please actually answer the question

Answer:

The rank of the frequencies from largest to smallest is

The largest frequency of oscillation is given by the string in option D

The second largest frequency of oscillation is given by the string in option B

The third largest frequency of oscillation is given by the string in option A

The smallest frequency of oscillation is given by the string in option C

Explanation:

The given parameters are;

The mass per unit length of all string, m/L = Constant

The tension of all the string, T = Constant

The frequency of oscillation, f, of a string is given as follows;

[tex]f = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L}[/tex]

Where;

T = The tension in the string

m = The mass of the string

L = The length of the string

n = The number of overtones

[tex]Therefore, \ {\sqrt{\dfrac{T}{m/L} } } = Constant \ for \ all \ strings = K[/tex]

For the string in option A, the length, L = 27 cm, n = 3 we have;

[tex]f_A = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 27} = \dfrac{2 \times K}{27} \approx 0.07407 \cdot K[/tex]

For the string in option B, the length, L = 30 cm, n = 4 we have;

[tex]f_B = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 30} = \dfrac{ K}{12} \approx 0.08 \overline 3\cdot K[/tex]

For the string in option C, the length, L = 30 cm, n = 3 we have;

[tex]f_C = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 30} = \dfrac{K}{15} \approx 0.0 \overline 6 \cdot K[/tex]

For the string in option D, the length, L = 24 cm, n = 4 we have;

[tex]f_D = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 24} = \dfrac{5 \times K}{48} \approx 0.1041 \overline 6 \cdot K[/tex]

Therefore, we have the rank of the frequency of oscillations of th strings from largest to smallest given as follows;

1 ) [tex]f_D[/tex] 2) [tex]f_B[/tex] 3) [tex]f_A[/tex] 4) [tex]f_C[/tex]

The order of the frequencies is  [tex]f_D>f_B>f_A>f_C[/tex]

The frequency of the standing wave in a string tied at both ends is given by:

[tex]f=\frac{nv}{2L}[/tex]

where n is the mode of frequency

v is the velocity of the wave

and L is the length of the string.

Now the velocity of a wave in a string tied at both ends is given by

[tex]v=\sqrt{\frac{T}{\mu}}[/tex]

where T is the tension and μ is the mass per unit length.

Since T and μ are the same for all the strings, velocity [tex]v[/tex] will be the same for all.

Now to find the mode of frequency we can calculate the number of nodes (including the nodes at the ends) in the given figure and subtract by 1. Nodes are the point where the amplitude of the wave is zero.

[tex]f_A=\frac{3v}{2\times27}=\frac{v}{18}\;s^{-1}\\\\f_B=\frac{4v}{2\times30}=\frac{v}{15}\;s^{-1}\\\\f_C=\frac{3v}{2\times30}=\frac{v}{20}\;s^{-1}\\\\f_D=\frac{4v}{2\times24}= \frac{v}{12}\;s^{-1}[/tex]

Hence, [tex]f_D>f_B>f_A>f_C[/tex]

Learn more about standing waves:

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Answer:

Atmospheric Pressure

Explanation:

Answer:

This is due to a relative decrease in atmospheric pressure in high places.

Explanation:

Given that atmospheric pressure decreases at the higher point or ground, this reduced atmospheric pressure, however, will be unable to contain the Mercury in the barometer tube.

Therefore, at the top of the mountain where the air pressure is low, the barometer reading ultimately goes down.

Hence, the level of mercury falls in a barometer while taking it to a mountain "due to a relative decrease in atmospheric pressure in high places."

Answer:

Originally Answered: What is the unit of measurement of pressure in the atmosphere? The SI derived unit of pressure is the pascal , abbreviated Pa. This is a pressure exerted by a force of 1 newton acting over an area of 1m².

Explanation:

Hope this helps you a lot my boo!

A boy of mass 85 kg is riding a bicycle in a circle with a radius of 7.2 meters, and it takes 6 seconds to make one revolution, then his velocity will be equal to 7.54 m/s.

The movement of an object along the circle's edge which path is always at the tangent to any specific point on the circle is described by tangential velocity.

As a result, tangential velocity is the amount of motion along a circle's edge that may be measured at any given time.

The speed at any location that really is tangent to the rotating wheel is quantified as the tangential velocity in a circular motion. The connection between rotational acceleration and tangential velocity is expressed by the formula. The part of movement along the circle's edge that can be detected at any time is called tangential velocity.

The given data in the question,

Radius, r = 7.2 meters.

Time, t = 6 seconds.

v = 2πr / t

v = 2π(7.2)/6

v = 7.54 m/s.

Therefore, the velocity of the boy is 7.54 m/s.

To know more about tangential velocity:

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Answer:

dark-field microscopy

Explanation:

A darkfield microscope can be regarded as a brightfield microscope with a significant modification to condenser. There is an opaque disk, with a diameter of about 1cm placed in between the illuminator and condenser lens, the disk responsible for the blocking of most of the light from the illuminator, passing through the condenser to objective lens , which will then form hollow cone of light that has its focus on the specimen. Using a darkfield microscope the light that get to the objective is the only refracted or reflected light of structures in the specimen. And the image formed usually display a bright object with a dark background.

It should be noted that darkfield microscope is a type of microscopy works by allowing only light waves that have reflected from or refracted though the sample to enter the lens system.

Answer:

False

Explanation:

i got it right

The statement is false. Because, the place where, it is easy to hear soft voices is acoustically good. Acoustically strong rooms facilitates the sound waves of even soft pitches.

Acoustics is the study of sound waves. Engineers strictly consider the concepts of acoustics to design the auditoriums and theater rooms to filter the sound effects in perfect pitches.

The frequency of a sound wave is called pitch. Thus lower frequency waves are lower pitch and they are termed as soft voices. Soft voices are hard to hear.

However, building where  it is very easy to hear soft voices is acoustically good room. Therefore, the statement is false. The building is good in acoustics suitable for sound effects.

To find more on acoustics, refer here:

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Answer:

it is applicable on all bodies having mass and the bodies Will be governed by the same law

Answer:

(a) the height of the diving board is 22.896 m

(b) the horizontal distance traveled by the girl is 7.02 m

(c) if she had just drop off the board, her time to drop to the water would have been longer.

Explanation:

Given;

initial speed of the girl, u = 3.9 m/s

time to hit the water, t = 1.8 s

(a) the height of the diving board is calculated as;

h = ut + ¹/₂gt²

h = (3.9 x 1.8)  +  ¹/₂ x 9.8 x 1.8²

h = 7.02 + 15.876

h =  22.896 m

(b) the horizontal distance traveled by the girl is calculated as;

X = ut

X = 3.9 x 1.8

X = 7.02 m

(c) if she just drop off the board, then the initial speed will be zero;

h = ut + ¹/₂gt²

h = 0 + ¹/₂gt²

2h = gt²

[tex]t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \ \times\ 22.896 }{9.8} }\\\\t = 2.16 \ s[/tex]

Thus, if she had just dropped off the board, her time to drop to the water would have been longer.

Answer:

The OatMeal

Explanation:

Answer:

C.) The Oatmeal


Since the oatmeal is the hottest it will spread the other substances which will increase the temperature of the milk, spoon, and the surrounding air.

The oatmeal had the most thermal energy out of the four options; the milk was cool, the spoon was at room temperature and the surrounding air was also at room temperature. Therefore, the heat from the oatmeal will travel to those substances and change their thermal energy.

Explanation:

Have a great rest of your day
#TheWizzer

Answer:

is it 3?

Explanation:

Im taking a guess and just dividing 6 and 2

Answer:

5 or 6

Explanation:you

Answer:

The 3rd graph

Explanation:

The graph that says:

Fn = 27 N

Ff= -102 N

Fp= 34 N

Fg= -27 N

Answer:

I'm gonna say it's D

Explanation:

but when u do the experiment on in u head you'll actually find out that it is actually , indeterminable

Answer:

The light enters the box along the normal to the side of the box or perpendicularly to the box's surface

Therefore, the light is expected to travel straight through the box

However, when a rectangular glass prism is placed inside the box, the light can then be refracted to pass through the box in the given path as shown

Light bends towards the normal when passing from a less dense medium to a denser medium with larger refractive index and vice versa

Therefore, when the glass prism with a larger refractive index than air is inclined with the top part further away from the incident beam and the bottom part closer to the incident beam as shown, the refracted ray through the box will be shifted downwards as shown in the drawing created with Microsoft Visio

Explanation:

[tex]Refractive \ index, n = \dfrac{sin(i)}{sin(r)}[/tex]

Where;

i = The angle between the incidence light and the normal line

r = The angle between the refracted light and the normal line

n = The refractive index

When n > 1 is large, we have, ∠i > ∠r and the light is bent towards the normal when moving from a less dense medium to a denser medium and vice versa.

Answer:

748 treats.

Explanation:

If the trainer gives out 34 treats and gave them out for 22 shows, then to find the total you need to multiply 34 by 22, or (a longer but more simple way) add 34, 22 times.

Answer:

d = 1.022 [m]

Explanation:

Work in physics is defined as the product of force by distance. In this way we have the following expression.

[tex]W=F*d[/tex]

where:

W = work done = 180 [J] (units of Joules)

F = force = 176 [N]

d = distance [m]

[tex]d = W/F\\d = 180/176\\d = 1.022 [m][/tex]

Answer:

c) those caused by parasites

Answer:

individuality

Explanation:

since he cannot run with paul he decided to run by himself making his exercise individual

Answer: individuality

Explanation:

(you can ignore this its just the deffintion of  individuality)

This is a crucial principle, the fundamental fact that everyone is different! Everyone responds to training in a different way. If you are walking or cycling with a friend, and doing exactly the same amount of training, don’t be concerned if one of you gets fitter faster than the other – this is what individualisation is all about.

It might be that one of you is having some pressure at work or difficulties at home, but wherever it is, it’s surprising what can affect your training. Some days your training can go really well and the next day, even though it was exactly the same length workout, it can be a nightmare. This is individualisation.

Answer:

3 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

Using the Boyle's law equation, the new volume (i.e final volume) of the Ne gas can be obtained as:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

P₁V₁ = P₂V₂

0.75 × 2 = 0.5 × V₂

1.5 = 0.5 × V₂

Divide both side by 0.5

V₂ = 1.5 / 0.5

V₂ = 3 L

Thus, the new volume of the Ne gas is 3 L

Answer:

In reality, the filament gets so hot it in a real sense bubbles off molecules and electrons. Now and again this material gathers as a dull spot at the highest point of the bulb. Eventually, the filament falls apart, gets frail, and breaks, subsequently finishing the life of the light. Lights radiate light by siphoning an electric flow through a dainty tungsten fiber. The filament warms and emits light. Over the long haul, the filament oxidizes and turns out to be increasingly fragile, until it splits up and the bulb goes out. ... Tungsten picks up obstruction as it warms.

Hope this helped :)

Answer:

displacement: 0

Distance: 30

Explanation:

lol, i asked my brother, he's also in 10th grade

Answer:

Group IA elements have only one valency electron while Group IIA have two valency electrons.

Group IA elements have cations with higher charge density hence polarizing anions easier resulting into covalent character while Group IIA elements have cations with lower charge density hence difficulty in distorting anions resulting into a ionic character. This is due to difference in cationic radii and charges

Answer:

104.59 m

Explanation:

The following data were obtained from the question:

Horizontal velocity (u) = 13 ms¯¹

Horizontal distance (s) = 60 m

Height (h) =?

Next, we shall determine the time taken for the car to get to the ground. This can be obtained as follow:

Horizontal velocity (u) = 13 ms¯¹

Horizontal distance (s) = 60 m

Time (t) =?

s = ut

60 = 13 × t

Divide both side by 13

t = 60 / 13

t = 4.62 s

Finally, we shall determine the height cliff. This can be obtained as follow:

Time (t) = 4.62 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

h = ½gt²

h = ½ × 9.8 × 4.62²

h = 4.9 × 21.3444

h = 104.59 m

Thus, the height of the cliff is 104.59 m

Answer:

1. A.) The moment of the truck before it hits the brakes is 214,400 kg·m/s

B.) The force it takes to stop the truck is approximately 17,290.4 N

Explanation:

1. A.) The given parameters are;

The mass of the truck, m = 8,000 kg

The velocity of the truck when it hits the brakes, u = 26.8 m/s

Momentum = Mass × Velocity

The moment of the truck = The mass of the truck × The velocity of the truck

Therefore;

The moment of the truck before it hits the brakes = 8,000 kg × 26.8 m/s = 214,400 kg·m/s

B.) The amount of momentum lost when the truck comes to a stop = The initial momentum of the truck

The time it takes the truck to come to a complete stop, t = 12.4 s

The deceleration, "a" of the truck is given by the following kinematic equation of motion

v = u - a·t

Where;

v = The final velocity of the truck = 0 m/s

u = The initial velocity = 26.8 m/s

a = the deceleration of the truck

t = The time of deceleration of the truck = 12.4 s

Substituting the known values gives;

0 = 26.8 - a × 12.4

Therefore;

26.8 = a × 12.4

a = 26.8/12.4 ≈ 2.1613

The deceleration (negative acceleration) of the truck, a ≈ 2.1613 m/s²

Force = Mass × Acceleration

The force required to stop the truck = The mass pf the truck × The deceleration (negative acceleration) given to the truck

∴ The force it takes to stop the truck = 8,000 kg × 2.1613 m/s² ≈ 17,290.4 N.

Answer:

1) Periodically check the no stop or NDL time on their computers

2) The dive computer planning mode can be used if available

3) Make use of a dive planning app

4) Check data from the RDP table or an eRDPML

Explanation:

The no stop times information from the computer gives the no-decompression limit (NDL) time allowable which is the time duration a diver theoretically is able to stay at a given depth without a need for a decompression stop

The dive computer plan mode or a downloadable dive planning app are presently the easiest methods of dive planning

The PADI RDP are dive planners based on several years of experience which provide reliable safety limits of depth and time.

Answer:

58.8m

Explanation:

Answer:

cant see to find the answer sorry :( i tried :( good luck !! youll do great <333

Explanation:

sorry ;( best of luck

Answer:

Two moles of aluminum chloride [tex](AlCl_3)[/tex] are produced when six miles of hydrogen Chloride [tex](HCl)[/tex] react with plenty of aluminum

Explanation:

6 Moles of [tex]HCl[/tex] will only react with 2 moles of [tex]Al[/tex] irrespective of the number of moles of each compound present. The reaction wiil take place in this ratio only. The products produced will be 2 moles of [tex]AlCl_3[/tex] and 3 moles of [tex]H_2[/tex] this ratio will also be constant.

So, six moles of hydrogen chloride [tex](HCl)[/tex] will react with plenty of aluminum to produce many 2 moles of aluminum chloride [tex](AlCl_3)[/tex].

Answer:

The work done by picking up 100 20-L bottles and raising it vertically 1 meter is 19614 joules.

Explanation:

By the Work-Energy Theorem, the work needed to raise vertically 100 bottles of water is equal to the gravitational potential energy, units for work and energy are in joules:

[tex]\Delta W = \Delta U_{g}[/tex] (1)

Where:

[tex]\Delta W[/tex] - Work.

[tex]\Delta U_{g}[/tex] - Gravitational potential energy.

The work is equal to the following formula:

[tex]\Delta W = n\cdot \rho \cdot V \cdot g \cdot \Delta h[/tex] (2)

Where:

[tex]n[/tex] - Number of bottles, dimensionless.

[tex]\rho[/tex] - Density of water, measured in kilograms per cubic meter.

[tex]V[/tex] - Volume, measured in cubic meters.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta h[/tex] - Vertical displacement, measured in meters.

If we know that [tex]n = 100[/tex], [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]V = 0.02\,m^{3}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta h = 1\,m[/tex], then the work done is:

[tex]\Delta W = (100)\cdot \left(1000\,\frac{kg}{m^{3}} \right)\cdot (0.02\,m^{3})\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (1\,m)[/tex]

[tex]\Delta W = 19614\,J[/tex]

The work done by picking up 100 20-L bottles and raising it vertically 1 meter is 19614 joules.