Pair A
Pair B
52,72 96, 64
Pair C
48,84
Select all the correct statements
about these pairs.
A Pair A and Pair C have the same GCF.
B All three pairs have GCFs that are
not prime numbers.
The GCF of Pair C is 12.
The GCF of Pair B is 16.
The prime factorization of the
GCF of Pair B is 2x2x2x2.

Answer:

960 grams

Step-by-step explanation:

We know from the problem that grams is proportional to fluid ounces.  Therefore, if we allow g to represent the number of grams of ground coffee Paula used, we can find it using a proportion:

[tex]\frac{64}{32}=\frac{g}{480}\\\\ 32g=30720\\\\ g=960[/tex]

We know that the double-angle formula for cosine is: cos(2x) = 2cos²(x) - 1. So, we can rewrite the given identity as: (2cos²(x) - 1) - cos

To use a half angle or reduction formula to fill in the blanks in the identity below:

(Cos(2x)) - Cos(x) = -2*(sin((3x)/2))^2

We can use the following reduction formula for cosine:

cos(2x) = 2cos^2(x) - 1

Substituting this into the identity above gives:

2cos^2(x) - 1 - cos(x) = -2*(sin((3x)/2))^2

Next, we can use the half angle formula for sine:

sin((3x)/2) = ±sqrt[(1 - cos(3x))/2]

Substituting this into the equation above gives:

2cos^2(x) - 1 - cos(x) = -2*(1 - cos(3x))/2

Simplifying further gives:

2cos^2(x) - 1 - cos(x) = -1 + cos(3x)

Finally, rearranging the terms gives the desired identity:

cos(2x) - cos(x) = -2*(sin((3x)/2))^2
Hello! I'd be happy to help you with your question. Using the half-angle formula, we can fill in the blanks in the identity:

The given identity is: (cos(2x))? - cos

We know that the double-angle formula for cosine is: cos(2x) = 2cos²(x) - 1

So, we can rewrite the given identity as: (2cos²(x) - 1) - cos

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Answer:

5 minutes

Step-by-step explanation:

The speed is the same, So its the ratio assuming that x minutes are required so,

[tex] \frac{640}{4} = \frac{800}{x} [/tex]

(Multiplication cross)

[tex] 640 \times = 800 \times 4[/tex]

[tex]x = \frac{800 \times 4}{640} [/tex]

Answer =

[tex]x = 5[/tex]

Hopefully this helps!! :)

please mark as brainliest! :)

The standard form is y= 3x² - 16x + 132.

We have Equation,

f(x) = 3(x-8)² - 160

We know the standard form is

y= ax² + bx + c

Now, converting vertex form to standard form

y = 3(x-8)² - 160

y = 3 (x² + 64 - 16x )-60

y= 3x² + 192 - 16x -60

y= 3x² - 16x + 132

Thus, the standard form is y= 3x² - 16x + 132.

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The correct P-value is 0.013 and the appropriate decision is to reject the null hypothesis and conclude that there is a significant difference between treatment A and treatment B.

To determine if there is a difference between treatment A and treatment B, we can conduct a two-sample t-test assuming equal variances.

Using a calculator or software, we find that the calculated t-statistic is 3.079 and the degrees of freedom is 8. With a significance level of 0.05, the critical t-value is 2.306.

The P-value is 0.013, which is less than 0.05, indicating that there is a statistically significant difference between treatment A and treatment B.

Therefore, we reject the null hypothesis that there is no difference between the means of treatment A and treatment B, and conclude that there is a significant difference between the two treatments.

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The volume of the composite figure is solved to be

The volume of the composite figure is calculated by dividing the figure into simpler figure and solve each volume. The volumes calculated is the added to give the volume of the composite figure

formula for volume = length x width x depth

First simpler part

volume = 10.5 ft x 3 ft x 6 ft

volume = 189 cubic ft

second simpler figure

volume = (9 - 3) ft x 4 1/2 ft x 6 ft

volume = 162 cubic ft

volume of the composite figure

= 189 + 162

= 351 cubic ft

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Based on the given p-value of 0.265 for the KW test, we cannot reject the null hypothesis that the group medians are equal. The correct answer is: d. No more test to do.

Therefore, we do not need to do any post-hoc tests such as Dunn.test or Tukey test. However, it is always a good practice to check the homogeneity of variance assumption before conducting any statistical analysis. Therefore, we may need to do the Levene test to check the equality of variances among the groups.

Based on the information provided, the correct answer is:

d. No more test to do.

Explanation: The p-value of the Kruskal-Wallis (KW) test is 0.265. Since it is greater than the given alpha level of 0.10, we fail to reject the null hypothesis. This means that there is no significant difference between the groups being compared. Therefore, no further tests, such as Dunn.test, Tukey test, or Levene test, are needed.

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We can find the probabilities of ever transiting from states 4, 5, and 6 to a transient state by looking at the fourth, fifth, and sixth rows of F, respectively.

To find the mean time spent by the Markov chain in any transient states of the chain which starts at any transient state, we need to first identify the transient states. In this case, we can see that states 1, 3, and 7 are transient states since there is a non-zero probability of reaching an absorbing state (states 4, 5, and 6) from these states.

Next, we need to find the expected time spent in each of the transient states before reaching an absorbing state. We can set up a system of equations to solve for these expected times using the fact that the expected time spent in a state is equal to 1 plus the sum of the expected times spent in each possible next state, weighted by their transition probabilities.

For example, for state 1, we have:

E(T1) = 1 + 0.5E(T2) + 0.25E(T3)

where E(Ti) is the expected time spent in state i before reaching an absorbing state.

Similarly, for state 3, we have:

E(T3) = 1 + 0.4E(T2) + 0.2E(T4)

And for state 7, we have:

E(T7) = 1 + 0.2E(T5) + 0.5E(T6)

Solving these equations, we get:

E(T1) = 5

E(T3) = 5.5

E(T7) = 4

Therefore, the mean time spent by the Markov chain in any transient state is:

(E(T1) + E(T3) + E(T7))/3 = (5 + 5.5 + 4)/3 = 4.83

To find the probability that the Markov chain will ever transit to one of the transient states starting from another transient state, we can use the concept of fundamental matrix. The fundamental matrix F is defined as the matrix (I-Q)^-1, where Q is the submatrix of P consisting of the transition probabilities between transient states.

In this case, we have:

Q = [0 0.25 0.2;

0.4 0 0.2;

0.2 0.2 0]

Using a calculator or software to calculate the inverse of (I-Q), we get:

(I-Q)^-1 = [1.25 0.625 1;

0.625 1.25 1;

1 1 1.5]

The (i,j)-th entry of F represents the expected number of times the Markov chain will visit state j starting from state i before reaching an absorbing state. Therefore, the probability of ever transiting to a transient state starting from another transient state is simply the sum of the corresponding entries in F.

For example, to find the probability of ever transiting from state 2 to a transient state, we look at the second row of F:

[0.625 1.25 1]

The sum of these entries is 0.625 + 1.25 + 1 = 2.875, so the probability of ever transiting from state 2 to a transient state is 2.875.

Similarly, we can find the probabilities of ever transiting from states 4, 5, and 6 to a transient state by looking at the fourth, fifth, and sixth rows of F, respectively.

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The size of the tire that he needed to buy is the one with a circumference of 75.4 inches.

Given that,

while working as a reace driver, Jalen needed to replace the tire on his car.

Tire is in the shape of a circle.

Diameter of the circle = 24 inches

Radius of the circle = 24/2 = 12 inches

We have to find the circumference of the tire.

Circumference = 2πr, where r is the radius.

Substituting,

Circumference = 2πr = 2π × 12 = 24π = 75.4 inches

Hence the size of the tire is 75.4 inches.

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The points that are more than the fraction 2 1/2 units and less than 3 1/4 units contains the points from 2.5 to 3.25.

Given measurements are 2 1/2 and 3 1/4.

We have to shade the region in between these two points.

Both are written in mixed fractional form.

This can be written in decimal as,

2 1/2 = 2 + 1/2 = 2 +6 0.5 = 2.5

3 1/4 = 3 + 1/4 = 3 + 0.25 = 3.25

Hence the shaded region will contain the points from 2.5 to 3.25.

2.5 is at the exact middle of 2 and 3.

3.25 is at 1/4th distance of 3 and 4. That is if we divide the distance between 3 and 4 to 4 equal spaces, the first space is 3 1/4.

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Answer: The answer is Does it have same matching sides, is it congruent. This is how we will know if it's a square.

Step-by-step explanation: Please give Brainlist.

Hope this helps!!!!

I can answer more questions.

Answer:

To solve for x in the equation −12(x + 5) = -10, we will use the following steps:

Distribute the -12 to the terms inside the parentheses:

-12x - 60 = -10

Add 60 to both sides of the equation to isolate the variable term:

-12x = 50

Finally, divide both sides of the equation by -12 to solve for x:

x = -50/12

Simplifying the answer, we get:

x = -25/6 or -4.1667 (rounded to four decimal places)

Step-by-step explanation:

Answer:

Step-by-step explanation:

menu 7,1 Open table labe A , B as x y

type the numbers provided and then 4 1 and whatever problem click it\

and you will see a table again type x y and there you will get youre asnwers

Answer: $640

Step-by-step explanation:

4 x 10 (months)

= 40

$600 + $40

= $640

Answer:

120, The answer is 120

Step-by-step explanation:

Determine the measure of the interior angle at vertex C.

A. 120

B. 180

C. 90

D. 200

To determine the appropriate prefix multiplier for reporting a measurement of 5.57 × 10^(-5) m, we need to find a suitable metric prefix that would make the number easier to read and understand.

1. Convert the original measurement (5.57 × 10^(-5) m) to a more suitable metric unit.
2. Compare the metric prefixes and their corresponding multipliers to find the best fit.

In this case, the closest metric prefix for 10^(-5) is "micro" (symbol: µ), which has a multiplier of 10^(-6). To use this prefix, we need to convert the measurement to micrometers (µm).

3. Divide the original measurement by the multiplier of the chosen prefix: (5.57 × 10^(-5) m) / (10^(-6) µm/m) = 55.7 µm.

So, the appropriate prefix multiplier for reporting the measurement of 5.57 × 10^(-5) m is "micro," and the measurement can be reported as 55.7 µm.

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The equations of the graph from the figure are y = 4 and y = -2

From the question, we have the following parameters that can be used in our computation:

The graph

On the graph, we can see that

We have two horizontal lines that pass through the points y = 4 and y = -2

This means that the equations represented on the graph are y = 4 and y = -2

So, we can conclude that none of the options are true from the options

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a) The sampling distribution of the sample mean has mean μ=300 and standard deviation  is 4.

b)Normal distribution.

c)No. Because the distribution of the variable under consideration is not specified, a sample size of at least 30 is needed for part (a) to be true.The correct answer is B.

a. The sampling distribution of the sample mean for samples of size 49 is approximately normally distributed with a mean (μ) of 300 and a standard deviation (σ) of 28/√49 (which is 28/7 or 4).

b. For part (a) to be true, the assumption made about the distribution of the variable under consideration is C. Normal distribution.

c. The statement in part (a) is still true if the sample size is 16 instead of 49 because of the Central Limit Theorem. However, the standard deviation will change.

The correct answer is B. No. Because the distribution of the variable under consideration is not specified, a sample size of at least 30 is needed for part (a) to be true.

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The probability that a student is a science major given that they are science student would be = 0.18.

To calculate the probability of the science major graduate student would need the use of the formula given below;

Probability = possible outcome/sample space

The possible outcome = 188

The sample space = 1073

The probability = 188/1073 = 0.18

Therefore, the probability that a student who is a graduate science student would be chosen at random would be = 0.18.

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101.9 cm is the length of the paper.

The paper is divided diagonally into two right triangles, each with a hypotenuse that is the same length as the paper. Let's call the paper's length "x" for short.

Using the Pythagorean theorem, we know that:

[tex]x^2 = 72^2 + 72^2[/tex]

Simplifying this equation, we get:

[tex]x^2 = 2(72^2)\\x = \sqrt{2(72^2)} = 101.9 cm[/tex]

(rounded to one decimal place)

Therefore, the paper's length is approximately 101.9 centimeters.

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The general solution for the second differential equation is y = [tex]e^[(1/2)x^2 + C2] - 4[/tex]

1. [tex]dy/dx = 2x/y[/tex]

Step 1: Separate variables. To do this, multiply both sides by y and divide both sides by dx:
[tex]y dy = 2x dx[/tex]

Step 2: Integrate both sides:
[tex]∫y dy = ∫2x dx[/tex]

Step 3: Evaluate the integrals:
[tex](1/2)y^2 = x^2 + C1[/tex], where C1 is the constant of integration.

Step 4: Solve for y to obtain the general solution:
[tex]y^2 = 2x^2 + 2C1\\y = ±√(2x^2 + 2C1)[/tex]

So, the general solution for the first differential equation is [tex]y = ±√(2x^2 + 2C1[/tex]).

2. [tex]dy/dx = x(y+4)[/tex]

Step 1: Separate variables. To do this, divide both sides by (y+4) and multiply both sides by dx:
[tex]dy / (y+4) = x dx[/tex]

Step 2: Integrate both sides:
[tex]∫[1 / (y+4)] dy = ∫x dx[/tex]

Step 3: Evaluate the integrals:
[tex]ln|y+4| = (1/2)x^2 + C2[/tex], where C2 is the constant of integration.

Step 4: Solve for y to obtain the general solution:
[tex]y+4 = e^[(1/2)x^2 + C2]\\y = e^[(1/2)x^2 + C2] - 4[/tex]

So, the general solution for the second differential equation is y = [tex]e^[(1/2)x^2 + C2] - 4[/tex]

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To speak to the circumstance depicted, able to type in the taking after imbalance: h ≥ 50 inches, where h speaks to the stature of the individual who needs to ride the rollercoaster. Her companion does not meet the tallness confinement since her tallness is less than 50 inches.

To change over Sarah's stature to inches, we are able to utilize the reality that 1 foot is break even with 12 inches. So, Sarah's stature in inches is:

4 feet × 12 inches/foot + 6 inches = 48 inches + 6 inches = 54 inches Sarah meets the tallness confinement since her tallness is more noteworthy than or breaks even with 50 inches. On the other hand, her friend's tallness in inches is:

4 feet × 12 inches/foot + 2 inches = 48 inches + 2 inches = 50 inches

thus, Her companion does not meet the tallness confinement since her tallness is less than 50 inches. 

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The value of angle x is 70⁰.

The value of angle x is calculated by applying intersecting chord theorem.

The intersecting chord theorem states that for two chords intersecting at the center of the circle, the angle formed by the intersection of the two chords is equal to the arc angle subtended at the circumference.

The value of the angle adjacent to angle x is calculated as follows;

∠QON = arc angle QN

∠QON = 110⁰

The value of angle x is calculated as;

x + ∠QON  = 180

x = 180 - ∠QON

x = 180 - 110⁰

x = 70⁰

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If you wanted to measure satisfaction with this course on a scale from 1, not very satisfied, to 7, very satisfied, you would use an ordinal scale.

An ordinal scale is a type of scale used to measure variables that have an inherent order or ranking, such as the level of satisfaction in this case. However, the differences between the categories are not necessarily equal or measurable, which rules out the use of an interval or ratio scale. A nominal scale is used for variables that are categorical and cannot be ranked or ordered, which is not appropriate for this scenario.

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The measure of arc angle DC is 60.

The measure angle A is  45⁰.

The measure angle B  is 50⁰.

The measure angle C is  45⁰.

The measure angle D  is 50⁰.

The measure of arc angle DC is calculated as follows;

arc DC = 360 - (100 + 110 + 90) (sum of angles in a circle)

arc DC = 60

The measure angle A is calculated as follows;

m∠A = ¹/₂( arc BC ) (intersecting chord theorem)

m∠A = ¹/₂ x 90

m∠A = = 45⁰

The measure angle B  is calculated as follows;

m∠B = ¹/₂( arc AD ) (intersecting chord theorem)

m∠B = ¹/₂ x 100

m∠B  = 50⁰

The measure angle C is calculated as follows;

m∠C = m∠A (vertical opposite angles)

m∠C = = 45⁰

The measure angle D is calculated as follows;

m∠D = m∠B  (vertical opposite angles)

m∠C = = 50⁰

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The rate of change of weight of the rabbit in pounds per week is 0.5 pounds per week.

To calculate the rate of change of weight of Samuel's rabbit in pounds per week, we need to look at how much the weight of the rabbit changes as the number of weeks since birth increases by one. This is also known as the slope of the linear relationship between the number of weeks and the weight of the rabbit.

Looking at the table below, we can see that when the rabbit is born (week 0), it weighs 0.5 pounds. As the number of weeks since birth increases by one, the weight of the rabbit increases by 0.5 pounds. This pattern continues for each subsequent week, with the weight of the rabbit increasing by 0.5 pounds each time.

| Number of Weeks Since Birth | Weight of Rabbit (in pounds) |
|-----------------------------|------------------------------|
|              0              |             0.5              |
|              1              |             1.0              |
|              2              |             1.5              |
|              3              |             2.0              |
|              4              |             2.5              |
|              5              |             3.0              |

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The total area to be painted as given in the figure is 467.4 sq ft

Area refers to the expanse of 2-Dimensional shapes. It has a different formula for different shapes. Such as for a rectangle, the area is the product of the length and breadth and for a square, it is the square of its side, and so on.

In the figure, the side is a combination of a rectangle and a triangle.

Therefore, the area of the side = area of the rectangle + area of the triangle

area of rectangle = l * b

where l is the length

b is the breadth

l = 22.8 ft

b = 14.5 ft

Area = 22.8 * 14.5

= 330.6 sq ft

area of triangle = [tex]\frac{1}{2}[/tex]bh

where b is the base

h is the height

b = 22.8 ft

h = 26.5 - 14.5 = 12 ft

Area = [tex]\frac{1}{2}[/tex] * 22.8 * 12

= 136.8 sq ft

Area of side = 330.6 + 136.8

= 467.4 sq ft

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The complete question might be:

The diagram shows one side of a storage barn. This side needs to be painted. Find the total area to be painted.

The fallacy committed by this argument is an informal fallacy, specifically the fallacy of false analogy. The comparison between the ship of state and a ship at sea is not a valid analogy as they are not completely analogous situations.

Additionally, the premise that sailors should not protest orders from the captain does not necessarily translate to the idea that citizens should not protest presidential policies. The argument you provided commits an informal fallacy called "false analogy." This fallacy occurs when two things are compared based on a superficial similarity, but the comparison doesn't hold up under scrutiny. In this case, the comparison between a ship at sea and the ship of state is used to argue that citizens shouldn't protest presidential policies, but the two situations are not directly comparable in terms of authority and dissent.

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Answer:

The answer is 120 seconds

Step-by-step explanation:

1 minutes---->60 seconds

2 minutes---->x seconds

x×1=2×60

x seconds =120 seconds

Answer:

120 seconds

Step-by-step explanation:

60 seconds per minute

60×2= 120 seconds