Answer:
B - Velocity
Explanation:
Velocity definition: “The speed of something in a given direction.”
A 2.00-kg ball is moving at 2.20 m/s toward the right. It collides elastically with a 4.00-kg ball that is initially at rest. 1) Calculate the final velocity of the 2.00-kg ball. (Express your answer to three significant figures.)
Answer:
The final velocity of the 2kg ball is 1.270 m/s
Explanation:
According to Newton's second and third laws of motion
Newton's second law state that "the rate of change of momentum is proportional to the applied force and takes place in the direction of that force".
Newton's third law state that "for every action, there must be an equal and opposite reaction".
The combinations of these two laws resulted in an elastic collision
Given that:
m1 = 2kg
u1 = 2.20m/s
m2 = 4.00kg
u2 = 0m/s
An Elastic collision is when kinetic energy before = kinetic energy after
E.K before = [tex]1/2mv^{2}[/tex]
E.K before = 1/2 * 2 * (2.20)^2
E.K = 1/2 * 2 * 4.84
E.K before = 4.84j
E.K after = 1/2 x (4 + 2)v^2
E.K after = 1/2(6v^2)
E.K after = 3v^2
Since E.K before = E.K after
4.84 = 3v^2
Divide through by 3
4.84/3 = 3v^2/3
1.6133 = v^2
[tex]V = \sqrt{1.6133} \\V = 1.270 m/s[/tex]
a toy of mass 600 is whirled by a child in a horizontal circle using a string of length 2m with a linear speed of 5 m/s determine the angular velocity of the toy?
Explanation:
angular velocity = velocity/radius
= 5/2
= 2.5 rad/s
The only way that heat can travel through outer space is ______
convection
radiation
conduction
none of the above
plssssssssssss answer correctly
1. A silicon BJT is connected as shown in Fig 1, where RC = 3.6 k 2. VBE = 0.8 V. (10%)
(a) Predict Ic and specify Rp to establish Vce at 5 V.(5%)
(b) The BJT is said to be in forward-reverse bias. Explain what is meant by this. (5%)
Answer:
The circuit is missing attached below is the required circuit
answer :
a) Ic = 1.944 mA
Rp = 288.66 kΩ
b) The Emitter-base Junction of the BJT is forward biased while its collector-base junction is reverse biased
Explanation:
Rc = 3.6 kΩ
VBE = 0.8 v
1) predict Ic and specify Rp to establish Vce at 5 V
we will apply Kirchhoff's voltage law to resolve this
solution attached below
b ) The BJT is said to be in Forward reverse bias because The Emitter-base Junction of the BJT is forward biased while its collector-base junction is reverse biased
Which of the following explains a projectile's parabolic motion? Choose all that apply
The law of inertia
acting on the x axis
The acceleration on
the x axis
The applied force
keeping the
projectile moving
The downward
force of gravity
An experiment is designed to compare the differences in learning outcomes
between learning math from a video game and learning it from traditional
classroom activities. The experiment finds no difference between the two.
Which experiment method is important for controlling bias?
A. Developing a video game with subjects' input
B. Randomly assigning students to the two different groups
C. Asking the subjects which group they preferred to be in
D. Using classroom activities with researchers' input
Answer:
B. Randomly assigning students to the two different groups
Explanation:
The bias can be controlled by making use of the randomized block design where we divide the subject into subgroups also called blocks and randomly assign treatment conditions to each block.
In this case, the blocks or sub groups are learning math from a video game and learning it from traditional classroom activities.
So the best way to control the bias is by randomly assigning students to the different groups.
Question 9 of 15
Locate the polyatomic ion in the compound MgSO4-
A. Mgs
B. o
C. Mg
D. SO4
Answer:
d
Explanation:
As a part of a project to construct a Rube Goldberg machine, a student wishes to construct a spring-loaded cube launcher. For examples of Rube Goldberg machines, see the beautiful Cog video or the Mythbusters Happy Holidays Rube Machine. Our student plans to trigger the release of the spring with a falling ball. The small cube to be launched has a mass of 119.0 grams. The available spring is a very stiff but light spring that has a spring constant of 461.0 N/m (the spring is so light that it may be considered massless). The spring will be mounted at the bottom of a wooden ramp which makes an angle of 50.0 degrees with the horizontal; the length of the spring is parallel to the ramp with the lower end of the spring fixed in place. For simplicity, assume that the part of the wooden ramp which is underneath the spring is highly polished and very slick; you may assume no friction on the cube by the ramp when the cube is moving on this portion of the ramp. For the rest of the wooden ramp, the coefficients of friction between the ramp surface and the cube surface are 0.590 for static friction and 0.470 for kinetic friction. Measured from the equilibrium position of the free end of the mounted spring, the distance to the top of the ramp is 17.0 cm (this is measured along the ramp) The plan is to compress the spring and maintain the compression with a simple trigger, which will be released by a falling ball. The cube will be at rest on the free end of the compressed spring. When the trigger is released, the spring will expand, shooting the cube up the ramp. The desired speed for the cube when it reaches the top of the ramp (where the cube will leave the ramp as a projectile to continue the Rube Goldberg sequence) is 45.0 cm/s. Your ultimate task will be to calculate the necessary amount of compression for the spring. The Spring is Compressed by 5.90 cm Before attempting the ultimate task, answer the following questions (Parts A-B) for the case in which the spring is compressed by 5.90 cm and then released, shooting the cube up the ramp and into the air.
A) Find the work done on the cube by the spring during the time that the cube is in contact with the spring.
B) What is the speed of the cube at the the instant just before the sliding cube leaves the ramp?
Answer:
1. The work done on the cube during the time the cube is in contact with the spring is 0.8023705 J
2. The speed of the cube at the instant just before the sliding cube leaves the ramp is approximately 31.5 cm/s
Explanation:
The given parameters of the Rube Goldberg machine are;
The distance from the free end of the spring to the top of the ramp, d = 17.0 cm = 0.17 m
The mass of the small cube to be launched, m = 119.0 g = 0.119 kg
The spring constant of the spring, k = 461.0 N/m
The angle of elevation of the ramp to the horizontal, θ = 50.0°
The coefficient of static friction of the wood, [tex]\mu_s[/tex] = 0.590
The coefficient of dynamic friction of the wood, [tex]\mu_k[/tex] = 0.470
The velocity of the cube at the top of the ramp, v = 45.0 cm/s = 0.45 m/s
The amount by which the cube is compressed, x = 5.90 cm = 0.059 m
The work done on the cube during the time the cube is in contact with the spring = The energy of the spring, E = (1/2)·k·x²
∴ E = (1/2) × 461.0 N/m × (0.059 m)² = 0.8023705 J
The work done on the cube during the time the cube is in contact with the spring= E = 0.8023705 J
2. The frictional force, [tex]F_f[/tex] = [tex]\mu_k[/tex]·m·g·cos(θ)
∴ [tex]F_f[/tex] = 0.470 × 0.119 × 9.8 × cos(50) ≈ 0.35232 N
The work loss to friction, W = [tex]F_f[/tex] × d
∴ W = 0.35232 N × 0.17 m ≈ 0.05989 J
The work lost to friction, W ≈ 0.05989 J
The potential energy of the cube at the top of the ramp, P.E. = m·g·h
∴ P.E. = 0.119 kg × 9.8 m/s² × 0.17 m × sin(50°) ≈ 0.151871375 J
By conservation of energy principle, the Kinetic Energy of the cube at the top of the ramp, K.E. = E - W - P.E.
∴ K.E. = 0.8023705 J - 0.05989 J - 0.151871375 J ≈ 0.590609125 J
K.E. = (1/2)·m·v²
Where;
v = The speed of the cube at the instant just before the sliding cube leaves the ramp
∴ K.E. = (1/2) × 0.119 kg × v² ≈ 0.590609125 J
v² ≈ 0.590609125 J/((1/2) × 0.119 kg) ≈ 9.92620378 m²/s²
v = √(9.92620378 m²/s²) ≈ 3.15058785 m/s ≈ 31.5 cm/s
The speed of the cube at the instant just before the sliding cube leaves the ramp, v ≈ 31.5 cm/s.
What season is the Southern hemisphere in
Answer:
hope this answer helps this is what I understand
Answer:
In the southern hemisphere it is fall but almost winter
Explanation:
They are 6 months ahead of the northern hemisphere. at least thats
how I think about it
What is the displacement for a driver who travels 10 km to get to a point that is 4 km from his starting point?
4 km
10 km
6 km
14 km
Answer:
6km
Explanation:
The tension in a string from which a 4.0 kg object is suspended in an elevator is equal to 44 N. What is the acceleration of the elevator, if upward is the positive direction. Write the numerical value only with 2 decimal places. Do not write the unit. If the acceleration is negative (downward) include the negative sign in your answer.
Answer: 1
Explanation:
Given
Tension is the string [tex]T=44\ N[/tex]
mass of object [tex]m=4\ kg[/tex]
Tension is greater than the weight of the object i.e. elevator is moving upward
we can write
[tex]\Rightarrow T-mg=ma\\\Rightarrow T=m(g+a)\\\Rightarrow 44=4(10+a)\\\Rightarrow 11=10+a\\\Rightarrow a=1\ m/s^2[/tex]
Which formula is used to find an object's acceleration?
a= Δt – Δν
a= Δv + Δt
a= Δv/ Δt
a= Δt/Δv
Answer:
its the third one
An elevator suspended by a vertical cable is moving downward at a constant speed. The tension in the cable must be A) greater than the weight of the elevator. B) less than the weight of the elevator. C) equal to the weight of the elevator.
Answer:
(C) because the elevator is not accelerating
Note F = M a = M g (the resultant force on the elevator is due to gravity)
or Fup = Fc the force exerted on the elevator by the cable
and Fdown = Fe the force exerted on the elevator by gravity
F = M a = Fup - Fdown = zero resultant force on elevator
2) How much work is required to pull a sled 15
meters if you use 30N of force?
2 people
Explanation:
Question 11 of 15
Which of the following compounds is carbon tetrahydride?
A. CaH4
B. CH4
C. CaH
D. CAH
the correct answer would be "B"
3. Tabulate the difference between a Static friction and Kinetic friction.
Answer:
Static friction is what keeps the box from moving without being pushed, and it must be overcome with a sufficient opposing force before the box will move. Kinetic friction is the force that resists the relative movement of the surfaces once they're in motion.
Directions: Follow the instructions to go through the simulation. Respond to the questions and prompts in the orange boxes. Vocabulary: air track, approach velocity, conservation of energy, conservation of momentum, elasticity, kinetic energy, momentum, separation velocity, velocity Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Imagine going to a bowling alley with a bowling ball and a ping pong ball. Why is a bowling ball better for knocking down pins than a ping pong ball?
Answer and Explanation: Momentum (Q) is defined as mass in motion, which means it relates mass of an object with its velocity:
Q = m.v
So, momentum only depends on mass of the object and the velocity it is moving.
Comparing bowling ball and ping pong ball, the first one has more mass than the second one. Therefore, a bowling pin will better knock down the pins than the ping pong ball.
A physics major is working to pay her college tuition by performing in a traveling carnival. She rides a motorcycle inside a hollow, transparent plastic sphere. After gaining sufficient speed, she travels in a vertical circle with a radius of 15.0 m. She has a mass of 80.0 kg and her motorcycle has mass 30.0 kg. What minimum speed must she have at the top of the circle for the motorcycle tires to remain in contact with the sphere
Answer:
v = 12.1 m/s
Explanation:
When at the top of the circle, there are two forces acting on the combined mass of the rider and the motorcycle.These are the force of gravity (downward) and the normal force, which is directed from the surface away from it, perpendicular to the surface.In this case, as the motorcycle runs in the interior of the circle, at the top point this force is completely vertical, and is also downward.Since the motorcycle is moving in a vertical circle, there must be a force, keeping the object moving around a circle.This force is the centripetal force, aims towards the center of the circle, and is just the net force aiming in this direction at any point.At the top point, this force is just the sum of the normal force and the weight of the mass of the rider and the motorcycle combined, as follows (we take the direction towards the center as positive):[tex]F_{c} = N + m*g (1)[/tex]
Now, we know that the centripetal force is related with the tangential speed at this point and the radius of the circle as follows:[tex]F_{c} = m*\frac{v^{2}}{r} (2)[/tex]
Since the normal force takes any value as needed to make (1) equal to (2), if the speed diminishes, it will be needed less force to keep the equality valid.In the limit, when the motorcyvle tires barely touch the surface, this normal force becomes zero.In this condition, from (1) and (2), we can find the minimum possible value of the speed that still keeps the motorcycle touching the surface, as follows:[tex]v_{min} =\sqrt{r*g} =\sqrt{15.0m*9.8m/s2} = 12.1 m/s (3)[/tex]The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid. Find the terminal velocity (in meters per second and kilometers per hour) of an 86.0 kg skydiver falling in a pike (headfirst) position with a surface area of 0.145 m2. (Assume that the density of air is 1.21 kg/m3 and the drag coefficient of a skydiver in a pike position is 0.7. For each answer, enter a number.)
Answer:
terminal velocity is;
v = 117.54 m/s
v = 423.144 km/hr
Explanation:
Given the data in the question;
we know that, the force on a body due to gravity is;
[tex]F_g[/tex] = mg
where m is mass and g is acceleration due to gravity
Force of drag is;
[tex]F_d[/tex] = [tex]\frac{1}{2}[/tex]pCAv²
where p is the density of fluid, C is the drag coefficient, A is the area and v is the terminal velocity.
Terminal velocity is reach when the force of gravity is equal to the force of drag.
[tex]F_g = F_d[/tex]
mg = [tex]\frac{1}{2}[/tex]pCAv²
we solve for v
v = √( 2mg / pCA )
so we substitute in our values
v = √( [2×(86 kg)×9.8 m/s² ] / [ 1.21 kg/m³ × 0.7 × 0.145 m²] )
v = √( 1685.6 / 0.122015 )
v = √( 13814.6949 )
v = 117.54 m/s
v = ( 117.54 m/s × 3.6 ) = 423.144 km/hr
Therefore terminal velocity is;
v = 117.54 m/s
v = 423.144 km/hr
see bellow
fffffffffffffff
Answer:
third, The water has potential energy at the top of the waterfall and increasing kinetic energy as it falls.
Explanation:
Water at the top is not falling, but will fall soon, so has potential energy. It has increasing kinetic energy as it falls because the speed of water falling increases.
Rubbing two objects together turns the energy of motion into heat energy because of _____
fuel
conduction
friction
electricity
plssssssssssssssss answer correctly
Answer:
Friction
Explanation:
Friction is a force that opposes motion
Answer:
Friction is your answer ☺️. If I'm right so,
Please mark me as brainliest. thanks!!
engaging in physical activities like agawang base helps me become
Explanation:
Agawang base is sport mainly played among children in eastern countries like Philippines. It is a game usually played using local props or instrument. Participants are divided into two teams with equal number of team members.
It becomes source of exercise for the players and improves their agility and endurance in the long run. It has also become tool of socializing and learning teamwork.
how does temperature affect brownian motion
Answer: This (random) thermal motion of the particles due to the temperature is also called Brownian motion. ... The higher the temperature, the faster the diffusion will be, because the stronger the molecule movement and thus the “mixing”.
Explanation:
What happens to the energy of a rubber band when it is stretched?
What impulse occurs when a cart that is originally at rest experiences an average force of
N for 2.5 s? *
(10 Points)
25 N
25 Nm
25 Ns
25 kg m/s
Explanation:
What impulse occurs when a cart that is originally at rest experiences an average force of
N for 2.5 s? *
(10 Points)
25 N
25 Nm
25 Ns
25 kg m/s
Sound wave A is moving through a medium that is decreasing temperature.
Sound wave B is moving from a liquid to a gas medium
Which statement can be made about both waves?
1. They will speed up
2. They will increase the
density of their medium
3. They will slow down
4. They will decrease the density of their medium
The satement that can be made about sound wave A and sound wave B is, they will slow down.
Relationship between sound wave and temperatureThe relationship between sound waves and temperature is given by the following formula;
[tex]v = \sqrt{\frac{\gamma RT}{M} }[/tex]
The speed of sound wave increases with increase in temperature, and vice versa.
Speed of sound wave in liquid and gaseous mediumSound wave is mechanical wave, because it requires material medium for its propagation. Sound will travel faster in liquid medium than gaseous medium because of number of molecules per unit volume.
Thus, the satement that can be made about sound wave A and sound wave B is, they will slow down.
Learn more about speed of sound waves here: https://brainly.com/question/2142871
5
Select the correct answer.
What is the current in a parallel circuit which has two resistors (17.2 ohms and
22.4 ohms) and a power source of 6.0 volts?
ОА.
0.30 amps
OB.
9.8 amps
OC.
0.61 amps
D.
1.2 amps
Reset
Next
Answer:
Current in a parallel circuit = 0.61 amps (Approx)
Explanation:
Given:
Voltage V = 6 volt
Two resistors = 17.2 , 22.4 in parallel circuit
Find:
Current in a parallel circuit
Computation:
1/R = 1/r1 + 1 / r2
1/R = 1/17.2 + 1 / 22.4
R = 9.73 ohms (Approx)
Current in a parallel circuit = V / R
Current in a parallel circuit = 6 / 9.73
Current in a parallel circuit = 0.61 amps (Approx)
The coefficients of static and kinetic friction between a 50.0-kg box and a horizontal surface are 0.500 and 0.400 respectively. (a) What is the acceleration of the object if a 250-N horizontal force is applied to the box
Answer:
1.08 m/s^2
Explanation:
The maximum value of static friction F_s = μ_s mg
where μ_s = coefficient of static friction
m= mass of box= 50kg
g= 9.81 m/s^2 , acceleration due to gravity
F_s = 0.5×50×9.81 =245 N
Since, the applied force is greater than the maximum value of static friction F_s, the object must be in motion. Hence, kinetic friction must be taken into account and not static friction.
By equilibrium condition
ma = F - μ_k m g
where F = 250 N, μ_k = coefficient of kinetic friction = 0.4, m= 50 Kg
a = acceleration of the box
50a = 250-0.4×50×9.81
Solving we get a= 1.08 m/s^2
What is a overly-simplified definition of Einstein's theory of general relativity?
Answer:
the laws of physics are the same for all non-accelerating observers
Explanation:
Which of the following electromagnets is the strongest? Why?
Answer:
Bitter Magnet inside a superconducting magnet
Explanation:
Since there are no options available, generally, the electromagnet that is considered the strongest is the Bitter Magnet inside a superconducting magnet.
This electromagnet produces 45 Tesla units which is a result of bitter magnet producing 33.5 Tesla and the superconducting coil produces the additional 11.5 Tesla.
Hence, justifying that the greater the current in the coil the stronger the electromagnet.