PLEASE HELP. I WILL REWARD BRAINLY TO WHO EVER ANSWERS CORRECTLY. (ignore selected answer) Recalling the SAT scores are always expressed as multiples of 10, how many points did you get on the test?

Answer:

[tex]\overline{DF}[/tex] could be a midsegment of ∠ABC.

Step-by-step explanation:

A midsegment of a triangle must be two things:

1. Parallel to the 3rd side, in this case, [tex]\overline{AD}[/tex].

2. Half the length of the 3rd side, in this case, [tex]\overline{AD}[/tex].

Since we don't know the lengths, we can only go off of 1. There is only one line that is parallel to  [tex]\overline{AD}[/tex] and it is [tex]\overline{DF}[/tex].

Hope this helped!

Answer:

[tex]y = \frac{5x}{2} - 5[/tex]

Step-by-step explanation:

Given the equation 5x - 2y = 10, to write the equation in slope-intercept form, we need to write it in the standard format y = mx+c where m is the slope/gradient and c is the intercept.

From the equation given  5x - 2y = 10, we will make y the subject of the formula as shown;

[tex]5x - 2y = 10\\\\subtract \ 5x \ from \ both \ sides\\\\5x - 2y - 5x = 10 - 5x\\\\-2y = 10-5x\\\\Dividing \ both \ sides\ by \ -2;\\\\\frac{-2y}{-2} = \frac{10-5x}{-2}\\ \\[/tex]

[tex]y = \frac{10}{-2} - \frac{5x}{-2} \\\\y = -5 + \frac{5x}{2}\\\\y = \frac{5x}{2} - 5[/tex]

Hence the equation that represents the first equation written in slope-intercept form is [tex]y = \frac{5x}{2} - 5[/tex]

Answer:

y = - 4x - 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 4 , thus

y = - 4x + c ← is the partial equation

To find c substitute (- 4, 6) into the partial equation

6 = 16 + c ⇒ c = 6 - 16 = - 10

y = - 4x - 10 ← equation of line

Answer:

y = -4x+10

Step-by-step explanation:

Using the slope intercept form of a line

y = mx+b where m is the slope and b is the y intercept

y = -4x +b

Substituting the point in

6 = -4(-4) + b

6 = 16+b

Subtract 16 from each side

-10 =b

The equation is

y = -4x+10

Answer:

The points of the image are;

E'(5, 1), D'(5, -1), C'(1, 0), E'(-2, -3)

Step-by-step explanation:

The coordinates of the preimage are E(-5, -1) D(-5, 1) C(-1, 0) B(-2, -3)

Rotation of a point 180° about the origin gives;

Coordinates of the point of the preimage before rotation = (x, y)

The coordinates of the image after rotation = (-x, -y)

Therefore, the coordinates of the points EDCB after 180° rotation about the origin are;

E(-5, -1) rotated 180° becomes E'(5, 1)

D(-5, 1) rotated 180° becomes D'(5, -1)

C(-1, 0) rotated 180° becomes C'(1, 0)

B(-2, -3) rotated 180° becomes E'(-2, -3).

━━━━━━━☆☆━━━━━━━

▹ Answer

You can use a graphing calculator. Attached is a picture of it graphed.

Hope this helps!

CloutAnswers ❁

Brainliest is greatly appreciated!

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Answer:

(2, −1) and (−4, 17)

Step-by-step explanation:

I used a graphing tool to graph the systems of equations. The parabola and line pass at points (2, -1) and (-4, 17).

Answer:(2, −1) and (−4, 17) Its C on Edge 2023

Step-by-step explanation: Its (C) after an extensive research

Answer:

G(x) = (1 - x)/4

is the inverse function required.

