sample, it is found that the p-value is of 0.0009.

At the null hypothesis, it is tested if the students study 20 hours, that is:

[tex]H_0: \mu = 20[/tex].

At the alternative hypothesis, it is tested if they study less than 20 hours, that is:

[tex]H_1: \mu < 20[/tex].

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

In this problem, the values of the parameters are given as:

[tex]\overline{x} = 17.7, \mu = 20, s = 3.9, n = 33[/tex].

Hence, the value of the test statistic is:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{17.7 - 20}{\frac{3.9}{\sqrt{33}}}[/tex]

[tex]t = -3.39[/tex]

Using a t-distribution calculator, considering a left-tailed test, as we are testing if the mean is less than value, the p-value is of 0.0009.

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The explicit rule formula an = -2n + 8 is an arithmetic progression

The value of a11 is -14

The explicit rule formula is given as:

an = -2n + 8

Substitute 11 for n to calculate a11

a11 = -2 * 11 + 8

Evaluate the product

a11 = -22 + 8

Evaluate the sum

a11 = -14

Hence, the value of a11 is -14

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eighteen thirds

two thirds refers to : [tex]\sf \sf \dfrac{2}{3}[/tex]

[tex]\sf \rightarrow 9 * \dfrac{2}{3}[/tex]

[tex]\sf \rightarrow \dfrac{9*2}{3}[/tex]

[tex]\sf \rightarrow \dfrac{18}{3}[/tex]     [ also refereed as eighteen thirds ]

Answer:

[tex]6\\six~is~2/3~of~9\\this~can~also~be~looked~at~as\\2 * 3 = 6\\[/tex]

↓ Second problem

[tex]11/27\\18/27\\11/3\\18/3[/tex]

                                          Hope it helps, be great!

Answer:

(A) QS = 8

(B) PS = 15

(C) SR = 6

(D) PQ = 17

(E) QR = 10

Step-by-step explanation:

i did it and got it correct! :D

All the distances are;

(A) QS = 8

(B) PS = 15

(C) SR = 6

(D) PQ = 17

(E) QR = 10

The length of the line segment bridging two points on a plane is known as the distance between the points.

The formula to find the distance between the two points is usually given by d=√{(x₂-x₁)² + (y₂-y₁)²}

Given:

The three points P(1,2), Q(16,10), and R(22,2) are on the coordinate plane.

To find the lengths of the different line segments in the given figure, we can use the distance formula:

Distance = √[(x2 - x1)² + (y2 - y1)²]

(A) To find the length of QS, we need to find the difference between the y-coordinates of Q and S:

QS = |10 - 2| = 8

Therefore, QS has a length of 8 units.

(B) To find the length of PS, we need to find the difference between the x-coordinates of P and S:

PS = |16 - 1| = 15

Therefore, PS has a length of 15 units.

(C) To find the length of SR, we need to find the difference between the x-coordinates of S and R:

SR = |22 - 16| = 6

Therefore, SR has a length of 6 units.

(D) To find the length of PQ, we need to find the difference between the x-coordinates of P and Q:

PQ = √[1 - 16)² + (2 - 10)²]

Therefore, PQ has a length of 17 units.

(E) To find the length of QR, we need to use the distance formula:

QR = √[(22 - 16)² + (2 - 10)²]

= √[36 + 64]

= √100

= 10

Therefore, QR has a length of 10 units.

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Hey There! Happy to Help! Your answer is below.

Answer:

17/20 = 0.85000

Step 1:

⇒ (3/4 + 4/5) - 7/10

Step 2:

⇒ (3/4 + 4/5) - 7/10

Step 3:

⇒(3/4 + 4/5) - 7/10

Step 4:

⇒ Find the Least Common Multiple

Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 0 2

5 0 1 1

Product of all

Prime Factors  4 5 20

  Least Common Multiple:

     20

⇒  Calculate multipliers for the two fractions

⇒  Denote the Least Common Multiple by  L.C.M

   ⇒ Denote the Left Multiplier by  Left_M

⇒   Denote the Right Multiplier by  Right_M

⇒    Denote the Left Deniminator by  L_Deno

⇒    Denote the Right Multiplier by  R_Deno

⇒ Rewrite the two fractions into equivalent fractions

⇒ Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num.               3 • 5

-----------------------------    =  ------------

L.C.M                                     20  

  R. Mult. • R. Num.      4 • 4

----------------------------- =  -------

   L.C.M                           20  

 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 + 4 • 4     31

------------------ = ---

     20           20

Equation at the end of step 4:

 31     7

---- - ----

20   10

Step 5:

 Find the Least Common Multiple

     The left denominator is :       20

     The right denominator is :       10

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 1 2

5 1 1 1

Product of all

Prime Factors  20 10 20

   Least Common Multiple:

     20

Calculating Multipliers :

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

Left_M = L.C.M / L_Deno = 1

  Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

Rewrite the two fractions into equivalent fractions

L. Mult. • L. Num.      31

------------------------- = ----

L.C.M                      20

R. Mult. • R. Num.      7 • 2

---------------------------- = -----

L.C.M              20  

Adding fractions that have a common denominator :

Adding up the two equivalent fractions

31 - (7 • 2)     17'

--------------  = ---

20          20

 17          

 —— = 0.85000

 20        

Answer:

B: Frequency of Foreign-Language Studies by Row

Answer:

2x/x+2

Step-by-step explanation:

Factor out 2x in the numerator

Then you get: 2x(x+4)

Factor the denominator

Two numbers that multiply to 8 and add to 6(2 and 4)

So you get: (x+2)(x+4)

Now you have: (2x(x+4))/(x+2)(x+4)

Simplify by cancelling the x+4

2x/x+2

Hey there!

Answer: [tex] \Rightarrow \boxed {\sf{\frac{2x}{(x+2)}}}[/tex]

Solving steps:-

[tex] \rightarrow\sf{\frac{ {2x}^{2} + 8x}{ {x}^{2} + 6x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ {x}^{2} + 4x +2x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ x (x + 4) +2(x + 4)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x\sout{(x + 4)}}{ \sout{(x + 4)} (x + 2)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x}{ (x + 2)} }[/tex]

~Done~

Answer:

1/8

Step-by-step explanation:

i believe this is the answer

Question:

The diameter of a construction pipe is 7ft. If the pipe is 35ft long, what is the volume. (Use 3.14 for pie and round your answer to the nearest cubic foot.)

Answer: V=pir^2h V=3.14*3.5^2*35 V=1346 cu ft

Not fully sure....

But it should be right...

Step-by-step explanation:

1/81 gallon for 1/4 mile.

what do I need to multiply 1/81 with to get 1 gallon ?

it is simple, right ? i need to multiply it by 81 to get 1 gallon.

in order to keep the relationship (ratio) unchanged, I need to multiply the other part (1/4 mile) with the same factor :

1/4 × 81 = 81/4 = 80/4 + 1/4 = 20 1/4 miles

so, at this rate, that car can travel 20 1/4 miles using 1 gallon of gas.

Answer:

39 sq inches

Area of sector = [tex]\frac{θ}{360}*\pi r^{2}[/tex]

Given: θ = 70°, radius (r) = 8 inches

Area of sector = [tex]\frac{70}{360} * \pi *8^{2}[/tex]

= 39.095

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hope it helps...

P = 2 x (5,5 + 3,5) = 18 cm

P = is the circumference of the figure

Answer:

the answer should be 18 cm

you can either do 2 × (length + width)

2 × (5.5 + 3.5)

2 × 9 = 18

or

5.5 + 5.5 = 11

3.5 + 3.5 = 7

11 + 7 = 18

either way it's 18, I hope this helps

Answer:

270

Step-by-step explanation:

5 x 7 x 6= 210

2 x 5 x 6= 60

210 + 60= 270

The required volume of the fish tank is 240 cubic inches. option D is correct.

Volume is defined as the mass of the object per unit density while for geometry it is calculated as profile area multiplied by the length at which that profile is extruded.

Here,
The requried volume of the figure is given as,
Volume  = height [area of the plot]

Since the area of the plot is given as,
area = area of the left rectangle + area of the right triangle.
area = 5 × 7 + 1/2 × [12-7]×[5-3]
area = 35 + 5
area = 40 square inches.

Volume = 6 [40]

Volume = 240 in³

Thus, the required volume of the fish tank is 240 cubic inches. option D is correct.

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Answer:

B, 20

Step-by-step explanation:

The Pythagorean Theorem states that the two shortest lengths in a right triangle (in our case, 12 and 16), is equal to the longest length in a right triangle (c). So,

a²+b²=c²

Substitute 12 and 16 for a and b, our side lengths

12²+16²=c²

144+256=400

400=c²

Square root both c and 400, which gives us...

20=c

So, the value of x is 20.

Answer:

x = 10.8

Explanation:

[tex]\sf \sf cos(x)= \dfrac{adjacent}{hypotensue}[/tex]

using cosine rule:

[tex]\rightarrow \sf cos(26)= \dfrac{x}{12}[/tex]

[tex]\rightarrow \sf x = cos(26) *12[/tex]

[tex]\rightarrow \sf x =10.8[/tex]

Answer:

The answer is rounded 10.8

Step-by-step explanation:

Cosine is the adjacent side over the hypotenuse, or a/h. So, cos 26=x/12. To solve for x, isolation of the variable is necessary. If both sides are multiplied by 12, the equation becomes 12 (cos 26)=x. The cosine of 26 is 0.8988, which multiplied by 12 is 10.8.

Hope this helps!