Pick the answer that correctly spells a layer of the atmosphere.
A. Mesosphere
B. Thermsphere
C. Mezosphere
D. Tropshere
E. Thermoshere

Answer:

true

Explanation:

Answer:

750 mmHg

Explanation:

From the question given above, the following data were obtained:

Partial pressure of CO₂ (Pₐ) = 250 mmHg

Partial pressure of N₂ (P₆) = 375 mmHg

Partial pressure of He (P꜀) = 125 mmHg

Pressure of the mixture (Pₜ) =?

The pressure of the mixture of the gases can be obtained as follow:

Pₜ = Pₐ + P₆ + P꜀

Pₜ = 250 + 375 + 125

Pₜ = 750 mmHg

Therefore, the pressure of the mixture of the gases is 750 mmHg

Answer:

2 NH3(g) + 3 O2(g) + 2 CH4(g) = 2 HCN(aq) + 6 H2O(l)

Explanation:

Reaction stoichiometry Limiting reagent

Compound Coefficient Molar Mass Moles Weight

NH3(g) 2 17.03052  

O2(g) 3 31.9988  

CH4(g) 2 16.04246  

HCN(aq) 2 27.02534  

H2O(l) 6 18.01528

Instructions on balancing chemical equations:

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below

Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.     Compare: Co - cobalt and CO - carbon monoxide

To enter an electron into a chemical equation use {-} or e

To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}.

Example: Fe{3+} + I{-} = Fe{2+} + I2

Substitute immutable groups in chemical compounds to avoid ambiguity.

For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced,

but PhC2H5 + O2 = PhOH + CO2 + H2O will

Compound states [like (s) (aq) or (g)] are not required.

If you do not know what products are enter reagents only and click 'Balance'. In many cases a complete equation will be suggested.

Reaction stoichiometry could be computed for a balanced equation. Enter either the number of moles or weight for one of the compounds to compute the rest.

Limiting reagent can be computed for a balanced equation by entering the number of moles or weight for all reagents.

The given chemical equation is already balanced and does not require any further balancing.

The chemical equation NH₃(g) + O₂(g) + CH₄(g) → HCN(aq) + H₂O(l) is already balanced because the number of atoms of each element is the same on both sides of the equation.

On the left side of the equation, there is 1 nitrogen (N) atom in NH₃ and 1 nitrogen (N) atom in HCN.

On the right side of the equation, there are 3 hydrogen (H) atoms in NH₃, 2 hydrogen (H) atoms in HCN, and 2 hydrogen (H) atoms in H₂O.

There are 3 oxygen (O) atoms in O₂ on the left side of the equation and 1 oxygen (O) atom in H₂O on the right side of the equation.

Finally, there is 1 carbon (C) atom in CH₄ on the left side of the equation.

Since the number of atoms of each element is balanced on both sides of the equation, we can conclude that the given equation is already balanced and does not require any further adjustments or coefficients.

To learn more about balanced equation, here

https://brainly.com/question/31242898

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The complete question is:

How can I balance NH₃(g) + O₂ (g) + CH₄ (g) -> HCN (aq) + H₂O (l)?

Answer:

(i) Concentrated HNO3 can be stored and transported in aluminium containers as it reacts with aluminium to form a thin protective oxide layer on the aluminium surface. This oxide layer renders aluminium passive. (ii) Sodium hydroxide and aluminium react to form sodium tetrahydroxoaluminate(III) and hydrogen gas.

Answer:

Explanation:

Mass = 66.6 gram

Density = 0.790 g/mL

Volume = Mass ÷ Density

Volume = 66.6 ÷ 0.790

Volume = 84.30 mL

Answer:

B. summer

Explanation:

The northern hemisphere experiences summer during the months of June, July, and August because it is tilted toward the sun and receives the most direct sunlight.

Answer:

A compound

Explanation:

Chemical compound can be regarded as any substance made up of identical molecules which consists atoms of two or more than two chemical elements. For example four hydrogen atoms bonds with a carbon atom to give methane molecule which is a compound. It should be noted that A compound is a new substance with unique chemical and physical properties formed when two or more elements are chemically bonded during a physical reaction.

Answer:

114.23g

Explanation:

Mass = xg

Mole = 0.334 mol

Molar mass of Sucrose

(C = 12, H = 1, O = 16)

C12H22O11

(12×12)+(1×22)+(16×11)

144 + 22 + 176

342g/mol

Mass = No of mole × Molar mass

Mass = 0.334 × 342

Mass = 114.228

Mass ≈ 114.23g

hope it helps you ❣❣

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Answer:

hello can you follow me

Explanation:

used in fire extinction, blasting rubber, foaming rubber and plastic

Answer:

11 electrons

Explanation:

The number of electrons is the same as the number of protona in a ATOM.

They will most likely be different in a ion, simple bond or a convalent bond.

Answer:

13 branches/tree

Explanation:

Step 1: Given data

Step 2: Calculate the total number of branches (b)

We will use the following expression.

b = l × b/l

b = 19565 leaves × 1 branch/35 leaves = 559 branch

Step 3: Calculate the number of branches per tree (b/t)

We will divide the total number of branches by the total number of trees.

559 branches/43 trees = 13 branches/tree

Explanation:

X = Group 1 metal

Y = Group 7 Non metal

The dots basically signifies the group.

Metal loses electrons and non metal gains electron. The valency of X is 1 and that of Y is 7.

X atom loses one electron and Y atom gains one electron.

The bond that forms between a metal and a non metal is an ionic bond.

Answer:

78.12 L

Explanation:

Given that,

Initial volume, V₁ = 105 L

Initial temperature, T₁ = 20°C = 20+273 = 293 K

New temperature, T₂ = -55 °C = 218 K

We need to find the new volume of the balloon. The relation between the volume and the temperature is given by :

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

Where

V₂ is the new volume

[tex]V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{105\times 218}{293}\\\\V_2=78.12\ L[/tex]

So, the new volume is 78.12 L.

Answer:

the water molecules have more energy and are moving faster than the molecules of cold water. This makes it easier for the dye to get mixed throughout the hot water.

Explanation:

Answer:

Because particles moves more by kinetic energy and diffusion will spread with the particles

Explanation:

Answer:we see 1 side because the other side is not visible

Explanation:

Answer:

Thermal energy comes from heat sources that provide energy from it's temp.

Explanation:

Produced when a rise in temperature causes atoms and molecules to move faster and collide with each other. The energy that comes from the temperature of the heated substance is called thermal energy. 6 min, 47 sec Heat Energy.

(If this doesn't help let me know in the comments, I'll try to explain better :> )

Answer:

Yes, they work in space. I forgot an example, will edit the post when I found it

Hope this helps!

Answer:  [tex][Ni(NH_3)_3Br]Cl[/tex] and [tex][Ni(NH_3)_3Cl]Br[/tex] are ionization isomers.

[tex][Pt(Cl)_2(SCN)_4]^{4-}[/tex] and [tex][Pt(Cl)_2(NCS)_4]^{4-}[/tex] are linkage isomers.

Explanation:

Ionization isomerism occur when a ligand that is bound to the metal center exchanges places with an anion or neutral molecule that was originally outside the coordination complex

Thus [tex][Ni(NH_3)_3Br]Cl[/tex] and [tex][Ni(NH_3)_3Cl]Br[/tex] are ionization isomers.

Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand.

Thus [tex][Pt(Cl)_2(SCN)_4]^{4-}[/tex] and [tex][Pt(Cl)_2(NCS)_4]^{4-}[/tex] are linkage isomers.

Answer:

0.5mol

Explanation:

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Explanation:

I don't really understand the question

Answer:

[tex]\boxed {\boxed {\sf 5.2 *10^{22} \ molecules \ NaCl}}[/tex]

Explanation:

1. Convert grams to moles

First, convert grams to moles using the molar mass. This can be found on the Periodic Table.

Sodium (Na) has an oxidation state of +1 and chlorine (Cl) has an oxidation state of -1, so they combine in a 1:1 ratio for a formula of NaCl. We can simply add their moles masses.

Use this as a ratio.

[tex]\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Multiply by the given number of grams.

[tex]5.0 \ g \ NaCl *\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Flip the fraction so the grams of sodium chloride cancel.

[tex]5.0 \ g \ NaCl *\frac {1 \ mol \ NaCl}{ 58.4397693 \ g \ NaCl}[/tex]

[tex]5.0 *\frac {1 \ mol \ NaCl}{ 58.4397693 }=\frac {5.0 \ mol \ NaCl} { 58.4397693 } = 0.0855581749 \ mol \ NaCl[/tex]

2. Convert moles to molecules

We must use Avogadro's Number. This tells us the amount of particles (molecules, atoms, etc.) in 1 mole of a substance. In this case, it is molecules of sodium chloride.

[tex]\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]

Multiply by the number of moles we calculated.

[tex]0.0855581749 \ mol \ NaCl*\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]

The moles of sodium chloride cancel.

[tex]0.0855581749 *\frac{6.022*10^{23} \ molecules \ NaCl}{1}=5.15231329*10^{22} \ molecules \ NaCl[/tex]

The original measurement of grams has 2 (2 and 0) significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 5 in the hundredth place tells us to round the 1 to a 2.

[tex]5.2 *10^{22} \ molecules \ NaCl[/tex]

Answer: A. 3.28 g of HCl

B. 6.30 g of [tex]HNO_3[/tex]

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} NaOH=\frac{3.65g}{40g/mol}=0.09moles[/tex]

[tex]\text{Moles of} Ca(OH)_2=\frac{3.65g}{74g/mol}=0.05moles[/tex]

a) [tex]HCl(aq)+NaOH(aq)\rightarrow H_2O(l)+NaCl(aq)[/tex]  

According to stoichiometry :

1 mole of [tex]NaOH[/tex] require = 1 mole of [tex]HCl[/tex]

Thus 0.09 moles of [tex]NaOH[/tex] will require=[tex]\frac{1}{1}\times 0.09=0.09moles[/tex]  of [tex]HCl[/tex]

Mass of [tex]HCl=moles\times {\text {Molar mass}}=0.09moles\times 36.5g/mol=3.28g[/tex]

b) [tex]2HNO_3(aq)+Ca(OH)_2(aq)\rightarrow 2H_2O(l)+Ca(NO_3)_2(aq)[/tex]  

According to stoichiometry :

1 mole of [tex]Ca(OH)_2[/tex] require = 2 moles of [tex]HNO_3[/tex]

Thus 0.05 moles of [tex]Ca(OH)_2[/tex] will require=[tex]\frac{2}{1}\times 0.05=0.1moles[/tex]  of [tex]HNO_3[/tex]

Mass of [tex]HNO_3=moles\times {\text {Molar mass}}=0.1moles\times 63g/mol=6.3g[/tex]

Answer:

pH value of HCL = 2.69897

Explanation:

Given:

Concentration of HCL = 0.002 M

Find:

pH value of HCL

Computation:

pH value of HCL = - log(Concentration of HCL)

pH value of HCL = - log(0.002)

pH value of HCL = 2.69897

C. picking a tray in the cafeteria line

Answer:

1072 torr

Explanation:

To answer this problem we can use Gay-Lussac's law, which states:

Now we convert the given temperatures into K:

We input the data:

And solve for P₂:

Answer:

23.92 g

Explanation:

Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

I mole of H2SO4 = 2 moles of NaOH

24.5/82 = 24.5/82 × 2

= 0.598 moles of NaOH will neutralize

Mass= mole× molar mass

Molar mass of NaOH= 23+16+1 = 40g/mol

Mass= 0.598 × 40 = 23.92g of NaOH

Answer:

20g

Explanation:

First of all, you have got your formula wrong. It should be [tex]H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O[/tex].

Start by finding the Relative Formula Mass for sulfuric acid. [tex]H_{2}SO_{4}[/tex] is equal to (2x1)+32+(16x4)=98. You then calculate Mols by doing [tex]Mols=\frac{Mass}{Relative Formula Mass}[/tex]. So, [tex]\frac{24.5}{98} = 0.25[/tex], so the Mols of Sulfuric Acid is 0.25.

The Mol ratio of Sulfuric Acid to Sodium Hydroxide is 1:2, so 0.25:0.5.

Now, you have to find the Relative Formula Mass of Sodium Hydroxide, or [tex]NaOH[/tex]. 23+16+1=40. Finally, multiply 0.5 by 40, and you'll find that the maximum mass is 20g.

Answer:

1.) Eyewash station --> D

2.) Absorbent material --> G

3.) Fire extinguisher --> F

4.) Safety Shower --> E

5.) Biohazard container --> J

6.) Broken glass container --> I

7.) Safety goggles --> C

8.) Lab apron --> H

9.) asbestos gloves --> A

10.) Latex gloves --> B

Explanation:

In an equipped laboratory, alot of safety equipments are made available and kept in area that it could be easily accessed in the laboratory. Safety or protective equipments are those materials that helps protect a laboratory personnel while at work on the lab.

These equipments include:

--> Eyewash station: This is an equipment used in the laboratory during emergency to rinse chemical from the eye. Therefore option D is correct.

--> Absorbent material: They are used to contain small spills in the laboratory. Therefore option G is correct.

--> Fire extinguisher: This equipment is used to put out small fires. Therefore F is correct.

--> Safety Shower: This is used to rinse away chemical from clothes and on skin during emergency. Therefore option E is correct.

--> Biohazard container: This container is used to safely dispose bacteria culture, blood and other living tissues. Therefore option J is correct.

--> Broken glass container: This is used to dispose cracked, chipped or broken bottle in the laboratory. Therefore option I is correct.

--> Safety goggles: This helps to protect the eye from chemical and broken glasses. Therefore option C is correct.

--> Lab apron: This is worn by the laboratory personnel to help protect the skin from chemical and biohazards. Therefore option H is correct.

--> Asbestos gloves: these are heat resistant gloves used to protect the hands from heat. Therefore option A is correct.

--> Latex gloves: these are equally worn by the laboratory personnel to protect the hands from chemicals and biohazards

[tex]Answer :—✔[/tex]