PLEASE HELP ASAP ITS DUE SOON

Lines R and S are parallel Find the value of x, then find the measure of m<1 and m<2.
m<1=(70-2x)"
m<2 = (82-3x)
x=
m<1=
m<2=


m<1 and m<2 are corresponding angle​

Answer:

it is 16 to 32

Step-by-step explanation:

if you divided 16 by 8 and 32 by eighth you get 2:4

Answer:

7 + 9x

Step-by-step explanation:

add 5 and 2 and 9x doesn't have a like term so it stays the same

Answer:

9x + 7

Step-by-step explanation:

Like terms are terms that have the same variables and powers. Here, for 9x, there is no other term that is multiplied by x. So, the only terms we can combine is 2 and 5 which leaves us with 9x+7.

Answer:

x = 37

Step-by-step explanation:

4x + 3 + x - 8 = 180

4x + x - 8 + 3 = 180

5x - 5 = 180

5x = 185

x = 37

Hope this helps!

Answer:

3/2

Step-by-step explanation:

3x - 2y = 18

y=(3/2)x-9

Slope of the given line=3/2

As parallel lines have same slope, slope of the line parallel to the line 3x - 2y = 18 is 3/2.

Hope it helps :)

Slope of a line parallel to the line whose equation is 3x - 2y = 18 is 3/2.

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

Two lines are said to be parallel when their slopes are same.

To find the slope of parallel line, we need to find slope of 3x - 2y = 18

3x-2y=18

-2y=18-3x

y=-18/2+3/2x

y=3/2x-18/2

Slope of line is 3/2

Hence, slope of a line parallel to the line whose equation is 3x - 2y = 18 is 3/2.

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Answer:

0

Step-by-step explanation:

A horizontal line has a slope of zero and a vertical line has an undefined slope

Answer:

1.24

Step-by-step explanation:

Answer:

Between x = 48 and x = 45.

Step-by-step explanation:

Average rate of change of a function in the given interval is represented by,

Average rate of change = [tex]\frac{\triangle y}{\triangle x}[/tex]

From the table attached,

Average rate of change of the function between x = 3 and x = 9

= [tex]\frac{16-7}{9-3}[/tex]

= 3

Average rate of change in the interval x = 9 and x = 22

= [tex]\frac{32-16}{22-9}[/tex]

= [tex]\frac{16}{13}[/tex]

= 1.23

Average rate of change in the interval x = 9 and x = 22,

= [tex]\frac{45-32}{45-22}[/tex]

= [tex]\frac{13}{23}[/tex]

= 0.57

Average rate of change in the interval x = 45 and x = 48,

= [tex]\frac{63-45}{48-45}[/tex]

= 6

Therefore, average rate of change is maximum between x = 45 and 48.

Option given in bottom right will be the answer.

It a bc i said so hahahahaha

Answer:

5.89 g/cm³

Step-by-step explanation:

givens,

Mass = 22.4 g

volume = 3.8 cm³

Density = mass / volume

= 22.4 / 3.8

= 5.89 g/cm³

The density with a volume of 3.8 cm³ and a mass of 22.4 g is 5.89 g / cm³.

Given,

The volume of a mineral = 3.8 cm3

And the mass of the mineral = 22.4 g

We need to find the density.

It is the ratio of mass and volume.

Density = mass / volume

Find the density.

Volume = 3.8 cm³

Mass = 22.4 g

Density

= Mass / Volume

= 22.4 / 3.8

= 5.89 g / cm³

Thus the density with a volume of 3.8 cm³ and a mass of 22.4 g is

5.89 g / cm³.

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Answer:

The answer is going to be option 1.

Step-by-step explanation:

The answer you get from multiply an number by itself is a perfect square.

Answer:

8×8 =8^2=64 (perfect square)

Step-by-step explanation:

64 is a perfect square because 8^2 =8×8 =64

Answer:

The correct option is  

Option A and Option C

Step-by-step explanation:

From the question we are told that

   The sample size of paired men is  [tex]n_p   =  11[/tex]

   The test statistics is  t≈1.971

    The  significance level is  α=0.05

    The rejection region is  t<−2.228 and t>2.228

    The null hypothesis is  [tex]H_o :\mu_ d=0[/tex]

     The alternative hypothesis  is  [tex]H_a :\mu_ d \ne 0[/tex]

Generally the degree of freedom is mathematically represented as

        [tex]df  =  n_1 +  n_2 - 2[/tex]

Here [tex]n_1[/tex] is the sample size of  father which is  [tex]n_1 =  11[/tex]

        [tex]n_2[/tex] is the sample size of males who are at least 18 years old  which is  [tex]n_2 =  11[/tex]

So

     [tex]df  =  11 +  11 - 2[/tex]

=>   [tex]df  =  20[/tex]

Generally the critical values of  α=0.05 from the  t- distribution table at a degree of freedom of  [tex]df  =  20[/tex]  for a two -tailed test  is  

     [tex]t_{0.05 , 20 } =  \pm 2.08596345  [/tex]

From the value  obtained we see that the critical value  is within the region of rejection hence

 The decision rule is

Reject the null hypothesis

The conclusion is  

  The conclusion of the hypothesis test is that there is sufficient evidence to suggest that the heights of males between generations are different.

