PLEASE HELP MEEEEE 80 points on the line and i need this done

why did my answer get deleted??

oh yeah i put a link on there- oopsies.

I wont this time!

I got 30!

From conservation of energy, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately

The given weight of Elliot is 600 N

From conservation of energy, the total mechanical energy of Elliot must have been converted to elastic potential energy. Then, the elastic potential energy from the spring was later converted to maximum potential energy P.E of Elliot.

P.E = mgh

where mg = Weight = 600

To find the height Elliot will reach, substitute all necessary parameters into the equation above.

250 = 600h

Make h the subject of the formula

h = 250/600

h = 0.4167 meters

Therefore, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately

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Answer: false

Explanation:

Answer:

E.visible lights

Explanation:

llll

hope its attachments

Answer:

0

Explanation:

the momentum will always be 0 when it is at rest because the object isnt moving!

Hope this helped!

To solve the problem it is necessary to apply the concepts of Torque and equilibrium.

The Torque is defined as:

Where

F= Force

d = Distance

In this particular case, the force is caused by the weight of both children.

In turn, when there is equilibrium, the two torques must be equal therefore

Replacing with our values

Re-arrange to find  

Therefore the distance that the second kid should sit to balance the see-saw is 1.8m from the pivot.

Answer:

Because in correspondence to the same distance from a mass, the gravitational acceleration is the same for all the bodies. It doesn't depend on the mass of the objects.

Answer:

velocity = distance / time

example:

if a body moves "20" meters in "2" seconds

, then it's velocity = 20/2 = "10m/s"

Answer:

Frictional force

Explanation:

The force that must be overcome in order to push an object along a horizontal surface is frictional force

If the force is more than frictional force the object moves

The answer is in the picture.

The main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.

The mechanical advantage of the ramp is calculated as follows;

[tex]M.A = \frac{L}{h}[/tex]

As the length of the ramp increases, people will be move up to a greater distance up the staircase.

Thus, the main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.

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Answer:

KE = 225000000 J

Explanation:

Answer:

10.954. from equation. KE=1/2m(v^2)

2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50

(v^2)=120. square root for all v=10.954 m/s

F = mass × Acceleration ( give Acceleration is 9.8 )

So force of 5 kg mass on A is

F = 5 × 9.8 = 49N

Force of mass 1 kg on A

F = 1 × 9.8 = 9.8 N

Force of mass 10 kg on A is

F = 10 × 9.8 = 98N

Clearly the 10 kg ball experts the most force cause it has more mass

Answer:   biogeochemical process

Explanation:

Answer:

100

Explanation:

Displacement is the shortest line between the starting point and the ending point

so , the starting point is "A"

,the ending point is "C"

so "AC" = AB - CB = 300 - 200 = "100"

Answer:

-6500N

Explanation:

F = ma

Note:  1N = 1 kg⋅m⋅s−2

a = (0-6.5m/s)/3s

a = -6.5m/s^2

F = 1000kg(-6.5m/s^2)

F = -6500kgm/s^2

F = -6500 N

Answer:

Muscle memory is found in many everyday activities that become automatic and improve with practice, such as riding bicycles, driving motor vehicles, playing ball sports, typing on keyboards, entering PINs, playing musical instruments, poker, martial arts, and dancing.

Explanation:

The perimeter of ΔWXY is : ( D ) 14.5 cm

Calculating the perimeter of ΔWXY

QR = WY / 2

RS = XW / 2

QS = XY / 2

Given that : QR = 2.93 cm ,  RS = 2.04 cm,  QS = 2.28 cm

Therefore

Perimeter of ΔWXY = ∑ WY + XW + XY  

                                 = 2SR + 2QS + 2QR

                                 = 2(2.04) + 2(2.28) + 2(2.93)

                                 = 14.5 cm

Hence we can conclude that the perimeter of ΔWXY = 14.5 cm

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Answer:

The name of the shape on the right is M prime N prime O prime P prime Q prime R prime S prime because it is the image of the shape on the left.

Explanation:

Explanation:

Joule is unit of work or energy in the International System of Units (SI)

[tex] \large \mathfrak {Formula}[/tex]

work (joules) = force (newtons) x distance (meters)

[tex] \large\mathfrak{Invented \: by} [/tex]

James Prescott Joule

Answer:

because of the gravity of the earth

Mass of the car having acceleration 2.5 m/s² and net force 4000 N is 1600 kg.

A physical cause that can change the state of motion or rest of a body is called force. It is the product of mass and acceleration  off the body.

Here,

Net force acting on the car, F = 4000 N

Acceleration of the car, a = 2..5 m/s²

We know that,

F = ma

So, m = F/a

 m = 4000/2.5

 m = 1600 kg

Hence,

Mass of the car having acceleration 2.5 m/s² and net force 4000 N is 1600 kg.

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Answer:

Jake’s horse will only need to exert enough force to make the carriage accelerate. Even though the carriage will pull on the horse as well, that force is not enough to make the horse accelerate in the direction of the carriage because it is only strong enough to make the carriage accelerate, not the horse.

Explanation:

Additional info: the horse has more mass than the carriage does so it would require a stronger force to make the horse accelerate.

Answer: Jake’s horse will only need to exert enough force to make the carriage accelerate .Since the horse has a greater mass than the carriage, it requires a stronger force to make the horse accelerate.

Explanation: Sorry it took so long lol

Answer:

This is the answer that I got.

Explanation:

Hope it is right.

:MAIN ANSWER:

determined that the laws of physics are the same for all non-accelerating observers

Explanation:

Albert Einstein, in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels, according to Wired.

HOPE IT HELPS

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Answer:

Approximately [tex]5.11 \times 10^{-19}\; {\rm J}[/tex].

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: [tex]R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}[/tex].

Look up the speed of light in vacuum: [tex]c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}[/tex].

Look up Planck's constant: [tex]h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}[/tex].

Apply the Rydberg formula to find the wavelength [tex]\lambda[/tex] (in vacuum) of the photon in question:

[tex]\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}[/tex].

The frequency of that photon would be:

[tex]\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}[/tex].

Combine this expression with the Rydberg formula to find the frequency of this photon:

[tex]\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}[/tex].

Apply the Einstein-Planck equation to find the energy of this photon:

[tex]\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}[/tex].

(Rounded to three significant figures.)

From the values of resistivity, the resistance of copper wire is 22 Ω.

Let us recall that;

R = ρl/A

ρ = resistivity

l = length of the wire

A = cross sectional area of the wire

For constantan;

R = 4.9 × 10^-7  × 1 × 10^3/[3.14 × ((1 × 10^-3)/2)^2]

R = 620 Ω

For copper;

R =  1.7 × 10-8 × 1 × 10^3/[3.14 × ((1 × 10^-3)/2)^2]

R = 22 Ω

The material that is best suitable to make resistors is constantan wire.

For constantan, the energy converted to heat is;

I^2 R = (1)^2 ×  620 Ω = 620 W

For copper, the energy converted to heat is;

I^2R = (1)^2 × 22 Ω = 22Ω

The potential difference of constantan = IR = 1 ×  620 Ω =   620 V

The potential difference of copper =  = IR = 1 ×  22Ω  = 22 V

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