Step-by-step explanation:

Given F(x) = -4x + 1

Let y = F(x)

Then y = -4x + 1

=> y - 1 = -4x

4x = 1 - y

x = (1 - y)/4

That is, the inverse is (1 - x)/4

Therefore, G(x) has to be (1 - x)/4

Answer:

T = - 3.2e + 80

Step-by-step explanation:

Given the following :

e = elevation in thousands of feets

T = temperature (°F)

e1 = 5 ; e2 = 10 (in thousands of feet)

T1 = 64° ; T2 = 48°

y = mx + c ; T = me + c

y = ; m = slope, c = intercept

64 = m5 + c - - - - (1)

48 = m10 + c - - - - (2)

From (1)

c = 64 - m5

Substitute c = 64 - m5 into (2)

48 = m10 + c - - - - (2)

48 = m10 + 64 - m5

48 - 64 = 10m - 5m

-16 = 5m

m = - 16 / 5

m = - 3.2

Substitute the value of m into c = 64 - m5

c = 64 - 5(-3.2)

c = 64 - (-16)

c = 64 + 16

c = 80

Inserting our c and m values into T = me + c

T = - 3.2e + 80

Where e is in thousands of feet

T is in °F

Answer: The area of land =108 m²

Step-by-step explanation:

In the given piece of land is in the shape of a parallelogram.

Diagonals divide it into 2 equal parts.

So, area of parallelogram = 2 x (Area of triangle with sides 12m and 9 m and  15 m)

Heron's formula :

Area of triangle = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex], where [tex]s=\dfrac{a+b+c}{2}[/tex]

Let a= 12 , b= 9 and c = 15

[tex]s=\dfrac{12+9+15}{2}=18[/tex]

Area of triangle = [tex]\sqrt{18(18-12)(18-9)(18-15)}[/tex]

[tex]=\sqrt{18\times6\times9\times3}=\sqrt{2916}=54\ m^2[/tex]

Then, area of parallelogram= 2 x 54 = 108 m²

Hence, the area of land =108 m²

Answer:

38

Step-by-step explanation:

f(-9) is the value of f(x) when x = -9. Therefore, f(-9) = 4 from the graph. Doing the same with g(6), we can see that g(6) = 6. Our expression becomes:

-1 * 4 + 7 * 6

= -4 + 42

= 38

Answer:

La magnitud del desplazamiento resultante es 2045.463 kilómetros. La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.

Step-by-step explanation:

En primer lugar, se construye el triángulo. La figura resultante se encuentra incluida como archivo adjunto. La magnitud del desplazamiento resultante se determina mediante la Ley del Coseno:

[tex]r = \sqrt{(800\,km)^{2}+(1400\,km)^{2}-2\cdot (800\,km)\cdot (1400\,km)\cdot \cos 135^{\circ}}[/tex]

[tex]r \approx 2045.463\,km[/tex]

La magnitud del desplazamiento resultante es 2045.463 kilómetros.

La dirección del desplazamiento resultante es hallada por medio de la Ley del Seno, sabiendo que el ángulo del desplazamiento resultante a la recta de 1400 kilómetros:

[tex]\frac{1400\,km}{\sin \alpha} = \frac{2045.463\,km}{\sin 135^{\circ}}[/tex]

Se despeja el ángulo correspondiente:

[tex]\alpha = \sin^{-1}\left(\frac{1400\,km}{2045.463\,km}\times \sin 135^{\circ} \right)[/tex]

[tex]\alpha \approx 28.945^{\circ}[/tex]

La dirección absoluta del desplazamiento resultante es:

[tex]\alpha' = 180^{\circ}-\alpha[/tex]

[tex]\alpha' = 180^{\circ}-28.945^{\circ}[/tex]

[tex]\alpha' = 151.055^{\circ}[/tex]

La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.

Answer:

The 1st selection is appropriate.

_____

2nd: the rotation would need to be 90° CCW

3rd, 4th: rotation or double reflection will give the original orientation. This figure is reflected an odd number of times, so has its orientation reversed.

Hope it helps.. Mark brainliest

The sequence of transformations are reflection over the y-axis and then a rotation 90 clockwise about the origin.

Here are the rotation rules: 90° clockwise rotation: (x, y) becomes (y, -x) 90° counterclockwise rotation: (x, y) becomes (-y, x) 180° clockwise and counterclockwise rotation: (x, y) becomes (-x,-y).

Given that, figure G is rotated 90° clockwise about the origin and then reflected over the x-axis, forming figure H.

Vertices of triangle G are (-3, 1), (-1, 2) and (-2, 5).

The reflection of point (x, y) across the y-axis is (-x, y).

On reflection over x-axis, we get coordinates as (3, 1), (1, 2) and (2, 5)

90° clockwise rotation: (x, y) becomes (y, -x)

On 90° clockwise rotation, we get coordinates as (1, -3), (2, -1) and (5, -2)

Triangle H has points (2, -1), (1, -3), (5, -2).

Hence, the sequence of transformations are reflection over the y-axis and then a rotation 90° clockwise about the origin.

Learn more about the rotation of 90° counterclockwise here:

brainly.com/question/1571997.

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Answer:

420

Step-by-step explanation:

To find 63% of 6000, we can do 0.63 * 6000 = 3780 because 63% = 0.63.

1/9th of that is 1/9 * 3780 = 420.

Answer:

420

Step-by-step explanation:

Let's first start by finding 63% of 6000 so we can later find 1/9 of that number.

We can set up a percentage proportion.

[tex]\frac{x}{6000} = \frac{63}{100}[/tex]

[tex]6000\cdot63=378000\\378000\div100 = 3780[/tex]

Now to find 1/9 of 3780.

[tex]\frac{1}{9} \cdot \frac{3780}{1}\\\\\frac{3780}{9} = 420[/tex]

So, the answer is 420.

Hope this helped!

Answer:

(5,-6)

Step-by-step explanation:

ONE WAY:

If [tex]f(x)=x^2-6x+3[/tex], then [tex]f(x-2)=(x-2)^2-6(x-2)+3[/tex].

Let's simplify that.

Distribute with [tex]-6(x-2)[/tex]:

[tex]f(x-2)=(x-2)^2-6x+12+3[/tex]

Combine the end like terms [tex]12+3[/tex]:

[tex]f(x-2)=(x-2)^2-6x+15[/tex]

Use [tex](x-b)^2=x^2-2bx+b^2[/tex] identity for [tex](x-2)^2[/tex]:

[tex]f(x-2)=x^2-4x+4-6x+15[/tex]

Combine like terms [tex]-4x-6x[/tex] and [tex]4+15[/tex]:

[tex]f(x-2)=x^2-10x+19[/tex]

We are given [tex]g(x)=f(x-2)[/tex].

So we have that [tex]g(x)=x^2-10x+19[/tex].

The vertex happens at [tex]x=\frac{-b}{2a}[/tex].

Compare [tex]x^2-10x+19[/tex] to [tex]ax^2+bx+c[/tex] to determine [tex]a,b,\text{ and } c[/tex].

[tex]a=1[/tex]

[tex]b=-10[/tex]

[tex]c=19[/tex]

Let's plug it in.

[tex]\frac{-b}{2a}[/tex]

[tex]\frac{-(-10)}{2(1)}[/tex]

[tex]\frac{10}{2}[/tex]

[tex]5[/tex]

So the [tex]x-[/tex] coordinate is 5.

Let's find the corresponding [tex]y-[/tex] coordinate by evaluating our expression named [tex]g[/tex] at [tex]x=5[/tex]:

[tex]5^2-10(5)+19[/tex]

[tex]25-50+19[/tex]

[tex]-25+19[/tex]

[tex]-6[/tex]

So the ordered pair of the vertex is (5,-6).

ANOTHER WAY:

The vertex form of a quadratic is [tex]a(x-h)^2+k[/tex] where the vertex is [tex](h,k)[/tex].

Let's put [tex]f[/tex] into this form.

We are given [tex]f(x)=x^2-6x+3[/tex].

We will need to complete the square.

I like to use the identity [tex]x^2+kx+(\frac{k}{2})^2=(x+\frac{k}{2})^2[/tex].

So If you add something in, you will have to take it out (and vice versa).

[tex]x^2-6x+3[/tex]

[tex]x^2-6x+(\frac{6}{2})^2+3-(\frac{6}{2})^2[/tex]

[tex](x+\frac{-6}{2})^2+3-3^2[/tex]

[tex](x+-3)^2+3-9[/tex]

[tex](x-3)^2+-6[/tex]

So we have in vertex form [tex]f[/tex] is:

[tex]f(x)=(x-3)^2+-6[/tex].

The vertex is (3,-6).

So if we are dealing with the function [tex]g(x)=f(x-2)[/tex].

This means we are going to move the vertex of [tex]f[/tex] right 2 units to figure out the vertex of [tex]g[/tex] which puts us at (3+2,-6)=(5,-6).

The [tex]y-[/tex] coordinate was not effected here because we were only moving horizontally not up/down.

Answer:

The value of x is 35

Step-by-step explanation:

In order to calculate the value of x in the  following parallelogram:  2x - 10  

2x + 50, we would have to calculate the following formula:

m<QPS+m<PQR=180°

According to the given data we have the following:

m<QPS=2x - 10  

m<PQR=2x + 50

Therefore, 2x - 10+2x + 50=180

4x+40=180

x=140/4

x=35

Answer:

22 units.

Step-by-step explanation:

In 45- 45- 90 triangles, there is a 1 to 1 to the square root of 2 formula. Each side length measures 1x, while the hypotenuse measures x times the square root of 2.

In this case, the hypotenuse measures 22 and the square root of 2 units. To find the value of x, simply divide that by the square root of 2 units, and you get x = 22 units. Multiply that by 1, and you get 22 units, which is the length of the leg of the triangle.

Hope this helps!

Answer:

25 children

So , each child will get 25 pens and 7 pencils

You have to find the highest common factor of 125 and 175 which is 25 and then you have to multiply it by those two numbers to find how may pens and pencils will be given to 1 child

Hope this helps and pls mark as brianliest :)

Answer:

prime

Step-by-step explanation:

x^2 - 2x + 3

What two numbers multiply to 3 and add to -2

There are none so this cannot be factored in the real numbers

Answer:

541.4 m²

Step-by-step Explanation:

Step 1: find m < V

V = 180 - (50+63) (sum of the angles in ∆)

V = 67

Step 2: find side length of XW using the law of sines

[tex] \frac{XW}{sin(V)} = \frac{XV}{sin(W)} [/tex]

Where,

V = 67°

W = 63°

XV = 37 m

XW

[tex] \frac{XW}{sin(67)} = \frac{37}{sin(63)} [/tex]

Multiply both sides by sin(67) to solve for XW

[tex] \frac{XW}{sin(67)}*sin(67) = \frac{37}{sin(63)}*sin(67) [/tex]

[tex] XW = \frac{37*sin(67)}{sin(63)} [/tex]

[tex] XW = 38.2 m [/tex] (to nearest tenth)

Step 3: find the area using the formula, ½*XW*XV*sin(X)

area = ½*38.2*37*sin(50)

Area = 541.4 m² (rounded to the nearest tenth.

Answer:

7.5 jars

Step-by-step explanation:

There are 25 students in the art class.

Mr Jones is planning that for the project, each of the 25 students will need 0.3 jar of paint.

The amount of paint Mr Jones needs for this project is therefore the product of the number of students in the class by the amount of paint each student needs.

That is:

25 * 0.3 = 7.5 jars of paint

Mr Jones needs 7.5 jars of paint for the art project.

Answer:

y= [tex]\sqrt{x}[/tex]

Step-by-step explanation:

Hey there! I'm happy to help!

When talking about percents, the word "is" usually means equals. Let's use this to solve an equation! We will call our number n. Note that 30% is equal to 0.3 in decimal form because 0.3 is 30% of one! :D

0.3n=45

To solve, we need to isolate the n. To do this, we divide both sides by 0.3 because this cancels out the 0.3 that is being multiplied by n and it shows us what n will then equal.

0.3n÷0.3=45÷0.3

n=150

Therefore, 30% of 150 is 45. Try multiplying 0.3 by 150 and you will get 45!

Have a wonderful day! :D

Answer:

The answer is 21.25cm

Step-by-step explanation:

Hope i am marked as brainliest

Answer:  y = -2

Step-by-step explanation:

f(x) = A cos (Bx - C) + D

                                  ↓

                                center line (aka midline)

f(x) = 2 cos (3x - 5π/6) - 2

                                      ↓

                                  midline = -2

The midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D

It is defined as a function that is sin-cos wave in nature, and it has a domain of all real numbers and lies between the [a, a] where is the amplitude of the function.

It is given that the cos function is:

f(x) = 2cos(3x - 5π/6) - 2

As we know, the standard form of the cos function is:

f(x) = Acos(Bx - C) + D

Here, A is the amplitude

B is the period of the cos function

C is the phase shift of the cos function

D is the vertical shift of the cos function/midline

On comparing:

D = -2

The midline:

y = -2

Thus, the midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D

Learn more about the cos function here:

https://brainly.com/question/14397255

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Answer:

2(a - 3). = 4

_______

3

Cross multiply.

2(a- 3) = 12

2a - 6 = 12

2a = 12 + 6

2a = 18

a = 18 ÷ 2

a = 9

Answer:

a = 9

Step-by-step explanation:

Given

[tex]\frac{2(a-3)}{3}[/tex] = 4 ( multiply both sides by 3 to clear the fraction

2(a - 3) = 12 ( divide both sides by 2 )

a - 3 = 6 ( add 3 to both sides )

a = 9

As a check substitute a = 9 into the left side of the equation and if equal to the right side then it is the solution.

[tex]\frac{2(9-3)}{3}[/tex] = [tex]\frac{2(6)}{3}[/tex] = [tex]\frac{12}{3}[/tex] = 4 = right side

Thus solution is a = 9

Answer:

y = -8

Step-by-step explanation:

Start by filling 8 in place of x

y = 8 - 2(8)

Multiply -2(8)

y = 8 - 16

Subtract 16 from 8

y = -8

Answer:

B, C, D

Step-by-step explanation:

if tan theta = 15/8 then the hypotenuse is 17

therefore the correct answers are B, C, D

Answer:

A,C,D

Step-by-step explanation:

When b=0, there is a proportional relationship.

The slope in y=mx+b is the value next to x.

Using RISE/RUN when there is a change of 3 units in x, there is a change of 2 units in y.

Answer:

I think that it should be

[tex] {(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)[/tex]

Step-by-step explanation:

Here,

we take , a - b = A,b-c = B , c - a= C

A+B+C = 0

we know that,

[tex] {a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)[/tex]

Here , A+B+C = 0

so,

A^3 +B^3 + C^3 = 3 ABC

now we put the values

[tex]{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)[/tex]

I am done .

I think that it should be

{(a - b)}^{3}  +  {(b - c)}^{3}  +  {(c - a)}^{3}  = 3(a - b)(b - c)(c - a)

Step-by-step explanation:

Here,

we take , a - b = A,b-c = B , c - a= C

A+B+C = 0

we know that,

{a}^{3}  +  {b}^{3}  +  {c}^{3}   - 3abc = (a + b + c)(  {a}^{2}  +  {b}^{2}  +  {c}^{2}  - ab - bc - ca)

Here , A+B+C = 0

so,

A^3 +B^3 + C^3 = 3 ABC

now we put the values

{(a - b)}^{3}  +  {(b - c)}^{3}  +  {(c - a)}^{3}  = 3(a - b)(b - c)(c - a)

I am done .