Particle q1 has a charge of 2.7 μc and a velocity of 773 m/s. if it experiences a magnetic force of 5.75 × 10–3 n, what is the strength of the magnetic field? t in the same magnetic field, particle q2 has a charge of 42.0 μc and a velocity of 1.21 × 103 m/s. what is the magnitude of the magnetic force exerted on particle 2? n

Answers

Answer 1

1)The strength of the magnetic field for particle 1 will be 2.8 T.

2)The magnitude of the magnetic force exerted on the particle will be 0.12 N.

What is a magnetic field?

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.

The given data in the problem is;

q₁ has a charge = 2.7 μc

v₁ is the velocity of particle 1 = 1 773 m/s.

F is magnetic force = 5.75 × 10–3 n,

q₂ has a charge of 42.0 μc

v₂ is the velocity of 1.21 × 103 m/s.

[tex]\rm F_{B2}[/tex]   is the magnitude of the magnetic force exerted on particle 2=?

The megnetic force for case 1 is found as;

[tex]\rm F_{B1}= qvB SIN \alpha_1 \\\\ 5.75 \times 10^{-3} =2.7 \times 10^{-6}\times 773 \times B sin 90^0 \\\\ B=\frac{5.75 \times 10^{-3}}{2.7 \times 10^{-6} \timesd 773 \times sin 90^0} \\\\ B=2.8 \ T[/tex]

The megnetic force for case 2 is found as;

[tex]\rm F_{B2} = q_2v_2bsin \alpha_2 \\\\ 42\times 10^{-6} \times 1.21 \times 10^3 \times 2.8 \times sin 55^0 \\\\ F_{B2}=0.12 T[/tex]

Hence the value of the megnetic force exerted on particle 2 will be 0.00122 T.

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Answer 2

Answer:

last one and second one

Explanation:

Particle q1 has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10–3 N, what is the strength of the magnetic field?

2.8

T

In the same magnetic field, particle q2 has a charge of 42.0 μC and a velocity of 1.21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2?

0.12

N


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A 1383-kg car moving south at 11.2m / s is struck by a 1732-kg car moving east at 31.3m/s. After the collision, the cars are stuck together. How fast and in what direction do they move immediately after the collision? Define the system as the two cars. ​

Answers

Answer: See below

Explanation:

[tex]\\ \mathrm{Given:} \\\mathrm{Mass \ of \ first \ car}$\left(m_{1}\right)=1383 \mathrm{~kg}$ \\ Velocity $\left(\overrightarrow{V_{1}}\right)=-11.2\ {\math} \mathrm{m} / \mathrm{s}$\\ Mass of second car -$\left(m_{2}\right)=1732 \mathrm{~kg}$\\ Velocity $\left(\vec{v}_{2}\right)=31.3 {\math} \mathrm{m} / \mathrm{s}$[/tex]

[tex]m_{1} \vec{v}_{1}+m_{2} \vec{v}_{2}=\left(m_{1}+m_{2}\right) \vec{v} \\1383(-11.2 {\math})+1732(31.3 {\math}) \\=(1383+1732) \vec{v} \\-15489.6 {\math}+54211.6 {\math}=3115 \vec{v} \\ \vec{v}=(17.4 {\math}-4.972 {\math}) \ \mathrm{m/s}[/tex]

[tex]\text { So magnitude } \vec{|v|} =\sqrt{(17.4)^{2}+(-4.972)^{2}} \\ =\sqrt{327.605} \\ =18.099 \mathrm \ {m/s} \\[/tex]

[tex]\text { Direction } \\\theta=\tan ^{-1}\left(\frac{-4.972}{17.4}\right) \\\theta=-15.945^{\circ}\end{gathered}[/tex]

Therefore, both cars move with a velocity of 18.099 m/s in the direction of 15.945° downward from the x-axis (east)

Answer:

Explanation:

Apply conservation of momentum in N-S direction:

Initial momentum: 1383*(-11.2) + 1732*(0) = -15490

Final momentum: (1383 + 1732) * Final N-S velocity = -15490

Final velocity = 1549/(1383+1732) = -4.97 m/s (-ve means South)

Repeat the same for E-W direction:

Initial momentum: 1383*(0) + 1732*(31.3) = 54211.6

Final momentum: (1383 + 1732) * Final E-W velocity = 54211.6

Final velocity = 54211.6/(1383+1732) = 17.4 m/s (+ve means East)

Combining, the final velocity = sqrt (-4.97^2 + 17.4^2) = 18.10 m/s

at direction of arctan(17.4/4.97) = 74 degree South of East.

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His desire to pay high wages.

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What led to Henry Ford’s success as an entrepreneur?

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Explanation:

1/R = 1/8 + 1/10 + 1/12
1/R = (30 + 24 + 20) / 240
1/R = 74 / 240
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We know that,
V = IR
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I = 12 × 37/120
I = 37/10
I = 3.7 A
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The parenting style that can be described as restrictive and controlling is called authoritarian.

What is authoritarian?

The rejection of political plurality, the use of strong central power to maintain the political status quo, and reductions in the rule of law,

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Many typologies of authoritarian systems of administration have been developed by political scientists.

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Answers

Answer:

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[tex] \text \red { \huge\underline{Question}}[/tex]




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The net torque on the seesaw is 294 Nm.

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A stationary siren on a firehouse is blaring at 81Hz. Assume the speed of sound to be 343m/s. What is the frequency perceived by a firefighter racing toward the station at 11km/h

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For a stationary siren on a firehouse is blaring at 81Hz. Assume the speed of sound to be 343m/s, the frequency perceived  is mathematically given as'

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Generally, the equation for the doppler effect  is mathematically given as

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Answer:

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The potential difference across the terminals of a battery is `8.4 V` when there is a current of `1.50 A` in the battery from the negative to the positive terminal. When the current is `3.50 Air`, the reverse direction, the potential difference becomes `9.4 V`. <br>(a) What is the internal resistance of the battery? <br>(b) What is the emf of the battery?

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Answer:

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What will happen to the fringe spacing if the wavelength of the light is decreased?.

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Answer:

The formula is the form -

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As the wavelength λ is decreased sin Θ will also decrease.

One can see from the derivation that as the wavelength, being considered,

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Answer:

C. In a valley .

.............................

A circuit has a resistance of 2.5 N and is powered by a 12.0 V battery.
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Answers


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If you were to build a pipe organ with open-tube pipes spanning the range from 25 hz to 19 khz. The speed of sound in air is 343 m/s

Answers

Building a pipe organ with open-tube pipes spanning the range from 25 hz to 19 khz will require the length of the shortest pipe to be 0.018m

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This is defined as the measurement or extent of a substance from end to end. The formula is shown below:

L = v/f where v is speed , f is frequency

f1 = 25hz , f2 = 19khz

The length for both sides is seen below:

l1 = 343/25 = 13.72m

l2 = 343/19000 = 0.018m.

The length of the shortest pipe is therefore 0.018m.

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The frequency of a repeated event is the number of occurrences per unit of time. The length of the shortest pipe is 0.018 m.

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The frequency of a repeated event is the number of occurrences per unit of time. It is also known as temporal frequency to distinguish it from spatial frequency, and ordinary frequency to distinguish it from angular frequency.

The formula of the length is given by the formula,

[tex]L=\dfrac vf[/tex]

where v is the velocity of the substance and f is the frequency.

Given that the speed of the sound in air is 343 m/sec, while the frequency is tanging from 25Hz to 19 kHz.

Therefore, the length of the pipe will be,

[tex]L=\dfrac vf\\\\L_1=\dfrac{343}{25} = 13.72\rm\ m[/tex]

[tex]L_2=\dfrac{343}{19 \times 1000} = 0.018\rm\ m[/tex]

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