Answer:
–0.11 N.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 6.1 g
Initial velocity (u) = 350 m/s
Time (t) = 0.32 mins
Final velocity (v) = 0 m/s
Force (F) =?
Next, we shall convert 0.32 mins to seconds. This can be obtained as follow:
1 min = 60 s
Therefore,
0.32 mins = 0.32 × 60 = 19.2 s
Next, we shall determine the acceleration of the the bullet. This can be obtained as follow:
Initial velocity (u) = 350 m/s
Time (t) = 19.2 s
Final velocity (v) = 0 m/s
v = u + at
0 = 350 + (a × 19.2)
0 = 350 + 19.2a
Collect like terms
0 – 350 = 19.2a
–350 = 19.2a
Divide both side by 19.2
a = –350 / 19.2
a = –18.23 m/s²
Next, we shall convert 6.1 g to Kg.
1000 g = 1 Kg
Therefore,
6.1 g = 6.1 g × 1 Kg / 1000 g
6.1 g = 0.0061 Kg
Finally, we shall determine the force. This can be obtained as follow:
Mass (m) = 0.0061 Kg
Acceleration (a) = –18.23 m/s²
Force (F) =?
F = ma
F = 0.0061 × –18.23
F = –0.11 N
NOTE: The negative sign indicates that the force is in opposite direction.
Answer:
–0.11 N.
Explanation:
Hope this helps
e Which of the following particles that may be emitted in radioactive decay is not ionising?
A alpha
B beta minus
C neutron
D beta plus
Explanation:
C. neutron.
it does not contain ionizing characteristics.
hope it helps. :)
A tiger leaps horizontally from a 6.5 m tall rock with a speed of 3.5 ms. How many seconds will it take for her to land?
Answer: 1.15 s
Explanation:
Given
Height of rock h=6.5 m
The horizontal speed of tiger u=3.5 m/s
In the vertical direction, there is no initial speed
Using the equation of motion
[tex]\Rightarrow h=ut+\frac{1}{2}at^2\\\\\Rightarrow 6.5=0+\frac{1}{2}\times 9.8\times t^2\\\\\Rightarrow t=\sqrt{\dfrac{13}{9.8}}=1.15\ s[/tex]
Time taken is 1.15 s
2. A3 kg ball rolls forward toward a 6 kg ball moving in the opposite direction at 4.6 m/s to
the left. After their collision, the 3 kg ball bounces backward at 4.2 m/s to the left and the 6 kg
ball continues to the left at 1.5 m/s in the same direction. What was the initial velocity of the
3 kg ball?
Answer:
m1 v1 + m2 v2 = m1 V1 + m2 V2 conservation of momentum
m1 = 3 m2 = 6
v2 = -4.6
V1 = -4.2
V2 = -1.5
v1 = (m1 V1 + m2 V2 - m2 v2) / m1
v1 = (3 * -4.2 + 6 * -1.5 - 6 * -4.6) / 3
v1 = (-12.6 - 9 + 27.6) / 3 = 2 initial velocity of 3 kg ball
Check:
3 * 2 + 6 * -4.6 = -21.6
3 * -4.2 + 6 -1.5 = -21.6
Define Inertia.
___________✨
Answer:
a tendency to do nothing or to remain unchanged.
Explanation:
Answer:
Inertia: The resistance an object has to a change in its state of motion.
Explanation:
Hope it helps....
Have a great day!!
1.what are barriers that you have encountered in dancing?
2.how do you think you can overcome them?
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answer this ⭐
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correct brainlies
wrong report
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thank you
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Answer:
heyy tell me ur yo u tube ch annel name I'll subscribe it and how many sub scriber u have friend
Explanation:
and are u from Ireland?
A + 32.2 μC charge feels a 0.544 N force from a + 12.3p μC charge. How far apart are they? (u stands for micro.) [?] m
Answer:
r = 2.55 m
Explanation:
Given that,
First charge, q₁ = 32.2 μC
Second charge, q₂ = + 12.3 μC
The force between charges, F = 0.544 N
We need to find the distance between charges. The force between two charges is given by the formula as follows :
[tex]F=k\dfrac{q_1q_2}{r^2}\\\\r=\sqrt{\dfrac{kq_1q_2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 32.2\times 10^{-6}\times 12.3\times 10^{-6}}{0.544}} \\\\r=2.55\ m[/tex]
So, the charges are 2.55 m apart.
Answer:
2.55
Explanation:
Right on Acellus
Give the other guy brainliest
You can only give brainliest if 2 people answer
Wondering if you have enough rope to rappel to the ground, you drop a rock off the top, and hear the sound of it hitting the bottom 4.2 seconds later. Find the height of the cliff ignoring the time that the sound takes to travel back to you from the bottom.
Answer:
86.5 m
Explanation:
[tex]s = ut + \frac{1}{2} at {}^{2} \\ s = (0)(4.2) + \frac{1}{2} (9.81)(4.2) {}^{2} \\ s = 86.5m [/tex]
Answer:
86.5 m
Explanation:
HELP!!
Differentiate between hertz and decibel.
Answer:
Explanation:Hertz is used to measure frequency, but decibel is used to measure intensity level.
Which statements about braking a car are true?
The greater the kinetic energy of a car, the longer it takes for the car to stop.
The lower the kinetic energy of a car, the longer it takes for the car to stop.
If the speed of a car doubles, the car’s kinetic energy and braking distance quadruple.
If the speed of a car doubles, the car’s kinetic energy and braking distance remain the same.
Answer:
the first statement...
Answer:
The first answer is correct.
Plz mark brainliest.
Hope I helped.
Explanation:
Help me please I need to turn it in before midnight...
Answer:
The statement which explains how the total time spent in the air is affected as the projectile's angle of launch increases from 25 degrees to 50 degrees is;
C. Increasing the angle from 25° to 50° will increase the total time spent in the air
Explanation:
The equation that can be used to find the total time, T, spent in the air of a projectile is given as follows;
[tex]T = \dfrac{2 \cdot u \cdot sin(\theta) }{g}[/tex]
Where;
T = The time of flight of the projectile = The time spent in the air
u = The initial velocity of the projectile
θ = The angle of launch of the projectile
g = The acceleration due to gravity ≈ 9.81 m/s²
Given that sin(50°) > sin(25°), when the angle of launch, θ, is increased from 25 degrees to 50 degrees, we have;
Let T₁ represent the time spent in the air when the angle of launch is 25°, and let T₂ represent the time spent in the air when the angle of launch is 50°, we have;
[tex]T_1 = \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}[/tex]
[tex]T_2 = \dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g}[/tex]
sin(50°) > sin(25°), therefore, we have;
[tex]\dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g} > \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}[/tex]
Therefore;
T₂ > T₁
Therefore, increasing the angle at which the projectile is launched from 25° to 50° will increase the total time spent in the air.
Apply: The earth's gravity is pulling on you. Are you pulling on the earth? Explain your
reasoning.
Answer:
Yes, you are pulling on Earth. Reasoning. Third Newton's law of motion, action and reaction law, sates that for every action force, there is an equal (in magnitude) and opposite reaction force.
Explanation:
goo gle.
10 Waves Question 2 of 10 A wave travels at a speed of 74 m/s. If the distance between crests is 12 m, what is the frequency of the wave? Use j A. 0.16 Hz B. 6.2 Hz C. 890 Hz D. 62 Hz SUBMIT
Answer: B 6.2 Hz
Explanation: Equation for waves v = λf.
Frequency = speed / wavelength f = v/λ
f = 74 m/s / 12 m = 6.166... Hz
Answer:
Rounding is necessary: the answer is 6.2 Hz
Explanation:
Help me solve this please
Hey there!
Based on the info this planet is likely to be located near the sun. If you would like to be exact it would be between Mercury and Venus. This is because it’s orbital period is half a year, Venus is about 3/4 of a year, and Mercury is about 1/3 of a year. Hopefully this helps! Good luck!
a solid sphere of mass and radius 20kg and 4m is rotating with an angular velocity of 40rad/sec is accelerated uniformly to 60rad/sec in 2sec what is the torque acting on the sphere? (I=0•4MR^2)
Answer:
1280Nm
Explanation:
torque= I×alpha(angular acceleration)
so Angular acceleration is found by the following process.
A rocket with a mass of 0.5kg is travelling at 400m/s strikes and sticks in a block of wood with a mass of 50kg. find velocity of rocket.
Answer:
36.36 m/s
Explanation:
From the question,
Applying the law of conservation of momentum.
Total momentum before collision = Total momentum after collision .
mu+m'u' = V(m+m')................ Equation 1
Where m = mass of the rocket, m' = mass of the wood, u = initial velocity of the rock, u' = initial velocity of the wood, V = Final velocity after collision
But, the wood was initially at rest
Therefore, u' = 0 m/s
mu = V(m+m')
make V the subject of the equation
V = mu/(m+m')................. Equation 2
Given: m = 0.5 kg, u = 400 m/s, m' = 50 kg
Substitute these values into equation 2
V = (0.5×400)/(0.5+50)
V = 200/5.5
V = 36.36 m/s
PLZ HELP ME ASAP!!! 50 POINTS IF CORRECT! AND BRAINLEST
Answer:
B and C is the Answer
Follow me please
Mark brainliest
Which of the following combinations would result in the least acceleration?
O SN and 0.35 kg
60N and 2.0 kg
O 12N and 1.0 kg
O IN and 0.20 kg
please help!!
A baseball cannon fires balls at an initial speed of 29 m/s. The cannon is tilted at a 52o angle.
(a) How long could one of these balls stay in the air ?
(b) How far from the cannon, will the ball hit the ground ?
(c) What will be ball’s maximum altitude ?
Answer:
(a) The time the ball stays in the air is approximately 4.66 seconds
(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters
(c) The maximum altitude of the ball is approximately 26.62 m
Explanation:
The given parameters of the question are;
The initial velocity at which a baseball cannon fires balls, u = 29 m/s
The angle at which the cannon is tilted, θ = 52°
(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;
[tex]2 \cdot t = \dfrac{2 \cdot u \cdot sin (\theta)}{g}[/tex]
Where;
t = The time it takes the baseball to reach maximum height
2·t = The total time of flight = The time the ball stays in the air
θ = The angle at which the ball is tilted = 52°
g = The acceleration due to gravity ≈ 9.81 m/s²
u = The initial velocity = 29 m/s
Therefore, we have;
[tex]2 \cdot t = \dfrac{2 \times 29 \ m/s\times sin (52^{\circ})}{9.81 \ m/s^2} \approx 4.66 \ s[/tex]
The time the ball stays in the air, 2·t ≈ 4.66 seconds
(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;
[tex]Horizontal \ range, R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}[/tex]
∴ The distance from the cannon at which the ball will hit the ground = R
[tex]Horizontal \ range, R = \dfrac{(29 \ (m/s))^2 \cdot sin(2 \times 52^{\circ}) }{9.81 \ m/s^2} \approx 83.18 \, m[/tex]
The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters
(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;
[tex]H = \dfrac{u^2 \cdot sin^2 (\theta)}{2 \cdot g}[/tex]
Therefore, we have;
[tex]H = \dfrac{(29 \ m/s)^2 \times sin^2 (52^{\circ})}{2 \times 9.81 \ m/s^2} \approx 26.62 \ m[/tex]
The maximum altitude of the ball ≈ 26.62 m
A moving object has a kinetic energy of 150J and a momentum of 20.3kgxm/s find the speed of the object in m/s
Answer:
[tex]v = 14.78m/s[/tex]
Explanation:
Given
[tex]KE = 150J[/tex]
[tex]p = 20.3kgm/s[/tex]
Required
Determine the object's speed
Kinetic Energy is calculated as:
[tex]KE = \frac{1}{2}mv^2[/tex]
Make m the subject
[tex]m = \frac{2KE}{v^2}[/tex]
Momentum is calculated as:
[tex]p = mv[/tex]
Make m the subject
[tex]m = \frac{p}{v}[/tex]
So, we have:
[tex]m = \frac{p}{v}[/tex] and [tex]m = \frac{2KE}{v^2}[/tex]
Equate both expressions: [tex]m = m[/tex]
[tex]\frac{2KE}{v^2} = \frac{p}{v}[/tex]
Multiply both sides by v
[tex]v * \frac{2KE}{v^2} = \frac{p}{v}*v[/tex]
[tex]\frac{2KE}{v} = p[/tex]
Make v the subject
[tex]v = \frac{2KE}{p}[/tex]
Substitute [tex]KE = 150J[/tex] and [tex]p = 20.3kgm/s[/tex]
[tex]v = \frac{2 * 150}{20.3}[/tex]
[tex]v = \frac{300}{20.3}[/tex]
[tex]v = 14.78m/s[/tex]
Define the unit of current. Name the device which is used to measure
electric current in a circuit.
Answer:
The ampere, symbol A, is the SI unit of electric current. It is defined by taking the fixed numerical value of the elementary charge e to be 1.602 176 634 x 10-19 when expressed in the unit C, which is equal to A s, where the second is defined in terms of ΔνCs.
the device used to measure current in a circuit is ammeter
which is the best description of a soil sample with a pH of 4.5?
a. acidic
b. basic
c. inconclusive
d. neutral
Answer:
A. Acidic
Explanation:
I hope this helped!
A race car has a mass of 710kg. It starts from rest and speeds up to 12m/s in 12.0s. The car is uniformly accelerated during the entire time. What net force is applied to it?
9- When the moon comes in an orbit higher from earth, ......... solar eclipse are formed.
a) total
b) annular
c) partial. d) annular and partial
It takes 20 Newtons to move a box. How long will it take a 25 Watt motor to move this box 5 meters?
Answer:
With F = MA Its should take 500 Newtons
Explanation:
F = MA
Gordo noted that the more airplanes he sold, the more money he made. This was:
directly proportional
inversely proportional
indirectly proportional
Answer:
Its indirectly Proportional
Explanation:
can someone help me :)
Answer:
mass= 60kg
velocity= 10m/s
momentum = mass × velocity
p=m×v
p= 60×10
p= 600kgm/s
Explain in detail why you cannot hear in space but you can see light(explanation includes particle movement of liquid, solids, gases, and plasma)
Answer:
The reason why one cannot hear in space but light can be seen is because light and sound are different kinds of wave
Light is an electromagnetic wave that propagates by a changing magnetic field hat creates a changing electric field. Light is created by a vibrating electric charge, and is transmitted through a medium by the absorption and reemission of the light by the medium particles
Sound is a longitudinal mechanical wave that is propagated by the vibration of the particles of the medium.
Sound requires a medium to propagate and it cannot be propagated or heard through space which is a vacuum.
Sound is created by a source that is vibrating and the vibration is transmitted to particles in the medium including solids, liquids, gases and plasma that the vibrating energy is in direct contact with and the transfer of the sound energy continues between layers of adjacent particles for the medium for the sound to be propagated from place to place
Explanation:
A lawn mower is pushed with a force of 79 N. If 11,099 J of work are done on mowing the lawn, what is the total distance the lawn mower was pushed? Round your answer to a whole number (no decimal places).
Answer:
141m
Explanation:
A object is placed between the focal point and the lens of a concave lens. Where will the image be formed?
Answer:
When object is placed between convex lens and focal point, image formed is virtual and magnified which is shown in the diagram. Was this answer helpful?
A sound wave is propagating through the air from left to right as shown in the diagram below.
Answer:
Explanation: Pules
Answer: longitudinal (compression)
Explanation: