Please help I will give out brainliest

Answer:

  $450,000

Step-by-step explanation:

  chad = (1/3)profit

  3×chad = profit = 3×$150,000 . . . . multiply the equation by 3; fill given value

  profit = $450,000

The company's overall profits were $450,000.

Answer: C. A function only

Step-by-step explanation:

There is not relation to the dots on the graph.

The graph represents a relation only.

Hence option D is correct.

Since we know that

A function is a mathematical concept that describes a relationship between two sets, where each element in the first set (the domain) corresponds to exactly one element in the second set (the range). In simpler terms, a function is a rule that assigns each input value a unique output value.

In contrast, a relation is a general concept that describes any set of objects that have some kind of relationship to each other. In mathematics, a relation is often represented as a set of ordered pairs and can be visualized as a graph. For example, a relation could be a set of all points on a circle, represented as an ordered pair of x and y coordinates.

As we can see in the graph

There is more than one value for the number represented on the X-axis

We can see that at a particular age, there is more than one gray hairs worker.

Hence the graph represents a relation only.

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Answer:

190 cans

Step-by-step explanation:

Total cans collected by Jacob and Dustin for the school can job = 245

Amount of cans they both gave to Dustin's little sister = 55

Now because they gave out cast out of the total they initially had, there would be a deduction in the amount both boys would now have.

To determine the amount the boys are left with, we would deduct 55 casts from the amount they had which 245.

Amount of cans left = 245-55 = 190

Amount of cans left for the boys class = 190 cans

Let's think about this. MQ is given to be a length of 24 units, PR a length of 10 whilst we must determine what length PM must be in order to satisfy the criteria of parallelogram MPQR to be a rhombus.

Assume this figure is a rhombus, rhombus MPQR. If that is so, all sides must be congruent, and the diagonals must be perpendicular ( ⊥ ) by " Properties of a Rhombus. " That would make triangle( s ) MRQ and say RMP isosceles, and by the Coincidence Theorem, MS ≅ QS, and RS ≅ PS. Therefore -

[tex]MS = 1 / 2( 24 ) = 12 = QS,\\RS = 1 / 2( 10 ) = 5 = PS[/tex]

PS and MS are legs of a right triangle, so by Pythagorean Theorem we can determine the hypotenuse, or in other words the length of PM. This length would make parallelogram MPQR a rhombus,

[tex]( PM )^2 = ( MS )^2 + ( PS )^2,\\PM^2 = ( 12 )^2 + ( 5 )^2,\\PM^2 = 144 + 25 = 169\\-----\\PM = 13[/tex]

And thus, PM should be 13 in length to make parallelogram MPQR a rhombus.

Answer:

The answer is explained below

Step-by-step explanation:

The steps to prioritize the mission with a scoring version are as follows:

Collection: This step consists of collecting and collecting all of the details associated with the mission.

Classification: This step consists of prioritization of the challenge based on a category method.

Verification: This step includes approval and verification of all classified projects.

They are then carried out in this order because these steps make certain safety, connectivity, integrity, cost-effectiveness, and right challenge implementation. Each step depends on the previous step. They are connected to every other; therefore, they are carried out in a particular sequence.

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean income = [tex]\frac{\sum X}{n}[/tex] = $4.70

            s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex]  = $1.83

            n = sample of parking meters = 10

            [tex]\mu[/tex] = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.262 < [tex]t_9[/tex] < 2.262) = 0.95  {As the critical value of t at 9 degrees of

                                            freedom are -2.262 & 2.262 with P = 2.5%}  

P(-2.262 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.262) = 0.95

P( [tex]-2.262 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu[/tex] < [tex]2.262 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

P( [tex]\bar X-2.262 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.262 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.262 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.262 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                         = [ [tex]4.70-2.262 \times {\frac{1.83}{\sqrt{10} } }[/tex] , [tex]4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } }[/tex] ]

                                         = [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error  =  [tex]2.262 \times {\frac{s}{\sqrt{n} } }[/tex]

                                          =  [tex]2.262 \times {\frac{1.83}{\sqrt{10} } }[/tex]  = 1.31

Using the t-distribution, it is found that:

a) The 95% confidence interval for the true mean is (3.39, 6.01). It means that we are 95% sure that the true mean income for all parking meters in the resort community from which the sample was taken is between these two values.

b) The margin of error is of $1.31.

Item a:

We will have the standard deviation for the sample, which is why the t-distribution is used to solve this question.

The sample size given is of [tex]n = 10[/tex], and using a calculator, it is found that:

The sample mean of [tex]\overline{x} = 4.7[/tex].

The sample standard deviation of [tex]s = 1.833[/tex].

The confidence interval is:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 10 - 1 = 9 df, is t = 2.2622.

Then, the interval is:

[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 4.7 - 2.2622\frac{1.833}{\sqrt{10}} = 3.39[/tex]

[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 4.7 + 2.2622\frac{1.833}{\sqrt{10}} = 6.01[/tex]

The 95% confidence interval for the true mean is (3.39, 6.01). It means that we are 95% sure that the true mean income for all parking meters in the resort community from which the sample was taken is between these two values.

Item b:

The margin of error is half the distance between the two bounds, hence:

[tex]M = \frac{6.01 - 3.39}{2} = 1.31[/tex]

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Step-by-step explanation:

2 is the answer because:

72/2=36

108/2=54

Answer:

2

Step-by-step explanation:

Well divisible means the lowest numbers it can be divided by.

So we can make a chart.

72 -  1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

108 - 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108

So besides 1, 2 is the lowest divisible number between 108 and 72.

Answer:

Inequality Form:

x≥130

Step-by-step explanation:

isolate the variable by dividing each side by factors that don’t contain the variable.

Answer:

[tex]a_n = 10-3(n - 1)[/tex]

10 + 7 + 4 + 1 + -2 + -5

Step-by-step explanation:

Explicit Arithmetic Formula: [tex]a_n = a_1 + d(n-1)[/tex]

To find d, take the common difference between 2 numbers.

To find the other terms of the sequence, plug them into the explicit formula or subtract 3 from the given numbers.

Answer:

[tex] b = {a}^{2} - 6[/tex]

Step-by-step explanation:

[tex]a = \sqrt{b + 6} \\ squaring \: both \: sides \\ {a}^{2} = {( \sqrt{b + 6)} }^{2} \\ {a}^{2} = b + 6 \\ {a}^{2} - 6 = b \\ \huge \purple { \boxed{ b = {a}^{2} - 6}}[/tex]

Answer:

b= a^2-6

Step-by-step explanation:

Check the attachment.

Hope it helps :)

Answer:

  h(n) = -17·0.2^(n-1)

Step-by-step explanation:

The explicit formula for a geometric sequence with first term a1 and common ratio r is ...

  an = a1·r^(n-1)

Your sequence h has first term a1 = -17 and common ratio r = 0.2. Then the explicit formula is ...

  h(n) = -17·0.2^(n-1)

Answer:

We use z = 1.96

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]

We use z = 1.96

Answer:

The pooled estimate is given by the following formula:

[tex] \hat p= \frac{x_1 +x_2 }{n_1 + n_2}[/tex]

And replacing we got:

[tex] \hat p= \frac{42+45}{100+100}= \frac{87}{200}= 0.435[/tex]

Step-by-step explanation:

We have the following info given:

n1 = 100,

n2 = 100,

x1 = 42,

x2 = 45

The pooled estimate is given by the following formula:

[tex] \hat p= \frac{x_1 +x_2 }{n_1 + n_2}[/tex]

And replacing we got:

[tex] \hat p= \frac{42+45}{100+100}= \frac{87}{200}= 0.435[/tex]

Answer:

1,474,951.

Step-by-step explanation:

Given a population that increases by a constant percentage, we can model the population's growth using the exponential model.

[tex]P(t)=P_o(1+r)^t,$ where \left\{\begin{array}{lll}P_o=$Initial Population\\r$=Growth rate\\$t=time (in years)\end{array}\right\\P_o=919,716\\r=3.7\%=0.037\\$t=13 years[/tex]

Therefore, the population of the city in 13 years time will be:

[tex]P(t)=919,716(1+0.037)^{13}\\\\=919,716(1.037)^{13}\\\\=1,474,950.9\\\\\approx 1,474,951[/tex]

The population be at that time will be approximately 1,474,951.

Answer:

c. you reject a null hypothesis that is true

Step-by-step explanation:

We need to remember the following concepts

Error type I: Is an error associated to the probability of reject a null  hypothesis when it is actually true

Error type II: Is an error associated of not rejecting a null  hypothesis when the alternative hypothesis is the true

And the best answer for this case would be:

c. you reject a null hypothesis that is true

Answer:

undefined

Step-by-step explanation:

Using the slope formula

m = (y2-y1)/ (x2-x1)

and the given points

m = ( 8 - -1)/( 2-2)

    = (8+1) / 0

We cannot divide by 0 so the slope is undefined

Answer:

A) According to the regression equation, regardless of whether or not smoking is allowed in bars, the number of cigarette packs sold per 1000 people decreases by approximately 1424 for each additional dollar of cigarette tax.

Step-by-step explanation:

Given the regression equation:

PACKS i= 57221.431732 − 1423.696906TAXi + 155.441784BARSi + eᵢ.

BARS i= 1 if city i allows smoking in bars

BARSi = 0 if city i does not allow smoking in bars

R2 = 0.351292

P-value = 0.086529

Conlusion:

Simnce p value, 0.0865 is greater than level of significance, 0.05, BARS is not significant. Thus, allowing smoking in bars increase cigarette sales, since the coefficient of BARS is positive.

Correct answer is option A.

According to the regression equation, regardless of whether or not smoking is allowed in bars, the number of cigarette packs sold per 1000 people decreases by approximately 1424 for each additional dollar of cigarette tax.

Answer:

  y = -1000x +11000

Step-by-step explanation:

Given:

  (x, y) = (sales price, number sold) = (3, 8000), (6, 5000)

Find:

  slope-intercept equation for a line through these points

Solution:

When given two points, it often works well to start with the 2-point form of the equation for a line.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

Filling in the given points, you have ...

  y = (5000 -8000)/(6 -3)/(x -3) +8000

  y = (-3000/3)(x -3) +8000

  y = -1000x +3000 +8000 . . . . eliminate parentheses

  y = -1000x +11000 . . . . the desired equation

Answer:

a. 0.5413

b. 20

c. 0.3724

d. 4.4721

Step-by-step explanation:

Solution:-

- We will start by defining a random variable X.

                     X : The number of support requests arrived

- The event defined by the random variable ( X ) is assumed to follow Poisson distribution. This means the number of request in two distinct time intervals are independent from one another. Also the probability of success is linear within a time interval.

- The time interval is basically the time required for a poisson event to occur. Consequently, each distributions is defined by its parameter(s).

- Poisson distribution is defined by " Rate at which the event occurs " - ( λ ). So in our case the rate at which a support request arrives in a defined time interval. We define our distributions as follows:

                                   X ~ Po ( λ )

Where,                        λ = 1 / 30 mins

Hence,

                                   X ~ Po ( 1/30 )

a)

- We see that the time interval for events has been expanded from 30 minutes to 1 hour. However, the rate ( λ ) is given per 30 mins. In such cases we utilize the second property of Poisson distribution i.e the probability of occurrence is proportional within a time interval. Then we scale the given rate to a larger time interval as follows:

                                   λ* =  [tex]\frac{1}{\frac{1}{2} hr} = \frac{2}{1hr}[/tex]

- We redefine our distribution as follows:

                                   X ~ Po ( 2/1 hr )

- Next we utilize the probability density function for poisson process and accumulate the probability for 2 to 4 request in an hour.

                           [tex]P ( X = x ) = \frac{e^-^l^a^m^b^d^a . lambda^x}{x!}[/tex]

- The required probability is:

                   [tex]P ( 2 \leq X \leq 4 ) = P ( X = 2 ) + P ( X = 3 ) + P ( X = 4 )\\\\P ( 2 \leq X \leq 4 ) = \frac{e^-^2 . 2^2}{2!} + \frac{e^-^2 . 2^3}{3!} + \frac{e^-^2 . 2^4}{4!}\\\\P ( 2 \leq X \leq 4 ) = 0.27067 + 0.18044 + 0.09022\\\\P ( 2 \leq X \leq 4 ) = 0.5413[/tex]            Answer    

b)

We will repeat the process we did in the previous part and scale the poisson parameter ( λ ) to a 10 hour work interval as follows:

                               λ* = [tex]\frac{2}{1 hr} * \frac{10}{10} = \frac{20}{10 hr}[/tex]

- The expected value of the poisson distribution is given as:

                             E ( X ) = λ

Hence,

                            E ( X ) = 20  (10 hour work day)    .... Answer

c)

- We redefine our distribution as follows:

                                   X ~ Po ( 20/10 hr )

- Next we utilize the probability density function for poisson process and accumulate the probability for 20 to 24 request in an 10 hour work day.

