Please help:
An object rolled 15m/s for 3 seconds. How far did it roll?

Answers

Answer 1
45m!

explanation:
15x3=45 :)
Answer 2
9 m/s is the answer,.,,,.,,

Related Questions

3. How many oxygen atoms are there in 5.0 mol of water?

Answers

Answer:

3.01 * 10^23 oxygen atoms

Explanation:

Water is H2O. So there are one oxygen atom for every molecule of water.

So in 5.0 mol of water molecules, there are 5.0 mol of oxygen atoms.

Since 5.0 mol = 5 * 6.02 * 10^23 molecules, there are 3.01 * 10^23 oxygen atoms.

Identify the Lewis base in this balanced equation: 6 upper H subscript 2 upper O plus UPper C r (upper H subscript 2 upper O) subscript 6 superscript 3 plus. H2O Cr3+ Cr(H2O)63+

Answers

The Lewis base that we can see in the equation is [tex]H_{2} O[/tex]

What is the Lewis base?

We have to bear in mind that the Lewis base is the substance that is able to donate a pair of electrons. The substances that is able to accept the pair of electrons is what we call the Lewis acid.

The Lewis acid must possess a space for the addition of an electron pair while the Lewis base would have to be a specie that has a lone pair of electrons or has a negative charge. Thus the water molecule would serve as a Lewis base in this regard.

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Answer:

6 upper H subscript 2 upper O plus UPper C r (upper H subscript 2 upper O) subscript 6 superscript 3 plus.

✔ H2O or A.)

Cr3+

Cr(H2O)63+

please answer asap!

What is the molarity of a KOH solution if 200 ml of the solution contains 0.6 moles KOH?

a. 0.3 M
b. 0.6 M
c. 3.0 M
d. 6.0 M

Answers

200 ml is 1/5 of a liter, so the answer is five times the number of moles present in the solution. 0.6 moles/0.2 liter = x moles/1.0 liter. Solving for x gives 0.2 x = 0.6 or x = 3.0 M

so the answer is c

Help (also tell me what the phenotype and genotypes are)

Answers

Answer:

genotype are the organism's hereditary information for example DNA

phenotype are the organism's physical characteristics for example your eyes or hair

or how your nose looks

If the number of moles of a gas doubles, its volume will also double
according to
*
Please hurry! What is the answer to this?

Answers

Explanation:

Boyle's Law

What is the molarity of a 9.79 L solution that contains 0.400 mol HCI

Answers

Answer:

0.041 M

Explanation:

The molarity of a solution when given the number of moles the substance and it's volume can be found by using the formula

[tex]c = \frac{n}{v} \\ [/tex]

n is the number of moles

v is the volume in L

We have

[tex]c = \frac{0.4}{9.79} \\ = 0.04058...[/tex]

We have the final answer as

0.041 M

Hope this helps you

Only animals and not plants can adapt to their environment true or false

Answers

Answer:

true

Explanation:

np have a good day brainliest?

Because a water molecule has a negative end and a positive end it displays?

Answers

Answer:

A water molecule displays polarity by having negative and positive ends. Due to this charge difference, a water molecule is called a dipole.

Explanation:

Try moving an electron from the metal to the non metal.What happens?

Answers

Answer:

Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.

Explanation:

A chemist titrates 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid. How many mL of NaOH will be required to titrate to the endpoint

Answers

[tex](normality \: of \: acid)×(volum \: of \: acid) = (normality \: of \: base)×(volum \: of \: base)[/tex]

0.15N × 50mL = 0.2N × (Vbase)

75mL = Volum of base

37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid to the endpoint.

How to calculate volume?

The volume of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentrationC2 = final concentrationV1 = initial volumeV2 = final volume

C1 = 0.200MC2 = 0.150MV1 = ?V2 = 50mL

0.2 × V1 = 0.150 × 50

0.2V1 = 7.5

V1 = 7.5/0.2

V1 = 37.5mL

Therefore, 37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 mL of 0.150 M HCI, strong acid to the endpoint.

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What kind of weather forms with an occluded front?

Answers

Answer:Occluded fronts usually form around areas of low atmospheric pressure. There is often precipitation along an occluded front from cumulonimbus or nimbostratus clouds. Wind changes direction as the front passes and the temperature either warms or cools.

Explanation:

Occluded fronts usually form when the area is of low atmospheric pressure.

How many moles of OH−(aq) (hydroxide ions)are present in the balanced redox reaction?
NO3−(aq) + ClO−(aq) + H2O(l) → NO(g) + ClO2−(aq) + OH−(aq)

Answers

There are 4 moles of (aq) showed in the reaction i think

A mixture of water and water vapor is present in a closed vessel at 20 degrees Celsius. the total pressure of the system is 755.0 mmHg. Partial pressure of water vapor at 20 degrees Celsius equals 17.5 mm Hg. What is the partial pressure of H2

Answers

Answer:

737.5 mmHg

Explanation:

Ptotal=PH2O+PH2

P is the pressure and since we have Ptotal and PH2O, we can solve for PH2

755=17.5+x

755-17.5=x

x=737.5

What is the fundamental different between combustion and nuclear reaction

Answers

Answer:

Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclear.

What's a house hold item that has nuclear energy

Answers

Answer:

Electricity, Weapons, Medicine · Food Treatments, ect.

If I have 7.0 x 10^24 formula units of magnesium chloride, how many grams of chlorine would I have?

Answers

Answer:

824 g

Explanation:

First we convert 7.0 x 10²⁴ formula units of magnesium chloride (MgCl₂) into moles, using Avogadro's number:

7.0 x 10²⁴ formula units ÷ 6.023x10²³ formula units/mol = 11.62 mol MgCl₂

There are two Cl moles per MgCl₂ moles, meaning that we have (2 * 11.62) 23.24 moles of Cl

Finally we convert 23.24 moles of chlorine into grams, using chlorine's molar mass:

23.24 mol * 35.45 g/mol = 824 g

the experimental control is the ?
A. Dependent variable
B. Design of the experiment.
C. Outcome of the experiment
D. the standard against which the results are measured .

Answers

Answer:

D. In an experiment, one of the variables will be giving a placebo and the other, a treatment

Explanation:

Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.

The most common experimental technique to perform elemental analysis is combustion analysis, where a sample is burned in a large excess of oxygen and the combustion products are trapped in a variety of ways. A 99.99% pure, 0.4808 g sample containing only carbon, hydrogen, and nitrogen is subjected to combustion analysis, resulting in the formation of 0.6859 g CO2, 0.6973 g H2O, and 0.4646 g NO. What is the empirical formula of the sample

Answers

Answer:

C₂H₅N₂

Explanation:

In the combustion analysis, all NO comes from the nitrogen of the sample, that means:

Moles NO = Moles N in the sample

In the same way:

Moles CO2 = Moles C in the sample

Moles H2O = 1/2 moles H in the sample

To solve this problem we must convert the mass of each gas to moles in order to find the moles of each atom. The empirical formula is the simplest whole number ratio of atoms presents in the molecule:

Moles NO = N -Molar mass: 30g/mol

0.4646g * (1mol / 30g) = 0.01549 moles N

Moles CO2 = C -Molar mass: 44.01g/mol-

0.6859g * (1mol / 44.01g) = 0.01559 moles C

Moles H2O = 1/2moles H -Molar mass: 18.02g/mol-

0.6973g * (1mol / 18.02g) = 0.03870 moles H

The ratio of atoms is -Dividing in the low number of moles = moles N-:

C = 0.01559 / 0.01549 = 1

N = 0.01549 / 0.01549 = 1

H = 0.03870 / 0.01549 = 2.5

Twice this ratio of atoms -Because empirical formula must be given only with whole numbers:

C = 2

N = 2

H = 5

The empirical formula is:

C₂H₅N₂

Imine formation from an aldehyde and an amine proceeds reversibly under slightly acidic conditions. The reaction is reversible due to acid-catalyzed hydrolysis of the imine. Imine formation generates an equivalent of water. Given these facts, explain why the imine can be isolated from the reaction mixture.

Answers

Answer:

Imine can be isolated from the reaction mixture as water is continuously removed from the reaction chamber

Explanation:

In this reaction, a non -aqueous solvent  is not used (not mentioned in the question). Thus, we can say that there is continuous removal water under suitable reacting conditions and hence the imine formed is left behind.

How many grams of hydroxide pellets, NaOh are required to prepare 50.0ml of a 0.150 M solution ?

A.0.300g
B.3.00g
C.2.00g
D.200.g
E. 0.025 M

Answers

the correct answer is E10.
(O.0500L) x (0.150mo/L)x(39.997 15 g NaOh/mol)=0.300 g NaOh



ANSWER A

Draw a structural formula for the organic product formed by treating butanal with the following reagent: NaBH4 in CH3OH/H2O You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Do not include lone pairs in your answer. They will not be considered in the grading. Include counter-ions, e.g., Na , I-, in your submission, but draw them in their own separate sketcher. Do not draw organic or inorganic by-products.

Answers

Answer:

Please find the solution in the attachment file.

Explanation:

The diagram shows that the boiling point of water is 100°C At a pressure of one atm.

How could you reduce the boiling point of water in this system?


A. Increase the size of the flame

B. Decrease the volume of the water

C. Decrease the pressure to 0 atm.

D. Increase the pressure to 2 atm

Answers

Answer:

I think the answer will be number A

The boiling point of a substance is constant and for water it is 100 degree celsius. However by reducing the surrounding pressure the boiling point can be reduced.

What is boiling point ?

Boiling point of a substances is the temperature at which the vapor pressure of the gas phase above the liquid equals to the atmospheric pressure where, the liquid converts to the vapor state.

Boiling point depends on the bond type, molar mass, temperature and pressure. As the and pressure increases, boiling point increases. Similarly with an increasing mass and more strength intermolecular force results in greater boiling point.

As the atmospheric pressure decreases, the temperature needed to equalise the vapor pressure of the gas phase over the liquid also decreases. Hence, boiling point decreases. Therefore, option C is correct.

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2. A plant growing in response to the sunlight.
A.Gravitropism
B.Phototropism
C.Thigmotropism
D.Hydrotropism

Answers

Answer:

phototropism

Explanation:

since photo is (light?

Phototropism - because she photo means light hydro is water and gravi thing of earth

Helen is studying the properties of solids. She is comparing the wooden cube and the steel cube shown in the picture below.

mc065-1

Which property is the same for the two cubes?


color

luster

texture

volume

Answers

volume. they are different colors, they aren’t the same luster, and one is smooth while the other might be slightly rough

Identify the reaction type of the chemical reaction below. Check all that apply.
Mg (s)+2 HCl (aq) MgCl 2 (aq)+H 2 (g)

Answers

Answer:

The type of reaction is a single-replacement reaction.

Explanation:

Mg switches places with H, leaving H by itself.

A 1.4639-g sample of limestone is analyzed for Fe, Ca, and Mg. The iron is determined as Fe2O3 yielding 0.0357 g. Calcium is isolated as CaSO4, yielding a precipitate of 1.4058 g, and Mg is isolated as 0.0672 g of Mg2P2O7. Report the amount of Fe, Ca, and Mg in the limestone sample as %w/w Fe2O3, %w/w CaO, and %w/w MgO

Answers

Answer:

A) w/w % of Fe - 2.44%

B) w/w % of Mg - 4.590%

C) w/w % of Ca - 96%

Explanation:

A) w/w % of Fe in limestone as Fe2O3 = (Mass of Fe2O3 /Mass of limestone) x 100

 0.0357/1.4639 X 100

= 2.438 =2.44

B) w/w % of Mg in limestone as Mg2P2O7 = (Mass of Mg2P2O7 /Mass of limestone) x 100

= 0.0672/1.4639 X 100

= 4.590

C) w/w % of Ca in limestone as CaSO4 = (Mass of CaSO4/Mass of limestone) x 100

= 1.4058/1.4639 X 100

= 96

                                                           

Answer:Fe =1.71%    Ma=0.99%    Ca=28.24%

Explanation:

Explain what is meant by a river’s load, and describe how the load is carried.
Please hurry I m timed T-T

Answers

Answer:

A rivers load is gravel and sand. It is carried by being dragged, rolled, and bounced along the bed of the river.

Explanation:

Answer:

the amount of gravel and sand at a river

the load is carried by the moving water

Pls someone help me with this question pls

Answers

The answer should be c because of the answer

In another experiment, the student titrated 50.0 mL of 0.100 M HC,H,O, with
0.100 M NaOH(aq). Calculate the pH of the solution at the equivalence point

Answers

Answer:

Eqv Pt pH = 8.73

Explanation:

    HOAc                   +            NaOH            =>            NaOAc              + H₂O

50ml(0.10M HOAc)  +  50ml(0.10M NaOH) => 100ml(0.05M NaOAc) + H₂O

For neutralized system, 100ml of 0.05M NaOAc remains

NaOAc => Na⁺ + OAc⁻

Na⁺ + H₂O => No Rxn

          OAc⁻  +  H₂O  => HOAc + OH⁻

C(i)   0.05M       -----        0M      0M

ΔC        -x           -----         +x        +x

C(f)    0.05-x      

       ≅ 0.05M    -----          x          x

Kb = Kw/Ka = [HOAc][OH⁻]/[OAc⁻] = 1 X 10⁻¹⁴/1.7 X 10⁻⁵ = (x)(x)/(0.05M)

=> x = [OH⁻] = SqrRt(0.05 x 10⁻¹⁴/1.7 x 10⁻⁵) = 5.42 x 10⁻⁶M

=> pOH = -log[OH⁻] = -log(5.42 x 10⁻⁶) = 5.27

pH + pOH = 14 => pH = 14 - pOH = 14 - 5.27 = 8.73 Eqv Pt pH

Which of the statements below about an acid-base buffer solution is/are true?
I. It can be prepared by combining a strong acid with a salt of its conjugate base.
II. It can be prepared by combining a weak acid with a salt of its conjugate base.
III. It can be prepared by combining a weak base with its conjugate acid.
IV. The pH of a buffer solution does not change when the solution is diluted.
V. A buffer solution resists changes in its pH when an acid or base is added to it.
A. I, II, and IV.
B. II, III, and V.
C. II, III, IV, and V.
D. I, II, IV, and V.
E. II, III, and IV.

Answers

Answer:

C. II, III, IV, and V.

Explanation:

Acid buffer is  generally formed by the combination of a weak acid as well as the salt of the conjugate base.

Basic buffer is formed the combination of a weak base and also the salt of the conjugate acid.

On dilution the ration of the concentration terms of the salt and weak acid/base does not change. Hence the pH of the buffer solution does not change.

When acid or base is added to buffer, it resists changes in the pH.

Therefore, option (C) is correct.

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