please help me. the picture can help me..​

Answer:

The answer would be 4.5

Answer:

3890000000

Step-by-step explanation:

Answer:

Given that;

There are three high schools, each having four sections of every 24 students

the 2 types of instructions are Standard curriculum  & computer based curriculum

a)

this study is experimental

this is because the study did not just observe the student's performance but randomly assign the performance to different techniques that have some certain control over the technique of teaching and then observe their performance afterwards

b)

-important  factors are; high schools, instruction type and scores

- Highschool has 2 levels: level one there are three high schools,  level 2 each having four sections of every 24 students

-instruction type: has one level which is  divided into two namely; standard base and computer based

Scores: doesn't have levels

c)

there are 3 schools and 4 sections  so the factor high school has between subjects components

factor instruction type also has between subjects because there are two different types available

there are 24 students in each section which are within subjects

d)

the score on the test  is the dependent measures

e)

“STUDENT” in each section is he basic experiment unit of study

Answer:

5 days = 5 * 24 = 120 hours

120 + 18 = 138hours

3450/138 * 24 = 600 watt hours  

600watt hours

Answer:

x=15ft

Step-by-step explanation:

a^2+b^2=c^2

8^2+b^2=17^2

b^2+64=289

b^2=225

b=15

Answer:

Yes blue liquid is toxic

Step-by-step explanation:

H0: p1 = p2

H1: p1>p2

For blue

We calculate proportion as

37/40 = 0.925

For white

9/40 = 0.2250

To get p

(X1 + x2)/(n1 + n2)

= 0.5750

After calculating the z as statistic (please check attachment) I got 6.33

P value = 0.0000

We reject null hypothesis and say in conclusion that enough evidence exists for us to say blu liquid is toxic!

Thank you!

Answer:

11.400 dollars... is the answer

Answer:

$5400

Step-by-step explanation:

9 x 600 = 5400

Answer:

The answer is...

f(x)=(x-3)+(x+3)

I think this is the answer. I haven't done this kind of math in a while so...

The chosen equation, (x +3)(x + 3) = 0, will serve as a representation of the provided graph.

ax²+bx+c=0, with a not, equals 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be simple or complicated.

given a Graph of a quadratic equation.

Contrarily, parabolas are used to graph quadratic equations. In other words, the data will be displayed as either an "open" or "upside-down" U-shaped curve. The graph is always quadratic if you are drawing a graph from a function and the equation involves x².

in this graph, we can observe that graph has only one root at x = -3

therefore the equation of the Given parabola is

(x + 3)² = 0

or

(x +3)(x + 3) = 0

therefore, the equation choice could represent the graph given will be (x +3)(x + 3) = 0.

Learn more about Quadratic equations here:

https://brainly.com/question/22364785

#SPJ2

Answer:

B. 40

Step-by-step explanation:

y varies directly as x

y=kx, k is a constant

when x=8, y=5. k*8=5

k=5/8

When x=64,

y= 5/8 * 64

y= 40

Answer:

I think the answer will be C 61

Step-by-step explanation:

y=5 when x=8

8-3=5

x=64 y=?

64-3=61

Answer:

y=-(2)/(7)x-5

Step-by-step explanation:

Answer:

=130

Step-by-step explanation:

(2x) (5x+5) = 180

7x + 5 = 180

7x = 175

x = 25

5(25) + 5 = 125 + 5 = 130

Hope this helps (:

Answer:

80%

Step-by-step explanation:

Deje que el evento de que lloverá el 3 de mayo sea A y el evento de que lloverá el 4 de mayo sea B.

P (A) = 50% = 0,5

P (B) =?

P (A n B) = 40% = 0,4

Para encontrar la probabilidad de B,

aplicamos el uso de la probabilidad de Bayes

P (B | A) = P (A n B) / P (A) = 40% / 50% = 40/50 = 0,8 o 80%

Por definición de probabilidad condicional, la opción correcta es opción b): si llovió el 3 de mayo, la probabilidad que  llueva el 4 de mayo es 80%.

