Please help!
Elizabeth brought a box of donuts to share. There are two-dozen (24) donuts in the box, all identical in size, shape, and color. Six are jelly-filled, 6 are lemon-filled, and 12 are custard-filled. You randomly select one donut, eat it, and select another donut. Find the probability of selecting two custard-filled donuts in a row. Type an integer or simplified fraction.

The missing values in the table that contains the equivalent ratios between X and Y would be = 5

An equivalent ratio is defined as the constant that exists between two different numbers when compared.

The figures in the table is as follows:

X= 1 3 ? 7

y = 5 15 25 35

If X = 1 when y = 5, X= ? when y= 25

That is;

1 =5

?= 25

? = 25/5 = 5

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Replacing stoplights with roundabouts does not significantly reduce the rate of accidents at intersections based on the given data.

Based on the statistical analysis, replacing stoplights with roundabouts does not significantly reduce the rate of accidents at intersections.

To test this hypothesis, we will use a paired t-test, which compares the means of two sets of paired data. The null hypothesis is that there is no significant difference between the mean accident rates before and after installing roundabouts, while the alternative hypothesis is that the mean accident rate after installing roundabouts is significantly lower than before.

Here are the steps to conduct the paired t-test:

Using the given data, the differences between the accident rates before and after installing roundabouts are:

-0.6, 0.2, 0.6, -0.1, 0

The mean of the differences is 0.02, and the standard deviation is 0.43. There are 5 paired observations, so the degrees of freedom are 4.

Using the formula, we get:

t = 0.02 / (0.43 / √(5)) = 0.14

The critical t-value at a 0.05 level of significance and 4 degrees of freedom is 2.776 from a t-distribution table.

Since the calculated t-value (0.14) is less than the critical t-value (2.776), we fail to reject the null hypothesis. Therefore, we can conclude that replacing stoplights with roundabouts does not significantly reduce the rate of accidents at intersections based on the given data.

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Answer: To find the new balance including interest, we need to take into account the interest charged on the current balance and the new purchase.

First, let's calculate the interest charged on the current balance. The monthly interest rate is 18.99% / 12 = 1.5825%.

The interest charged on the current balance is therefore:

interest on current balance = 0.015825 * 9160.00 = 144.98

So the total balance including interest for the current month is:

current balance including interest = 9160.00 + 144.98 = 9304.98

Next, let's calculate the interest charged on the new purchase of $1,098.00. The interest charged on the new purchase is:

interest on new purchase = 0.015825 * 1098.00 = 17.39

So the total balance including interest for the new purchase is:

new balance including interest = 1098.00 + 17.39 = 1115.39

Finally, we add the current balance including interest and the new balance including interest to get the total balance including interest:

total balance including interest = current balance including interest + new balance including interest

total balance including interest = 9304.98 + 1115.39

total balance including interest = 10420.37

Therefore, the new balance including interest is $10,420.37.

Step-by-step explanation:

The first point to plot on the mean control chart would be at 1.9 at control chart with both limits.

1. There are four measurements in each sample, as shown in the table.

2. To plot the first point on the mean control chart, we need to calculate the mean of the first sample. Adding up the four measurements from the 10:00 am sample (2.0 + 1.8 + 2.0 + 1.8) gives a total of 7.6. Dividing by the number of measurements in the sample (4) gives a mean of 1.9. Since the mean is within the control limits of 1.8 and 2.2, the first point on the chart would be plotted at 1.9.
1. To determine how many measurements are in each sample, we simply count the number of measurements provided for each time.

10:00 am: 4 measurements (2.0, 1.8, 2.0, 1.8)
10:15 am: 4 measurements (2.0, 2.0, 2.0, 2.0)
10:30 am: 4 measurements (1.8, 1.9, 2.1, 2.2)
10:45 am: 4 measurements (2.1, 2.1, 1.9, 1.9)
11:00 am: 4 measurements (1.6, 2.0, 2.2, 1.7)

Each sample contains 4 measurements.

2. To plot the first point on a mean control chart, we need to calculate the mean of the first sample (10:00 am).

Mean = (2.0 + 1.8 + 2.0 + 1.8) / 4
Mean = 7.6 / 4
Mean = 1.9

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1. There are 4 measurements in each sample.

2. The first point to plot on the mean control chart would be 1.9, corresponding to the 10:00 am sample.

To determine the number of measurements in each sample, simply count the number of values for each time point.
10:00 am: 4 measurements (2.0, 1.8, 2.0, 1.8)
10:15 am: 4 measurements (2.0, 2.0, 2.0, 2.0)
10:30 am: 4 measurements (1.8, 1.9, 2.1, 2.2)
10:45 am: 4 measurements (2.1, 2.1, 1.9, 1.9)
11:00 am: 4 measurements (1.6, 2.0, 2.2, 1.7)
There are 4 measurements in each sample.
To plot the first point on the mean control chart, calculate the mean of the first sample (10:00 am).
Mean = (2.0 + 1.8 + 2.0 + 1.8) / 4 = 7.6 / 4 = 1.9.

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Answer: question#7 is 7/12

question#8 is 1  3/8

question#5 is 1/2

question#6 is 12

question#9 is 1  1/6

question#10 is 31/40

question#11 is 3/4

Step-by-step explanation: give brainliest

Question #5: Option A, [tex]\frac{1}{2}[/tex]

Question #6: Option A, 12

Question #7: Option A, [tex]\frac{7}{12}[/tex]

Question #8: Option D, [tex]1\frac{3}{8}[/tex]

Question #9: Option D, [tex]1\frac{1}{6}[/tex]

Question #10: [tex]\frac{31}{40}[/tex]

Question #11: [tex]\frac{3}{4}[/tex]

Pls mark brainliest

Thus, the values of x,y, and z for the similar triangles are obtained:

Part A: y = 6.70; z = 13.41 and x = 6.

Part B: z = 17.88 ; y = 35.77 and x = 32.

Congruent triangles and similar triangles are two distinct but closely related concepts. There are two different kinds of similar triangle problems: those that ask you to determine whether a set of triangles is similar and those that ask you to determine the angles and side length of similar triangles that are missing.

Part A: using similarity of the triangle, taking the ratios of corresponding side.

y/15 = x/z = 3/y

Consider

y/15 = 3/y

y² = 15*3

y² = 45

y = 6.70

Now,

applying Pythagorean theorem:

y² = 3² + x²

x² = y² - 3²

x² = 45 - 9

x² = 36

x = 6

And,

z² = 12² + x²

z² = 144 + 36

z² = 180

z = 13.41

Part B:using similarity of the triangle, taking the ratios of corresponding side.

z/(x + 8) = 16/y = 8/x  ... eq 1

applying Pythagorean theorem:

z² = 16² + 8²

z² = 256 + 64

z² = 320

z = 17.88

Now, from eq 1

z² = 8(8 +x)

320 = 64 + 8x

8x = 320 - 64

x = 256/8

x = 32

Now,

applying Pythagorean theorem:

y² = 16² + x²

y² = 256 + 32²

y² = 1280

y = 35.77

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The population of your friend's town is 300,000 if the population of your town is about 30,000.

To solve this problem, we can use the fact that if one quantity is a fraction of another quantity, we can multiply or divide the given quantity by that fraction to find the other quantity. In this case, we know that the population of your town is 1/10th of your friend's town's population, so we can multiply your town's population by 10 to get your friend's town's population.

If the population of your town is about 30,000, and it's about 1/10 the population of your friend's town, we can calculate your friend's town's population by multiplying your town's population by 10.

So, the population of your friend's town is

30,000 x 10 = 300,000

Therefore, your friend's town has a population of about 300,000.

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The value of x is approximately 10.57 and the value of y is approximately 15.25.

In mathematics, a chord is a straight line segment that connects two points on a curve. More specifically, a chord is a line segment that has its endpoints on the curve.

The term "chord" is most commonly used in the context of circle geometry, where a chord is a line segment that connects two points on the circumference of a circle. In this context, the length of a chord can be calculated using the Pythagorean theorem, given the lengths of the radii of the circle and the distance between the endpoints of the chord.

In a circle, if four chords are connected to form a quadrilateral, then opposite angles of the quadrilateral are supplementary. Using this property, we can set up the following equation:

105 + (7y + 1) + (7x + 1) + (4y + 14) = 180

Simplifying and solving for x and y, we get:

7x + 4y + 122 = 180

7x + 4y = 58 ......(1)

Also, we know that the opposite angles of a cyclic quadrilateral are supplementary. Therefore, we can set up the following equations:

105 + (4y + 14) = 180 ......(2)

(7y + 1) + (7x + 1) = 180 ......(3)

Simplifying and solving for y in equation (2), we get:

4y + 119 = 180

4y = 61

y = 15.25

Substituting this value of y in equation (3) and solving for x, we get:

(7x + 1) + (7*15.25 + 1) = 180

7x + 106 = 180

7x = 74

x = 10.57

Therefore, the value of x is approximately 10.57 and the value of y is approximately 15.25.

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the volume of the apple would increase by ΔVtotal over the five-week period

The volume of the apple is directly proportional to the cube of its radius. Therefore, if the radius increases by 1/8 inch per week for five weeks, the total increase in radius would be 5/8 inches.

To calculate the change in volume, we can use the formula V = (4/3)πr^3.

Initially, let's assume the radius of the apple is r.

After the first week, the radius would be r + 1/8 inches. Therefore, the new volume would be:
[tex]V_1 = (4/3)\pi(r + 1/8)^3[/tex]

To calculate the change in volume, we can subtract the initial volume from the new volume:

[tex]\DeltaV_1 = V_1 - V_0[/tex]

where V0 is the initial volume of the apple.

Similarly, after the second week, the radius would be r + 2/8 inches, and the new volume would be:

[tex]V2 = (4/3)\pi(r + 2/8)^3[/tex]

The change in volume after the second week would be:

ΔV2 = V2 - V1

We can repeat this process for the remaining three weeks and find the total change in volume by adding all the individual changes:

ΔVtotal = ΔV1 + ΔV2 + ΔV3 + ΔV4 + ΔV5

By simplifying this equation, we get:

[tex]\Delta V_{total }=  (4/3) \pi r^3[(r + 1/8)^3 + (r + 2/8)^3 + (r + 3/8)^3 + (r + 4/8)^3 + (r + 5/8)^3 - 5r^3][/tex]

Therefore, the volume of the apple would increase by ΔVtotal over the five-week period.

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The volume of the apple will increase by [tex](4/3)π[(r0 + 5/8)^3 - r0^3][/tex] during the five-week period.

Assuming that the apple is a perfect sphere, we can use the formula for the volume of a sphere:

[tex]V = (4/3)πr^3[/tex]

where V is the volume of the sphere and r is the radius of the sphere.

Let's start by finding the initial volume of the apple. We are not given the initial radius, so let's assume it to be r0.

[tex]V0 = (4/3)πr0^3[/tex]

After one week, the radius increases by 1/8 inch, so the new radius is r1 = r0 + 1/8. The new volume is:

[tex]V1 = (4/3)π(r0 + 1/8)^3[/tex]

After two weeks, the radius increases by another 1/8 inch, so the new radius is r2 = r0 + 2/8. The new volume is:

[tex]V2 = (4/3)π(r0 + 2/8)^3[/tex]

Similarly, after three weeks, the new radius is r3 = r0 + 3/8 and the new volume is:

[tex]V3 = (4/3)π(r0 + 3/8)^3[/tex]

After four weeks, the new radius is r4 = r0 + 4/8 and the new volume is:

[tex]V4 = (4/3)π(r0 + 4/8)^3[/tex]

Finally, after five weeks, the new radius is r5 = r0 + 5/8 and the new volume is:

[tex]V5 = (4/3)π(r0 + 5/8)^3[/tex]

To find how the volume changes during the five-week period, we need to subtract the initial volume from the final volume:

ΔV = V5 - V0

[tex]ΔV = (4/3)π(r0 + 5/8)^3 - (4/3)πr0^3[/tex]

Simplifying this expression, we get:

[tex]ΔV = (4/3)π[(r0 + 5/8)^3 - r0^3][/tex]

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A number multiplied by itself.

What is square?

In mathematics, a square is a number that is obtained by multiplying a number by itself. It is also a geometric shape with four equal sides and four right angles. The area of a square is calculated by multiplying the length of one of its sides by itself. The formula for calculating the area of a square is A = s^2, where A is the area and s is the length of one side.

Squares have many important applications in mathematics, including in algebra, geometry, trigonometry, and calculus. They are used in the Pythagorean theorem, which relates to the sides of a right triangle, and they are used to represent variables in algebraic equations. Squares are also important in geometry, where they are used to construct geometric shapes and to calculate their areas and perimeters.

The better definition of squares is:

A number multiplied by itself.

In mathematics, a square refers to the product of a number multiplied by itself. For example, the square of 4 is 16, because 4 multiplied by 4 equals 16. Squares have a variety of important applications in mathematics, including in geometry, algebra, and calculus.

While a result that has been proved to be true is sometimes referred to as a "square" in certain contexts, it is not the primary definition of the term. Similarly, a triangle with a right angle is referred to as a "right triangle" or a "right-angled triangle," but not a square.

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The range of a function is the set of all possible output values (y-values) of the function. To find the range of f(x) = (5/2)^x - 5, we need to find the minimum and maximum values of y that can be obtained by plugging in all possible x values.

To find the maximum value of f(x), we can take the limit as x approaches infinity:

Answer:

≈ $26

Step-by-step explanation:

13% = 0.13

199.99 x 0.13 = $25.9987

So, 13% markup is ≈ $26

The greatest common factor of 90 and 315 when divided by the least common multiple of 5 and 15 is 45.

When we multiply all the common prime factors, we get the greatest common factor of the numbers.

These prime factors should come from the prime factorization of the numbers given. These should be in all the unique combinations possible.

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The number of ways to arrange the letters of PENCIL when the first letter can't be N or L is option (B) 480.

The word PENCIL has 6 letters, here we have to use permutation method.  If all the letters are used, there are 6! = 720 ways to arrange them. However, the first letter can’t be N or L. This means that there are only 4 choices for the first letter (P, E, C, or I). After choosing the first letter, there are 5 letters left to arrange,

So there are 5! = 120 ways to arrange them.

Therefore, the total number of ways to arrange the letters of PENCIL when the first letter can’t be N or L is

4 x 5! = 4 x 120 = 480

Therefore, the correct option is (B) 480.

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Answer:

To graph this inequality, you can start by graphing the related function y = -x^2 - 1. This is a downward-facing parabola that opens downwards and has a vertex at (0, -1).

To graph the inequality y ≥ -x^2 - 1, you need to shade the region above the graph of the parabola. This is because any point above the parabola will have a y-coordinate that is greater than or equal to the corresponding y-coordinate on the parabola.

So, to graph the inequality, you can shade the region above the parabola. You can use a dotted line to represent the boundary of the inequality, since the inequality includes the possibility of equality (y = -x^2 - 1).

I hope this helps!

Answer:

$13.25 .

Step-by-step explanation:

In case 1 he buys 1 kg of gummy bears and 2 kg of jelly beans .

So By the given condition :-

••••This will serve as equation (1) .

In case 2 he buys 2 kg of gummy bears and 3kg of jelly beans .

So by given condition :-

•••••This will serve as equation (2) .

