Answer:
the costs for the holiday for each person
£250
Step-by-step explanation:
So ,
£250 × 7 = 1,750
13^5/13^x=13^4
Anyone know how to solve this?
[tex]\frac{13^5}{13^x} =13^4 =>13^{5-x} =13^4\\ =>5-x=4=> x=5-4=1[/tex]
ANSWER: x = 1
ok done. Thank to me :>
HELPPPPP PLEASE ACTUALLY GIVE ME THE ANSWER AND NOT JUST A link PLSSS ITS DUE IN 23 MINUTESSS!!!!!!!!!!!! HELP
Answer:
4 1/9
Step-by-step explanation:
Well we can infer that the whole number will be 4. And 0.111 repeating is 1/9 as a fraction.
In a certain town, 80% of all married men are working, and 75% of all married men are over 35 years old. Among working married men, 70% are over 35 years old. What proportion of non-working married men are over 35 years old?
answer: 95%
working is needed
It helps to set up a two way table as shown below. Such tables compare 2 different variables. In this case, we're comparing the variables "working status" and "age".
Specifically, the working status separates the men into "working vs non-working". The age variable splits the men into groups of "35 or younger" and "over 35". Usually, but not always, each variable will take on two values.
Let's say this town had 1000 married men. 80% of this is 0.80*1000 = 800 to indicate there are 800 married working men. So we write this in the "total" column for the "working" row. This leaves 1000-800 = 200 nonworking married men, which will go right under the 800.
We're told that 75% of the married men are over 35, so 0.75*1000 = 750 married men are over 35. This goes in the "total" row for the "over 35" column. There are 1000-750 = 250 married men who are 35 and under.
As you can see, the stuff in the total column and the total row must add back to the grand total of 1000 married men overall.
--------------------------------
Another bit of info given is that "Among the working married men, 70% are over 35". We'll only focus on the "working" row. We have 800 total and 70% of this is 0.70*800 = 560 which is the number of working married men over 35. This leaves 800-560 = 240 married men who are not over 35.
At this point, we have 2 spots left in the table. Through guess and check, or using algebra, you should find that there are 190 non-working men over 35 and 10 non-working men who aren't over 35. Make sure that each row and column total checks out.
--------------------------------
By now, the table is fully filled out. See below.
Your teacher now asks "what proportion of non-working married men are over 35 years old?" which means we'll only focus on the "non-working" row. There are 200 men total here, and of this total, 190 are over 35.
So, 190/200 = 0.95 = 95% of the non-working married men are over 35.
At the beginning of the year, Wyatt had $40 in savings and saved an additional $14 each week thereafter. Julian started the year with $20 and saved $19 every week. Let WW represent the amount of money Wyatt has saved tt weeks after the beginning of the year and let JJ represent the amount of money Julian has saved tt weeks after the beginning of the year. Write an equation for each situation, in terms of t,t, and determine the interval of time when Wyatt has more in savings than Julian.
Answer:
4 weeks
Step-by-step explanation:
Wyatt's equation:
t=14w+40
Julian's equation:
t=19j+20
Since both equations equal the same thing, or t, we can equal them against each other as 1 equation
14t+40=19t+20
(subtract 20 from both sides)
14t+20=19t
(subtract 14t from both sides)
20=5t
(divide both sides by 5)
t=4 weeks
Fill in the missing numbers to complete the linear equation that gives the rule for this table.
Answer:
y= -10x-24
Step-by-step explanation:
To write the linear equation, first find the slope.
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
Let's pick the first two x and y values as our coordinate points.
(1, -34) (2, -44)
[tex]\frac{-44-(-34)}{2-1} =-10[/tex]
The slope is -10.
Use the point-slope formula to write the equation.
y-y1= m(x-x1)
y-(-34)= -10(x-1)
y+34= -10x+10
y= -10x-24
Line v passes through points (4,1) and (6, 6). Line w is parallel to line v. What is the slope of
line w
What is the solution to the inequality
Answer:
Search Results
Featured snippet from the web
A solution for an inequality in x is a number such that when we substitute that number for x we have a true statement. So, 4 is a solution for example 1, while 8 is not. The solution set of an inequality is the set of all solutions.
Step-by-step explanation:
I need help and I can’t find any sadly. Help!!
Answer:
See answer below.
Step-by-step explanation:
3x - 2 = 4 Given
+2 = +2
3x = 6 Addition Property of Equality
3x/3 = 6/3
x = 2 Division Property of Equality
a sweater was on 20% discount. the amount of discount was $7 what was the original price?
Answer:
$35
Step-by-step explanation:
if $7 is only 20% of the original price multiply 7×5
-20%×5=100%
same thing as 7×5=35
just switch the percent by its worth
which expression is equivalent to 4√8/3√2
Answer:
8/3
Step-by-step explanation:
The square root of 8 can actually be written [tex]2\sqrt2[/tex], so [tex]4\sqrt2 = 4 \cdot 2\sqrt2 = 8\sqrt2[/tex]
Now, we are looking for [tex]\frac{8\sqrt2}{3\sqrt2}[/tex]. Both the square root of 2s cancel, so we are left with 8/3
Consider the number. -|-34.5| what is the distance from this number to zero on a standard number line??
Answer:
34.5
Step-by-step explanation:
The absolute value of -|-34.5| is -34.5. So, -34.5 is 34.5 away from 0.
Answer:
34.5 units.
Step-by-step explanation:
When we simplify -|-34.5|, we get -34.5, which is basically 34.5 units away from 0.
Hoped this helped.
Find the area of an equilateral triangle with side length 4.6 cm. Round your answer to 1 DP.
Answer:
A = 9.2 cm²
Step-by-step explanation:
A = 1/2 bh, you know the base = 4.6 and you need to find the height of the triangle.
Drawn the attitude of the equilateral triangle to the base and use a² + b² = c²
c = side of the triangle = 4.6 , b = 1/2 0f 4.6 = 2.3 . the attitude to the base ÷ the base in half.
a² + (2.3)² = (4.6)²
a² + 5.29 = 21.16
a² = 21.16 - 5.29
a² = 15.87
[tex]a = \sqrt{15.87}[/tex]
Now we know the height of the triangle = [tex]\sqrt{15.87}[/tex] , the base = 4.6
A = 1/2bh
A = 1/2 (4.6)([tex]\sqrt{15.87}[/tex] )
A = 9.1625
A = 9.2 cm² or the A of any equilateral triangle = [tex]\frac{\sqrt{3} }{4} s^2[/tex]
A = [tex]\frac{\sqrt{3} }{4} (4.6)^2[/tex]
A = 9.1625
A = 9.2
How many ways are possible to select a president and vice president from an
association with 5400 members?
The Answer there are 9*8 = 72 ways to choose a president and vice president
Step-by-step explanation:
Pete grabbed 18 mixed nuts, StartFraction 2 Over 9 EndFraction of which were almonds. Which equation shows how to determine the number of almonds Pete grabbed?
Answer:
Thats one heck of a whole lot nuts
Step-by-step explanation:
Drag and drop the answers to the boxes to correctly complete the proof.
Given: Rhombus JKMH with diagonals intersecting at point P
Rhombus J K M H with diagonals J M and H K intersecting at P
Prove: JM⎯⎯⎯⎯⎯⊥HK⎯⎯⎯⎯⎯⎯
By the definition of Response area, JK⎯⎯⎯⎯⎯≅KM⎯⎯⎯⎯⎯⎯ and by the reflexive property of congruence, KP⎯⎯⎯⎯⎯≅KP⎯⎯⎯⎯⎯ . Because the diagonals of a rhombus bisect a pair of opposite angles, ∠JKP≅∠MKP , making △JKP≅△MKP by the Response area. Because Response area, ∠JPK≅∠MPK, and these angles are right angles because two angles that form a linear pair are congruent, thereby making JM⎯⎯⎯⎯⎯⊥HK⎯⎯⎯⎯⎯⎯ by the definition of perpendicular segments.
Response area means blank
The answers are Congruent segments, a rhombus, a parallelogram, SSS congruence postulate, ASA congruence postulate, SAS congruence postulate, CPCTC, they are adjacent, and vertical angles are congruent
The completed proof is presented as follows;
By definition of a rhombus [tex]\overline{JK} \cong \overline{KM}[/tex] and by the reflexive property of
congruence [tex]\overline{KP} \cong \overline{KP}[/tex], because the diagonals of a rhombus bisect a pair
of opposite angles, ∠JKP ≅ ∠MKP, making ΔJKP ≅ ΔMKP by the SAS
congruency postulate, because CPCTC, ∠JPK ≅ ∠MPK, and these angles
are right angles because two angles that form a linear pair are congruent,
thereby making, [tex]\overline{JK} \perp \overline{KM}[/tex] by definition of perpendicular segments.
Reasons:
Please find attached the drawing of the given rhombus JKMH, that show
the point of intersection of the diagonals JM and HK at point P.
A rhombus is an equilateral quadrilateral, therefore, the adjacent sides [tex]\overline{JK} \ and \ \overline{KM}[/tex] are congruent.The SAS congruency postulate states that if a triangle has two sides and an included angle that are congruent to two sides and an included angle of another triangle, then the two triangles are congruent.CPCTC is an acronym for Congruent Parts of Congruent Triangles are Congruent.Learn more about the properties of a rhombus here:
https://brainly.com/question/10618409
A fishbowl has a capacity of 192 fluid ounces. How many quarts is that?
Answer:
hope this helps
Step-by-step explanation:
192 fl oz. = 6 quarts
to get this you divide the fluid ounces by 32.
Complete the tables of values. X 4â’x â’1 4 0 a 2 b 4 c a = b = c = x ( 2 3 ) x â’1 3 2 0 d 2 e 4 f d = e = f =.
The corresponding values of d, e ad f are 1, 1/16, and 1/256 respectively
Find the table of values attached. From the given table the function of the output is expressed as [tex]g(x) = 4^{-x}[/tex]
If x = 0, then;
[tex]g(0) = 4^{-0}\\g(0) = 1/4^0\\g(0)=1/1 = 1\\[/tex]
If x = 2
[tex]g(2) = 4^{-2}\\g(2) = 1/4^2\\g(2)=1/16[/tex]
If x = 4;
[tex]g(4) = 4^{-4}\\g(4) = 1/4^4\\g(4)=1/256[/tex]
Therefore the corresponding values of d, e ad f are 1, 1/16 and 1/256 respectively
Learn more on table of functions here: https://brainly.com/question/3632175
Answer:
a = ⇒ 1
b = ⇒ 1/16
c = ⇒ 1/256
d = ⇒ 1
e = ⇒ 4/9
f = ⇒ 16/81
Will mark brainliest for 2 possible answers
Answer:
x³ +7x² +7x -15
Step-by-step explanation:
Apply the distributive property repeatedly, and/or recognize the ways that the coefficients of the product are formed.
distributive property
(x -1)(x +3)(x +5)
= (x -1)(x(x +5) +3(x +5))
= (x -1)(x² +5x +3x +15) = (x -1)(x² +8x +15)
= x(x² +8x +15) -1(x² +8x +15)
= x³ +8x² +15x -x² -8x -15
= x³ +7x² +7x -15
__
using knowledge of products of powers
The x³ term will be the product of all of the x-terms.
The x² term will be the pairwise sum of products of two x-terms and the third constant.
The x term will be the pairwise sum of products of one x-term and the two other constants.
The constant term will be the product of all of the constants.
These computations are simplified a bit because all of the x-coefficients are 1.
= x³ +(-1 +3 +5)x² +(-1·3 +(-1)·5 +3·5)x +(-1)·3·5
= x³ +7x² +7x -15
If there is a 30% chance of snow today and a 10% chance of snow tomorrow, what is the chance that it will not snow today and tomorrow? Write your answer as a percent.
Answer:
The weather forecast says that there is a "30% chance of rain," and we think we understand what it means. This quantitative statement is assumed to be unambiguous and to convey more information than does a qualitative statement like "It might rain tomorrow." Because the forecast is expressed as a single-event probability, however, it does not specify the class of events it refers to. Therefore, even numerical probabilities can be interpreted by members of the public in multiple, mutually contradictory ways. To find out whether the same statement about rain probability evokes various interpretations, we randomly surveyed pedestrians in five metropolises located in countries that have had different degrees of exposure to probabilistic forecasts--Amsterdam, Athens, Berlin, Milan, and New York. They were asked what a "30% chance of rain tomorrow" means both in a multiple-choice and a free-response format. Only in New York did a majority of them supply the standard meteorological interpretation, namely, that when the weather conditions are like today, in 3 out of 10 cases there will be (at least a trace of) rain the next day. In each of the European cities, this alternative was judged as the least appropriate. The preferred interpretation in Europe was that it will rain tomorrow "30% of the time," followed by "in 30% of the area." To improve risk communication with the public, experts need to specify the reference class, that is, the class of events to which a single-event probability refers.
1.86÷2=1, point, 86, divided by, 2, equals
\text{ hundredths}\div 2 hundredths÷2start text, space, h, u, n, d, r, e, d, t, h, s, end text, divided by, 2
1.86 \div 2 =1.86÷2=1, point, 86, divided by, 2, equals
\text{ hundredths} hundredthsstart text, space, h, u, n, d, r, e, d, t, h, s, end text
1.86 \div 2 =1.86÷2=1, point, 86, divided by, 2, equals
The equivalent value of the expression 1, point, 86, divided by, 2 is given by A = 0.93.
Given data:
Let the expression be represented as A.
Now, the value of A is
A = 1, point, 86, divided by, 2.
Substituting the values in the equation:
[tex]A=\frac{1.86}{2}[/tex]
On simplifying the equation:
[tex]A=0.93[/tex]
Therefore, the value of A is 0.93
Hence, the equation is A = 0.93
To learn more about equations, refer:
https://brainly.com/question/19297665
#SPJ6
The complete question is attached below:
Find the equivalent value of the expression "1, point, 86, divided by, 2".
If p is the smallest of four consecutive even integers, what is their sum interms of P?
plz be fast
I need full step by step the explanation
The sum in terms of p of four consecutive even integers with p been the smallest is 4(p + 3)
Even numbers are numbers that can be divided into two equal groups and they can be easily divisible by 2 without any remainder.
p is the smallest of the four consecutive even integers. This means p come first and it is the first term of the numbers.
Therefore, the 4 consecutive even integers is represented as follows;
p, p + 2, p + 4, p + 6
So the sum is equal to:
sum = p + p + 2 + p + 4 + p + 6
sum = 4p + 12
sum = 4(p + 3)
learn more on even numbers here: https://brainly.com/question/21514478?referrer=searchResults
Topic 1: Translate
The sum of twice a number and 9 is -25."
Answer:
2n + 9 = - 25
Step-by-step explanation:
let the number be n then twice the number is 2n
The sum of 2n and 9 is 2n + 9
the result is - 25 , that is
2n + 9 = - 25
Answer:
x=-17Step-by-step explanation:
The sum of twice a number and 9 is -25."
2x + 9 = -25
2x = -34
x = -17
-----------------------------------------
check
2 * (-17) + 9 = -25
-25 = -25
the answer is good
Help...? Thanks! No links
Answer: C) Move it 3 places to the left
Explanation:
We're dividing the number [tex]34.62[/tex] by [tex]10^3[/tex], which is the same as dividing by 1000.
The exponent 3 tells us how many spots to move the decimal point. We move to the left because the number gets smaller. If we multiplied by [tex]10^3[/tex], then we'd move the decimal point 3 spots to the right.
So, [tex]34.62 \div 10^3 = 34.62 \div 1000 = 0.03462[/tex]
x*y=xy+2y find 4*[1*-5]
Answer:
- 90
Step-by-step explanation:
Evaluate 1*- 5 then the outer one
1*- 5 ( with x = 1 and y = - 5 )
= 1(- 5) + 2(- 5)
= - 5 - 10
= - 15
Then
4*- 15 ( with x = 4 and y = - 15 )
= 4(- 15) + 2(- 15)
= - 60 - 30
= - 90
how many lines of symmetry does the figure have?
Answer:
Step-by-step explanation:
2
If TU = 6 units, what must be true?
O SU + UT = RT
O RT + TU = RS
© RS + SU = RU
TU + US = RS
Answer:
SU + UT = RT
Step-by-step explanation:
Given that TU = 6 units, RT = 12 units and RS = 24 units.
So,
For finding US, we will subtract the length of RT and TU from RS.
US = RS - RT - TU
US = 24 - 12 - 6
US = 6 units
Putting all the given values in the given conditions, we get the first option right, which is:
SU + UT = RT
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807May I please receive help?
Answer:
a = 19.6 (rounded to the nearest tenth)
Step-by-step explanation:
a^2 + b^2 = c^2
Hypotenuse - 35 m, Legs - 29 m, x
a^2 +29^2 = 35^2
a^2 + 841 = 1225
Subtract 841 from both sides
a^2 = 384
Square root both sides
√a^2 = √384
a = 19.595
can someone help me with this
[tex]\dfrac{2x-3}x = \dfrac{14}{x+5}\\\\\implies (2x-3)(x+5) = 14x\\\\\implies 2x^2 +10x -3x -15 -14x=0\\\\\implies 2x^2-7x-15=0\\\\\text{Apply quadratic formula,}~~x= \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}.\\\\\text{In this case,}~ a=2, b=-7~ \text{and}~ c = -15. \\\\\\x = \dfrac{-(-7) \pm \sqrt{(-7)^2 -4\cdot 2 \cdot (-15)}}{2(2)}\\\\\\\implies x = \dfrac{7 \pm \sqrt{169}}{4}\\\\\\\implies x = \dfrac{7 \pm 13}4\\\\\\[/tex]
[tex]\text{Hence} ~x = \dfrac{7+13}{4} = \dfrac{20}4 = 5 ~\text{or}~ x = \dfrac{7-13}4 = -\dfrac{6}4 = -\dfrac 32[/tex]
I do believe i need help.
Answer:
A
Step-by-step explanation:
Can't have 0 in the denominator
1/3x^2 = -3
The solution to the equation is ___?
[tex]\dfrac 1{3x^2} = -3\\\\\implies -9x^2 = 1\\\\\implies x^2 = -\dfrac 19\\\\\implies x = \pm\sqrt{-\dfrac 19} = \pm \dfrac 13i[/tex]