PLEASE HELP its due today
On a flat field, a ball is kicked and given an initial velocity of 28 m/s at an angle of 20 degrees above the horizontal.
a) What are the x and y components of the ball’s initial velocity?
b)From the moment it is kicked, how long will it take for the ball to reach its maximum height?
c)What is the maximum height of the ball?
d) Find the horizontal distance between the point at which the ball was kicked and the point where it lands.

Answer:

The answer is "[tex]\bold{dosage = 0.031 rem}[/tex]"

Explanation:

please find the complete question in the attached file.

Given value:

[tex]m = 79\ kg \\\\n = 3.4 \times 10^9 \\\\E = 5.5 \times 10^{-13} \\\\ RBE = 15[/tex]

[tex]\to E = n E\\[/tex]

        [tex]= 3.4 \times 10^9 \times 5.5 \times 10^{-13} \\\\ = 1.87 \times 10^{-3}[/tex]

[tex]\to E(absorbed) = 1.87 \times 10^{-3} \times 0.87 = 1.63 \times 10^{-3}[/tex]

calculating the radiation absorbed per kg:

[tex]= \frac{1.63 \times 10^{-3}}{79} \\\\ = 2.06 \times 10^{-5} \\\\ = 0.00206 \ rad[/tex]

[tex]\to Dosage = 0.00206 \times 15 \\[/tex]

                 [tex]= 0.031 \ \ rem[/tex]

Answer:

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields. They are also perpendicular to the direction of the EM

Explanation:

Answer:

spherical shape

Explanation:

The Earth is massive enough that the pull of gravity maintains its roughly spherical shape. Most of its deviation from spherical stems from the centrifugal force caused by rotation around its north-south axis. This force deforms the sphere into an oblate ellipsoid.

Answer: 600 feet

Explanation:

Answer:

The average force exerted on the bullet while it is being accelerated is 6,522.52 N.

Explanation:

Given;

mass of the bullet, m = 23 g = 0.023 kg

length of the barrel, L = 62 cm = 0.62 m

speed of the bullet, v = 593 m/s

Applying work-energy theorem;

the work done in accelerating the bullet in the riffle = kinetic energy acquired by the bullet.

W = K.E

F x d = ¹/₂mv²

where;

d is the is the distance traveled by the bullet in the riffle = L

F(0.62) = ¹/₂ x 0.023 x (593²)

F(0.62) = 4043.964

F = (4043.964) / (0.62)

F = 6,522.52 N

Therefore, the average force exerted on the bullet while it is being accelerated is 6,522.52 N.

Answer:

applied force

Explanation:

I think that's right

Answer:

whats the question tho

Answer:

A and E.

Explanation:

Physical properties have to do with things that are not done chemically.

A has to do with light that you can see.

B has to do with Ph (If not A this is your next answer)

C mentions a Patina which is a chemical reaction known as oxidation

D has to do with chemical reactions

E is always correct.  One of the fundamental laws about matter is that it must always have mass.

I am 99% confident in A and E as your answer, but if it is wrong go with B and E.

Hope this helps!

Answer:

4 blocks west is final displacement. So 4 blocks per hour

Answer:

a) 6.9*10^14 Hz

b) 9*10^-12 T

Explanation:

From the question, we know that

435 nm is given as the wavelength of the wave, at the same time, we also know that the amplitude of the electric field, E(max) has been given to be 2.7*10^-3 V/m

a)

To find the frequency of the wave, we would be applying this formula

c = fλ, where c = speed of light

f = c/λ

f = 3*10^8 / 435*10^-9

f = 6.90*10^14 Hz

b) again, to find the amplitude of the magnetic field, we would use this relation

E(max) = B(max) * c, magnetic field amplitude, B(max) =

B(max) = E(max)/c

B(max) = 2.7*10^-3 / 3*10^8

B(max) = 9*10^-12 T

c) and lastly,

1T = 1 (V.s/m^2)

Answer:

6.25 ms²

Explanation:

..................

Answer:

Vf = 18.78 m/s

Explanation:

As, the block does not trunk does not slide while falling. hence, we can use third equation of motion to find its velocity before it hits the ground:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = Height of Trunk = 18 m

Vf = Velocity of trunk just before it hits the ground = ?

Vi = Initial Velocity of the trunk = 0 m/s

Therefore, using these values in the equation, we get:

(2)(9.8 m/s²)(18 m) = Vf² - (0 m/s)²

Vf = √(352.8 m²/s²)

Vf = 18.78 m/s

Answer:

The voltage is [tex]\= DC _v = 2.6 \ V[/tex]

Explanation:

From the question we are told that

  The duty cycle is  p =  65% = 0.65

   The on - state voltage is  [tex]V = 40 \ volt[/tex]

Generally the average DC voltage is mathematically represented as

        [tex]\= DC _v = p * V[/tex]

=>      [tex]\= DC _v = 40 * 0.65[/tex]

=>      [tex]\= DC _v = 2.6 \ V[/tex]

Answer:

[tex]\mathbf{x = 3te ^{-2 \sqrt{2t}}}[/tex]

Explanation:

From the given information concerning the spring-mass system:

Let us apply Hooke law.

Then, we have:

mg = ks

8 = k4

k = 8/4

k = 2

Provided that the mass weighing 8 lbs is attached to a spring.

Then, we can divide it by gravity 32 ft/s².

∴

m = 8/32

m = 1/4 slugs

The medium that offers the damping force [tex]\beta = \sqrt{2}[/tex]

Now, let us set up a differential equation that explains the motion of the spring-mass system.

The general equation is:

[tex]mx '' + \beta x' + kx = 0[/tex]

where;

[tex]m = \dfrac{1}{4}[/tex]

k = 2,  and

[tex]\beta = \sqrt{2}[/tex]

Then;

[tex]\dfrac{1}{4}x'' + \sqrt{2} x' + 2x = 0[/tex]

By solving the above equation, the auxiliary equation is:

[tex]m^2 + 4 \sqrt{2} m + 8n = 0[/tex]

Using quadratic formula:

[tex]\dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]

[tex]m = \dfrac{-4 \sqrt{2} \pm \sqrt{(4 \sqrt{2})^2 -4(1)(8) }}{2}[/tex]

[tex]m = \dfrac{-4 \sqrt{2} \pm \sqrt{32 -32 }}{2}[/tex]

[tex]m = -2 \sqrt{2}[/tex]

Since this is a repeated root, the solution to their differential equation took the form.

[tex]x_c = c_1 e^{mt} + c_2 t e^{mt}[/tex]

[tex]x_c = c_1 e^{-2\sqrt{2} t} + c_2 t e^{-2\sqrt{2} t}[/tex]

From the initial condition.

At equilibrium position where the mass is being from:

x(0) = 0

Also, at the downward velocity of 3 ft/s

x'(0) = 3

Then, at the first initial condition:

[tex]x_c (0) = c_1 e^{-2\sqrt{2} *0} + c_2 (0) e^{-2\sqrt{2} *0}[/tex]

[tex]0= c_1 e^{0} + 0[/tex]

[tex]0= c_1[/tex]

At the second initial condition;

[tex]x' = -2 \sqrt{2} c_1 e^{-2 \sqrt{2} t } -2 \sqrt{2} c_2 t e^{-2 \sqrt{2} t } + c_2 e^{-2 \sqrt{2} t}[/tex]

where;

x'(0) = 3

[tex]x' (0) = -2 \sqrt{2} c_1 e^{-2 \sqrt{2}* 0 } -2 \sqrt{2} c_2 (0) e^{-2 \sqrt{2} *0 } + c_2 e^{-2 \sqrt{2} *0}[/tex]

[tex]3 = -2 \sqrt{2} * 0 *e^0 - 0 + c_2 e^0[/tex]

[tex]3 = 0 + c_2[/tex]

[tex]3 = c_2[/tex]

Replacing in the constraints, the equation of the motion is:

[tex]\mathbf{x = 3te ^{-2 \sqrt{2t}}}[/tex]

Answer:

sine the resistors are connected in series, we could add the sum and that single value replaces the individual resistors in series. therefore, 100ohm resistor can do.

Answer:

Centripetal forces are directed toward the center of a circle.

Hope this helps.

Explanation:

The force needed to move a body in a curved way is understood as centripetal force. Centripetal forces are always directed toward the center of a circle.

The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.

The direction of centripetal force is always in the path of the center of the course.

Hence center is the right option. Centripetal forces are always directed toward the center of a circle.

To learn more about the centripetal force refer to the link;

https://brainly.com/question/10596517

Answer:

Homes, Workplaces, Statues, Meuseums

Explanation:

if you did look into it you would know after the earthquake there was a tsunami which flooded alot of places, this made many homeless, jobless, and many lossing vaklueable things

Answer:

it would be 11.95 seconds

Explanation:

sorry for saying i did not know

Answer:

the kinetic energy of A will be twice that of B

Explanation:

The formula for calculating kinetic energy is expressed using the formula

KE = 1/2mv²

m is the mass of the object

v is the velocity

For object A:

KEA = 1/2mAvA²

For object B:

KEB = 1/2mBvB² ... 1

If object A is twice the mass of object B, then mA = 2mB

From 1:

KEA = 1/2mAvA²

Substitute mA = 2mB

KEA = 1/2(2mB)vA² .... 2

Divide 1 by 2

KEB/KEA = 1/2mBvB²/mBvA²

KEB/KEA = 1/2vB²/vA²

Assuming they have the same velocities then vA ,= VB

The equation becomes:

KEB/KEA = 1/2vB²/vA²

KEB/KEA = 1/2vB²/vB²

KEB/KEA = 1/2

KEA = 2EB

Hence the kinetic energy of A will be twice that of B

Answer: chemical energy

Explanation:

Complete Question

A 8.0 A current is charging a 1.0 -cm-diameter parallel-plate capacitor. What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor?

Answer:

The magnetic field is  [tex]B = 6.4*10^{-4} \ T[/tex]

Explanation:

From the question we are told that

    The current is  [tex]I = 8.0 \ A[/tex]

    The diameter is  [tex]d = \ cm = \frac{1}{100} = 0.01 m[/tex]

      The position considered is  [tex]d = 2.5 \ mm = 0.0025 \ m[/tex]

 Generally the magnetic field is mathematically represented as

           [tex]B = \frac{\mu_o * I }{ 2 \pi d}[/tex]

Here [tex]\mu_o[/tex] is permeability of free space with value  

[tex]\mu_o = 4\pi * 10^{-7} \ N/A^2[/tex]

      So

                 [tex]B = \frac{ 4\pi * 10^{-7} * 8 }{ 2 \pi * 0.0025 }[/tex]

=>               [tex]B = \frac{ 2 * 10^{-7} * 8 }{ * 0.0025 }[/tex]

=>               [tex]B = 6.4*10^{-4} \ T[/tex]

Answer:

Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions.

Explanation:

Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells.

Hope this helps!

Brain-LIst?

Answer:

The force on rope is equal for both of them at any time.

For winning the game the force on ground is responsible.

Explanation:

Answer:    

Two ways carbon can get from the ocean to the lithosphere is through the marine plants + animals (in the ocean) , sediments, petroleum then to the lithosphere.

Hope that helps!

Answer:

A Necklace is most likely made from both metals and gemstones

Explanation:

Brainliest?

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 1.4 \times {2.2}^{2} \\ = 0.7 \times 4.84 \\ = 3.388 \: \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

Hope this helps you

Answer:

im not sure

Explanation:

Answer:

D. Newton's third law of motion

Answer:

Concept: Physics analysis

Answer:

b. transparent

Explanation:

Photons interact with an object by some combination of reflection, absorption and transmission. Some materials, such as plate glass and clean water, transmit much of the light that falls on them and reflect little of it; such materials are called optically transparent.

Answer:

D. the same as force. the applied force per cross-sectional area.

Explanation:

Tensile stress of a material is defined as the ratio of the applied force on the material to its cross sectional area. this is expressed mathematically as;

Tensile stress = Force/cross sectional area

Tensile stress = F/A

Force is measured in newton while cross sectional area is measured in m

Hence the unit of Tensile stress is N/m²

The tensile stress is the same as force. the applied force per cross-sectional area. Hence, option (D) is correct .

The given problem is based on the concept of stress and strain. The force applied on a material per unit area is known as Stress. It is denoted by the symbol [tex]\sigma[/tex] .

And due to the applied force, the ratio of change in length to the original length is known as Strain. It is denoted by the symbol [tex]\epsilon[/tex].

And the ratio of Stress and Strain is known as Elastic modulus. That is,

[tex]E = \dfrac{stress}{strain}\\\\E = \dfrac{\sigma }{\epsilon}[/tex]

So, the tensile stress is obtained as,

[tex]E = \dfrac{\sigma}{\epsilon}\\\\\sigma = E \times \epsilon[/tex]

So, clearly stress is nothing but the force applied per unit cross sectional area. That is,

[tex]\sigma = \dfrac{F}{A}[/tex]

Thus, we can conclude that the tensile stress is the same as force. the applied force per cross-sectional area. Hence, option (D) is correct .

Learn more about the tensile stress here:

https://brainly.com/question/17077464