Answer:3rd one

Step-by-step explanation:

Answer:

sumthing that we hate doing

Step-by-step explanation:ughhhhhhhhhh

Complete Question

Researchers investigated whether the proportion of American teenagers with some level of hearing loss was different in 2005–2006 than in 1988–1994. They collected data on random samples of American teenagers in those two time periods. Let the symbol [tex]\pi __{05-06}}[/tex] denote the population proportion of American teenagers with some level of hearing loss in 2005–2006 and similarly for [tex]\pi__{{88-94}}[/tex]. A 95% confidence interval for the parameter [tex]\pi__{{05-06}} }- \pi__{{88-94}}[/tex] turns out to be (0.0015, 0.0467).

Required:

What is an appropriate conclusion to draw?

Answer:

The appropriate conclusion is  

The sample data provide little evidence to doubt that the proportion of American teenagers with hearing loss was the same in 1988-1994 as in 2005-2006

Step-by-step explanation:

Generally the appropriate conclusion is

The sample data provide little evidence to doubt that the proportion of American teenagers with hearing loss was the same in 1988-1994 as in 2005-2006.

This because the confidence intervals are very close to zero , i.e both the upper limit and the lower limit are close to zero  and if we are take 0.05 as our level of significance we see that the both values of the confidence level are small to be significant

9514 1404 393

Answer:

Step-by-step explanation:

The audience per dollar is ...

  Newspaper: 1000/$200 = 5/$

  Radio: 800/$100 = 8/$

  TV: 14000/$800 = 17.5/$

So, TV gives the greatest exposure. As much of the budget as possible should be spent on TV ads. That amount is the lesser of $6000 and ...

  (7 ads)($800/ad) = $5600

With $5600 spent on TV ads, the remaining advertising budget is ...

  $6000 -5600 = $400

The next most cost-effective medium is radio. The remaining $400 budget allows for ...

  $400/($100/ad) = 4 ads

__

To maximize exposure, the advertising budget should be spent this way:

Answer:

More formally, statistical power is the probability of finding a statistically significant result, given that there really is a difference (or effect) in the population. ... So, larger sample sizes give more reliable results with greater precision and power, but they also cost more time and money.

Answer:

[tex](-5,\frac{1}{2} )[/tex]

Step-by-step explanation:

Midpoint Formula: [tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )[/tex]

Simply plug in your coordinates into the midpoint formula to find midpoint:

R(-2, 3)

S(-8, -2)

[tex](\frac{-2+-8}{2},\frac{3+-2}{2} )[/tex]

[tex](\frac{-10}{2},\frac{1}{2} )[/tex]

[tex](-5,\frac{1}{2} )[/tex]

Answer:

x=½, -2

x= 0.5, -2

possibly im not perfect

Answer:

LOL UGH THAT KEEPS HAPPENING TO ME

Step-by-step explanation:

Answer:

try reloading the page or check your internet

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

they are not equivalent

The required simplified product is 3/2.

Given that fractions  3/8 ÷ 1/4.

To divide two fractions by multiplying the first fraction with the reciprocal of the second fraction.

Let a, b, c and d be any real numbers. Consider a/b ÷ c/d that gives

[tex]\frac{a}{b}[/tex]  ÷  [tex]\frac{c}{d}[/tex] = [tex]\frac{a}{b}[/tex] ×  [tex]\frac{c}{d}[/tex].

That implies, [tex]\frac{3}{4}[/tex]  ÷  [tex]\frac{1}{4}[/tex] = [tex]\frac{3}{8}[/tex] ×  [tex]\frac{4}{1}[/tex] = [tex]\frac{3}{2}[/tex].

Hence, the required simplified product is 3/2.

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Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 [tex]\mu_{\hat p}= p[/tex]

The standard deviation of this sampling distribution of sample proportion is:

 [tex]\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}[/tex]

(a)

The sample selected is of size n = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

[tex]\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204[/tex]

So, the sampling distribution of sample proportion is [tex]\hat p\sim N(0.75,0.0204^{2})[/tex].

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

[tex]P(p-0.04<\hat p<p+0.04)=P(\frac{-0.04}{0.0204}<\frac{\hat p-p}{\sigma_{\hat p}}<\frac{0.04}{0.0204})[/tex]

                                          [tex]=P(-1.96<Z<196)\\=P(Z<1.96)-P(Z<-1.96)\\=0.975-0.025\\=0.95[/tex]

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size n = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

[tex]\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306[/tex]

So, the sampling distribution of sample proportion is [tex]\hat p\sim N(0.75,0.0306^{2})[/tex].

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

[tex]P(p-0.04<\hat p<p+0.04)=P(\frac{-0.04}{0.0306}<\frac{\hat p-p}{\sigma_{\hat p}}<\frac{0.04}{0.0306})[/tex]

                                          [tex]=P(-1.31<Z<196)\\=P(Z<1.31)-P(Z<-1.96)\\=0.9049-0.0951\\=0.8098\\\approx 0.81[/tex]

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.