Out a certain function machine, and input of three has an output of negative sex. And input of -2 has an output of four. And input zero has an output of zero. Which of the following phrases describes the functional rule?
Answers
Question:
Solution:
Consider the following diagram related to the function rule:
Notice that the only function that fits the problem description is:
f(x) = -2x
that is, because:
f(0) = -2(0) = 0
f(3) = -2(3) = -6
and
f(-2)= -2(-2) = 4
so, the correct answer would be:
MULTIPLY THE INPUT BY -2.
Related Questions
O How many times greater is:the value of the digit 2 in234,567 than the value ofthe digit 2 in 765,432?
Answers
Given:
The given numbers are 234,567 and 765,432.
Required:
We need to find the number of times the value of the digit 2 in 234,567 is greater than the value of digit 2 in 765,432.
Explanation:
The value of digit 2 in 234,567 is 200,000.
The value of digit 2 in 765,432 is 2.
Divide 200,000 by 2.
[tex]\frac{200,000}{2}=100,000[/tex]200,000 is 100,000 times greater than 2.
The value of digit 2 in 234,567 is 100,000 times greater than the value of digit 2 in 765,432 is 2.
Final answer:
The value of digit 2 in 234,567 is 100,000 times greater than the value of digit 2 in 765,432 is 2.
[tex]100,000[/tex]GOF and DISERBUHVE PROPERE25 + 20
Answers
the given expression is
= 25 + 20
now we can break these numbers'
[tex]=5\times5+5\times4[/tex](we know that 5 x 5 = 25
and 5 x 4 = 20)
now we can take greatest common factor 5 as common, then
[tex]\begin{gathered} =5\times(5+4) \\ =5\times9 \\ =45 \end{gathered}[/tex]so the answer is 45
For this question it is asking for the mean, standard deviation, Q1, Q3, lower fence, and upper fence
Answers
Step 1
Given;
[tex]10,\:15,\:19,\:52,\:34,\:44,\:47,\:20,\:60,\:25[/tex]Step 2
Find the mean
[tex]\begin{gathered} The\:arithemtic\:mean\:\left(average\right)\:is\:the\:sum\:of\:the\:values\:in\:the\:set\: \\ \begin{equation*} divided\:by\:the\:number\:of\:elements\:in\:that\:set. \end{equation*} \\ \mathrm{If\:our\:data\:set\:contains\:the\:values\:}a_1,\:\ldots \:,\:a_n\mathrm{\:\left(n\:elements\right)\:then\:the\:average}= \\ \frac{\sum x}{n}=\frac{326}{10}=32.6 \end{gathered}[/tex]Step 3
Find the standard deviation
[tex]S\mathrm{tandard\:deviation,\:}\sigma\left(X\right)\mathrm{,\:is\:the\:square\:root\:of\:the\:variance:}\sigma\left(X\right)=\sqrt{\frac{\sum(x_i-\mu)^2}{N}}[/tex][tex]Standard\text{ deviation=}17.28326[/tex]Step 4
Find Q1
[tex]\begin{gathered} The\:first\:quartile\:is\:computed\:by\:taking\:the\:median\:of\:the\:lower\:half\:of\:a\:sorted\:set \\ Arrange\text{ in ascending order} \\ 10,\:15,\:19,\:20,\:25,\:34,\:44,\:47,\:52,\:60 \\ Take\text{ the lower half of the ascending set} \\ 10,15,19,20,25 \\ Q_1=19 \end{gathered}[/tex]Step 5
Find Q3
[tex]\begin{gathered} \mathrm{The\:third\:quartile\:is\:computed\:by\:taking\:the\:median\:of\:the\:higher\:half\:of\:a\:sorted\:set.} \\ Arrange\text{ the terms in ascending order} \\ 10,\:15,\:19,\:20,\:25,\:34,\:44,\:47,\:52,\:60 \\ Take\text{ the upper half of the ascending term} \\ 34,44,47,52,60 \\ Q_3=47 \end{gathered}[/tex]Step 6
Find the lower fence
[tex]\begin{gathered} =Q_1-1.5(IQR) \\ IQR=Q_3-Q_1=47-19=28 \\ =19-1.5(28)=-23 \end{gathered}[/tex]Step 7
Find the upper fence
[tex]\begin{gathered} =Q_3+1.5(IQR) \\ =47+1.5(28)=89 \end{gathered}[/tex]a bus route takes about 45 minutes. the company's goal is mad of less than 0.5 minute. one drivers times for 9 runs of the route. did the driver meet the goal?44.2 , 44.9 , 46.1, 45.8 , 44.7 , 45.2 , 45.1 , 45.3, 44.6
Answers
Answer:
The driver meet the goal
Explanation:
We are given that a bus route takes about 45 minutes
If companys goal is made less than 0.5minute, then, the company's goal is 45 - 0.5 = 44.5minutes
If one drivers times for 9 runs of the route, as ahown;
44.2 , 44.9 , 46.1, 45.8 , 44.7 , 45.2 , 45.1 , 45.3, 44.6
We will have to calculate the mean data first as shown;
Mean time = 44.2 +44.9+46.1 +45.8+ 44.7+ 45.2+45.1+45.3+44.6/9
Mean time = 405.9/9
Mean time = 45.1minutes
Since the mean time(45.1minutes) is greater than the company's goal (44.5minutes), hence the driver meet the goal
Construct the 270° rotation of the square ABCD about point P.
Answers
We want to rotate square ABCD by 270° around point P, lets see
We can think that the square is "glued" to segment PC, so if we rotate the segment PC by 270°, the square will also be rotate by 270°, as follows
So, we have our rotation about point P.
Answer: the answer is B
Step-by-step explanation: just trust me, I got it right
7x + 15+9x - 5 = It’s is negative-10 or 10
Answers
1) Solving for x, the following expression:
7x + 15+9x - 5 = 0 Combine like terms
7x +9x +15 -5 =0
16x +10 =0 Subtract 10 from both sides
16x = -10 Divide both sides by 16
x = -10/16 Simplify it
x=-5/8
Erika has a baking company and needs to purchase 17 pounds of flour for her cakes. The Baking Goods Store sells two different-sized bags of flour. The table shows the amounts of flour in the bag, the number of bags at the store, and the cost per bag of flour. Size Pounds 1 Bags for Sale 75 Cost per Bag Small $0.84 5 Large 4 4 $16.80 If Erika buys all of the large bags, how many small bags will she need? A. 7 small bags B. 12 small bags C. 28 small bags D. 71 small bags
Answers
There are 4 large bags, and each one has 4 pounds. Then, since she buys all of the large bags, she already has
[tex]4\times4=16[/tex]16 pounds. So, she only needs
[tex]17\text{ }\frac{2}{5}-16=1\text{ }\frac{2}{5}=\frac{5}{5}+\frac{2}{5}=\frac{7}{5}[/tex]1 2/5 pounds more, this fraction is equals to 7/5 pounds. Since the small bags only contains 1/5 pounds of flour, then, she needs
[tex]\frac{\frac{7}{5}}{\frac{1}{5}}=\frac{7}{5}\times\frac{5}{1}=\frac{7\times5}{5\times1}=7[/tex]7 small bags
Find the indicated probability for a randomly selected x value from the distribution
Answers
We need to find:
[tex]P(x\ge\mu-\sigma)[/tex]For the graph we get
here we know that the probability that we want is all the values from the mu-sigma line onwards
Four more than eight times a number (written as a expression)
Answers
'Four more than' is written as 4+
Let n be 'a number'
Then, the whole expression is:
[tex]4+8n[/tex]Choose the answer with the proper number of sig figs
Answers
the answer is
[tex]69\times10^9[/tex]The amount of time needed to Stuff and address envelopes for the local high schools followers in campaign varies inversely with the number of parent and student volunteers that attend the envelope stuffing event last year It took 20 people 3 hours to stuff in the dress the envelopes select the equation that could be used to estimate the amount of time Y, it will take the X number of volunteers to stuff and address the same number of envelopes.
Answers
This is a proportion question. In this case, it states that the time, y, and the number of volunteers, x, are inversely proportion. So:
20 -- 3
x -- y
Because the proportion is inverse, we inverse one of them to write the equation:
[tex]\begin{gathered} \frac{20}{x}=\frac{y}{3} \\ y=\frac{60}{x} \end{gathered}[/tex]The equation asked is:
[tex]y=\frac{60}{x}[/tex]If mZDEF = (7x + 4)", mZDEG = (5x + 1)', and mZGEF = 23", find eachmeasure.EFDAngle DEF -What is x?Number 4
Answers
m∠FEH is 49 degrees greater than m∠HEG (option 1)
Explanation:4) ∠FEH = 90 degrees
m∠HEG = 41 degrees
∠FEH = m∠HEG + m∠FEG
90 = 41 + m∠FEG
m∠FEG = 90 - 41
m∠FEG = 49 degrees
Since m∠FEH = 90 degree and m∠HEG = 41 degree, their difference is 49 degrees
It means m∠FEH is 49 degrees greater than m∠HEG (option 1)
The above statement is true
Write the next explicit form of this sequence, given a1 = 20 and r= 0.5 (1/2) and find n=15.
Answers
Given the first term, a1=20
Common ratio, r=0.5*1/2=0.25
A geometric sequence is represented by the following expression:
[tex]\begin{gathered} a_n=ar^{n-1} \\ \end{gathered}[/tex]We want to find the 15th term:
[tex]\begin{gathered} a_{15}=20(0.25)^{15-1} \\ a_{15}=7.45\times10^{-8} \end{gathered}[/tex]I need to find area of them composite shape please
Answers
Answer:
[tex]A=1,026\imaginaryI n^2[/tex]Explanation: We have to find the total area of the figure shown, the total area would be the area of the triangle and the square:
[tex]\begin{gathered} A=A_T+A_S\rightarrow(1) \\ \\ A_T=\frac{1}{2}(B\times H) \\ \\ A_S=S^2 \end{gathered}[/tex]plugging in the unknowns in the equation (1) gives the answer as follows:
[tex]\begin{gathered} H=35in \\ \\ \\ B=\sqrt{37in^2-35in^2} \\ \\ \\ A_T=2\times\frac{1}{2}(BH)=(35in\times\sqrt{37\imaginaryI n^2-35\imaginaryI n^2}) \\ \\ \\ A_T=(35in\times\sqrt{37\mathrm{i}n^2-35\mathrm{i}n^2})=35in\times\sqrt{144}=35in\times12in^2 \\ \\ \\ A_T=420in^2 \\ \\ \\ A_S=S^2 \\ \\ \\ S=2\times B=2\times12in=24in \\ \\ \\ A_S=24in^2=576in^2 \\ \\ \\ A=A_T+A_S\Rightarrow A=420in^2+576in^2 \\ \\ \\ A=1,026in^2 \end{gathered}[/tex]graph the line that has a slope of 2/3 and includes the point (6,4)
Answers
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
m = 2/3
[tex]\begin{gathered} b=y-mx \\ b=4-2/3\cdot6 \\ b=4-4 \\ b=0 \end{gathered}[/tex]The equation of the line that passes through the point (6,4) with a slope of 2/3
[tex]y=\frac{2}{3}x[/tex]Please help me help help me please help help me out to
Answers
Step 1:
Write the expression
[tex]undefined[/tex]Look at this graph: 5 3 2 0 1 2 3 4 5 6 7 8 9 10 What is the slope?
Answers
Here, we want to find the value of the slope
To do this, we will need to select two points on the graph
Any two points selected will sufice as far as they are reasonably apart to draw the slope triangle
The points we are seecting are (6,3) and (9,4)
Mathematically, the slope formula is as follows;
[tex]\begin{gathered} m\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ m\text{ = }\frac{4-3}{9-6} \\ \\ m\text{ = }\frac{1}{3} \end{gathered}[/tex]The following table gives the cost, C(n), of producing a certain good as a linear function of n, the number of units produced. Use the information in this table to answer the questions that follow it. a. Evaluate each of the following expressions. Give economic interpretation of each. C(200) = _______ C(200) - C(150) = ________ C(200) - C(150) / 200 - 150 = _______ b. Estimate C(0). _______ c. the fixed cost of production is the cost incurred before any goods are produced. The unit cost is the cost of producing an additional unit. Find a formula for C(n) in terms of n, given that: Total cost = fixed cost + unit cost x number of units C(n) = _________
Answers
a. Based on the table, when 200 units is produced, the cost of production is $12,100 hence, C(200) = $12,100.
On the other hand, when 150 units is produced, the cost of production is $12,000 hence, C(150) = $12,000.
Subtracting C(200) - C(150), we have $100.
Dividing this result $100 by the difference of 200 and 150, we get 2.
[tex]\frac{C(200)-C(150)}{200-150}=\frac{12,100-12,000}{50}=\frac{100}{50}=2[/tex]b. Estimate C(0).
Based on the answers in letter a, we can see that for every additional unit produced, the additional cost of production is $2.
So, if we subtract 100 units, there will be 2*100 = $200 less on the cost of production.
From $11, 900 total cost of production of 100 units as shown in the table, we remove 100 units that cost $200, the total cost of production will now be $11, 700. Hence, at 0 units produced, the cost of production is $11, 700. C(0) = $11, 700.
c. Based on the answer in letter b, with 0 units produced, there is already a fixed cost of $11, 700.
Based on the answer in letter a, the unit cost per number of units produced is $2. If "n" is the number of units produced, the additional cost is 2n.
With these information, the formula for the finding the total cost of production is:
[tex]\begin{gathered} C(n)=FixedCost+(UnitCost\times no.ofunits)\text{ } \\ C(n)=11,700+2n \end{gathered}[/tex]
Describe how the formula is a transformation of a toolkit function. Then sketch a graph of the transformation.. Be sure to include labels for the increments on your x and y axis. Take a picture of that written work and upload it when submitting your answer. You may want to create a table of values to help you graph the function.p(x)=(\frac {1}{3}x)^3-3
Answers
Given the function:
[tex]p(x)=(\frac{1}{3}x)^3-3[/tex]The parent function to the given function is f(x) = x³
To get the function p(x) from f(x), we will perform the following translations:
1) Horizontal stretch with a factor of 1/3
2) Shift downward 3 units
The graph of f(x) and p(x) will be as shown in the following picture:
What is the solution set to the following system?x + y = 3x^2 = y^2 = 9
Answers
To solve the given system of equations:
1. Solve x in the first equation:
[tex]\begin{gathered} x+y-y=3-y \\ \\ x=3-y \end{gathered}[/tex]2. Use the value of x=3-y in the second equation:
[tex](3-y)^2+y^2=9[/tex]3. Solve y:
[tex]\begin{gathered} (a-b)^2=a^2-2ab+b^2 \\ \\ 3^2-2(3)(y)+y^2+y^2=9 \\ 9-6y+2y^2=9 \\ \\ 2y^2-6y=0 \\ 2y(y-3)=0 \\ \\ \end{gathered}[/tex]When the product of two factors is equal to zero, then you equal each factor to zero to find the solutions of the variable:
[tex]\begin{gathered} 2y=0 \\ y=\frac{0}{2} \\ y=0 \\ \\ y-3=0 \\ y-3+3=0+3 \\ y=3 \end{gathered}[/tex]Then, the solutions for variable y in the given system are:
y=0
y=3
4. Use the values of y to find the corresponding values of x:
[tex]\begin{gathered} x=3-y \\ \\ y=0 \\ x=3-0 \\ x=3 \\ \text{Solution 1: (3,0)} \\ \\ y=3 \\ x=3-3 \\ x=0 \\ \text{Solution 2: (0,3)} \end{gathered}[/tex]Then, the solutions for the given system of equations are: (3,0) and (0,3)quations4. Use the values of y to find the corresponding values of x:
[tex]undefined[/tex]4. Use the values of y to find the corresponding values of x:
[tex]undefined[/tex]If the diameter of a circle is changed from 5 cm to 10 cm, how will the circumference change?
Answers
Solution
Step 1
Write out an expression for the circumference of a circle
[tex]\begin{gathered} C\text{ =}\pi d \\ C\text{ is the circumference} \\ d\text{ is the diameter} \end{gathered}[/tex][tex]\begin{gathered} \text{when d = 5}cm \\ C=5\pi cm \end{gathered}[/tex][tex]\begin{gathered} \text{when d=10cm} \\ C=10\pi cm \end{gathered}[/tex]Thus, when the diameter changed from 5cm to 10cm, the circumference is twice the previous size
That is, the circumference when the diameter is 10cm is 2 times the circumference when the diameter is 5cm
Caitlin travels from 1 1/3 hours to visit a friend who lives 4 and 1/2 miles away Martin travels 4 1/4 miles to visit a friend it takes in 1 1/5 hours to get there who travels at a greater rate of 4 miles per hour
Answers
Caitlin travels 4.5 miles at 11/3 hours.
So his rate of travel will be
[tex]\frac{4.5}{\frac{11}{3}}=1.23[/tex]His rate is 1.23 mile/hour
Again Martin travels 4.25 miles at 11/5 hours
So his rate will be
[tex]\frac{4.25}{\frac{11}{5}}=1.93[/tex]Hence martins rate is 1.93 miles/hour.
SO Martin travels at a greater rate than Caitlin.
Answer:
Step-by-step explanation:
A point P(x,y) is shown on the unit circle corresponding to a real number t. Find the values of the trigonometric functions at t. The point P is (√10/10 , -3√10/10) sin t=cos t= tan t=csc t=sec t=cot t=
Answers
Given
Graph
Procedure
Point P
[tex]P=(\frac{\sqrt[]{10}}{10},-\frac{3\sqrt[]{10}}{10})[/tex]Let's calculate the swept angle
[tex]\begin{gathered} \sin \theta=\frac{\frac{3\sqrt[]{10}}{10}}{1} \\ \sin \theta=\frac{3\sqrt[]{10}}{10} \\ \theta=\sin ^{-1}(\frac{3\sqrt[]{10}}{10}) \\ \theta=71.56\text{ \degree} \end{gathered}[/tex]Now the angle swept by t is
[tex]\begin{gathered} t=360-\theta \\ t=288.44\text{ \degree} \end{gathered}[/tex][tex]\begin{gathered} \sin (288.44)=-0.948 \\ \cos (288.44)=0.3163 \\ \tan (288.44)=-2.999 \\ \end{gathered}[/tex][tex]\begin{gathered} \csc (288.44)=-1.054 \\ \sec (288.44)=3.1614 \\ \cot (288.44)=-0.333 \end{gathered}[/tex]find three consecutive intergers whose sum is 276
Answers
If we need to find three consecutive integers, we have that they can be written as follows:
[tex]x,x+1,x+2[/tex]Since the sum of all of them is equal to 276, we can write the following equation:
[tex]x+(x+1)+(x+2)=276[/tex]Now, adding like terms, we have:
[tex]\begin{gathered} (x+x+x)+(1+2)=276 \\ 3x+3=276 \\ \end{gathered}[/tex]Now, we can subtract 3 from both sides of the equation, and then divide by 3 as follows:
[tex]\begin{gathered} 3x+3-3=276-3 \\ 3x=273 \\ \frac{3x}{3}=\frac{273}{3} \\ x=91 \end{gathered}[/tex]Then, we have that:
[tex]\begin{gathered} x=91 \\ x+1=92 \\ x+2=93 \end{gathered}[/tex]If we add these three consecutive integers, we will have:
[tex]\begin{gathered} 91+92+93=276 \\ 276=276\Rightarrow This\text{ is True.} \end{gathered}[/tex]In summary, the three consecutive integers whose sum is 276 are 91, 92, and 93.
Justin has 16 new magazines to readi.Let M be the number of magazines the would have left to read after reading R of them.Write an equation relating Mr. R. Then use this equation to find the number of magazines he would have left to read after reading9 of them.Equation:금Х$?Number left to read after reading of them: magazines
Answers
Let M be the number of magazines Justin would have left to read after reading R of them, then we can set the following equation:
[tex]M+R=16.[/tex]If R=9, then:
[tex]M+9=16.[/tex]Solving the above equation for M we get:
[tex]M=16-9=7.[/tex]Answer: After reading 9 magazines, Justin has 7 left to read.
What is the weight of the piece of aluminum shown below at 0.0974 lbs/in.^3 (hint:subtract the volume of the cylindrical hole.) Round to the nearest tenth as needed.
Answers
We will have the following:
First, we will determine the volume of the side plate:
[tex]V_1=0.5\cdot4\cdot5\Rightarrow V_1=10[/tex]Now, we find the volume of the front plate:
[tex]V_2=0.5\cdot4\cdot4-\pi(2)^2(0.5)\Rightarrow V_2=8-2\pi[/tex]Now, we calculate the total volume:
[tex]V_t=2V_1+V_2\Rightarrow V_t=2(10)+(8-2\pi)[/tex][tex]\Rightarrow V_t=28-2\pi[/tex]Now, we calculate its weight:
[tex]w=0.0974\cdot\frac{b}{in^3}\cdot(28-2\pi)\cdot in^3\Rightarrow w=2.115217751\ldots[/tex][tex]\Rightarrow w\approx2.1[/tex]So, it's weight is approximately 2.1 Lb.
Ava bought a rectangular rug for her hallway. The rug is į yards wide and 2 yards long 2 3 What is the area of the rug?
Answers
Answer:
Concept:
The area of the rectangle is given below as
[tex]\begin{gathered} A_{\text{rectangle}}=\text{length}\times width \\ A_{\text{rectangle}}=l\times w \\ \text{where,} \\ l=2\frac{3}{4}yd \\ w=\frac{2}{3}yd \end{gathered}[/tex]By substituting the values, we will have
[tex]\begin{gathered} A_{\text{rectangle}}=\text{length}\times width \\ =2\frac{3}{4}yd\times\frac{2}{3}yd \\ A_{\text{rectangle}}=\frac{11}{4}yd\times\frac{2}{3}yd \\ A_{\text{rectangle}}=\frac{11}{6}yd^2 \\ A_{\text{rectangle}}=1\frac{5}{6}yd^2 \end{gathered}[/tex]Hence,
The final answer is
[tex]1\frac{5}{6}yd^2[/tex]sofia makes pies for sale the materials for each pie cost $4.00 and she sells the pies for $7.00. to find her profits, she writes the equation p=7.50X-4.00X explain what the variable x represents
Answers
Andrew, this is the solution:
Price of the pie materials = $ 4
Sale price of each pie = $ 7
Sofia writes this equation:
p= 7.50X - 4.00X
X represents the number of pies Sofia makes and sells
Andrew, the equation Sofia wrote is wrong.
This is the correct equation:
p= 7.00X - 4.00X
If you don’t need any further explanation, I’ll go ahead and end our session. Feel free to let me know how I did by rating our session - all feedback is welcome and appreciated. Thanks for coming today!
Remember that the solutions from tutors are always available in your profile!
Drag each tile to the correct box.Arrange the steps to perform this subtraction operation in the correct order.(1.93 x 10"- (9.7 x 105)(1.93x107)–(9.7x106)0.96x107(1.93x10?)–(0.97X107)10 (0.96X107)(1.93-0.97)x107(1.93x10?)–10(9.7x106)9.6x106
Answers
We make the subtraction following this order:
1.
[tex]1.93\times10^7-9.7\times10^6[/tex]2.
[tex]1.93\times10^7-\frac{10}{10}\times(9.7\times10^6)[/tex]3.
[tex]1.93\times10^7-0.97\times10^7[/tex]4.
[tex](1.93-0.97)\times10^7[/tex]5.
[tex](0.96)\times10^7[/tex]6.
[tex]\frac{10}{10}(0.96\times10^7)[/tex]7.
[tex](9.6)\times10^6[/tex]What fraction is considered zero? when zero is on top o depends on the numerator when zero is on bottom no fraction is undefined
Answers
When the numerator of the fraction = 0 then the fraction is consider to be zero