Solving equation (1) and (2)

From equation (1)

x=38-2y .

we obtain,

2(38-2y)+3y=62.75

76-4y+3y=62.75

y=76-62.75=13.25 .

So cost of 1 kg of jelly bean is $13.25 .

Answer:

p < -2

Step-by-step explanation:

Answer:

The answer is -2

Step-by-step explanation:

4/5-1/2p>9/5

C.L.T

-1/2p>9/5-4/5

-1/2p>5/5

-1/2p=1

-p/2>1

-p=2

p= -2

Answer:

Your answer should be A

Applying the Angle Bisector Theorem, the length of the segments are:

AB = 15;    AC = 20.

The Angle Bisector Theorem states that in a triangle, if a line segment bisects an angle of the triangle and intersects the opposite side, then it divides that side into two segments that are proportional to the lengths of the other two sides of the triangle.

Therefore, we would have the following equation based on the angle bisector theorem:

5y/8 = 4y - 1 / 6

Cross multiply:

8(4y - 1) = 6(5y)

32y - 8 = 30y

32y - 30y = 8

2y = 8

y = 4

AB = 4y - 1 = 4(4) - 1 = 15

AC = 5y = 5(4) = 20

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Maybe 9/12? I counted the amount of times 6 or 9 shows up on the graph. :D. Hope that helps.

The product of 7 and 4 is 28, which is equal to the number of tiles in the product area.

Therefore, this configuration represents the factors of the quadratic expression [tex]x^2 + 9x + 8.[/tex]

To represent the factors of the quadratic expression x^2 + 9x + 8 using algebra tiles, we need to arrange the tiles into two rectangular areas representing the two factors, and the total number of tiles in the product area should be equal to the product of the number of tiles in each factor area.

Based on the information given, we can arrange the tiles as follows:

Factor 1 area: 7 tiles, with 1 x-tile and 6 blank tiles (represented by underscores):

Copy code

x

_

_

_

_

_

_

Factor 2 area: 4 tiles, with 1 x-tile and 3 blank tiles (represented by underscores):

Copy code

x

_

_

_

Product area: 28 tiles, with 1 x^2-tile, 9 x-tiles, 9 negative tiles (represented by red tiles), and 9 blank tiles (represented by underscores):

Copy code

x^2   -     -     -

x     x     x     x

_     _     _     _

_     _     _     _

_     _     _     _

_     _     _     _

_     _     _     _

To check that this configuration represents the given quadratic expression, we can count the number of tiles in each area and verify that the product of the two factors equals the number of tiles in the product area:

Factor 1 area: 7 tiles

Factor 2 area: 4 tiles

Product area: 28 tiles.

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The "possible-sources" of in the measurement error of an experiment are Instrument error, Human error, sampling error and environmental factors, these sources "may" or "may-not" be enough to account for the percent differences calculated from the data.

There are several possible sources of "measurement-error" in an experiment which affect the accuracy and precision of the results.

These sources include instrument error, human error, environmental factors, and sampling error.

(i) "Instrument-Error" : is defined as inaccuracies in the measuring instruments used in the experiment. This include issues such as calibration errors, sensitivity of the instruments.

(ii) "Human-Error" can arise from mistakes made by experimenters during data collection or analysis, such as misreading measurements or recording data incorrectly.

(iii) "Environmental-Factors", such as temperature, humidity, or electromagnetic interference, can also cause error into experiment if they affect performance of measuring instruments.

(iv) "Sampling-Error" occur when a subset of the population is used for the experiment, and the results are generalized to the entire population.

Depending on the magnitude of these sources of error, they may or may not be enough to account for the percent differences calculated from the data.

If the measurement errors are small and within an acceptable range for the experiment, they may not significantly impact the results.

If the errors are large or systematic, they can introduce significant bias into the data and affect the percent differences calculated.

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The given question is incomplete, the complete question is

Discuss the possible sources of measurement error in an experiment. Are these sources of error enough to account for the percent differences you calculated from your data? write out your answer in a clear and well supported paragraph.

The fireworks will explode after 1.125 seconds of launching Firework B.

Distance = Speed × time

Let time = t

Firework A:

[tex]D(t) = 360t - - - (1)[/tex]

Firework B:

[tex]D(t) = 280(0.25) + 280t[/tex]

[tex]D(t) = 70 + 280t - - - (2)[/tex]

Equate 1 and 2 :

[tex]360t = 280t + 70[/tex]

Collection of like terms

[tex]360t - 280t = 70[/tex]

[tex]80t = 70[/tex]

[tex]t = 70/80[/tex]

[tex]t = 0.875 seconds[/tex]

[tex]0.875 + 0.25 = 1.125 seconds[/tex]

Therefore, the fireworks will explode after 1.125 seconds of launching Firework B.

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The probability of obtaining exactly as many heads as you just obtained if your coin is the fair coin is 0.2461.

Option C is correct

The probability of obtaining exactly as many heads as you just obtained if your coin is the fair coin is given by the binomial probability formula:

P(X = k) = (n choose k) [tex]* p^k * (1-p)^(n-k)[/tex]

where X is the random variable representing the number of heads, n is the total number of coin flips, k is the number of heads obtained, and p is the probability of getting a head on any individual flip.

Since we are assuming that the coin is fair, p = 0.5. Let's say you flipped the coin n times and obtained k heads. Then the probability of obtaining exactly k heads with a fair coin is:

P(X = k) = (n choose k [tex]* 0.5^k * ()1-0.5)^(n-k)[/tex]

We don't know what n or k are, so we can't compute the exact probability. However, we can use the fact that the coin is fair to get an estimate. If we assume that the number of heads obtained is roughly half of the total number of flips, then k = n/2. Plugging this into the formula, we get:

[tex]P(X = n/2) = (n choose n/2) * 0.5^(n/2) * (1-0.5)^(n/2)[/tex]

Simplifying this expression, we get:

[tex]P(X = n/2) = (n choose n/2) * 0.5^n[/tex]

Now, we want to find the probability of obtaining exactly as many heads as we just obtained. Let's say we flipped the coin 10 times and obtained 5 heads. Then we want to find P(X = 5), which is:

P(X = 5) = (10 choose 5) [tex]* 0.5^5 * (1-0.5)^(10-5)[/tex] = 0.2461

Therefore, the probability of obtaining exactly as many heads as you just obtained if your coin is the fair coin is 0.2461.

Option C is correct

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The paired t-test results suggest that there is no significant improvement in students' learning after the new unit on factoring, based on a 90% confidence level.

To determine if there has been an improvement in students' learning after a new unit on factoring, we can perform a paired t-test on the pre-test and post-test scores of the five randomly selected students.

The differences between the pre-test and post-test scores for each student are: 3, 3, 4, 8, 0.

The mean of the differences is 3.6, and the sample standard deviation is 2.39.

The t-value for a 90% confidence interval with 4 degrees of freedom is 2.776. Since the calculated t-value of 2.68 (calculated as the mean of the differences divided by the standard error of the mean of the differences) is less than the critical t-value of 2.776, we fail to reject the null hypothesis that there is no improvement in students' learning.

Therefore, there is not enough evidence to conclude that the new unit on factoring has helped students learn based on the sample data.

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Answer:

d. 1 7/30...............

Answer:

D

Step-by-step explanation:

2/5 + 5/6

Make the denominator same

(2×6)/30 + (5×5)/30

12+25/30

37/30

1 7/30

The parent function which is represented by the given table as required in the task content is; Choice B. f(x) = |x|.

It follows from the task content that the parent function which is represented by the table is to be determined.

On this note, by observation of the function; the values of y represent the positive version of x.

Consequently, it follows that the table represents the absolute value function.

Therefore, Choice B; f(x) = |x| is correct.

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Answer:

25

Step-by-step explanation: