Answer: 50 weeks
First, since he has a scholarship and a grant, those are used to pay off college debt. So $1,500 + $200 = $1,700
Now we subtract that from the total debt.
$14,200 - $1,700 = $12,500
Now since we're only seeing how much can pay for HALF of his debt, we divide $12,500 by 2.
$12,500 ÷ 2 = $6,250
Finally, we have to divide by the amount of money he earns in a week to find the total weeks.
$6,250 ÷ $125 = 50
50 weeks!
Find the TWO integers whos product is -12 and whose sum is 1
Answer:
[tex] \rm Numbers = 4 \ and \ -3.[/tex]
Step-by-step explanation:
Given :-
The sum of two numbers is 1 .The product of the nos . is 12 .And we need to find out the numbers. So let us take ,
First number be x Second number be 1-x .According to first condition :-
[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]
Hence the numbers are 4 and -3
Step-by-step explanation:
[tex]integers \: = x \: and \: y \\ then \: x \times y = - 12 ....(1)\\ x + y = 1.....(2) \\ x = 1 - y.....(3) \\ put \: (3 )\: in \: (1) \\ then \: (1 - y) \times y = - 12 \\ y - {y}^{2} + 12 = 0 \\ {y}^{2} - y - 12 = 0 \\ factorise \\ {y}^{2} - 4y + 3y - 12 = 0 \\ y( y - 4) + 3(y - 4) \\ (y - 4)(y + 3) \\ y = 4 \: and \: - 3 \\ thank \: you[/tex]
(this is 6th grade math) please help whats the equation for this?
Answer:
t=100-s
Step-by-step explanation:
Since we know T as the total amount, we need to figure out how much was spent from the $100 Julie has. She can't gain more money magically so you have to take away from the 100. The amount taken away is the S (a.k.a- how much was SPENT). After putting that together, you get t=100-s.
hope this helps!!
Marta's line of fit __ a line of best fit because her line __
Padra's line of fit__ a line of best fit because his line __
first part A. is
B. is not
Answer:
the awnser is B.
Step-by-step explanation: