Answer:
Every object in space exerts a gravitational pull on every other
explanation : gravity influences the paths taken by everything traveling through space. It is the glue that holds together entire galaxies. It keeps planets in orbit. It can also cause life-destroying asteroids to crash into planets..
A 5.00 cm tall object is placed a distance of 24 cm from a convex lens. If the image is
formed 48 cm from the lens, determine the type and height of the image?
Answer.:
Explanation:
The image is either virtual or real and the height of the image is 10cm.
To find the image type and its height, we need to know about the magnification of convex lens.
What is magnification of an image formed by lens?magnification of an image is the comparison of the image size with respect to that of object.It's the ratio of image height to that of object height.What is the mathematical formula of magnification of image?Mathematically, the magnification of an image isHeight of image/height of object or image distance(V) / object distance(U)
If the magnification is positive, image is virtual and if it's negative, the image is real.What is the magnification, if image distance is 48cm and object distance is 24 cm?Object is placed on the left of the lens and the object distance is taken as negative using sign convention.If the image is also formed on the left, the image distance is taken as negative. Corresponding magnification is -48cm/-24cm = 2. Since, the magnification is positive, so, image is virtual.But, if the image is formed on the right of the lens at 48cm, the image distance is taken as positive. So the magnification is 48cm/(-24)cm = -2. Since, the magnification is negative, so image is real.What is the image height, absolute value of magnification is 2 and object height is 5cm?Magnification = image height / object heightSo, image height = magnification × object height
= 2×5 = 10 cm
Thus, we can conclude that the image is virtual if it's formed on the left of the lens and is real if it's formed on the right of the lens. The height of the image is 10 cm.
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The types of electronic components include diodes, transistors,
and integrated circuits.
TRUE
FALSE
Yep. Those three things are all electronic components.
There are a lot more besides those.
write down two advantages of parallel combination
Answer:
In parallel combination each appliance gets the full voltage.
If one appliance is switched on/of others are not affected.
The parallel circuit divide the current through the appliances.
In a parallel combination it is very easy to connect or disconnect a new appliance without affecting the working of other appliances.
pls mark me as brainlist
Explanation:
Two cells each of EMF 1.5 v and an internal resistance of 2 ohms are connected in parallel. calculate the current flowing when the cells are connected to 1 ohm resistor
Answer:2.30
Explanation:
Please help me with this no wrong answer I am begging you please help me ASAP thanks
Answer: Hope This Helps!
Explanation:
1: The first one is true because, if it was full there would be more weight and you would have to apply more force for it to start moving. But an empty one you don't have to apply so much force to it. (Newtons 2nd Law.)
2: The second one is true because, the skate board has a lot of kinetic energy and when it hits the rocks a collosion occurs where all the enrgy points into the front of the board and the back side lifts of the floor so it flips over the rock.(Newtons 1st Law.)
3: The third one is false because, the road cant push onto the tire the tire can push onto the road though. Additional information: Also the when the tire pushes on the road friction happens and because of the rough surface of the road.(Newtons 3rd Law.)
what was the main cause of the near extinction of the black-footed ferret?
A. Climate change
B. Dwindling prairie dog populations
C. Natural predators
D. For hunters hunted them to extinction
Answer:
b
Explanation:
What is transformation of energy
Answer:
Energy transformation
Explanation:
Energy transformation means the changing of energy from one type to another.
small block with a mass of 0.150 kg is attached to a cord passing through a hole in a frictionless, horizontal surface. The block is originally revolving a distance of 0.5 m from thehole with a seed of 0.9 m/s. The cord is then pulled from below, shortening the radius of the circle in which the block revolves to 0.23 m. a) Explain if the tension force causes the change of angular momentum. b) What is the tension in the cord in the final situation when the block moving in a circle with smaller radius. c) How much work was done by the person who pulled on the cord
Answer:
a. Thus, the tension in the cord causes no change in angular momentum.
b. 0.112 N
c. -0.048 J
Explanation:
a) Explain if the tension force causes the change of angular momentum.
A centripetal force F initially acts on the block to keep at at a radius of 0.5 m and speed of 0.9 m/s.
When the cord is pulled, the tension causes a change in the centripetal force to a new value at a radius of 0.23 m.
But since the force is applied in the radial direction and not perpendicular to the radius, there is no torque applied (since torque τ = rFsinθ and θ = 0 thus τ = rFsin0 = 0)and thus, there is tangential acceleration α (since α = τ/I where I = rotational inertia of block)and thus no change in angular speed ω (since α = Δω/Δt, α = 0 ⇒ Δω/Δt ⇒ Δω = 0).
Since there is a no change in angular speed, there is thus no change in angular momentum.
Thus, the tension in the cord causes no change in angular momentum.
b) What is the tension in the cord in the final situation when the block moving in a circle with smaller radius.
The centripetal force in the cord is equal to the tension at the smaller radius.
We find the angular speed of the block from v = rω where v = initial tangential speed of block at r = 0.5 m = 0.9 m/s and r = 0.5 m.
So, ω = v/r = 0.9 m/s ÷ 0.5 m = 1.8 rad/s
The centripetal force at radius r = 0.23 m is F = mrω² where m = mass of block = 0.150 kg, r = distance = 0.23 m and ω = angular speed = 1.8 rad/s
So, F = 0.150 kg × 0.23 m × (1.8 rad/s)²
F = 0.150 kg × 0.23 m × 3.24 rad²/s²
F = 0.11178 kgmrad²/s²
F ≅ 0.112 N
c) How much work was done by the person who pulled on the cord
From work-kinetic energy principles, the work done by the tension equals the kinetic energy change of the block.
ΔK = W
1/2m(v₂² - v₁²) = W where m = mass of block = 0.150 kg, v₁ = initial speed of block = 0.9 m/s, v₂ = final speed of block distance r = 0.23 m,
Since the tangential speed v ∝ r the radial distance,
v₂/v₁ = r₂/r₁
v₂ = (r₂/r₁)v₁
= 0.23 m × 0.9 m/s ÷ 0.5m
= 0.207 m²/s ÷ 0.5 m
= 0.414 m/s
So, W = 1/2m(v₂² - v₁²)
W = 1/2 × 0.150 kg((0.414 m/s)² - (0.9 m/s)²)
W = 1/2 × 0.150 kg((0.1714 m/s)² - (0.81 m/s)²)
W = 1/2 × 0.150 kg((-0.6386 m²/s²)
W = 1/2 × -0.09579 kgm²/s²)
W = -0.0479 kgm²/s²
W = -0.0479 J
W ≅ -0.048 J
light waves with a frequency of 7.26 x 10^14 HZ lies in the violet region of the visible spectrum. what is the wavelength of this frequency of light?
Answer:
4.13×10⁻⁷ m
Explanation:
Applying
v = λf................... Equation 1
Wherfe v = speed of light, λ = wavelength of light, f = frequency of light.
make λ the subject of the equation
λ = v/f....................... Equation 2
Note: Light is an electromagnetic wave, and all electromagnetic wave moves with thesame speed which is 3×10⁸ m/s.
From the question,
Given: f = 7.26×10¹⁴ Hz
Constant: v = 3×10⁸ m/s
Substitute these values into equation 2
λ = (3×10⁸)/(7.26×10¹⁴)
λ = 4.13×10⁻⁷ m
Which is an example of negative acceleration?
A) a snowboarder who increases speed when traveling downhill
B) a biker who maintains a constant speed through a race
C) a skateboarder who reduces speed when moving up a hill
D) a runner who fluctuates speed by increasing and decreasing speed
Answer:
A) a snowboarder who increases speed when traveling downhill
A snowboarder who increases speed when traveling downhill will have negative acceleration.
What is acceleration ?
Acceleration is described as the rate of change of velocity with time.
[tex]a&=\frac{\Delta v}{\Delta t}[/tex]
Here, as the snowboarder is traveling in negative y direction therefore the final velocity will be great than initial velocity with negative sign. It should be noted that velocity and acceleration are vector quantities i.e. depends upon the direction in which they have been applied.
Also negative acceleration is denoted as the situation when the object moves in the direction that is opposite to its direction of velocity.
In the above situation, the force is being applied to travel downhill(speeding up in the negative direction) in the opposite direction which exemplifies negative acceleration.
Thus, option A is the correct answer.
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What is a disadvantage of using fuses? A.When a fuse burns out, it cannot be used again b.
A fuse shuts off when the current gets too high c. A fuse contains a thin strip of metal that can melt d. A fuse prevents circuits from overheating
At what voltage can a 10 μF capacitor be energized to 0.45 J?
Given :
Capacity of capacitor is, [tex]C = 10\ \mu F[/tex].
To Find :
At what voltage can a 10 μF capacitor be energized to 0.45 J.
Solution :
We know, energy in capacitor is given by :
[tex]E = \dfrac{CV^2}{2}[/tex]
So,
[tex]V = \sqrt{\dfrac{2E}{C}}\\\\V = \sqrt{\dfrac{2\times 0.45}{10}}\ \mu V\\\\V = 0.3 \ \mu V[/tex]
Therefore, voltage required is [tex]0.3 \ \mu V[/tex] .
when there is a constant unbalanced force applied in the opposite direction as the motion what will happen to speed and acceleration
Answer:
speed will be constant and so no acceleration
Explanation:
the body will move toward the weaker force, but since the forces are constant there will be no acceleration.
The acceleration of a motorcycle is given by ax(t)=At-Bt2,A=1.5m/s2,B=0.120m/s2,the motorcycle at rest at t=0 a)Find its position and velocity as function of time b)What maximum velocity it attains
Answer:
(a)
[tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex] --- velocity
[tex]x(t) = \frac{At^3}{6} -\frac{Bt^4}{12} + x(0)[/tex] --- position
(b) The maximum velocity is: 39.0625m/s
Explanation:
Given
[tex]a_x(t) =At -Bt^2[/tex]
[tex]A = 1.5m/s^3[/tex]
[tex]B = 0.120m/s^4[/tex]
Solving (a): The position and velocity as a function
To calculate the change in velocity, we integrate the given acceleration
i.e.
[tex]\int\limits^{v(t)}_{v(0)} {dv} = \int\limits^t_0 {a(t)} \, dt[/tex]
Integrate
[tex]v|\limits^{v(t)}_{v(0)} = \int\limits^t_0 {a(t)} \, dt[/tex]
Substitute v(t) and v(0) for v
[tex]v(t) - v(0) = \int\limits^t_0 {a(t)} \, dt[/tex]
[tex]v(0) = 0[/tex] ---- The initial velocity.
So, we have:
[tex]v(t) - 0 = \int\limits^t_0 {a(t)} \, dt[/tex]
[tex]v(t) = \int\limits^t_0 {a(t)} \, dt[/tex]
Substitute: [tex]a_x(t) =At -Bt^2[/tex]
[tex]v(t) = \int\limits^t_0 {[At -Bt^2]} \, dt[/tex]
Integrate
[tex]v(t) = {\frac{At^2}{2} -\frac{Bt^3}{3}}|\limits^t_0[/tex]
Substitute 0 and t for t
[tex]v(t) = [\frac{At^2}{2} -\frac{Bt^3}{3}] - [\frac{A*0^2}{2} -\frac{B*0^3}{3}][/tex]
[tex]v(t) = [\frac{At^2}{2} -\frac{Bt^3}{3}] - 0[/tex]
[tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex]
To calculate the change in position, we integrate the calculated velocity
i.e.
[tex]\int\limits^{x(t)}_{x(0)} {dx} = \int\limits^t_0 {v(t)} \, dt[/tex]
Integrate
[tex]x(t)|\limits^{x(t)}_{x(0)} = \int\limits^t_0 {v(t)} \, dt[/tex]
Substitute x(t) and x(0) for x(t)
[tex]x(t) - x(0) = \int\limits^t_0 {v(t)} \, dt[/tex]
Substitute: [tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex]
[tex]x(t) - x(0) = \int\limits^t_0 {\frac{At^2}{2} -\frac{Bt^3}{3}} \, dt[/tex]
Integrate
[tex]x(t) - x(0) = \frac{At^3}{6} -\frac{Bt^4}{12}}|\limits^t_0[/tex]
Substitute t and 0 for t
[tex]x(t) - x(0) = [\frac{At^3}{6} -\frac{Bt^4}{12}] - [\frac{A*0^3}{6} -\frac{B*0^4}{12}][/tex]
[tex]x(t) - x(0) = [\frac{At^3}{6} -\frac{Bt^4}{12}] - [0][/tex]
[tex]x(t) - x(0) = \frac{At^3}{6} -\frac{Bt^4}{12}[/tex]
Make x(t) the subject
[tex]x(t) = \frac{At^3}{6} -\frac{Bt^4}{12} + x(0)[/tex]
Where x(0) represents the initial position
Solving (b): The maximum velocity
First, we calculate the time at which it attains the maximum height
Set acceleration to 0
[tex]a_x(t) =At -Bt^2[/tex]
[tex]At - Bt^2 = 0[/tex]
Factorize
[tex]t(A - Bt) = 0[/tex]
Split
[tex]t = 0\ or\ A - Bt = 0[/tex]
t can't be 0.
So, we have:
[tex]A - Bt = 0[/tex]
Solve for t
[tex]-Bt = -A[/tex]
[tex]t = \frac{-A}{-B}[/tex]
[tex]t = \frac{A}{B}[/tex]
Substitute: [tex]A = 1.5m/s^3[/tex] and [tex]B = 0.120m/s^4[/tex]
[tex]t = \frac{1.5m/s^3}{0.120m/s^4}[/tex]
[tex]t = \frac{1.5}{0.120}s[/tex]
[tex]t = 12.5s[/tex]
Substitute [tex]t = 12.5s[/tex] in v(t) to get the maximum velocity
[tex]v(t) = \frac{At^2}{2} -\frac{Bt^3}{3}[/tex]
[tex]v(t) = \frac{A*12.5^2}{2} -\frac{B*12.5^3}{3}[/tex]
[tex]v(t) = \frac{156.25A}{2} -\frac{1953.125B}{3}[/tex]
Substitute: [tex]A = 1.5m/s^3[/tex] and [tex]B = 0.120m/s^4[/tex]
[tex]vmax = (156.25*1.5)/2 -(1953.125*0.120)/3[/tex]
[tex]v_{max} = 117.1875 - 78.125[/tex]
[tex]v_{max} = 39.0625[/tex]
do transistors amplfy a.c or d.c
Explanation:
thet amplify DC, because of the voltage ( small current input signal)
Answer:
Yes,by using direct coupling(transistors) amplifier we will amplify low frequency (DC) signals. A transistor is certainly capable of taking a small-current input signal and controlling a high-current output at the same voltage, thereby amplifying the power of the input signal whether it's AC or DC.
Can you give me brainliest?please?
Someone help me with these questions
Answer:
Im not 100% sure so don't completly rely on these answer s
#1 is B
#2 ia B
#3 is A
#4 is A
#5 is A
and i think #6 is A
im 100% sure that 3 and 4 are A tho
Explanation:
If 230 W of power is produced in 10 seconds, how much work is done?
Answer:
Hello There!!
Explanation:
Use this equation:Work done = Force x Distance.
Work done=230W×10s
Work done=2300J
hope this helps,have a great day!!
~Pinky~
[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]
Work done = force × distance
work done = 230W×10s
work done = 2300J
Thanks hope it helps.How does the digestive system help the muscular system?
A.
The digestive system absorbs the nutrients necessary for the functioning of the muscular system.
B.The digestive system delivers the blood used by the muscular system.
C.
The digestive system exchanges gases used by the muscular system.
D.The digestive system provides structural support to the muscular system.
Answer:
I would say the answer is A... but I'm not so sure ....
Distance and ___ are really the same quantity. A. length b. direction c. speed d. displacement
Answer:
distance and length are the same quantity
You toss a ball at 30 m/s straight upwards. How much time will take the ball to reach the top of its path?
Answer:
Explanation:
One thing we need to remember is that at the max height of parabolic motion, the velocity is 0 (because the object has to stop for a millisecond in the air to turn around and head back down). Use the one-dimensional motion equation
v = v₀ + at and filling in:
0 = 30 + (-9.8)(t) and
-30 = -9.8t so
t = 3 seconds
hello please help i’ll give brainliest
Answer:
B. Large mountain ranges
PLEASE HELP!!
The movement or flow of electrons through a wire is called _____________.
A.Current
B.Voltage
C.Resistance
D .Velocity
Fast cooling rates tends to promote transformations that result in relatively course structures (e.g. for a reaction resulting in multiple product phases, the secondary phase particles are (i) fewer in count (ii) larger in size and (iii) relatively spherical). True or False
For most materials, the formation of a glass from a liquid typically requires extremely slow cooling rates, thereby taking on the order of years or even centuries to produce. True or False
For a system below its melting point, a glass (or non-crystalline / amorphous) configuration is the most energetically stable state that is possible, since it offers the lowest Gibbs free energy for all possible solid configurations. True or False
When measured experimentally, most materials tend to exhibit the same exact temperature value for both melting and freezing (crystallization). True or False
Gray iron is a microstructure that tends to result when a cast iron of appropriate composition is cooled fairly quickly. True or False
Coarsening refers to the scenario where, upon heating and/or annealing for sufficient time, the scale of a microstructure tends to reduce (e.g. grains become smaller, secondary phase particles separate into smaller particles and become more finely dispersed, often reverting to high aspect ratio or high surface-area-to-volume ratio configurations. True or False
Answer:
1) correct answer is ii larger size
2) false, 3) false, 4) true, 5) true, 6) true
Explanation:
In this exercise, the answer is asked if the statement is true.
1) in the rapid cooling speed, there is no thermodynamic equilibrium, so the secondary phases do not have time to transform into the main one, therefore many phases appear in the products,
the correct answer is ii
2) False. The transformation of a material to the glass state requires a fixed temperature and rapid changes to reach this temperature,
3) False. The most stable state is the crystalline state, the glass states are metastable, their Gibbs energy is not the lowest possible and they must transition to the crystalline state over time, it can be years or centuries.
4) True. The melting and freezing temperatures change for each material, within the same material it always has the same value, since it corresponds to a change in the state of the system.
5) true. Cast iron is called gray because of the impurities inside that have not had time to move due to rapid cooling.
6) True. The microstructure is reduced in the process of cooling and heating
is ammonia a substance
Answer:
yes
Explanation:
it is regulated in United States that is non flamable gas
How does energy affect the appearance of light?
Answer:
The bigger the energy source the more light it makes
Answer:
Energy effects light by heat, and radiation. and the depth of it and how big and other things, radiation can change the appearance slightly and heat also.
for example energy can make light, the light bulb in my opinion is electricity turned off and on Etc.
Energy can be made by light also, and other things that are completely complicated. Just look into generators and how they do that and etc.
The height of an object is 10 cm, and the height of its image is 6 cm. What is the magnification?
Question 23 options:
4
16
0.6
1.67
magnification = [tex]\bf\dfrac{height of image}{height of object}[/tex]
= [tex]\bf\dfrac{6cm}{10cm}[/tex]
= 0.6
How much power flows through a circuit with 5 amps and 120 volts?
what are the Properties of Transverse Waves and Longitudinal wave
Answer:
Key terms
TermMeaningTransverse waveOscillations where particles are displaced perpendicular to the wave direction.Longitudinal waveOscillations where particles are displaced parallel to the wave direction
calculate their densties in Si unit.
200mg,0.0004m
Question: calculate their densties in Si unit.
200mg,0.0004m³
Answer:
0.5 kg/m³
Explanation:
Applying,
D = m/V........................ Equation 1
Where D = density, m = mass, V = volume.
From the question,
Given: m = 200 mg = (200/1000000) kg = 2.0×10⁻⁴ kg, V = 0.0004 m³ = 4.0×10⁻⁴ m³
Substitute these values into equation 1
D = (2.0×10⁻⁴ kg)/(4.0×10⁻⁴)
D = 2/4
D = 0.5 kg/m³
Hence the density in S.I unit is 0.5 kg/m³
The fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that Select one: A. they must be in directions where intergalactic absorption by dark matter is minimum, allowing us to see them. B. they must be intrinsically far more luminous than the brightest galaxies. C. they have not been as redshifted by their motion as have galaxies, and hence they can still be seen. D. they must be in directions where gravitational focusing by the masses of nearer galaxies makes them visible from Earth.
Answer:
B. they must be intrinsically far more luminous than the brightest galaxies.
Explanation:
Quasar is famous for being an intergalactic object which is billions of years away from the earth yet can still be seen, unlike the other star body, unlike giant galaxies.
Hence, the fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that "they must be intrinsically far more luminous than the brightest galaxies."
This condition, including other related evidence gotten in recent years concerning our galaxy, has shown that quasars are probably the central nuclei of very distant, very active galaxies.