En primer lugar, debes saber que la Probabilidad es la mayor o menor posibilidad de que ocurra un determinado suceso.

En otras palabras, la probabilidad establece una relación entre el número de sucesos favorables y el número total de sucesos posibles.

En este caso, se llama suceso A al evento de que llueva el 3 de mayo en El Salvador, mientras que el suceso B será el evento de que llueva el 4 de mayo en El Salvador.

Siendo el suceso A∩B (A intersección B)  cuando A y B ocurren simultáneamente, entonces:

Por otro lado, la probabilidad condicional P(A|B) es la probabilidad de que ocurra un evento A, sabiendo que también sucede otro evento B. Esto es, es la probabilidad de que ocurra el suceso A si ha ocurrido el suceso B. Se define como:

P(A|B) = P(A∩B)÷ P(B)

En este caso, si llovió el 3 de mayo, deseas conocer la probabilidad que  llueva el 4 de mayo. Entonces la probabilidad condicional a conocer es:

P(B|A) = P(A∩B)÷ P(A)

Entonces:

P(B|A) = 0,4÷ 0,5

P(B|A) = 0,8= 80%

Finalmente, la opción correcta es opción b): si llovió el 3 de mayo, la probabilidad que  llueva el 4 de mayo es 80%.

Aprende más:

Answer:

Step-by-step explanation:

Inequality: (x-1)(x+2)(2x-7)≤0

If we solve the corresponding equation (x-1)(x+2)(2x-7)²= 0, we get roots

We need to consider the following 4 intervals:

1st interval (−∞; −2)

2nd interval  [−2; 1]

3rd interval (1; 3.5)

4th interval

So, the answer to the inequality is:

Answer:

5/18

Step-by-step explanation:

Parentheses next to each other mean to multiply. So, this problem means you need to multiply -4/9 and -5/8. To multiply fractions, you just have to multiply across. To make it easier to understand what I mean...

-4 x -5  = 20 (when you multiply two negatives, it makes a positive)

9 x 8   = 72

20/72 simplifies to 5/18.

Hope this helps!! Have a wonderful day C:

Answer: Log9,(11/7)^4

Step-by-step explanation:

according to the rules of logarithm

1)Subtraction sign(-) becomes division(÷),while addition(+)becomes multiplication (x)

2) the number in front of the log figure becomes an indices

Answer:

log9 (11/7)4

Step-by-step explanation:

got it right on the test

Answer and Step-by-step explanation:

Please find attached

Answer:

b

Step-by-step explanation:

Answer:

I don’t think it’s neither less than it equal

Step-by-step explanation:

I could be wrong don’t listen to me :)

Step-by-step explanation:

In 1/10 of 1hr = 1/2 mile

10*(1/10) of 1hr = 10(1/2) mile

(10/10) of 1hr = (10/2) mile

1 of 1hr = 5mile

It says, he can run 5 miles in 1 hour

Answer:

If the positive whole number is a multiple of 3, one divided by that number will always be a non-terminating decimal.

Answer:

223 and 224

Step-by-step explanation:

Divide 447 by 2. It gives a decimal of 223.5, but obviously you don't have half pages. So the page number would be 223 and 224.

Answer:

223,224

Step-by-step explanation:

page 1-x

page 2-x+1

2x+1=447

2x=446

x=223

page 1=223

page 2=224

Brainliest is Very Appreciated!

Answer:

2 mi per hour

Step-by-step explanation:

1/3*6=

6/3= 2

2 mi per hour

Answer:

2mph

Step-by-step explanation:

If a person walks 1/3 of a mile every 1/6 of an hour you divide to solve.

[tex]\frac{\frac{1}{3}}{\frac{1}{6}}[/tex] To solve you flip the bottom and multiply:

[tex]\frac{1}{3} *\frac{6}{1}[/tex] = [tex]\frac{6}{3} = 2[/tex]

The person is walking 2mph

The answer is 11.9 units

First you must set up the distance formula.

[tex]\sqrt[]{ (-10-0)^2+(-4-0)^2+(5-0)^2}[/tex]

Then, simplify like terms.

[tex]\sqrt{(-10)^2+(-4)^2+(5)^2}[/tex]

Next, simplify exponents.

[tex]\sqrt{100+16+25}[/tex]

Then, add like terms.

[tex]\sqrt{141}[/tex]

Finally, round to the nearest tenth.

11.9

Answer:

6 primos de dos cifras(casos favorables) / 90 numeros de dos cifras(casos posibles) = 1/15

Step-by-step explanation:

Usando el concepto de probabilidad, se encuentra que hay una probabilidad de [tex]\frac{1}{15}[/tex], opcion A, de que al escoger un número positivo de dos cifras, este sea  primo y termine en 3.

------------------------------

Entonces:

[tex]p = \frac{6}{90} = \frac{1}{15}[/tex]

Probabilidad de [tex]\frac{1}{15}[/tex], opcion A, de que al escoger un número positivo de dos cifras, este sea  primo y termine en 3.

Un problema similar es dado en https://brainly.com/question/24583317

Answer:

Step-by-step explanation:

[tex]6 \:cups = 5\:batches\\x\:cups = 1\:batch\\\\Cross\:Multiply\\\\5x = 6\\\\Divide\:both\:sides\:of\:the\:equation\:by\:5\\\\\frac{5x}{5} =\frac{6}{5} \\\\x = 1\frac{1}{5}[/tex]

Answer:

a

The confidence interval for the population variance is ​[tex] 5.49 < \sigma^2 < 37.02 [/tex]  

The correct option is  C

b

The confidence interval for the population standard deviation is [tex] 2.34 < \sigma < 6.08 [/tex]

The correct option is  A

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  14

    The standard deviation is  [tex]s = \$3.42[/tex]

Generally the degree of freedom is mathematically represented as

     [tex]df =  14 -1[/tex]

=>   [tex]df =  13 [/tex]    

Given that the confidence level is  98%  then that level of significance is  

     [tex]\alpha = (100 -98) \%[/tex]

=>  [tex]\alpha = 0.02[/tex]

Generally the 98% confidence interval for the variance  is mathematically represented as

     [tex]\frac{(n- 1) s^2}{x^2 _{[\frac{\alpha }{2} , df]}}  < \sigma^2 < \frac{(n- 1) s^2}{x^2 _{[1- \frac{\alpha }{2} , df]}}[/tex]

=> [tex]\frac{(14- 1) (3.42)^2}{x^2 _{[\frac{0.02 }{2} , 13]}}  < \sigma^2 < \frac{(14- 1) (3.42)^2}{x^2 _{[1- \frac{0.02 }{2} , 13]}}[/tex]

From the chi -distribution table  

     [tex]x^2 _{[1- \frac{0.02 }{2} , 13]} = 4.107[/tex]

and

    [tex]x^2 _{[\frac{0.02 }{2} , 13]} = 27.689[/tex]

So

=> [tex]\frac{(14- 1) (3.42)^2}{27.689}  < \sigma^2 < \frac{(14- 1) (3.42)^2}{4.107}[/tex]    

=> [tex] 5.49 < \sigma^2 < 37.02 [/tex]    

Generally the 98% confidence interval for the standard deviation   is mathematically represented as

   [tex]\sqrt{\frac{(n- 1) s^2}{x^2 _{[\frac{\alpha }{2} , df]}}}   < \sigma <\sqrt{ \frac{(n- 1) s^2}{x^2 _{[1- \frac{\alpha }{2} , df]}}}[/tex]

=> [tex]\sqrt{5.49}  < \sigma < \sqrt{37.02 }[/tex]

=> [tex] 2.34 < \sigma < 6.08 [/tex]

Answer: 1.325

Step-by-step explanation: I multiplied