                           [tex]P ( X = x ) = \frac{e^-^l^a^m^b^d^a . lambda^x}{x!}[/tex]

- The required probability is:

                   [tex]P ( 20 \leq X \leq 24 ) = P ( X = 20 ) + P ( X = 21 ) + P ( X = 22 )+P ( X = 23 ) + P ( X = 24 )\\\\P ( 20 \leq X \leq 24 ) = \frac{e^-^2^0 . 20^2^0}{20!} + \frac{e^-^2^0 . 20^2^1}{21!} + \frac{e^-^2^0 . 20^2^2}{22!} + \frac{e^-^2^0 . 20^2^3}{23!} + \frac{e^-^2^0 . 20^2^4}{24!} \\\\P ( 20 \leq X \leq 24 ) = 0.0883 +0.08460 +0.07691 +0.06688+0.05573\\\\P ( 20 \leq X \leq 24 ) = 0.3724[/tex]            Answer  

c)

The standard deviation of the poisson process is determined from the application of Poisson Limit theorem. I.e Normal approximation of Poisson distribution. The results are:

                                σ = √λ

                                σ = √20

                                σ = 4.4721 ... Answer

Answer:

0.01958mol

Step-by-step explanation:

you want to go from grams to mols so when set up it looks like this

6.7 x [tex]\frac{1mol}{the mass of aluminum sulfate}[/tex]

(you want what your multiplying to cancel out with the denominator(g cancel out g so your left with mols))

to get the mass of aluminum sulfate you must first find the chemical formula which is

Al2(SO4)3

get the amount of every element

so there is:

2 Al

3 S

12 O

(multiply the three to everything inside the parenthesis)

next find the total mass of everything

Al=26.982g x 2

S=32.06g x 3

O=16g x 12

add everything together and you get 342.144g so you plug that number into the first equation

6.7 x[tex]\frac{1mol}{342.144g}[/tex] → [tex]\frac{6.7}{342.144}[/tex]→0.01958mol

Answer:

Step-by-step explanation:

f(x) = 4 is a constant function whose graph is a horizontal line.  As such it has NO inverse.  It fails the horizontal line test.

Answer:

Step-by-step explanation:

Hello!

Full exercise in attachment.

The data set represents the volumes of a generic soda brand in ounces.

a)

To make a dotplot you have to determine a scale, and then make a dot for each observation that corresponds to the values of the scale. I've determined a scale  10 by ten

(see second attachment)

Out of the 4 plots the one that represents a dotplot for the data is the fourth (D.)

b)

An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.

Normally values that are 3 standard deviations away from the mean can be considered outliers.

[tex]\frac{}{X}[/tex]= 71.43

S= 8.42

[tex]\frac{}{X}[/tex] - 3*S= 71.43-3*8.42= 46.17

[tex]\frac{}{X}[/tex] + 3*S= 71.43+3*8.42= 96.69

For this data set, any value below 46.17 ounces or above 96.69 ounces can be considered outliers. Although the values of 50 and 85 ounces seem to be outliers, they are within the limits.

So the correct option for this A.

I hope this helps!

Answer:

Shifting/Translating the function

Step-by-step explanation:

Answer:

Step-by-step explanation:

nice

Answer:

x = - [tex]\frac{5}{3}[/tex] , x = 1

Step-by-step explanation:

Given

2x - 5 = - 3x² ( add 3x² to both sides )

3x² + 2x - 5 = 0 ← in standard form

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 5 = - 15 and sum = + 2

The factors are - 3 and + 5

Use these factors to split the x- term

3x² - 3x + 5x - 5 = 0 ( factor the first/second and third/fourth terms )

3x(x - 1) + 5(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(3x + 5) = 0 ← in factored form

Equate each factor to zero and solve for x

3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = - [tex]\frac{5}{3}[/tex]

x - 1 = 0 ⇒ x = 1

Answer:

$833

Step-by-step explanation:

Since there are 9 people, we need to determine the cost of accommodation and flights for all 9 people:

9(273) + 9(184) = 2457 + 1656 = 4167 for 9 people

We then subtract that amount from the amount of money she won:

5000 - 4167 = 833

Answer:

B. y = (x – 1)^2 + 10

Step-by-step explanation:

Answer: B

Step-by-step explanation:

B     y= (x-1)^2 + 10

[tex]\text{Find the values of x:}\\\\x(x+3)(x+3)=0\\\\\text{We know for the x outside of the parenthesis, it has to equal 0}\\\\\text{For the x inside the parenthesis, we would need to equal it to 0 and }\\\text{solve for x}\\\\x+3=0\\\\x=-3\\\\\text{There are two of them, so we would have two of the same answer}\\\\\boxed{\text{x= 0 or x = -3 or x = -3}}[/tex]

E(m) = 2000 + 0.15( m - 20000) is the function calculates his monthly earnings.

The composition of a function is an operation in which two functions say f and g generate a new function say h in the sort of manner that h(x) = g(f(x)). It method right here characteristic g is carried out to the characteristic of x. So, basically, a feature is implemented to the end result of another feature.

In systems engineering, software engineering, and pc science, a function version or practical model is an established illustration of the capabilities (activities, movements, procedures, operations) inside the modeled system or situation vicinity.

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