please help ASAP!!!!!

Answers

Answer 1

The rational function is

[tex]\frac{2x+2}{x^2-1}[/tex]

For calculate vertical asymptote we need to find which value of x make zero the denominator

[tex]\begin{gathered} x^2-1=0 \\ (x+1)(x-1)=0 \\ x=1 \\ x=-1 \end{gathered}[/tex]

And for the numerator

[tex]\begin{gathered} 2x+2 \\ 2(x+1) \\ \end{gathered}[/tex]

The whole expression

[tex]\begin{gathered} \frac{2(x+1)}{(x+1)(x-1)} \\ \frac{2}{(x-1)} \end{gathered}[/tex]

In this case, the vertical asymptote is at -1

Please Help ASAP!!!!!

Related Questions

Please help with question 5.Finish the sequence and find the growth factor

Answers

First term: 8

Last term: 40.5

Growth factor or constant multiplier = 1.5

To solve this problem, we need to find out the factor that each number grows by. Since this is a geometric sequence, we know that multiplication is involved to get from term to term. To find the factor, we can divide any term by the term before it. Doing this, we get:

18/12 = 1.5

To find the first term, we divide 12 by the factor as follows:

12 / 1.5 = 8

To find the last term, we multiply 27 by the factor as follows:

27 * 1.5 = 40.5

three times a certain number plus 6 is equal to twice the number plus 15.what is the number ​

Answers

The value of the number is 9

How to determine the number?

From the question, the statement is given as

Three times a certain number plus 6 is equal to twice the number plus 15

Let the number be x

So, we have the following equation

Three times x + 6 = twice x plus 15

Express the statements as numbers

So, we have

3x + 6 = 2x + 15

Collect the like terms

This gives

3x - 2x = 15 - 6

Evaluate the difference

x = 9

Hence, the number is 9

Read more about word problems at

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Choose the inequality that represents this situation. During a summer afternoon, the water in the tank was used at a rate of 300 gallons per hour. During the winter the rate was less than half that. How many gallons were used in h hours on February 3rd? A f < ½ x (300 x h)B f ≤ ½ x (300 x h)C ½ x f < (300 x h)D f > ½ x (300 x h)

Answers

f < ½ x (300 x h)

f is the number of gallons used

since it was stated that it was less than. we will use the symbol <

If h(x)=|1-7x|, find each value
1. h(1)
2. h(-7)
3. -h(9)
Please and thanks!

Answers

Step-by-step explanation:

1. h(1)=|1-7*1|=|-6|=6;

2. h(-7)=|1-7*(-7)|=|50|=50;

3. -h(9)= -|1-7*9|=-|-62|= -62.

Michael bought a 4pound bag of cat food he fed his cat the same amount of food from from the bags each day as shown in the graph belowWhat is the slope of the graph?

Answers

ANSWER

-1/2

EXPLANATION

The slope of a line passing through the points (x₁, y₁) and (x₂, y₂) is,

[tex]m=\frac{y_1-y_2}{x_1-x_2}[/tex]

In the graph, we can take any two points,

Find the slope using the points (0, 4) and (5, 3/2),

[tex]m=\frac{4-\frac{3}{2}}{0-5}=\frac{\frac{4\cdot2-3}{2}}{-5}=\frac{\frac{8-3}{2}}{-5}=\frac{\frac{5}{2}}{-5}=\frac{5}{-5\cdot2}=-\frac{1}{2}[/tex]

Hence, the slope is -1/2.

State the equation of the graph below * у Х

Answers

If the square box is of 1 squre unit then line passes through point (0,3) and (2,1).

The formula for equation of line passing through two point is,

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Substitute the values in the equation to obtain the equation of line.

[tex]\begin{gathered} y-3=\frac{1-3}{2-0}(x-0) \\ y-3=-2(x) \\ y=-2x+3 \end{gathered}[/tex]

So the equation of line is y=-2x+3.

Write an equivalent unit rate to eating 4 hot dogs in 1/3 of a minute

Answers

To write an equivalent unit rate, we have to divide the number of hot dogs by the number of minutes, as follows:

[tex]\frac{4\text{ hot dogs}}{\frac{1}{3}\text{ minutes}}=3\cdot4\frac{\text{ hot dogs}}{\text{ minute}}=12\frac{\text{ hot dogs}}{\text{ minute}}[/tex]

the numbers from 1 to 12 are written on separate papers folded and shaken. 6 students pick a pair each and adds the number..they sum of the pair of each student is 4,6,13,14,20,21.find the numbers in each pair

Answers

To answer this question, we will have to list the possible combinations for each outcome.

We can'rt have repetitions and we only have integer numbers from 1 to 12.

So, for 4, we would have the possible pairs of 1 and 3 or 2 and 2, but since we don't have repeating numbers, we only can have 1 and 3.

We will need to do this for every number:

[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(1+5),(2+4) \\ 13\colon(1+12),(2+11),(3+10),(4+9),(5+8),(6+7) \\ 14\colon(2+12),(3+11),(4+10),(5+9),(6+8) \\ 20\colon(8+12),(9+11) \\ 21\colon(9+12),(10+11) \end{gathered}[/tex]

Now, the outcome of 4 has onle the possible pair of 1 and 3, so we already know that the first par is 1 and 3.

Since we can't have repetitions, every other pair that has either 1 or 3 can't happen, so:

[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon\cancel{\mleft(1+5\mright)},(2+4) \\ 13\colon\cancel{(1+12)},(2+11),\cancel{\mleft(3+10\mright)},(4+9),(5+8),(6+7) \\ 14\colon(2+12),\cancel{\mleft(3+11\mright)},(4+10),(5+9),(6+8) \\ 20\colon(8+12),(9+11) \\ 21\colon(9+12),(10+11) \end{gathered}[/tex]

Now, the outcome of 6 has only one possible pair: 2 and 4. So, we need to exclude any other pair with either 2 or 4:

[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(2+4) \\ 13\colon\cancel{(1+12)},\cancel{(2+11)},\cancel{\mleft(3+10\mright)},\cancel{\mleft(4+9\mright)},(5+8),(6+7) \\ 14\colon\cancel{\mleft(2+12\mright)},\cancel{\mleft(3+11\mright)},\cancel{\mleft(4+10\mright)},(5+9),(6+8) \\ 20\colon(8+12),(9+11) \\ 21\colon(9+12),(10+11) \end{gathered}[/tex]

Now, notice that if we pick the pair 5 and 8 for the outcome 13, both remaining possbile outcomes for 14 would be impossible, because each has either 5 or 8. This means that the outcome 13 can't be 5 and 8, so it has to be 6 and 7, so we can exclue the other pairs with 6 or 7:

[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(2+4) \\ 13\colon(6+7) \\ 14\colon\cancel{\mleft(2+12\mright)},\cancel{\mleft(3+11\mright)},\cancel{\mleft(4+10\mright)},(5+9),\cancel{\mleft(6+8\mright)} \\ 20\colon(8+12),(9+11) \\ 21\colon(9+12),(10+11) \end{gathered}[/tex]

This makes the only possible pair for 14 to be 5 and 9, so we can exclude the other pairs with either 5 or 9:

[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(2+4) \\ 13\colon(6+7) \\ 14\colon(5+9) \\ 20\colon(8+12),\cancel{\mleft(9+11\mright)} \\ 21\colon\cancel{\mleft(9+12\mright)},(10+11) \end{gathered}[/tex]

And this leave us with only one possible pair for 20 and 21, which is 8 and 12 and 10 and 11, so we have all pairs:

[tex]\begin{gathered} 4\colon(1+3) \\ 6\colon(2+4) \\ 13\colon(6+7) \\ 14\colon(5+9) \\ 20\colon(8+12) \\ 21\colon(10+11) \end{gathered}[/tex]

Below is the graph of y= f (x)Translate it to make it the graph of y= f (x+3)

Answers

Solution:

Given the graph of y=f(x):

The translation 3units left is; y=f(x+3) is shown in the graph below:

Which inequality is true?O A /> 2B. 7 +8 < 11C. 37 > 9D. 21 – 1 < 5SUBMIT

Answers

Verify eact option

Option A

we have

pi/2 > 2

remember that

pi=3.14

so

pi/2=1.57

1.57 > 2 -------> is not true

Option B

we have

pi+8< 11

3.14+8 < 11

11.14 < 11 ------> is not true

Option C

we have

3pi > 9

3(3.14) > 9

9.42 > 9 -------> is true

Option D

we have

2pi-1 < 5

2(3.14)-1 < 5

5,28 < 5 ------> is not true

Determine the range using interval notation f(x)= -1/2x-3 for the domain (-4,2]

Answers

We have the following:

[tex]\begin{gathered} f(x)=-\frac{1}{2}x-3 \\ \end{gathered}[/tex]

the domain is the input values and the range the output values, therefore:

[tex]\begin{gathered} f(-4)=-\frac{1}{2}\cdot-4-3=2-3=-1 \\ f(2)=-\frac{1}{2}\cdot2-3=-1-3=-4 \end{gathered}[/tex]

now, the range is:

[tex]\lbrack-4,1)[/tex]

The answer is the option 2

what is the polar form of the parametric equations x=4t and y=t^2

Answers

Answer:

Given that,

The parametric equations x=4t and y=t^2

To find the polar form of the parametric equations

Explanation:

we know that,

The polar form of the equation is expressed in terms of r and theta,

The conversion of Cartesian co-ordinate to Polar co-ordinate is given by,

[tex]\begin{gathered} r^2=x^2+y^2 \\ \\ \tan\theta=\frac{y}{x} \end{gathered}[/tex]

Using this we get,

[tex]r^2=(4t)^2+(t^2)^2[/tex]

[tex]r^2=16t^2+t^4[/tex][tex]r=\sqrt{16t^2+t^4}[/tex]

we have that,

[tex]\tan\theta=\frac{t}{4}[/tex][tex]t=4\tan\theta[/tex]

Substitute this we get,

[tex]r=\sqrt{16t^2+t^4}[/tex][tex]undefined[/tex]

Alanah is picking up two friends to go to a concert. She drives from her house to pick up Mia, then she drives to pick up Teresa, and then they go to the arena to see the concert. The grid shows the coordinates of their houses on a map. All distances are in miles. 16 12 10 1 8 Alanah 6 Arena 2 Teresa 2. 8 10 12 14 16 Answer the questions to find the total distance of Alanah's trip to the arena. When necessary, round answers to the nearest tenth. 1. Find the distance from Alanah's house to Mia's house. Show your work.

Answers

We are going to use the idea of Pythagorean Theorem t

Aiman is 4 times as old as Sakeenah. Sakeenah is 2 times as old as Ahmad. Aiman is 14 years older than Ahmad. What is their total age? Answer years old

Answers

Let:

x = Aiman age

y = Sakeenah age

z = Ahmad age

Aiman is 4 times as old as Sakeenah, so:

[tex]x=4y_{\text{ }}(1)[/tex]

Sakeenah is 2 times as old as Ahmad:

[tex]z=2y_{\text{ }}(2)[/tex]

Aiman is 14 years older than Ahmad:

[tex]z=x-14_{}(3)[/tex]

Replace (2) and (1) into (3):

[tex]\begin{gathered} 2y=4y-14 \\ 2y=14 \\ y=\frac{14}{2} \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} z=2(7) \\ z=14 \end{gathered}[/tex][tex]\begin{gathered} x=4(7) \\ x=28 \end{gathered}[/tex]

So, their total age is:

[tex]x+y+z=28+7+14=49[/tex]

Answer:

49

Jack had a box Good and plenty candy. The ratio of pink to white candy's was 5:7 If Jack buys a bigger bag of candy with the same pink to white ratio and a total of 120 candies, how many candy's are white?

Answers

[tex]\begin{gathered} \text{Ratio of pink to white is 5:7} \\ \text{Total Ratio=5+7=12} \\ \text{Total candies=120} \end{gathered}[/tex]

Thus, the number of white candies are:

[tex]\begin{gathered} \frac{7}{12}\times120 \\ 7\times10=70\text{ candies} \end{gathered}[/tex]

Hence, there are 70 white candies in the bigger bag

Which of the following is the inverse of f(x) = - 19x + 13?OA.− 19 (x − 13)f¹(x) =OB. f¹(x) = 19 (x − 13)-OC. f-¹(x) = 130219OD. f¹(x) = x+1319

Answers

Step 1

Given;

Step 2

[tex]\begin{gathered} y=f(x) \\ Thus, \\ y=-19x+13 \\ \mathrm{A\:function\:g\:is\:the\:inverse\:of\:function\:f\:if\:for}\:y=f\left(x\right),\:\:x=g\left(y\right)\: \\ replace\text{ y with x and x with y} \\ x=-19y+13 \end{gathered}[/tex]

Solve for y

[tex]\begin{gathered} 19y=13-x \\ \frac{19y}{19}=\frac{13-x}{19} \\ y=\frac{13-x}{19} \\ f^{-1}(x)=\frac{13-x}{19} \end{gathered}[/tex]

Answer; Option C

[tex]f^{-1}(x)=\frac{13-x}{19}[/tex]

Write the fraction as a percent. Round to the nearest tenth of a percent if necessary.7/11A) 63.6%B) 57.8%C) 6.4%D) 110%

Answers

To express a fraction as a percent, divide the numerator by the denominator, then multiply by 100.

7 / 11 = 0.636

0.636 x 100 = 63.6 %

Answer:

A) 63.6 %

Given the residual plot below, which of the following statements is correct?Residual Plot10.5Residuals0010-0.5VariableA. There is a pattern, so the data is linear.aB. There is not a pattern, so the data is linear.Ο Ο Ο ΟC. There is not a pattern, so the data is non-linear.D. There is a pattern, so the data is non-linear.

Answers

From the graph we notice that there are no pattern; when this happens we can't use a linear model to fit the data.

Therefore, there is not a pattern so the data is non-linear and the answer is C.

an octopus weighs 586 kilograms after 2 weeks away was increased by 3 out of 10 campgrounds afterwards they lost 105 kilograms in weight idealistic what is the current weight

Answers

Corrina, this is the solution:

• Initial weight of the octopus = 5/6 kg

,

• Weight the octopus gained in two weeks = 3/10 kg

,

• Weight lost because of the sickness = 1/5 kg

In consequence, the current weight is:

5/6 + 3/10 - 1/5

Least commond denominator = 30

(25 + 9 - 6)/30 = 28/30

Simplifying:

• 14/15 kilograms is the current weight of the octopus

Identify the rational function whose graph is given below. The y-intercept is (0,−1/2).

Answers

The numerator relates to the x-intercepts:

    (-1,0) means (x+1) is a factor in the numerator.

The denominator relates to the vertical intercepts:

   x = -2 as a VA means (x+2) is a factor in the denominator.

   x = 1 as a VA means (x-1) is a factor in the denominator.

Since the x-intercept crosses and the VA's are "one up, one down", we know these all have odd multiplicities.

So, we think the function could be [tex]r(x) = \dfrac{x+1}{(x+2)(x-1)}[/tex]

Checking the y-intercept with this function
      [tex]r(0)= \dfrac{0+1}{(0+2)(0-1)} = \dfrac{1}{-2}=-\dfrac{1}{2}[/tex]

This checks out.  That's your function: [tex]r(x) = \dfrac{x+1}{(x+2)(x-1)}[/tex]

A farm has 5 brown cows and 10 white cows. A fence is open and a cow escapes. What is the probobility that it will be a brown cow? A. 50%B.1/2C.33%D.20%

Answers

A farm has 5 brown cows and 10 white cows

Total of cows:

[tex]5+10=15[/tex]

Probability is represented by:

[tex]P=\frac{NU\text{MBER OF FAVOURABLE OUTCOMES}}{\text{TOTAL NUMBER OF FAVOURABLE OUTCOMES}}[/tex]

So, the probability of a brown cow escapes:

[tex]\begin{gathered} P=\frac{5}{15}=0.33\text{ (decimal form)} \\ P=0.33\cdot100=33\text{ percent} \end{gathered}[/tex]

2. The weight of a paper clip is about 0.0009 grams . Write this number in Scientific notation *(2 points)O A. 9 x 10-3B. 9 x 104C. 9 x 10-4D. 9 x 104

Answers

Note that we can "get rid of" the point (in 0.0009) if we move it four spaces (numbers) to the right. These four spaces amount to the exponent in the Scientific notation. For we're moving to the right, the exponent must be negative. The answer is

[tex]9\times10^{-4}[/tex]

C.

Shane made a scale drawing of a hotel. A room in the hotel, which is 18 feet wide in real life, is 51 inches wide in the drawing. What is the scale of the drawing?17 inches :____Feet

Answers

We know that 18 feet in real life are 51 inches in the drawing. And we must find hoy many feet are 17 inches

We can write the next equation for the situation

[tex]\frac{18\text{feet}}{51\text{inches}}=\frac{\text{x }}{17\text{ inches}}[/tex]

Then, we must solve it for x

[tex]x=\frac{18\text{ feet }\cdot17\text{ inches}}{51\text{ inches}}=6\text{ feet}[/tex]

Finally, the answer is

17 inches : 6 Feet

Can someone pls help me with question 10 out of 10 I’m in desperate need and crying

Answers

Answer:

[tex]\begin{gathered} \text{ A. The range for this function is the set }\lbrace3\rbrace\text{.} \\ D\text{. The domain for this function is all real numbers.} \\ \text{ E. All real numbers are in the range of this function.} \end{gathered}[/tex]

Step-by-step explanation:

To be considered as a function, every x-value has just only one image or y-value.

The domain of a function is the set of x-values that the function can take and the range is the set of y-values that the function can take.

Therefore, for the given horizontal linear function:

[tex]\begin{gathered} \text{ A. The range for this function is the set }\lbrace3\rbrace\text{.} \\ D\text{. The domain for this function is all real numbers.} \\ \text{ E. All real numbers are in the range of this function.} \end{gathered}[/tex]

OOnly question 4For questions 1 – 5, answer the questions about triangles.**When answers are not a whole number, please write the exact answer (radical form) AND a decimal approximation**

Answers

SOLUTION:

Case: Trigonometry

Method:

Step 1: Start with the diagram

From te diagram above, theline representing the altitude sis a perpendicular bisector.

We will aply Pythagoras' therrem to solve the problem ioffindin g 'h'

Step 2:

[tex]\begin{gathered} 11^2+h^2=22^2 \\ 121+h^2=484 \\ h^2=484-121 \\ h^2=363 \\ h=\sqrt{363} \\ h=\sqrt{121\times3} \\ h=11\sqrt{3}(exact\text{ }value) \\ h=19.05(2\text{ }decimal\text{ }places) \end{gathered}[/tex]

Final answer:

[tex]\begin{gathered} h=11\sqrt{3}(exact\text{ }value) \\ h=19.05(2\text{ }dp) \end{gathered}[/tex]

Solve equation: 2x^2-50=0

Answers

Given:

[tex]2x^2-50=0[/tex]

To solve for x:

[tex]\begin{gathered} 2x^2-50=0 \\ 2x^2=50 \\ x^2=25 \\ x=\pm5 \end{gathered}[/tex]

Hence, the solution is x=-5, 5.

Answer:

[tex]x=[/tex] ± [tex]5[/tex]

Step-by-step explanation:

[tex]2x^{2} -50=0[/tex]

[tex]2x^{2} =50[/tex]

[tex]x^{2} =\frac{50}{2}[/tex]

[tex]x^{2} =25[/tex]

[tex]x=\sqrt{25}[/tex]

[tex]x=[/tex] ± [tex]5[/tex]

There are 2 solutions for x: 5 positive and 5 negative. If you square them they result in 25

Hope this helps

Find the lengths of the missing sides in the following shapes

Answers

Given:

Base of the triangle = 5 cm

Let's find the altitude of the triangle x.

Let's first solve for each base of the triangle:

[tex]\frac{5}{2}=2.5\operatorname{cm}[/tex]

Here, we have an equilateral triangle.

This means the length of each side of the big triangle is 5 cm.

To find the length of x, apply Pythagorean Theorem:

[tex]c^2=a^2+b^2[/tex]

Where:

a = 2.5 cm

c = 5 cm

Let's solve for b.

Rewrite the equation for b:

[tex]\begin{gathered} b=\sqrt[]{c^2-a^2} \\ \\ b=\sqrt[]{5^2-2.5^2} \\ \\ b=\sqrt[]{25-6.25} \\ \\ b=\sqrt[]{18.75} \\ \\ b=4.3 \end{gathered}[/tex]

Therefore, the length of x is 4.3 cm

ANSWER:

x = 4.3 cm

Solve for x. Using that value, find the measurement of

Answers

Given: Four corners of a perpendicular intersection

[tex]\begin{gathered} m\angle ABE=(6x+2)^0 \\ m\angle DBE=40^0 \end{gathered}[/tex]

To Determine: The value of x and the measure of angle m∠ABE

From the given diagram, it can be seen that m∠ABE and m∠DBE are in one of the four corners of the perpendicular intersection.

Also note that all four corners of a perpendicular intersection is a right angle. Therefore:

[tex]\begin{gathered} m\angle ABE+m\angle DBE=90^0 \\ 6x+2^0+40^0=90^0_{} \\ 6x+42^0=90^0 \\ 6x=90^0-42^0 \\ 6x=48^0 \\ x=\frac{48^0}{6} \\ x=8^0 \end{gathered}[/tex][tex]\begin{gathered} m\angle ABE=6x+2 \\ m\angle ABE=6(8)+2 \\ m\angle ABE=48+2 \\ m\angle ABE=50^0 \end{gathered}[/tex]

Hence:

x = 8⁰

m∠ABE = 50⁰

Explain how the Quotient of Powers Property was used to simplify this expression. 5 to the fourth power, over 25 = 52By simplifying 25 to 52 to make both powers base five and subtracting the exponentsBy simplifying 25 to 52 to make both powers base five and adding the exponentsBy finding the quotient of the bases to be one fifth and cancelling common factorsBy finding the quotient of the bases to be one fifth and simplifying the expression

Answers

We need to know how the given expression was simplified.

"5 to the fourth power, over 25 = 52":

[tex]\frac{5^4}{25}[/tex]

First, we need to convert 25 into a number with power

5²= 25

Then:

[tex]\frac{5^4}{5^2}[/tex]

Simplify by subtracting exponents:

[tex]\frac{5^{4}}{5^{2}}=5^4\ast5^2=5^{4-2}=5^2[/tex]

Hence, we used the first option method.

The correct answer is the first one.

This is one practice problem that I need help on It asks to solve logarithmic equations, and It includes a question within it. Please note that this is a lengthy problem. & I have enlarged the equations for better view.

Answers

The Solution:

We are required to solve each of the following logarithmic equations:

a.

[tex]\begin{gathered} 1.\text{ }\log _464=m \\ \text{cross multiplying, we get} \\ 64=4^m \\ 4^3=4^m \\ m=3 \end{gathered}[/tex][tex]\begin{gathered} 2.\text{ }\log _8n=3 \\ \text{Cross multiplying, we get} \\ n=8^3=512 \end{gathered}[/tex][tex]\begin{gathered} 3.\text{ }\log _p4096=3 \\ \text{Cross multiplying, we get} \\ 4096=p^3 \\ \text{ Equalising the base in both sides, we get} \\ 16^3=p^3 \\ 16=p \\ p=16 \end{gathered}[/tex]

[tex]\begin{gathered} 4.\text{ }\log _{32}q=3 \\ \text{cross multiplying, we get} \\ q=32^3=32\times32\times32=32768 \end{gathered}[/tex]

b.

Given the equation below:

[tex]\log _{4^x}2^a=3[/tex]

We are required to express a in terms of x.

[tex]\begin{gathered} \log _{4^x}2^a=3 \\ \text{Cross multiplying, we get} \\ 2^a=(4^x)^3 \\ \text{Equalizing the base, we get} \\ 2^a=(2^{2x})^3 \\ 2^a=2^{6x} \\ a=6x \end{gathered}[/tex]

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a class rolled number cubes. their results are shown in the table. what is the experimental probability of rolling number 1? round your answer to the nearest tenth. factorizar 4y^2= -16y If three tacos and two drinks cost $13.00, and four tacos and one drink costs $15.25, how much does a taco cost? gains and losses that are notam and frequent are reported as Solve y3 = 8. Please help im desperate 3.3125 as converted to a precent solve for v9= 5v+27+4v Carpenter 4-U charges a consultation fee of $50. Once he starts a job, he charges $45 an hour. Part A Give a linear equation to represent the cost y of hiring Carpenter 4-U for x hours. Part B What is the slope of this equation? What is the y-intercept of this equation?1 Give a linear equation to represent the cost of y hiring carpenter-4u for x hours 2 what is the slope of the equation 3 what is the y intercept in this equation 4 Determine the cost of having the -4u remodel a basement if it takes him 20 hours 1. Describe how cellular respiration and photosynthesis are like two sides of the same coin? Was wondering if you can solve this so I can work off it Summarize evidence that bonds are broken and new bonds are formed during the Krebs cycle. How do changes in light wavelengths support the most widely accepted ideas about the universe?A. Galaxies are moving away from Earth, as shown by the shift of their light toward the blue end of the spectrum.B. Galaxies are moving toward Earth, as shown by the shift of their light toward the blue end of the spectrum.C. Galaxies are moving toward Earth, as shown by the shift of their light toward the red end of the spectrum.D. Galaxies are moving away from Earth, as shown by the shift of their light toward the red end of the spectrum. A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8 m/s at a -47.0 angle. Whatis the x-component of the ball'sfinal velocity?X-component (m/s) How do hydrogen bonds contribute to body temperature regulation? 10Determine whether each statement is true or false. If it is false, explain why.(a) Part AIf a quadrilateral is a kite, then it has two pairs of adjacent, congruent sides. I am afraid we won't be able to the airportin time.There is --petrol left. Two identical balls are at rest side by side at the bottom of a hill. Some time after ball A is kicked up the hill, ball B is given a kick up the hill. Ball A is headed downhill when it passes ball B headed up the hill. At the instant when ball A passes ball B 2x+5 greater than or equal to -1 As a student you are able to earn extra money by assisting your neighbors with odd jobs. If you charge 10.25 broken over an hour for your assistant, about how many hours would you need to work to earn $8,425? Megan Hughes deposits $3,500 in an account that pays simple interest. When she withdraws her money 6 months later, she receives $3,692.50. What rate of interest did the account pay? Round to the nearest whole percentOA 13% per yearOB 10% per yearOC 12% per yearOD 115 per year