Please help i'm in a hurry

Answer:

3 5/7

Step-by-step explanation:

Answer: to get range you subtract the largest and smallest numbers. so 18-3= 15 therefor, 15 is the range.

Hope this helps :)

50×100÷110=45.454545r6

Answer:

1. 6cm , 8cm , 10cm

2. 3cm , 4cm , 5cm

Step-by-step explanation:

Answer:

I think answer is C. 4

Step-by-step explanation:

8:2=4

Given:

The equations of circle are

4. [tex]\left(x+\dfrac{2}{3}\right)^2+(y+1)^2=24[/tex]

5. [tex](x-1)^2+(y+2)^2=28[/tex]

6 .[tex](x+12)^2+y^2=\dfrac{3}{64}[/tex]

To find:

The center and radius for the given circles.

Solution:

The standard form of a circle is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where, [tex](h,k)[/tex] is center and [tex]r[/tex] is the radius of the circle.

4.

The equation of the circle is

[tex]\left(x+\dfrac{2}{3}\right)^2+(y+1)^2=24[/tex]

The standard form of this circle is

[tex]\left(x-(-\dfrac{2}{3})\right)^2+(y-(-1))^2=(\sqrt{24})^2[/tex]

[tex]\left(x-(-\dfrac{2}{3})\right)^2+(y-(-1))^2=(2\sqrt{6})^2[/tex]

Therefore, the center of the circle is [tex]\left(-\dfrac{2}{3},-1\right)[/tex] and the radius of the circle is [tex]2\sqrt{6}[/tex].

5.

The equation of the circle is

[tex](x-1)^2+(y+2)^2=28[/tex]

The standard form of this circle is

[tex](x-1)^2+(y-(-2))^2=(\sqrt{28})^2[/tex]

[tex](x-1)^2+(y-(-2))^2=(2\sqrt{7})^2[/tex]

Therefore, the center of the circle is [tex]\left(1,-2\right)[/tex] and the radius of the circle is [tex]2\sqrt{7}[/tex].

6.

The equation of the circle is

[tex](x+12)^2+y^2=\dfrac{3}{64}[/tex]

The standard form of this circle is

[tex](x-(-12))^2+(y-0)^2=(\sqrt{\dfrac{3}{64}})^2[/tex]

[tex](x-(-12))^2+(y-0)^2=\dfrac{\sqrt{3}}{8}[/tex]

Therefore, the center of the circle is [tex]\left(-12,0\right)[/tex] and the radius of the circle is [tex]\dfrac{\sqrt{3}}{8}[/tex].

Answer:

2676 yards

Step-by-step explanation:

12*223 is 2676

if each costume requires 223 yards then all you do is multiply the numbers

Answer:

A is 5, B is a irrational number because it doesn't terminate or repeat c is 7 and d is 8

Answer:

Student 2 and Student 3

Step-by-step explanation:

Student 2

-(5r - 3s + 1)

= - 5r +3s - 1

Student 3

= - 5r +3s - 1

Answer:

The probability of not spinning a 3 is [tex]\frac{8}{9}[/tex]

Step-by-step explanation:

The probability of spinning a 3 is 1/9. What is the probability of not spinning a 3?

Spinning a 3 and not spinning a 3 are complementary events, which means that the sum of their probabilities is decimal 1. So

[tex]\frac{1}{9} + p = 1[/tex]

[tex]p = 1 - \frac{1}{9} = \frac{9}{9} - \frac{1}{9} = \frac{8}{9}[/tex]

The probability of not spinning a 3 is [tex]\frac{8}{9}[/tex]

Answer:

20.76 ✨

hope that helped!!!!

Answer:

i think it's $60.68

Step-by-step explanation:

if I'm wrong plz correct me

Answer:

13/15

Step-by-step explanation:

The fraction of the cookies that are chocolate chip can be determined by solving this equation

1 - ([tex]\frac{4}{12}[/tex] - [tex]\frac{1}{5}[/tex])

1 - [tex]\frac{20 - 12}{60}[/tex]

1 - [tex]\frac{8}{60}[/tex]

[tex]\frac{60}{60}[/tex] - [tex]\frac{8}{60}[/tex] = [tex]\frac{52}{60}[/tex] = 13/15

Step-by-step explanation:

1. true

2. false

3.true

4.false

5. ( may be false)

6 .(may be false)

Answer:

(3,4)

Step-by-step explanation:

Answer:

90

Step-by-step explanation:

you have to multiply A B and C and you should get 90

i think i'm right

Answer:

naniiiiiiiiiiiiiiiiiiiiii

Answer:

uhmmuhmmmmmmmmuhmmmm

Answer:

Step-by-step explanation:

Given,

Marks of the four exams = 65, 80, 76, 68

Let the mark for the fifth exam be = x

Mean of the five exams = 70

Therefore,

By the problem,

[tex] = > \frac{65 + 80 + 76 + 68 + x}{5} = 70[/tex]

[tex] = > \frac{289 + x}{5} = 70[/tex]

=> 289 + x = 70 × 5

=> 289 + x = 350

=> x = 350 - 289

=> x = 61

Hence,

Marks of the fifth exam is 61 (Ans)

18.84

Hope this helps you!

Answer:

18.84

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

Apply absolute rule: | a | = a, a ≥ 0

| 13 | = 13

= 13 + | -2 |

| -2 | = 2

= 13 + 2

= 15

Answer:

angle B = 66.42

Step-by-step explanation:

cos-1 B = [tex]\frac{adjacent}{hypotenuse}[/tex]

cos-1 B = [tex]\frac{2}{5}[/tex]

cos-1 B = 0.40

cos-1 of 0.40 is 66.4218

round to the nearest hundreth = 66.42

angle b = 66.42

Answer:

y ≥ 1

since the graph starts at 1 and doesn't come below that

Answer:

I hoped this helped :))

Answer:

See below, please!

Step-by-step explanation:

We know that 6z-31+something is going to be equal to 180 degrees, because it is supplementary. But what is that something? We see 67 degrees. Do you think this is a corresponding angle to the something that we need to find? Yes, it is! So we know that 6z-31+67 is equal to 180. So, z is 24. Now, since we know the value of the something (67 degrees because of corresponding angles) we can find yet another pair of supplementary angles. 67+x=180! Kind of neat, huh? So, x is equal to 113.

Hope this helped!

Answer:

The discount takes $25 dollars off

Step-by-step explanation:

So yes, he'll pay $100 after the discount is applied

Answer:

25 dollars

Step-by-step explanation:

125 - 100= 25

Given:

The expression is

[tex]3x^4-81x[/tex]

To find:

The product of prime polynomials which is equivalent to the given expression.

Solution:

We have,

[tex]3x^4-81x[/tex]

Taking out the common factors, we get

[tex]=3x(x^3-27)[/tex]

It can be written as

[tex]=3x(x^3-3^3)[/tex]

[tex]=3x(x-3)(x^2+3x+3^2)[/tex]        [tex][\because a^3-b^3=(a-b)(a^2+ab+b^2)][/tex]

[tex]=3x(x-3)(x^2+3x+3^2)[/tex]

[tex]=3x(x-3)(x^2+3x+9)[/tex]

Therefore, the correct option is B.

Answer:

It's B

Step-by-step explanation:

Given:

In a triangle, side x has a length of 15 cm and side y has a length of 4 cm.

To find:

The possible value of side z.

Solution:

In a triangle, the sum of two smaller sides must be greater than the largest side otherwise the triangle is not possible.

Case I: Let x be the largest side, then

[tex]y+z>x[/tex]

[tex]4+z>15[/tex]

[tex]z>15-4[/tex]

[tex]z>11[/tex]               ...(i)

It is clear that [tex]y<x[/tex]. So, y cannot be a largest side.

Case II: Let z be the largest side, then

[tex]x+y>z[/tex]

[tex]15+4>z[/tex]

[tex]19>z[/tex]               ...(ii)

From (i) and (ii), we get

[tex]11<z<19[/tex]

It means the value of z lies between 11 and 19.

From the given options, only 17 is the value which lies between 11 and 19. So, the possible length of side z is 17 cm.

Therefore, the correct option is C.

Answer:

77 is 35% of:  220

Step-by-step explanation: