The wavelength and frequency of the sound in the string is greater than the wavelength and frequency of the sound in the air.
Wavelength and freqeuncy of the soundThe wavelength and frequency of the sound is determined using the following formulas.
v = fλ
f = v/λ
λ = v/f
where;
f is the frequency of the soundλ is the wavelengthWavelength and frequency of the sound in the stringf = 600/λ
λ = 600/f
Wavelength and frequency of the sound in airf = 333/λ
λ = 333/f
Thus, the wavelength and frequency of the sound in the string is greater than the wavelength and frequency of the sound in the air.
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A car travels from City A to City B to the north. It takes 4 hours, and the road mileage is 200 miles. The map shows that
the cities are only 80 miles apart (straight-line distance).
Answer:
The average speed would be the 200 miles/4 hours.
The average velocity would be the net displacement to the north at 80 miles/4 hrs = mph
Explanation:
Questions #19 and 20:
Part 1 of 2: A Carnot engine has a power output of 122 kW. The engine operates between two reservoirs at 9 °C and 458 °C. How much thermal energy is absorbed each hour? Answer in units of J.
Part 2 of 2: How much thermal energy is lost per hour? Answer in units of J.
(1) The thermal energy absorbed by the Carnot engine is 7.15 x 10⁸ J.
(2) The thermal energy lost per hour by the Carnot engine is 2.75 x 10⁸ J.
Thermal energy entering the heat engineThe thermal energy absorbed by the heat engine is calculated as follows;
[tex]Q_h = \frac{P\Delta t}{1 - T_c/T_h}[/tex]
where;
Tc is the temperature of the cold reservoir = 9 + 273 = 282 KTh is the temperature of the hot reservoir = 458 + 273 = 731 K[tex]Q_h = \frac{(122,000) \times (3600)}{1 - \frac{282}{731} } \\\\Q_h = 7.15\times 10^8 \ J[/tex]
Thermal energy lost by the heat engineThe thermal energy lost per hour by the heat engine is calculated as follows;
[tex]Q_c = Q_h - P\Delta t\\\\Q_c = (7.15 \times 10^8 )\ - \ (122,000 \times 3600)\\\\Q_c = 2.75 \times 10^8 \ J[/tex]
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Look at the diagram. Both cars start from the same point. Which describes the motion shown?
A:One car travels south at 4 m/s. The other car travels east at 2 m/s.
B:One car travels north at 4 m/s. The other car travels west at 2 m/s.
C;One car travels north at 2 m/s. The other car travels east at 4 m/s.
D: One car travels south at 4 m/s. The other car travels west at 2 m/s. 7 of 10
Answer:
I can't see anything so I can't to answer this question
Answer:
I think it MIGHT be A Can't see much ....
Explanation:
He did it well ( into negative)
Answer:
He did not do it very well.
Explanation:
He did it well ( into negative)
= He didn't do it well....
what type of matter is always made up of only one kind of atom
Light with a wavelength of about 490 nm is made to pass through a diffraction grating. the angle formed between the path of the incident light and the diffracted light is 9.2° and forms a first-order bright band. what is the number of lines per mm in the diffraction grating? round your answer to the nearest whole number. lines per mm
The number of lines per mm in the diffraction grating is 326.
What is diffraction grating?A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.
The given data in the problem is
[tex]\rm \theta[/tex] is the angle formed between the path of the incident light and the diffracted light = 9. 2°
λ is the wavelength of the light=490nm=4.9
N is the number of lines per mm in the diffraction grating=?
n is ordered = 1
The formula for the diffraction grating is;
[tex]n \lambda = d sin\theta \\\\ d = \frac{n \lambda}{sin \theta } \\\\ d = \frac{1 \times 4.90 \times 10^{-7}}{sin 9.2^0 } \\\\ d=3.06 \times 10^{-6} \\\\ d=3.06 \times 10^{-3} \ mm[/tex]
The number of lines per mm is found as;
[tex]\rm N= \frac{1}{d} \\\\ N= \frac{1}{3.06 \TIMES 10^{-3}} \\\\ N=326.8 /mm[/tex]
Hence the number of lines per mm in the diffraction grating is 326.
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A cart with mass 2m has a velocity v before it strikes another cart of mass 3m at rest. The two carts couple and move off together with a velocity of?
Answer:
2/5 v
Explanation:
Use conservation of momentum
originally mv = 2m v
after the crash mv is still the same (2mv)
but the mass is now 5m x where x is the new velocity
2mv = 5 mx
x = 2/5 v
The momentum of two objects in a collision is conserved. Hence, the total initial momentum is equal to the final momentum of the coupled mass. Here the final velocity will then be 2/5 v.
What is momentum ?Momentum of a moving object is the product of mass and velocity. It is a vector quantity with direction and magnitude. The total momentum of two colliding bodies is equal to the total final momentum after collision.
Let m1 and m2 be the masses and v1 and v2 be the final velocities. Vt be the velocity of the coupled mass.
Then, m1 v1 + m2 v2 = (m1 + m2) Vt
Given, mass of cart 1 = 2m
cart 2 = 3m
velocity of cart 1 = v
cart = 0 since it was at rest.
Then, 2m v + 0 = (2m + 3m) Vt
Vt = 2/5 v
Therefore, the final velocity of the couple of carts will be 2/5 v.
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elastic materials maintain their nature in all circumstance. true or flase
Answer:
False
Explanation:
If an elastic material is stretched with enough force it will go beyond its 'Elastic Limit' otherwise known as its 'Limit of Proportionality'.
When this happens permentant deformation wiil occur.
Think of a spring... if it is stretched with enough force it won't return back to its original shape. Therefore it has NOT maintained its nature.
A car of mass 10.0 ks traveling at 5.00 m/s comes to rest due to friction after traveling 20.0 m. What is the work done on the car by the friction?
A. –125 J
B. –50 J
C. 50 J
D. 125 J
The work done on the car due to friction is -125 J.
What is workdone?Work is said to be done when a force moves an object through a certain distance.
To calculate the workdone on the car by friction, we use the formula below
Formula:
W = m(v²-u²)/2.......... Equation 1
Where:
W = Work done due to fricionm = mass of the carv = Final velocityu = Initial velocityFrom the question,
Given:
m = 10 kgv = 0 m/su = 5 m/sSubstitute these values into equation 1
W = 10(0²-5²)/2W = 5(-25)W = -125 JHence, The work done on the car due to friction is -125 J.
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Choose the clincher sentence that best restates the following topic sentence.
Scientists recently discovered that fun is not just fun; it's
good for the brain.
O A. Not having fun can be bad for the brain.
O B. Fun is definitely good for the brain!
O C. Sometimes, you can have too much fun for the brain to process.
O D. A fun activity like horseback riding can actually make the brain
smarter.
what is the voltage of a circuit with power 36 W and current 4.5 A
Answer:
8 v
Explanation:
power = watts = v i
36 = v (4.5)
v = 8 v
m=3000km v=25m/s what’s the momentum
Momentum of the given body will be : 75000 Kg m/s
Explanation:According to Newton's first law of motion, all bodies continue to be in the state of rest or motion unless an external force is applied on the body. We can use this in the case of momentum also
The formula of momentum is given by :
[tex]:\implies \sf\quad \sf \: P = mv[/tex]
Here, we are given the mass of the body ( m ) as 3000kg and the velocity of the body ( v ) as 25 m/s. On putting the values in the formula:
[tex] \begin{aligned}&:\implies \sf\quad \sf \: P = mv \\& :\implies \sf\quad \sf \: P = 3000 \times 25 \\ & :\implies \sf\quad \sf \: \boxed{ \sf \: P = 75000kgm {s}^{ - 1} } \end{aligned}[/tex]
Momentum is associated with the mass of the moving body and can be defined as the quantity of motion measured as a product of mass and velocity.
Answer :-
Momentum is [tex] \bf{75,000 \: {kg \: ms}^{ - 1} } [/tex] .Explanation :-
As per the provided information in the given question, we have been given that The Mass is 3000 kg . The Velocity is given as 25 m/s . And, we have been asked to calculate the Momentum .
For calculating the Momentum , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed {\sf { \: Momentum \: = \: Mass \: \times \: Velocity \: }} [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf { Momentum \: = \: Mass \: \times \: Velocity} [/tex]
[tex] \Longrightarrow \: \: \: \sf { Momentum \: = \: 3000 \: \times \: 25} [/tex]
[tex] \Longrightarrow \: \: \: \textbf {\textsf {Momentum \: = \: 75000 }} [/tex]
Hence :-
Momentum = [tex] \bf{75,000 \: {kg \: ms}^{ - 1} } [/tex] .[tex] \underline {\rule {180pt} {4pt}} [/tex]
How does nuclear fusion differ from nuclear fission
Answer:
They are the polar opposite of each other.
How?Nuclear fusion is when two or more atomic nuclei combine together to form a different atomic nuclei. Nuclear fission is when the atom splits into two smaller nuclei.
WILL GIVE BRAINLIEST!!!
What is the equivalent resistance of a circut that contains two 50.0 resistors connects in parellels with a 12.0 V battery?
o A. 25.0
o B. 0.040
o C. 100.0
o D. 0.48
Answer:
1/Re=1/R1 +1/R2= 2x1/R1=2/R1=2/R2=2/50=1/25
1/Re=1/25, so the answer is Re= 25
the answer is A. 25.0
Answer:
A. 25.0
Explanation:
1/Re = 1/R1 + 1/R2 = 2 x 1/R1 = 2/R1 = 2/R2 = 2/50 = 1/251/Re = 1/25
The answer is Re= 25
I hope this helps! Have a great day!
Anygays-
What is the wasted energy in each of the energy transfers?
a) clockwork toy
b) boy kicking a football
c) boiling kettle on a gas ring
d) person walking upstairs
Answer:
a person walking upstairs is a wasted energy
A solenoid with an iron core is 25 cm long and is wrapped with 100 turns of wire. When the current through the solenoid is 10 A, the magnetic field inside it is 2.0 T. For this current, what is the permeability of the iron
Answer:
A solenoid is a long coil of wire wrapped in many turns. When a current passes through it, it creates a nearly uniform magnetic field inside. Solenoids can convert electric current to mechanical action, and so are very commonly used as switches. The magnetic field within a solenoid depends upon the current and density of turns.
Explanation:
hope this helped its pretty long
The students changed the release distance of the sphere during their investigation. Which statements best describe the purpose for increasing the release distance between the trials? Select all that apply.
A. to indicate balanced forces are acting on the spheres
B. to determine the types of forces acting on the spheres
C. to measure the strength of the force acting on the spheres
D. to change the direction of the force acting on the spheres
E. to observe the effect of unbalanced forces acting on the spheres
Since unbalanced forces acts on the spheres, the aim of increasing the release distance of the spheres is to observe the effect of unbalanced forces acting on the spheres.
What is an experiment?An experiment is a study whose objective is to study cause and effect relationships. In this case, the students had to increase the distance at which the spheres was released.
The aim of increasing the release distance of the spheres is to observe the effect of unbalanced forces acting on the spheres.
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HELPP
You are given two particles, each with a positive charge,
and a box that is 1 m by 1 m. How would you arrange the
particles to create the weakest electric force between
them? Explain.
Answer:
they are like charges so they magnitude repulsive & direction will be ones left &ones right. but it depends on the axis of rotation.
You are given two particles, each with a positive charge, and a box that is 1 m by 1 m. To arrange the particles to create the weakest electric force between them i put at opposite direction diagonally.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
According to Coulomb's law, the force of attraction or repulsion between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
To arrange the particles to create the weakest electric force between them i put at opposite direction diagonally.
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How does an object's acceleration change if the net force on the object is doubled?
A. The acceleration is cut in half.
B. The acceleration does not change.
C. The acceleration is doubled.
D. The acceleration is multiplied by four
Answer:
its acceleration is doubled.
Explanation:
If the mass is doubled, then acceleration will be halved.
**halved is to divide into two equal parts**
What is the name for a supporting force that acts upward and in a direction perpendicular to a surface
Suppose that a sound wave has a wavelength of 12 meters and a frequency of 100Hz. What is the speed of sound
Answer:
1200Hz
Explanation:
You would have to multiply 12 by 100 to get the answer.
12 • 100 = 1200 Hz
I hope it helps! Have a great day!
Anygays-
A lever where the input force is between the fulcrum and the output force (a broom) is what type of lever?
Answer:
first class lever
in a first class lever fulcrum is b/w input and output force
calculate the kinetic energy of a 71 kg man running at 5 m/s
Answer:
887.5 J
Explanation:
Kinetic energy is the energy gained by a body due to its motion.
Its formula is :-
KE = [tex]\frac{1}{2} mv^{2}[/tex]
m = massv = velocityValues we are given :
m = 71 kgv = 5 m/sSubstituting :
KE = 1/2 x 71 x 5²KE = 35.5 x 25KE = 887.5 Jdefine 1 calorie heat
Answer:
"One calorie of heat is defined as the amount of heat needed to raise the temperature of one gram of water by one degree Celsius"
Hope this Helps!
Explanation:
One calorie of heat is defined as the amount of heat needed to raise the temperature of one gram of water by one degree Celsius (or one kelvin).
Question 1 of 25 Which produces the most energy?
Answer:
electric stuff
Explanation:
I didn't see any option choices so srry
What are dogs trained to do when they find an explosive device?.
Answer:
They sit or lay quietly
Explanation:
That's what they are trained to do when they find a explosive device
Which situation results in no work being done?
O lifting an object off the ground
O throwing a baseball to your friend
O carrying a book at a constant velocity
O pushing a car that will not start out of the garage
Answer:
C
Explanation:
C should be the right answer
A machine puts out 100 watts of power for every 1000 watts put into it. The efficiency of the machine is 50%. 90%. 10%. 110%. none of the above
Answer:
Explanation: 10%
Determine an expression for the coefficient of static friction in terms of m2 and m1.
The dimensions of a triangle are shown below.
What is the area of the triangle?
Answer:
7. answered because ia an pro
Explanation:
[tex]area = \frac{1}{2} bh[/tex]
[tex]area = \frac{1}{2} \times 60 \times 50[/tex]
[tex]area = \frac{3000}{2} [/tex]
[tex]area = 1500mm ^{2} [/tex]