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Answer:

Which of the following graphs is described by the function given below?

y = 2x2 + 6x + 3

-A. Graph A

The function y = 2x^2 + 6x + 3 is a quadratic function that has a vertex of (-1.5,-1.5)

The equation of the function is given as:

y = 2x^2 + 6x + 3

Differentiate

y' = 4x + 6

Set to 0

4x + 6 = 0

This gives

4x = -6

Divide by 4

x = -1.5

Substitute x = -1.5 in y = 2x^2 + 6x + 3

y = 2(-1.5)^2 + 6(-1.5) + 3

Evaluate

y = -1.5

This means that the function y = 2x^2 + 6x + 3 has a vertex of (-1.5,-1.5)

See attachment for the graph of y = 2x^2 + 6x + 3

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subtract 2 from both sides

3a - 3y =  15 - 2x

factor out the common term 3

3 (a-y) = 15 - 2x

divide both sides by 3

a - y = 15 - 2x/3

add y to both sides

a = 15-2x/3 + y

then solve put the value for a =

15-2x/3 + y + 7 ÷10​

simplify using the common denominator

10(15-2x)+7*3/30

simplify 7 * 3 to 21

10(15-2x)+21/30

expand

150-20x+21/30

simplify 150-20x+21 to -20x + 171

-20x+171/30

Answer: -20x+171/30

[tex]\huge\bf Question:– [/tex]

[tex]\sf \longmapsto \: 3a+2x−3y=15[/tex]

[tex] \bf \huge \: To \: Find:–[/tex]

[tex] \boxed{\bf \: Value\: of \: A}[/tex]

[tex]\huge\bf Solution:–[/tex]

[tex]\sf \longmapsto \: 3a+2x−3y=15[/tex]

[tex]\boxed{ \bf \: Add -2x \: to \: both \: sides}[/tex]

[tex]\sf \longmapsto \: 3a+2x−3y+−2x=15+−2x[/tex]

[tex]\sf \longmapsto \: 3a−3y=−2x+15[/tex]

[tex]\boxed{ \bf \: Add \: 3y \: to \: both \: sides}[/tex]

[tex]\sf \longmapsto \: 3a−3y+3y=−2x+15+3y[/tex]

[tex]\sf \longmapsto \: 3a=−2x+3y+15[/tex]

[tex] \boxed{\bf \: \: Divide \: both \: sides \: by \: 3}[/tex]

[tex]\sf \longmapsto \: \dfrac{3a}{3} = \dfrac{−2x+3y+15}{3} [/tex]

[tex] \boxed{\bf \: Cross \: Multiply}[/tex]

[tex]\boxed{\sf \longmapsto \: a = \dfrac{ - 2}{3} x + y + 5}[/tex]

______________________________________

[tex]\bf \: Put\:The\: Value[/tex]

[tex] \sf \longmapsto \: \dfrac{−2x+3y+15}{3} +7÷10[/tex]

[tex] \boxed{\bf \: Distribute}[/tex]

[tex]\sf \longmapsto \: \dfrac{ - 2}{3} x+y+5+ \dfrac{7}{10} [/tex]

[tex] \boxed{\bf \: Combine \: Like \: terms}[/tex]

[tex]\sf \longmapsto \: \bigg( \dfrac{ - 2}{3} x\bigg) + y +\bigg( 5 + \dfrac{7}{10} \bigg)[/tex]

[tex]\sf \longmapsto \: \dfrac{ - 2}{3} x + y + \dfrac{57}{10} [/tex]

______________________________________

[tex]\boxed{\bf The Answer\: is:–}[/tex]

[tex]\boxed{{\underline{\bf\dfrac{ - 2}{3} x + y + \dfrac{57}{10}} }}[/tex]

Answer:

18.6cm

Step-by-step explanation:

there is a theorem that states that the midsegment of a triangle (midpoint to midpoint, in this case X and Y) is half of the base (in this case BC)

when applied to the triangle shown:

XY= 1/2 BC

substitute to get

XY=1/2*6.4

XY=3.2

perimeter of BCYX

=XY+YC+CB+BX

=3.2+4+6.4+5

=18.6cm

hope this helps

Answer: B

Step-by-step explanation: Jacob doesn't know either colleges' actual price. Bayside could still be equal to or more expensive than Lakeshore.

Based on the equation given, it can be deduced that the value of the number will be 36.

Let the number be represented by x

Therefore, seven less than one-fourth of a number will be:

=(1/4 × x) - 7

= 0.25x - 7

Now, seven less than one-fourth of a number is 2 will be written as:

0.25x - 7 = 2

0.25x = 2 + 7

0.25x = 9

x = 9/0.25

x = 36

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Answer:

6cm

Step-by-step explanation:

let height of ladder be x

so if height of ladder is x then the distance from the base of the ladder to the base of the slide is x+2

Assuming this is a right angle triangle, the slide is the longest lenght (c)

so

x²+(x+2)²=10²

x²+x²+4x+4=100

2x²+4x+4=100

2x²+4x+4-100=0

2x²+4x-96=0

2(x²+2x-48)=0

x²+2x-48=0 -- Factor

(x+8)(x-6)=0

x=-8 and x=6

since height cannot be a negative number

height of ladder is 6 cm

The base length is 8 feet. Then the height of the triangle will be 6 feet.

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

The length of a slide on a swing set is 10 ft.

The distance from the base of the ladder to the base of the slide is 2 ft more than the height of the ladder.

Let x be the length of the height of the triangle. Then the base of the triangle will be (x + 2).

10² = (x + 2)² + x²

100 = x² + 4x + 4 + x²

96 = 2x² + 4x

48 = x² + 2x

0 = x² + 2x - 48

0 = (x - 6)(x + 8)

x = 6, -8

Then the base length is 6 ft. Then the height of the triangle will be

B = x + 2

B = 6 + 2

B  = 8 ft

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Answer:

communtitve property of multiplication

Answer:

3.0

4.5

6.0

7.5

Step-by-step explanation:

it rains at the rate of 1.5cm per hour

In two hours, the amount will be; 1.5 × 2

= 3cm

in the three hours, the amount will be 1.5×3

=4.5cm

in four hours, the amount will be; 1.5×4

=6cm

in five hours, the amount will be; 1.5×5

=7.5cm

Answer:

speed = distance/ time so:

(2/7) / (2/5) = (2/7) x (5/2) = 10/14 = 5/7 mph

5/7 = 0.71 miles per hour if you need decimal formatStep-by-step explanation:

Step-by-step explanation:

2/7 miles in 2/5 hours.

to bring this to x miles / 1 hour, we must find the factor for 2/5 to turn into 1.

2/5 × f = 1

f = 5/2

in order to keep the value of the original ratio, we now need to multiply also 2/7 by the same factor (5/2).

2/7 × 5/2 = 10/14 = 5/7

so, the unit rate is 5/7 miles / hour.

which is very slow walking.

Answer:

8 1/10

Step-by-step explanation:

mark brainliest if correct

Answer:

x = 35°

Step-by-step explanation:

These are corresponding angles. When a transversal crosses 2 parallel lines, 4 angles are created at each intersection, and each pair of corresponding angles between those are congruent.

These angles are congruent, so you can set them equal to each other:

[tex]2x+20=3x-15[/tex]

Then, just solve for x:

[tex]20=x-15\\35=x\\x=35[/tex]

You can check that by plugging it back into both:

[tex]2x+20=3x-15\\2(35)+20=3(35)-15\\70+20=105-15\\90=90[/tex]

Answer:

x = 35

Step-by-step explanation:

The angles shown are corresponding angles

Corresponding angles are congruent ( equal to each other )

This means that 2x + 20 should equal 3x - 15

Note that we've just created an equation that we can use to solve for x

We know use that equation to solve for x

2x + 20 = 3x - 15

add 15 to both sides

2x + 35 = 3x

subtract 2x from both sides

35 = x

And we are done!

The distance traveled by Raven in 1 hour at the given rate is 4.0 miles.

The given parameters:

The speed of Raven motion is calculated as follows;

[tex]V = \frac{Distance}{Time} \\\\V = Distance\ \times \ \frac{1}{Time} \\\\V = 2\frac{2}{5} \ miles \ \ \times \ \ \frac{1}{3/5 \ hr} \\\\V = \frac{12}{5} \ miles \ \ \times \ \ \frac{5}{3 hr} \\\\V = 4 \ mph[/tex]

The distance traveled by Raven in 1 hour at the given rate is calculated as follows;

[tex]D = 4 \times 1\\\\D = 4 \ miles[/tex]

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[tex] \sqrt[6]{x} . \sqrt[4]{ {y}^{3} } \\ = {x}^{ \frac{1}{6} } . {y}^{ \frac{3}{4} } \\ = {x}^{ - 6} . {y}^{ \frac{3}{4} } [/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

You can send 405 texts in 2008 without going over 100$

Step-by-step explanation:

Equation for 2008:

59$ for 200 texts + .20 dollars per text after that < or = $100

So minus $59 dollars

.20 * (number of txts) < 100 - 59

.20 * (number of txts) < 41

divide both sides by .2

number of txts < or = 205

so therefore you can send exactly 405 texts without going over $100

Then to find how much you would pay plug into this equation

If total number of texts is lower than 200 texts, then you would be paying $59, but if it is more then plug into the following equation

(Total number of texts - 200) * .20 + 59 = Total $ spent for a 2008 text plan per month.

The total number of texts that can be sent is 405 texts in 2008 without going over 100$. The amount will be $99.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The equation for 2008:

59$ for 200 texts + 0.20 dollars per text after that < or = $100 and minus $59 dollars

0.20 x  (number of texts) < 100 - 59

0.20 x  (number of texts) < 41

Divide both sides by 0.2

number of texts < or = 205

405 texts can be sent without going over $100

If the total number of texts is lower than 200 texts, then you would be paying $59, but if it is more then plug into the following equation

(Total number of texts - 200) x  0.20 + 59 = Total $ spent for a 2008 text plan per month.

( 405 - 200 ) x 0.2 + 59 = $99

Therefore,  the total number of texts that can be sent is 405 texts in 2008 without going over 100$. The amount will be $99.

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Answer:

9x = 72; x = 8 times as many stamps

Step-by-step explanation:

Answer:

9×=72;×=8 times as many stamps

Answer:

Domain:(−∞,2)∪(2,∞),{x|x≠2}

Range:(−∞,0)∪(0,∞),{y|y≠0}

Answer:

2

Ok lets start off with your 3 numbers

First do 10 / 5 = 2

Then do 12 / 6 = 2

After that do 20 / 10 = 2

now you see you that its all equivalent to 2 that's your answer!

Answer:

440 miles

Step-by-step explanation:

First, you need to calculate the number of miles per hour. To do this, take the total number of miles traveled and divide it by the number of hours it took. 360/9=40. This means Kaitlyn drove at 40 miles per hour. Then, we need to multiply 40 by 11 to figure out the number of miles she drove in 11 hours because her speed stayed the same. 40*11=440. This means Kaitlyn will have driven 440 miles in 11 hours.

Hope this helps! :)

Answer:

three hundred twenty one and fifty one hundredths

Answer:

The choice 3;

[tex]x = 15 \: \: \: \\ y = 17[/tex]

Step-by-step explanation:

[tex]m < 2 = m < 4[/tex]

Opposite;

[tex]7x + 7 = 112 \\ 7x = 112 - 7 \\ 7x = 105 \\ \\ x = \frac{105}{7} \\ \\ x = 15[/tex]

____o__o___

[tex]m < 3 + m < 4 = 180 \\ 4y + 112 = 180 \\ 4y = 180 - 112 \\ 4y = 68 \\ \\ y = \frac{68}{4} \\ \\ y = 17[/tex]

Answer:

Multiples: 16, 32, 48, 64, 80 Factors: 1, 2, 4, 8 and 16

Step-by-step explanation:

hope this helped :3

Answer:

  (c)  y^2/16 -(x -7)^2/9 = 1

Step-by-step explanation:

The center, focus, and vertex are on a vertical line, so the hyperbola opens in the direction of the y-axis. The y-term will have the positive coefficient.

The vertex-center distance in the y-direction is 4, so the denominator of the y-term is 4^2 = 16. The denominator of the x-term is 5^2 -16 = 9, where 5 is the center-focus distance.

The equation is ...

  y^2/16 -(x -7)^2/9 = 1

The inverse of an implication p ⇒ q is ¬p ⇒ ¬q.

The converse of p ⇒ q is q ⇒ p.

The contrapositive of p ⇒ q is ¬q ⇒ ¬p.

Then

• the inverse of the inverse of p ⇒ q is p ⇒ q

• the inverse of the the converse of p ⇒ q is ¬q ⇒ ¬p

• the inverse of the contrapositive of p ⇒ q is q ⇒ p

Answer:

hi there !

The answer is "30/40"

because by dividing each nominator and denominator by "10" it gives 3/4

Answer:

  x + y -z = 6

Step-by-step explanation:

The equation of the line can be rewritten as ...

  (x, y, z) = (2, -3, 0) +t(1, 1, -1)

The direction vector of the line tells you the coefficients of the variables in the equation of the plane. The constant in that plane equation will be the value required to make it pass through the given point.

  x + y - z = (-1) +(4) -(-3)

  x + y - z = 6 . . . . equation of the plane

Answer:

Every f(x) shall decrease to 5 times the previous value.

Answer:

180 - 17 - 14 =149

180 - 149 = 31*

Step-by-step explanation:

Answer: 180 - 17 - 14 =149180 - 149 = 31*

Step-by-step explanation: it’s right

[tex]\text{First term, a =6}\\\\\text{Common difference, d = 13 -6 = 7}\\\\\text{Nth term} = a+(n-1)d = 6 +(n-1)7 = 6+7n-7 = 7n-1\\\\\text{60th term} = 7(60) -1 = 419[/tex]

The charge of the electrons is [tex]8.02 \times 10^{-19} \ C[/tex].

The given parameters:

The angular speed of the electron is calculated as follows;

[tex]\omega = 2\pi N\\\\\omega = 2\pi \ \frac{rad}{1 \ rev} \times 1.4 \times 10^6 \ rev/s\\\\\omega = 8.798 \times 10^6 \ rad/s[/tex]

The charge of the electrons is calculated as follows;

[tex]F_c= m\omega ^2 r\\\\F_{B}= qvB = q\omega r B \\\\F_c = F_B\\\\m\omega ^2 r = q\omega r B \\\\q = \frac{m\omega ^2 r}{\omega r B} \\\\q = \frac{m \omega }{B} \\\\q = \frac{9.11 \times 10^{-31} \times 8.798 \times 10^6}{10^{-5}} \\\\q = 8.02 \times 10^{-19} \ C[/tex]

The charge of the electrons is [tex]8.02 \times 10^{-19} \ C[/tex].

The complete question here:

Electrons execute 1.4*10^6 revolutions per sec in a magnetic field of flux density 10⁻⁵ T. What will be the value of charge of the electron?

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