Patricio measured the length of the line at Muffles' truffle shop on Tuesday and found
that it was 11 yards long. How many inches long was the line on Tuesday?

Step-by-step explanation:

We know that

<L = <N so

2(4x + 23)° + (3x + 46)° = 180°.. b/c all sum is 180°

8x + 46 + 3x + 46 = 180°

11x +92 = 180

11x = 180 - 92

11x = 88

11x /11 = 88 / 11

x = 8 so we can solve angle of each <M = 3x+ 46

<M =3(8) +46

<M = 24 + 46

<M =70 so angle M measure 70°

the other 2 sides are congrunt so their base angles are equal.

< L = < N =4x + 23

< L = < N =4(8) + 23

< L = < N =32 + 23

< L = < N =55°

So angle L and N is 55° .

The radius of convergence of the series is 1/8.

The radius of convergence, r, of the given series can be found using the ratio test.

Taking the limit of the ratio of the (n+1)th and nth term as n approaches infinity gives:

lim |(8(n+1) -1)/(n+1)| / |8n-1)/n| = lim |(8n +7)/(n+1)| = 8

Since the limit is finite and less than 1, the series converges absolutely.

Therefore, the radius of convergence, r, is given by the formula r = 1/lim sup(|an|^1/n) where an is the nth term of the series.

Substituting the given values and simplifying, we get r = 1/8.

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we can use the information given about its growth rate and the height after 4.5 years:So, it took 7 years from the time Vlad moved in until the tree was 357 centimeters tall.

Height increase per year = 26 centimeters
Years since Vlad moved in = 4.5 years
Height after 4.5 years = 292 centimeters
To calculate the initial height of the tree, we can multiply the growth rate by the number of years and add it to the starting height:
Initial height = Height after 4.5 years - (Height increase per year x Years since Vlad moved in)
Initial height = 292 - (26 x 4.5)
Initial height = 168 centimeters
Therefore, the tree was 168 centimeters tall when Vlad moved into the house.
To find out how many years passed from the time Vlad moved in until the tree was 357 centimeters tall, we can use the same formula and solve for the number of years:
Height increase per year = 26 centimeters
Initial height = 168 centimeters
Final height = 357 centimeters
To calculate the number of years, we can rearrange the formula as follows:
Years = (Final height - Initial height) / Height increase per year
Years = (357 - 168) / 26
Years = 6.04 years (rounded to two decimal places)
Therefore, it took approximately 6 years and 1 month for the tree to grow from 168 centimeters to 357 centimeters tall.
To determine the height of the oak tree when Vlad moved into the house, we can use the given information. The tree grows by 26 centimeters each year, and it was 292 centimeters tall after 4.5 years.
First, let's find the total growth during the 4.5 years:
26 cm/year * 4.5 years = 117 cm
Now, subtract the total growth from the current height to find the initial height:
292 cm - 117 cm = 175 cm
So, the oak tree was 175 centimeters tall when Vlad moved into the house.
To find out how many years passed until the tree was 357 centimeters tall, we can use the growth rate again:
First, find the difference in height between the target height (357 cm) and the initial height (175 cm):
357 cm - 175 cm = 182 cm
Now, divide the difference in height by the growth rate to find the number of years:
182 cm / 26 cm/year = 7 years

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When the logarithmic transformation is applied to the nonlinear model y=β0eβ1xε, the resulting model is intrinsically linear with an intercept of ln(β0).

This transformation involves taking the natural logarithm of both sides of the equation, which yields ln(y) = ln(β0) + β1x + ε. The resulting equation is now linear, as it has a constant slope (β1) and an intercept (ln(β0)). This transformation is often used to simplify the analysis of nonlinear relationships, as it allows for the use of linear regression techniques. Additionally, taking the logarithm of the dependent variable can help to stabilize the variance of the errors, which can improve the accuracy of the model. However, it is important to note that this transformation can also make the interpretation of the coefficients more difficult, as they now represent the percentage change in y associated with a one-unit increase in x, rather than the absolute change in y. Overall, the logarithmic transformation can be a useful tool in analyzing nonlinear relationships, but it is important to carefully consider the implications of this transformation on the interpretation of the model and its coefficients.

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Let's denote the cost of making one vegetable sandwich as x. Then we know that the cost of a vegetable burger is x + 12. The cost of a vegetable burger is 14.75 rupee

From the problem statement, we know that the cost of making one sandwich is 2.75 rupees, so we can set up the equation:

x = 2.75

Then the cost of a vegetable burger is:

x + 12 = 2.75 + 12 = 14.75

In summary, the cost of a vegetable burger from the school canteen is 14.75 rupees. We can find this by adding the cost of making one sandwich (2.75 rupees) to the extra cost of 12 rupees for the burger.

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Let's denote the cost of making one vegetable sandwich as x. Then we know that the cost of a vegetable burger is x + 12. The cost of a vegetable burger is 14.75 rupee

From the problem statement, we know that the cost of making one sandwich is 2.75 rupees, so we can set up the equation:

x = 2.75

Then the cost of a vegetable burger is:

x + 12 = 2.75 + 12 = 14.75

In summary, the cost of a vegetable burger from the school canteen is 14.75 rupees. We can find this by adding the cost of making one sandwich (2.75 rupees) to the extra cost of 12 rupees for the burger.

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The statement that is true when calculating a 95% confidence interval for the difference between two means is that when the confidence interval ranges from a negative value to a positive value.

When calculating a 95% confidence interval for the difference between two means, the confidence interval represents a range of values that is likely to contain the true difference between the two population means. A confidence interval that ranges from a negative value to a positive value indicates that there is a range of possible differences between the two population means, including the possibility of no difference (i.e., the difference is zero).

However, since the confidence interval does not include zero, we can conclude (at 95% confidence) that there is a statistically significant difference between the two population means. On the other hand, if the confidence interval ranges from a negative value to a negative value or from a positive value to a positive value, we can conclude (at 95% confidence) that both population means are either negative or positive, respectively. Finally, if the confidence interval includes zero, we cannot conclude that there is a significant difference between the two population means.

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Using the concept of bearing and displacement, the seal is 3.276km from it's starting point.

To determine how far north the seal is from its starting point, we need to find the northward component of its displacement.

Given that the seal swims on a bearing of 055 degrees, we can consider this as the direction with respect to true north. To find the northward component, we need to calculate the sine of the angle.

The northward component can be found using the formula:

Northward component = Displacement * sin(Bearing)

In this case, the displacement is 4 km, and the bearing is 055 degrees.

Northward component = 4 km * sin(55 degrees)

Using a calculator, we find that sin(55 degrees) ≈ 0.8192.

Northward component ≈ 4 km * 0.8192

Northward component ≈ 3.276 km

Therefore, the seal is approximately 3.2768 km north of its starting point.

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If the rate of interest is the same in both years, the rate of interest is 12%.

The man took a loan of Rs.10,000 at simple interest. He paid Rs. 5,000 at the end of first year in which interest is also included and Rs. 6,944 at the end of the second year and clears the debt.

Here is the solution:

Interest paid in the first year = Rs. (10,000 - 5,000) = Rs. 5,000

Interest paid in the second year = Rs. (6,944 - 10,000) = Rs. -3,056

Total interest paid = Rs. (5,000 + (-3,056)) = Rs. 1,944

Principal amount = Rs. 10,000

Rate of interest = (100 * 1,944) / (10,000 * 2) = 12%

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The resulting value will give you the mass of the ball of radius 3 centered at the origin with the given density function.

To find the mass of the ball with a radius of 3 centered at the origin, we need to integrate the density function over the volume of the ball.

The density function is given as f(ρ, φ, θ) = 5e^(-ρ^3), where ρ represents the radial distance, φ represents the azimuthal angle, and θ represents the polar angle.

In spherical coordinates, the volume element is given by ρ^2 sin(φ) dρ dφ dθ.

To integrate over the ball, we need to set the limits of integration as follows:

ρ: 0 to 3

φ: 0 to π

θ: 0 to 2π

The mass of the ball can be calculated using the integral:

Mass = ∫∫∫ f(ρ, φ, θ) ρ^2 sin(φ) dρ dφ dθ

Mass = ∫[0 to 2π] ∫[0 to π] ∫[0 to 3] 5e^(-ρ^3) ρ^2 sin(φ) dρ dφ dθ

This integral needs to be evaluated numerically using appropriate software or numerical techniques.

The resulting value will give you the mass of the ball of radius 3 centered at the origin with the given density function.

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The concept of marginal thinking suggests that you should only consider the marginal benefit and marginal cost of accepting the piece of chocolate.

Marginal benefit refers to the additional pleasure or satisfaction that you will receive from consuming the chocolate, while marginal cost refers to any negative consequences, such as calories or sugar intake, or potential discomfort if you have an allergy. It's important to consider the trade-off between these two factors and decide whether the marginal benefit outweighs the marginal cost. If it does, then accepting the piece of chocolate may be a good decision. However, if the marginal cost is too high, then it may be better to decline the offer and seek alternative sources of pleasure or satisfaction. In this way, the concept of marginal thinking helps you make rational and informed decisions that optimize your well-being and resources.

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Answer: x=6

Step-by-step explanation:

Since isosceles triangles have two sides of equal length, the side of 24 in is equal to the side of 6x-12. So, with the equation 24=6x-12, you should find x to be 6.

The probability of selecting an executive with a type A personality can be calculated by dividing the number of executives with a type A personality by the total number of executives in the group. the probability of selecting an executive with a type A personality from this group is 0.54, or 54%.

P(type A) = number of executives with type A personality / total number of executives
P(type A) = 27 / 50
P(type A) = 0.54 or 54%
Therefore, the probability of selecting an executive with a type A personality from this group is 54%. Probability = (Number of desired outcomes) / (Total number of possible outcomes)
Probability = 27 / 50
Now, we can simplify the fraction:
Probability = 0.54
So, the probability of selecting an executive with a type A personality from this group is 0.54, or 54%.

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Answer:

pick the first one

Step-by-step explanation:

The following characteristics are true of the graph of all proportional relationships. The graph is linear. The line of the graph passes through the origin. The slope of the line is the constant of proportionality.

the only graph that goes through the origin (0,0) is the first one. it doesn't have an intercept.

so pick y=(2/3)x

Answer:

First choice:  y = 2/3x

Step-by-step explanation:

A linear equation is proportional if it is straight AND passes through the origin (0,0).  The only equation that meets this definition is the first one,

y = 2/3x

Answer:

[tex]\frac{3}{26}[/tex] of pulling a queen or a black 3.

Step-by-step explanation:

Since there's 52 cards in an average deck and there's 4 queens, divide 52 with 4 and you'll get 13, so that means it's a [tex]\frac{1}{13}[/tex] chance of getting a queen.

Also because there's 4 "3"s and 50% of those cards are black (clubs and spades), divide 52 with 2 and you'll get a [tex]\frac{1}{26}[/tex] chance of getting a black 3.

Add both quotients to a common denominator of 52 and you will end up with 6/52. Then simplify the sum.

You should end up with [tex]\frac{3}{26}[/tex].

The distance from my town to the little village is $35$ miles.

To find the distance from my town to the little village, we need to add up the distances of each segment of the trip. We know that the straight-line distance from the capital city to the little village is $140$ miles, but we can't use that information directly. Instead, we need to use the distances between each town.
From the capital city to my town is $80$ miles, from my town to your town is $25$ miles, and from your town to the little village is $35$ miles. Adding those distances gives us:
$80 + 25 + 35 = 140$ miles
So the distance from my town to the little village is $35$ miles.

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Answer:

y < 106

Step-by-step explanation:

In this equation, we simply add 21 to both sides, so we get y < 106.

[tex]x + x^3[/tex] is the simplified expression of [tex]x/4x + x^2[/tex]

To simplify , we will find common denominator. A common denominator means the number which can be divided by all the denominators in a group of fractions.

The denominator of first fraction is 4x, so we will rewrite the expression as:

From [tex]x/4x + x^2[/tex]

To: [tex](x/4x) + (x^2(4x)/4x).[/tex]

Simplifying second fraction gives us:

(4x^3)/4x.

We will cancel out common factor of 4x, so, we are left with [tex]x + x^3[/tex]as the simplified expression.

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There is a 5% chance that we have wrongly rejected the null hypothesis and that the new ingredient does not actually reduce the drying time.

Hypothesis testing is a statistical method used to determine whether an assumption about a population parameter is supported by the sample data. In this case, the product developer is interested in determining whether the new ingredient in the primer paint reduces the drying time.

The null hypothesis assumes that there is no difference between the population means of drying time for the two formulations, while the alternative hypothesis assumes that the new ingredient reduces the drying time.

To determine the effectiveness of the new ingredient, the product developer can perform a hypothesis test.

Let's assume that the null hypothesis (H₀) is that the new ingredient does not reduce the drying time, and the alternative hypothesis (Hₐ) is that the new ingredient reduces the drying time.

H₀: μ₁ - μ₂ = 0

Hₐ: μ₁ - μ₂ > 0

Where μ₁ and μ₂ are the population means of drying time for formulation 1 and formulation 2, respectively.

Since the population standard deviation (σ) is known and the sample size is large enough (n = 10), we can use a two-sample z-test.

The test statistic can be calculated as:

z = (x₁ - x₂) / [σ × √(1/n₁ + 1/n₂)]

Where x₁ and x₂ are the sample means of drying time for formulation 1 and formulation 2, respectively.

Plugging in the given values, we get:

z = (121 - 112) / [8 × √(1/10 + 1/10)] = 4.14

Using a one-tailed test and a significance level of α = 0.05, the critical z-value is 1.645.

Since the calculated z-value (4.14) is greater than the critical z-value (1.645), we can reject the null hypothesis and conclude that there is evidence that the new ingredient reduces the drying time.

However, it's important to note that this conclusion is subject to a type I error, which is the probability of rejecting the null hypothesis when it is actually true. The probability of type I error is equal to the significance level (α), which in this case is 0.05.

Therefore,

There is a 5% chance that we have wrongly rejected the null hypothesis and that the new ingredient does not actually reduce the drying time.

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The set of parametric equations for the line y = 3x - 2, with t = 0 at the point (2,4), is x = t + 2, y = 3t + 4.

We can use the point-slope form of a line to find the parametric equations:

y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope of the line.

The slope of the line y = 3x - 2 is 3, so we have:

y - 4 = 3(x - 2)

Simplifying, we get:

y = 3x - 2

We can rewrite this as a set of parametric equations:

x = t + 2

y = 3t + 4

So the set of parametric equations for the line y = 3x - 2, with t = 0 at the point (2,4), is:

x = t + 2, y = 3t + 4.

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The exact length of the curve is approximately 32.953 units.

The length of a curve defined parametrically by x=f(t) and y=g(t) for a≤t≤b can be calculated by using the following formula:

L = ∫a^b √[f'(t)^2 + g'(t)^2] dt

Using the given values, we have:

f(t) = 2/3 t^3

g(t) = t^2 - 2

a = 0

b = 5

Taking the derivatives, we get:

f'(t) = 2t^2

g'(t) = 2t

Plugging these values into the formula, we get:

L = ∫0^5 √[(2t^2)^2 + (2t)^2] dt = ∫0^5 2t√(5t^2 + 4) dt

This integral cannot be evaluated using elementary functions, so we need to use numerical methods to find an approximate value.

Using a numerical integration method such as Simpson's rule with n=10, we get:

L ≈ 32.953

Therefore, the exact length of the curve is approximately 32.953 units.

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The simplified expression is: x(x - 6) + y(y + 14) - 40

The given expression is:

x² - 6x - 40 + 14y + y²

This is a quadratic expression in terms of x and y. To factorize it, group the terms that involve x together and the terms that involve y together:

(x² - 6x) + (y² + 14y) - 40

Now, factorize the terms involving x and y:

x(x - 6) + y(y + 14) - 40

So, the simplified expression is:

x(x - 6) + y(y + 14) - 40

Note that this expression cannot be simplified any further.

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The complete question goes thus:

Factorize: x ^ 2 - 6x - 40 + 14y + y ^ 2

Answer:

[C] 30

Step-by-step explanation:

------------------------------------------------------------------------------------------------------------                      

                            Preferred Food

                               Pizza                    Burger                 Other                 Total

               Girl             5                             6                       4

Gender   Boy            7                              5                       3

               Total

------------------------------------------------------------------------------------------------------------                      

------------------------------------------------------------------------------------------------------------                      

                            Preferred Food

                               Pizza                    Burger                 Other                 Total

               Girl             5                             6                       4                        15

Gender   Boy            7                              5                       3                        15

               Total        12                            11                        7                       30

------------------------------------------------------------------------------------------------------------              

Based on what we record in the table. We can see that;

30 people took part in the survey.

RevyBreeze

Answer:

30 people took part in the survey.

Answer:

68 boys

Step-by-step explanation:

8 girls + 17 boys = 25 students.

boys make up 17/25.

17 out of 25 = (17 X 100) / 25 = 68 (%)

so, out of 100 students, there will be 68 boys

The domain of f(x, y) is a closed and bounded region, hence by the Extreme Value Theorem, absolute maximum and minimum values exist.

To find them, we first check for critical points by setting the partial derivatives equal to zero:

fx = 2x = 0, so x = 0

fy = -2y = 0, so y = 0

The only critical point is (0, 0). We also need to check for extreme values on the boundary of the domain.

On the curve x = 0, we have f(0, y) = -y^2 - 23, which has a maximum value of -20 at y = 0 and a minimum value of -24 at y = ±1.

On the curve x = 3, we have f(3, y) = 9 - y^2 - 23, which has a maximum value of -14 at y = 0 and a minimum value of -30 at y = ±1.

On the curve y = ±1, we have f(x, ±1) = x^2 - 21, which has a maximum value of 2 at x = ±√21 and a minimum value of -19 at x = 0.

Therefore, the absolute maximum value of f(x, y) is 2, which occurs at (±√21, ±1), and the absolute minimum value of f(x, y) is -30, which occurs at (3, ±1).

(b) The domain of g(x, y) is y > 0 and y < 1, which is an open and unbounded region. Therefore, the absolute maximum and minimum values may not exist. However, we can still find critical points by setting the partial derivatives equal to zero:

gx = y = 0, so y = 0

gy = x - 4y^3 = 0, so x = 4y^3

The only critical point is (0, 0), but it is not in the domain of g(x, y). Therefore, there are no critical points to consider.

(c) The domain of h(x, y) is the unit circle centered at the origin, which is a closed and bounded region. Hence, by the Extreme Value Theorem, absolute maximum and minimum values exist. To find them, we first find critical points by setting the partial derivatives equal to zero:

hx = 2x = 0, so x = 0

hy = 2y + r = 0, so y = -r/2

Substituting y = -r/2 into the equation of the circle x^2 + y^2 = 1, we get x^2 + r^2/4 = 1, or x = ±√(1 - r^2/4). Thus, the critical points are (±√(1 - r^2/4), -r/2).

We also need to check for extreme values on the boundary of the domain (the unit circle). Since the unit circle is a closed and bounded region, by the Extreme Value Theorem, the absolute maximum and minimum values of h(x, y) on the unit circle occur at either the critical points or at the endpoints of the boundary.

At the endpoints of the boundary, we have h(1, 0) = 23, which is the maximum value, and h(-1, 0) = 25, which is the minimum value.

At the critical points, we have h(±√(1 - r^2/4), -r/2) = 22 + r^2/4, which

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For values of y near 0, the functions can be ordered in increasing order as follows: 1 - cos(y) < ln(1 + y^2) < 1/(1 - y^2) - 1.

To determine the increasing order of the functions for values of y near 0 using their Taylor expansions, let's calculate the Taylor series expansions for each function and compare them.

(a) 1 - cos(y):

The Taylor series expansion for 1 - cos(y) centered at y = 0 is:

1 - cos(y) = 0 + (1/2!)y^2 + (0) + ...

The second-order term is positive, and all higher-order terms are non-negative. Therefore, for values of y near 0, the function 1 - cos(y) is increasing.

(b) ln(1 + y^2):

The Taylor series expansion for ln(1 + y^2) centered at y = 0 is:

ln(1 + y^2) = (0) + (1/1)(y - 0) + (0) + ...

The first-order term is positive, and all higher-order terms are non-negative. Therefore, for values of y near 0, the function ln(1 + y^2) is increasing.

(c) 1/(1 - y^2) - 1:

The Taylor series expansion for 1/(1 - y^2) - 1 centered at y = 0 is:

1/(1 - y^2) - 1 = 1/(1 - 0^2) - 1 + (0) + ...

The constant term is positive, and all higher-order terms are non-negative. Therefore, for values of y near 0, the function 1/(1 - y^2) - 1 is increasing.

Therefore, in increasing order for values of y near 0, we have:

1 - cos(y) < ln(1 + y^2) < 1/(1 - y^2)

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the instantaneous velocity function of the object moving along the line described by y=f(x)=6x^2-5x at time x (in seconds) is v = f'(x) = 12x - 5 feet per second.

the instantaneous velocity of an object is the rate of change of its position at a particular moment in time. In other words, it is the slope of the tangent line to the position function at that specific point.

To find the instantaneous velocity function, we take the derivative of the position function with respect to time. In this case, the derivative of f(x) is f'(x) = 12x - 5.

To find the velocity at times x = 1, 3, and 5 seconds, we simply plug in those values for x into the instantaneous velocity function. Therefore, the velocity at x = 1 second is v(1) = f'(1) = 12(1) - 5 = 7 feet per second. The velocity at x = 3 seconds is v(3) = f'(3) = 12(3) - 5 = 31 feet per second. Finally, the velocity at x = 5 seconds is v(5) = f'(5) = 12(5) - 5 = 55 feet per second.

the instantaneous velocity function of the object is v = f'(x) = 12x - 5 feet per second, and the velocity at times x = 1, 3, and 5 seconds is 7 feet per second, 31 feet per second, and 55 feet per second, respectively.

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The probability of selecting a sample with a mean of 1450 or less, given a known population mean of 1500 and a known standard error of the mean of 42.50, is approximately 11.90%.

Probability plays a significant role in statistics and helps us understand the likelihood of an event occurring. In this case, we will discuss the probability of selecting a sample with a mean of 1450 or less, given a known population mean of 1500 and a known standard error of the mean of 42.50.

To calculate the probability of selecting a sample with a mean of 1450 or less, we will use the concept of the standard normal distribution. The standard normal distribution is a probability distribution that has a mean of 0 and a standard deviation of 1.

We can convert any normal distribution to a standard normal distribution by using the formula z = (x - μ) / σ, where z is the standard score, x is the raw score, μ is the population mean, and σ is the standard deviation.

In this case, we know the population mean is 1500, and the standard error of the mean is 42.50. The standard error of the mean is the standard deviation of the sample means, and we can calculate it using the formula σ/√n, where σ is the population standard deviation and n is the sample size. However, in this case, we already know the standard error of the mean.

Using the formula z = (x - μ) / σ, we can find the z-score for a sample mean of 1450:

z = (1450 - 1500) / 42.50

z = -1.18

We can then use a standard normal distribution table to find the probability of a z-score of -1.18 or less.

The probability of a z-score of -1.18 or less is 0.1190, or approximately 11.90%.

Therefore, the probability of selecting a sample with a mean of 1450 or less, given a known population mean of 1500 and a known standard error of the mean of 42.50, is approximately 11.90%.

This means that if we were to randomly select samples from the population, about 11.90% of them would have a mean of 1450 or less.

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Calculated t-test statistic (-2.21) is less than the critical value (-1.711), we reject the null hypothesis

The critical value for this hypothesis test can be found using a t-distribution with degrees of freedom (df) equal to the sample size minus one (df = 25-1 = 24) and a significance level of 5%.

Using a t-distribution table or calculator, the critical value for a one-tailed test (since we are testing if the mean is less than 1,150 hours) with 24 degrees of freedom and a 5% significance level is approximately -1.711. Therefore, the answer is B) -1.711.

To conduct the hypothesis test, we would calculate the t-test statistic using the formula:

[tex]t = (sample mean - hypothesized population mean) / (sample standard deviation / \sqrt{sample size})[/tex]
In this case, the sample mean is 1,097 hours, the hypothesized population mean is 1,150 hours, the sample standard deviation is 133 hours, and the sample size is 25. Plugging these values into the formula, we get:

[tex]t = (1,097 - 1,150) / (133 / \sqrt{25} )[/tex]= -2.21

Since the calculated t-test statistic (-2.21) is less than the critical value (-1.711), we reject the null hypothesis and conclude that there is sufficient evidence to support the claim that the mean life of light bulbs produced by this company is less than 1,150 hours.

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The equations for each object's velocity, in meters/second, in terms of its mass in kilograms are:

[tex]V_A=\sqrt{\frac{200}{m} }\\\\V_B=\sqrt{\frac{50}{m} }[/tex]

A graph of the two functions is shown below.

In Mathematics, the kinetic energy of an object can be calculated by using the following equation (formula):

K.E = 1/2 × mv²

Where:

By making velocity (v) the subject of formula, we have:

[tex]V= \sqrt{\frac{2K.E}{m} }[/tex]

In this context, the equations for each object's velocity, in terms of its mass can be written as follows;

Velocity of object A = [tex]V_A= \sqrt{\frac{2(100)}{m} }[/tex]

Velocity of object A = [tex]V_A= \sqrt{\frac{200}{m} }[/tex]

Velocity of object B = [tex]V_B= \sqrt{\frac{2(25)}{m} }[/tex]

Velocity of object B = [tex]V_B= \sqrt{\frac{50}{m} }[/tex]

When mass (m) = 2 kg, the velocity of object A can be calculated as follows;

[tex]V_A=\sqrt{\frac{200}{m} } \\\\V_A=\sqrt{\frac{200}{2} }\\\\V_A=10 \;m/s[/tex]

When mass (m) = 2 kg, the velocity of object B can be calculated as follows;

[tex]V_B=\sqrt{\frac{50}{m} } \\\\V_B=\sqrt{\frac{50}{2} }\\\\V_B=5 \;m/s[/tex]

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Complete Question:

The kinetic energy, E₁, in kilograms meters squared per second squared (kg.m²/sec) of an object can be modeled with the equation E, = 1/2mv².

where m is the object's mass in kilograms and v is the object's velocity in meters per second.

A physics student is investigating 2 moving objects:

Object A's kinetic energy is 100 kg m²/sec².

Object B's kinetic energy is 25 kg m²/sec²

Write equations for each object's velocity, in meters/second, in terms of its mass in kilograms. Then graph the two functions on the same coordinate grid. Provide evidence to support your answer.