Patrick purchased a new tires that were regularly priced at $92.99 each but are on sale for $20 off per tire. If the sales tax rate is 4% how much will be charged to Patrick’s Visa card??
Answers
Since the regular price is 92.99 for each tire, and it has a discount of 20, the final price of each tire is:
92.99 - 20 = 72.99
Now, since he bought 8 tires, the total cost would be:
8 * 72.99 = 583.92
We now need to include the sale tax rate of 4%. We can do so by using the following formula:
price + tax = (1 + tax rate) * price
So, we have:
price + tax = (1 + 4%) * 583.92
Notice that:
4% = 4/100 = 0.04
Then:
price + tax = (1 + 4%) * 583.92
= (1 + 0.04) * 583.92
= 1.04 * 583.92
= 607.2768
≅ 607.28
Therefore,
$607.28 will be charged to Patrick's VISA card.
Related Questions
Solve a 2x + 6x z for X.
Answers
Given data:
The given expression is a=2x+6xz.
the given expression can be written as,
a=2x(1+3z)
a/(1+3z)=2x
x=a/2(1+3z).
hus, the value of x is a/2(1+3z).
ive got this due tomorrow and i literally CANNOT find the answer keys so imma need help in these three
Answers
13x=32+5x
First wee need to put all the terms on the same side of the equation remember if you change from one side to the other side of the equation the sign change
13x-5x=32
8x=32
we clear x
x=32/8
x=4
the solution is x=4
Find the area of a triangle that has a base of 7 ft and a height of 6 ft
Answers
Area of a triangle = 1/2 * (Base *height )
Replacing your data
Area of the triangle = 1/2 * (7 *6 )
Area of the triangle = 21 ft^2
_______________
Solve for X 5 (3x + 1) = X -4 A. 9/14 B. 3/11 C. 1 D. 1/2
Answers
Solve for x:
[tex]5(3x+1)=x-4[/tex]To solve for x, we are going to use inverse operations to solve equatons.
Addition and subtraction are inverse operations, multiplication and division are inverse operations too.
Then,
[tex]\begin{gathered} As\text{ a first step, using distributive property:} \\ 15x+5=x-4 \\ 15x-x=-4-5 \\ 14x=-9 \\ x=-\frac{9}{14} \end{gathered}[/tex]Therefore, the correct answer would be A.
A movie club surveyed 150 high school students. The students were asked how often they go to the movies and whether they prefer action movies or comedies.Thelr responses are summarized in the following table.Twice a month Three times a monthAction4527Comedy 6612or lessor more(a) What percentage of the students go to the movies three times a month or more?(b) What percentage of the students prefer action movies ?(a) 096Х5?(b) 1%Submit AContinue2021 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center
Answers
Answer:
(a) 26 %
(b) 48%
Explanation:
The total number of students is
[tex]45+27+66+12[/tex][tex]=150[/tex](a).
The total number of students that go to the movies three times or more is
[tex]27+12=39[/tex]Therefore, the percentage is
[tex]\frac{39}{150}\times100\%[/tex][tex]=26\%[/tex](b).
The total number of students that prefer action movies is
[tex]45+27=72[/tex]therefore, the percentage is
[tex]\frac{72}{150}\times100\%=48\%[/tex]Hence, to summerise:
(a) 26 %
(b) 48%
Susy has a square plot of grass in her backyard. Each side of the plot has a length of 14.5 feet. On one side, a semicircular fountain with a radius of 2.5 feet cuts into the plot of grass. She wants to put a brick border around the edge of the grass, so that it will also separate the grass from the fountain.What is the approximate length of the brick border?
Answers
Given:-
Susy has a square plot of grass in her backyard. Each side of the plot has a length of 14.5 feet. On one side, a semicircular fountain with a radius of 2.5 feet cuts into the plot of grass. She wants to put a brick border around the edge of the grass, so that it will also separate the grass from the fountain.
To find:-
What is the approximate length of the brick border?
The length of squares four sides is,
[tex]4\times14.5=58[/tex]All four sides of square are equall,
[tex]58-(2.5\times2)=53[/tex]Diameter of a circle is twice its radius,
[tex]\pi r=\pi2.5=7.85[/tex]Formula of circumference is,
[tex]2\pi r[/tex]So the length of brick is,
[tex]53+7.85=60.85[/tex]So the approximate length is 60.85ft.
Create a multi-step equation(that requires at least 3 steps to solve). For the equation you create, include thefollowing things in your initial response:• The equation clearly written out• The mathematical work needed to solve the equation (be sure to show allsteps)• The solution to the equationFor each step in the solution process, write a brief sentence or two that explainsthe step. For example, you might write something like "I divided both sides of theequation by 2 to cancel out the multiplication by 2..."
Answers
SOLUTION
[tex]Given\text{ the question on the question tab;}[/tex]To create a multi-step equation
(that requires at least 3 steps to solve).
[tex]\begin{gathered} Writing\text{ out the equation;} \\ 9x-6=5x+18 \end{gathered}[/tex][tex]\begin{gathered} Solving\text{ the equation and giving brief sentence to explain the steps;} \\ 9x-6=5x+18 \\ Subtract\text{ 5x from both sides;} \\ 9x-5x-6=5x-5x+18 \\ 4x-6=18 \end{gathered}[/tex][tex]\begin{gathered} Add\text{ 6 to both sides} \\ 4x-6+6=18+6 \\ 4x=24 \\ Divide\text{ both sides by 4;} \\ \frac{4x}{4}=\frac{24}{4} \\ x=6 \end{gathered}[/tex]There is a population of 9,000 bacteria in a colony. If the number of bacteria doubles every 245 hours, what will the population be 980 hours from now?
Answers
There is a population of 9,000 bacteria in a colony.
If the number of bacteria doubles every 245 hours, what will the population be 980 hours from now?
Recall that the exponential growth formula is given by
[tex]y=a\cdot b^x[/tex]Where a is the initial population, b is the rate of growth, and x is the time.
For the given case, we have
a = 9,000
b = 2 (doubles)
x = 980/245 = 4
Let us substitute these values into the above formula
[tex]\begin{gathered} y=a\cdot b^x \\ y=9,000\cdot2^4 \\ y=9,000\cdot16 \\ y=144,000 \end{gathered}[/tex]Therefore, the population of the bacteria will be 144,000 after 980 hours from now.
You can pick any question to solve. I really need help though...
If you solve all of it, I'll give you 115 points.
Answers
The simplification of the number 3⁷.3⁸/3¹⁹ is found as 1/3⁴.
What is meant by the term indices/ index?An index can be assigned to a number or a variable. A variable's index (or constant) is a value raised to a power of a variable. Indexes are also referred to as powers as well as exponents. It indicates how many times a provided number must be multiplied. The index specifies that a specific number (or base) be multiplied on its own an amount equal to a index raised to it.The given expression in the question is-
= 3⁷.3⁸/3¹⁹
By the power rule of the indices.
With the same base, the power of the number get added with sign.
= 3¹⁵/3¹⁹
Now, taking reciprocal.
= 3¹⁵.3⁻¹⁹
Subtract the powers.
= 3⁻⁴
Again take the reciprocal
= 1/3⁴
Thus, the simplification of the number is found as 1/3⁴.
To know more about the indices/ index, here
https://brainly.com/question/10339517
#SPJ1
The correct question is-
Simplify the given expression;
3⁷.3⁸/3¹⁹
You and three friends go to a baseball game. You each pay 2$ for a drink and x dollars for nachos. Use the distributive property to write and simplify an expression for the total the group pays.
Answers
You and three friends go to a baseball game.
So, there are a total of 4 persons.
You each pay $2 for a drink and x dollars for nachos.
Recall that the distributive property is given by
[tex]a\cdot(b+c)=a\cdot b+a\cdot c[/tex]For the given case, we have
a = 4
b = 2
c = x
Let us apply the distributive property to write and simplify an expression for the total the group pays.
[tex]\begin{gathered} 4\cdot(2+x)=4\cdot2+4\cdot x \\ 4\cdot(2+x)=8+4x \end{gathered}[/tex]Therefore, the simplified expression for the total amount that the group pays is
[tex]8+4x[/tex]simplify the following expreission(2m^3 -5m+3m^2) + (4+5m^2-2m)
Answers
Answer:
[tex]2m^3+8m^2-7m+4[/tex]Explanation:
Given the expression:
[tex]\mleft(2m^3-5^{}m+3m^2\mright)+(4+5m^2-2m)[/tex]First, we open the brackets to get:
[tex]=2m^3-5^{}m+3m^2+4+5m^2-2m[/tex]Next, we collect like terms and simplify.
[tex]\begin{gathered} =2m^3+3m^2+5m^2-5m-2m+4 \\ =2m^3+8m^2-7m+4 \end{gathered}[/tex]What would make the following equation true? -4+_____=2m+(3m-4)A: -5mB: -4mC: -1mD: 6mE: 5m
Answers
When you open the parenthesis at the right-hand side of the equation
2m + (3m - 4) = 2m + 3m - 4
= 5m - 4
Comparing the left-hand side with the right -hand side
5m is the answer
Find the amount of aluminum needed to make this bucket. Include the base.90cm at top 30.6 cm on the side24 cm in the middle52cm at the bottom
Answers
The amount of aluminium need to make the bucket is the same as the surface area. In this case the surface area is made of the circular bottom base plus the lateral area. The lateral area is a trapezoid.
The area of a trapezoid is given by:
[tex]A=\frac{b_1+b_2}{2}\cdot h[/tex]to find the bases we need to remember that the greater base is equal to the circumference of the upper circle and the smaller base is equal to the circumference of the bottom circle. Then we have that the surface area is:
[tex]\begin{gathered} S=\frac{90\pi+52\pi}{2}\cdot30.6+\pi(\frac{52}{2})^2 \\ S=2172.6\pi+676\pi \\ S=2848.6\pi \\ S=8949 \end{gathered}[/tex]Therefore we need 8949 squared centimeters of aluminium
А group of college students bought a couch for $80. However, five of them failed to pay their share so the others had to each pay $8 more. How many students were in the original group?
Answers
А group of college students bought a couch for $80. Let's say that the number of the students in that group is A.
Five of them failed to pay their share so the others had to each pay $8 more. Then the number of students that finally paid it was A - 5.
We have to find the value of A.
We know that in the beggining $80/A was the amount of money each student had to pay.
Then, each one had to pay $80/(A-5).
Since they had to pay $8 more than the initial amount, each one had to pay ($80/A) + $8 .
Then $80/(A-5) = ($80/A) + $8
Now, we have to find A from the previous equation
[tex]\begin{gathered} \frac{80}{A-5}=\frac{80}{A}+8 \\ \frac{80}{A-5}-\frac{80}{A}=8 \\ \frac{80A-80\mleft(A-5\mright)}{(A-5)A}=8 \\ \frac{80A-80A+400}{A^2-5A}=8 \\ \frac{400}{A^2-A}=8 \\ \frac{400}{8(A^2-A)}=1 \\ \frac{50}{A^2-5A}=1 \\ 50=A^2-5A \\ 0=A^2-5A-50 \\ 0=(A-10)(A+5) \end{gathered}[/tex]SThen A has two possible values
A₁ = (1 + √201)/2
A₂ = (1 - √201)/2
Since A should be possitive and 1 - √201 is negative then,
A = (1 + √201)/2
≅ (1 + 14) /2 = 15 / 2
= 7.5 ≅ 8
Answer: 8 students were in the original group
Directions: Solve each equation. Check your solution(s) then indicate whether or not the solutions are extraneous.
Answers
we have
Part 3
[tex]3\mleft|x-2\mright|=18[/tex]step 1
Divide by 3 both sides
[tex]|x-2|=6[/tex]Solve the first case (positive)
[tex]\begin{gathered} +(x-2)=6 \\ x=6+2 \\ x=8 \end{gathered}[/tex]Solve the second case (negative)
[tex]\begin{gathered} -(x-2)=6 \\ x-2=-6 \\ x=-6+2 \\ x=-4 \end{gathered}[/tex]Which of the following are reasons used in proof that the angle bisector construction can be used to bisect any angle
Answers
In the construction we use the fact that all radius of a circle are congruent, so AB ≅ AC, as both segments are radius of the same circle.
In the same way, this let us write:
[tex]BD\cong CD[/tex]As, by reflexive property, we can write AD ≅ AD.
Then, we have triangles with 3 pairs of congruent sides, so they are congruent by the SSS postulate.
Then, because of CPCTC (corresponding parts of congruent triangles are congruent), the angle BAD is congruent to angle CAD, meaning that AD is a bisector of angle BAC.
Answer: Options A, C and D.
Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 2 L, the pressure is 1165 kPa (kilopascals),What is the volume when the pressure is 466 kPa ?
Answers
SOLUTION
The volume of a gas varies inversely with the pressure
This is written as:
[tex]PV=k[/tex]Where k is a constant
When V=2L, P=1165kPa
Substitute these values into the above equation
[tex]1165\times2=k[/tex]It follows:
[tex]k=2330[/tex]Substituting the value of k into the equation gives
[tex]PV=2330[/tex]Find V when P=466kpa
Substitute P=466 into the equation PV=2330
[tex]466\times V=2330[/tex]Solve for V
[tex]\begin{gathered} V=\frac{2330}{466} \\ V=5 \end{gathered}[/tex]Therefore The required volume is 5L
An integer is 3 more than 4 times another. If the product of the two integers is 45, then findthe integers
Answers
Define the equations that describe the situation
[tex]\begin{gathered} x=4y+3 \\ x\cdot y=45 \end{gathered}[/tex]Clear x from the second equation
[tex]x=\frac{45}{y}[/tex]Make both equations equal
[tex]\begin{gathered} 4y+3=\frac{45}{y} \\ y(4y+3)=45 \\ 4y^2+3y=45 \\ 4y^2+3y-45=0 \end{gathered}[/tex]Solve the cuadratic equation
[tex]\begin{gathered} y=\frac{-3\pm\sqrt[]{3^2-4\cdot4\cdot(-45)}}{2\cdot4} \\ y=\frac{-3\pm\sqrt[]{9+720}}{8} \\ y=\frac{-3\pm27}{8} \\ y1=-\frac{30}{8}=-\frac{15}{4} \\ y2=\frac{24}{8}=3 \end{gathered}[/tex]As we are dealing with integers, the value of y is 3, now use one of the first equations to find x
[tex]\begin{gathered} x=\frac{45}{y} \\ x=\frac{45}{3} \\ x=15 \end{gathered}[/tex]The integers are 3 and 15
Which of the binomials is a factor of this trinomial?
Answers
Part A: complete the statement below about inscribed quadrilateralsPart B: select all of the statements that are true
Answers
Because the quadrilateral is incribed in a circle, the opposite vetices forms supplementary arcs of the circle, which means that opposite angles of it are supplementary.
This means that the first option is opposite angles and the second is supplementary.
They being supplementaty means that their sum is equal to 180°, so:
[tex]\begin{gathered} m\angle A+m\angle C=180\degree \\ m\angle B+m\angle D=180\degree \end{gathered}[/tex]However, notrhing can be said about congruency of opposite angles, so the first option of part be is not necessarily true.
The second is true, as we showed above.
The third shows a relationship between adjacent angle, which is not necessarily true.
The fourth is false because the opposite angles should add to 180° no 90°.
The last is a property of all quadrilaterals (independetly of them being inscribed or not): the sum of its internal angles is equal to 360°, so the fifth option is true.
So, in part B the only true statements are the second and the fifth.
Write an equation (a) in slope-intercept form and (b) in standard form for the line passing through (-1,6) and parallel to x + 3y = 7.a) The equation of the line in slope-intercept form is.(Type your answer in slope-intercept form. Use integers or fractions for any numbers in the equation.)
Answers
Answer:
[tex]y=\frac{1}{3}x+\frac{19}{3}[/tex]Step-by-step explanation:
Linear equations are represented in slope-intercept form by the following equation:
[tex]\begin{gathered} y=mx+b \\ \text{where,} \\ m=\text{slope} \\ b=\text{ y-intercept} \end{gathered}[/tex]If the line is parallel to x+3y=7, it means they have the same slope. Then, the slope would be;
[tex]\begin{gathered} x+3y=7 \\ y=\frac{x}{3}-\frac{7}{3} \\ \text{ Slope is the coefficient that goes with the ''x''} \\ \text{Slope}=\text{ }\frac{1}{3} \end{gathered}[/tex]Then, to find the y-intercept of the equation, substitute the slope and the given point, solve for b:
[tex]\begin{gathered} 6=\frac{1}{3}(-1)+b \\ b=6+\frac{1}{3} \\ b=\frac{19}{3} \end{gathered}[/tex]Hence, the equation would be:
[tex]y=\frac{1}{3}x+\frac{19}{3}[/tex]the table below shows Luke's golf score each week he participated in a golf tournament used to line of best fit to estimate Lux score for week 12
Answers
To estimate the score of Luke for week 12, we need to determine first the equation for the line of best fit.
To get the equation, here are the steps:
1. Solve for the average value of the x-coordinates and y-coordinates.
Our x-coordinates will be the number of week while the y-coordinates will be the score in each week.
Average for the x-coordinates is:
[tex]\text{average (x)}=\frac{1+2+3+4+5+6}{6}=\frac{21}{6}=3.5[/tex]Average for the y-coordinate is:
[tex]\text{average(y)}=\frac{95+92+89+88+86+84}{6}=\frac{534}{6}=89[/tex]2. Subtract each x and y coordinates to its corresponding averages.
3. Multiply the difference of x and its average to the difference of y and its average. (5th column)
4. Square the difference of x and its average. (6th column)
5. Solve for the slope of the equation. The formula is:
[tex]m=\frac{\sum ^{}_{}(x-ave_x)(y-ave_y)}{\sum ^{}_{}(x-ave_x)^2\text{ }}[/tex][tex]\begin{gathered} m=\frac{-15-4.5+0-0.5-4.5-12.5}{6.25+2.25+0.25+0.25+2.25+6.25} \\ m=-\frac{37}{17.5} \\ m=-2.11429 \end{gathered}[/tex]The slope of the line is m = -2.11429.
6. Solve for the y-intercept. The formula is:
[tex]b=ave_y-m(ave_x)[/tex]Since we already have ave y = 89, ave x = 3.5, and m = -2.11429, let's plug them in to the formula above.
[tex]\begin{gathered} b=89-(-2.11429)(3.5) \\ b=89+7.4 \\ b=96.4 \end{gathered}[/tex]The y-intercept is 96.4.
Hence, the equation of the line of best fit is y = -2.11429x + 96.4.
To estimate the score of Luke for week 12, plug in x = 12 in the equation above and solve for y.
[tex]\begin{gathered} y=-2.11429x+96.4 \\ y=-2.11429(12)+96.4 \\ y=-25.37148+96.4 \\ y=71.02852 \\ y\approx71 \end{gathered}[/tex]Therefore, the score of Luke for week 12 is estimatedly to be 71.
Find the length of ZX to the nearest tenth of a foot.
Answers
Answer:
22.9 feet
Explanation:
We can solve for ZX by taking the tangent of angle 73 as shown below;
[tex]\begin{gathered} \tan 73=\frac{75}{X} \\ X\tan 73=75 \\ X=\frac{75}{\tan73} \\ \therefore X=22.9\text{feet} \end{gathered}[/tex]I need help will this besin A =a/c or the followingsin A =b/csin A =b/asin A =c/bsin A =c/asin A =a/csin A =a/b
Answers
In a right-angled triangle, the side facing the reference angle is the opposite side, the side facing the right angle is the hypotenuse
Since sinA= opposite/hypotenuse
opposite= a
hypotenuse = c
Thus, sinA= a/c
Write all classifications that apply to the real number -5.O rational, integer, terminating decimalO rational, integer, whole number, natural number, terminating decimalO natural number, terminating decimal© rational, integer, natural number
Answers
Given the following question:
Classifications of -5
-5 isn't a whole number, since it's a negative
-5 is a integer
-5 is a rational number since it can be written as a fraction
-5 isn't a natural
-5 is a terminating decimal
Option A is your answer.
a triangle has rotation symmetry that can take any of its verticles to any of its other vehicles. select all conclusions that we can reach from thisA. all sides of the triangle have the same lengthb. all angles of the triangle have the same measurec. a rotation of 60° will map the triangle to itselfd. a rotation of 120° will map the triangle to itself
Answers
In order for a triangle to be rotated in a symmetry that involves each rotation to matching vertices of the triangle, involves several of the options given in the list:
* All sides have the same length (we are dealing with an equilateral triangle)
* All angles ofthe triangle have the same measure (60 degrees each angle)
* A rotation of 60 degrees will map the traingle to itself (typical for a case of equilateral triangle)
* A rotation of 120 degrees will map the triangle with itself. (also in agreement with the answer immediately above, since 120 degree rotetion is the same as two consecutive 60 degree rotations)
What is the equation of the flower garden represented on the blueprint?
Answers
Given: a rectangleis given .
Find : equation of flower garden represents the blue point.
Explanation:
the center of the circle is
[tex](\frac{10+0}{2},\frac{40+0}{2})=(5,20)[/tex]and the radius of the circle is 60 feet.
so the equation of the folwer garden will be .
[tex](x-5)^2+(y-20)^2=60^2[/tex]Hello, please help me find arc AC in this circle for geometry
Answers
Given that
[tex]\begin{gathered} \text{arcAB}=\text{arcDC} \\ \text{Thus,} \\ AB+BC+DC+DA=360^0(sum\text{ of angles of a circumference)} \end{gathered}[/tex]Given that
[tex]\begin{gathered} arcDA=2BC \\ 104^0+104^0+2BC+BC=360^0_{} \\ 3BC=360^0-208^0 \\ BC=\frac{152^0}{3}=50.7^0 \\ \text{Hence} \\ AC=50.7^0+104=154.7^0\approx155^0 \end{gathered}[/tex]the figure to the right shows two parallel lines intersected by more than one transversal. let x = 34 degrees. find the measure of angles 1, 2 and 3.
Answers
Explanation
Step 1
as the horizontal lines are parallel, the angles (1) and x are congruents, so
[tex]\begin{gathered} m\measuredangle1=x \\ so,\text{replacing} \\ m\measuredangle1=34 \end{gathered}[/tex]Step 2
Now, we can see that angles (1) and (2) are complementary angesl (When two angles add to 90°)
so
[tex]\begin{gathered} m\measuredangle1+m\measuredangle2=90 \\ \text{replacing} \\ 34+m\measuredangle2=90 \\ \text{subtract 34 in boht sides} \\ -34+34+m\measuredangle2=90-34 \\ m\measuredangle2=56 \end{gathered}[/tex]Step 3
finally, angles (1) and angle (3) are supplementary angles (Two Angles are Supplementary when they add up to 180 degrees)
so
[tex]\begin{gathered} m\measuredangle1+m\measuredangle3=180 \\ \text{replace} \\ 34+m\measuredangle3=180 \\ to\text{ solve for x, subtract 34 in both sides} \\ -34+34+m\measuredangle3=180-34 \\ m\measuredangle3=146 \end{gathered}[/tex]i hope this helps you
There are 3 red balls,2 blue balls and 5 whiteballs in an urn. A ball is selected and color notedthen replaced. A second ball is selected and it'scolor noted. Find the probability of getting 2blue balls. Also find the probability of getting 1blue ball and 1 white ball. And then find theprobability of getting 1 red ball and 1 blue ball
Answers
Solution:
The probability of an event is expressed as
[tex]pr(\text{event)}=\frac{\text{number of desired outcome}}{number\text{ of possible outcome}}[/tex]Given that 3 red balls,2 blue balls and 5 white balls in an urn, this implies that
[tex]\begin{gathered} \text{Number of red }\Rightarrow\text{N(R)=}3 \\ Number\text{ of blue balls}\Rightarrow N(B)=2 \\ \text{Number of white}\Rightarrow N(W)=5 \\ \text{Total number of balls}\Rightarrow N(Total)=10 \end{gathered}[/tex]A ball is selected and color noted then replaced, a second ball is selected and its color noted.
A) Probability of getting 2 blue balls.
[tex]\begin{gathered} Pr(B\text{ and B)= Pr(B)}\times Pr(B) \\ \Rightarrow Pr(B_{})=\frac{N(B)\text{ }}{N(\text{Total)}}=\frac{2}{10}=\frac{1}{5} \\ \text{thus,} \\ Pr(B\text{ and B)=}\frac{1}{5}\times\frac{1}{5} \\ \therefore Pr(B\text{ and B)}=\frac{1}{25} \end{gathered}[/tex]The probability of picking 2 blue balls is
[tex]\frac{1}{25}[/tex]B) Probability of getting 1 blue ball and 1 white ball.
[tex]\begin{gathered} Pr(1\text{ blue and 1 white ball)=Pr(B and W) or Pr(W and B)} \\ \Rightarrow Pr(B)=\frac{N(B)}{N(\text{Total)}}=\frac{2}{10}=\frac{1}{5} \\ \Rightarrow Pr(W)=\frac{N(W)}{N(\text{Total)}}=\frac{5}{10}=\frac{1}{2} \\ \text{Thus, we have} \\ Pr(1\text{ blue and 1 white ball)=Pr(B and W) or Pr(W and B)} \\ =(\frac{1}{5}\times\frac{1}{2})+(\frac{1}{2}\times\frac{1}{5}) \\ =\frac{1}{10}+\frac{1}{10}=\frac{2}{10} \\ \Rightarrow Pr(1\text{ blue and 1 white ball)}=\frac{1}{5} \end{gathered}[/tex]The probability of getting 1 blue ball and 1 white ball is
[tex]\frac{1}{5}[/tex]C) Probability of getting 1 red ball and 1 blue ball
[tex]\begin{gathered} Pr(1\text{ red ball and 1 blue ball) = Pr(R and B) or Pr(B and R)} \\ \Rightarrow Pr(B)=\frac{1}{5} \\ \Rightarrow Pr(R)=\frac{N(R)}{N(\text{Total)}}=\frac{3}{10} \\ Pr(1\text{ red ball and 1 blue ball) = Pr(R and B) or Pr(B and R)} \\ =(\frac{3}{10}\times\frac{1}{5})+(\frac{1}{5}\times\frac{3}{10}) \\ =\frac{3}{50}+\frac{3}{50}=\frac{6}{50} \\ \Rightarrow Pr(1\text{ red ball and 1 blue ball) }=\frac{3}{25} \end{gathered}[/tex]The probability of getting 1 red ball and 1 blue ball is
[tex]\frac{3}{25}[/tex]