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How many grams of ammonium sulfate can be produced if 2500.0 g of H2SO4 react with excess NH3 according to the equation 2NH3(aq) + H2SO4(aq) → (NH4)2SO4(aq)? Calculate the percent yield if 3100 g (NH4)2SO4 were actually produced.
-Calculate the theoretical yield of ammonium sulfate.
-Calculate the percent yield for the associated question
-Write the unit for the theoretical yield (see related question)

Answer:

CO2 molecules don't really interact with sunlight's wavelengths. Only after the Earth absorbs sunlight and reemits the energy as infrared waves can the CO2 and other greenhouse gases absorb the energy.

Explanation:

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Carbon dioxide molecules don't directly react with the sunlight but they can absorb the energy in the form of infrared waves when it is emitted after reflection through the Earth's surface.

Infrared radiation (IR), sometimes referred to simply as infrared, is a region of the electromagnetic radiation spectrum where wavelengths range from about 700 nanometers (nm) to 1 millimeter (mm).

[tex]CO_2[/tex] molecules don't really interact with sunlight's wavelengths. Only after the Earth absorbs sunlight and reemits the energy as infrared waves can the [tex]CO_2[/tex] and some other greenhouse gases absorb the energy.

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Answer:

Ways we use radio waves on Earth are television and FM and AM radio broadcasts, military communications, mobile phones, ham radio, wireless computer networks, and numerous other communications applications.

Explanation:

Ways we use radio waves on Earth are television and FM and AM radio broadcasts, military communications, mobile phones, ham radio, wireless computer networks, and numerous other communications applications.

An electromagnetic wave of a frequency between about [tex]10^4[/tex] and [tex]10^{11}[/tex]or [tex]10^{12}[/tex] Hz, as used for long-distance communication.

AM and FM Radio Broadcasting which involves transmitting sound to a wide audience.

Radar is a detection system that uses radio waves to get information about objects.

Bluetooth and wireless communication use radio waves to create connections between devices.

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mol = 0.75 L(750 ml) x 0.132 mol/L =0.099 mol

potassium carbonate: K₂CO₃ ⇒ MM = 138,205 g/mol

mass = 0.099 x 138.205 = 13.68 g

Answer:

it takes the train 1 hour and 75 minutes

Explanation:

you multiply the constant speed starting from 1 (which represents 1 hour) then you add as many decimal places as you need. Bit of a confusing explanation

Answer:

great keep up the good work your teacher

Explanation:

The question had been answered above

Answer:

10.77

Explanation:

The relationship between pH and pOH is

pH + pOH = 14

Plugging in the pOH makes

pH + 3.23 = 14

And solving for pH by subtracting 3.23 on both sides

pH = 10.77

Answer:

A.moles of solute per liter of solution

Explanation:

the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams.

:-befrank

[tex] \text{V}_1 = 50 \text{ml }\\ \text{T}_1 = 200 \text{K} \\ \text{V}_2 = ? \\ \text{T}_2 = 400 \text{K}[/tex]

[tex] \text{The Value of V}_2[/tex]

[tex]\frac{ \text{V}_1}{ \text{T}_1} = \frac{ \text{V}_2}{ \text{T}_2}[/tex]

[tex] \frac{50}{200} =\frac{ \text{V}_2}{400} \\ \\ \fbox{cross multiplying} \\ \\ \implies 200 \times V_2 = 50 \times 400 \\ \\ \implies V_2 = \frac{50 \times 400}{200} \\ \\ \implies V_2 = \frac{50 \times \cancel{ 400} { \: \: \: }^{2} }{ \cancel{200}} \\ \\ \implies V_2 = 50 \times 2 \\ \\ \implies V_2 = 100[/tex]

[tex] \therefore \implies V_2 = 100 \text{ml}[/tex]

If the colored spheres are solutes, the overall direction of water would be out of the cell based on the principle of osmosis.

It is the movement of water molecules from the region of high water potential (low solutes) to the region of low water potential (high solute) through a selectively permeable membrane.

In the illustration, there are more colored spheres outside of the cell than inside of it. This means that there are more solutes outside the cell (lower water potential) than inside of the cell (higher water potential).

Thus, water will move from the inside of the cell to the outside until an equilibrium is established.

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Answer:

12.979 m:L (3 d.p.)

Explanation:

Combined Gas Law

[tex]\sf \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

Temperature must be in kelvins (K).

To convert Celsius to kelvins, add 273.15.

Volume can be in any unit.

Given values:

Rearrange the equation to isolate V₂:

[tex]\implies \sf V_2=\dfrac{P_1V_1T_2}{P_2T_1}[/tex]

Substitute the given values into the equation:

[tex]\implies \sf V_2=\dfrac{0.837 \cdot 17.5 \cdot 283.15}{0.995 \cdot 321.15}[/tex]

[tex]\implies \sf V_2=12.979\:mL\:(3\:d.p.)[/tex]

Therefore, the volume at 10°C will be 12.979 mL (3 d.p.).

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Temperatures

Apply combined gas law

[tex]\\ \rm\dashrightarrow \dfrac{P1V1}{T1}=\dfrac{P2V2}{T2}[/tex]

[tex]\\ \rm\dashrightarrow V2=\dfrac{P1V1T2}{P2T1}[/tex]

[tex]\\ \rm\dashrightarrow V2=\dfrac{0.837(17.5)(283)}{0.995(321)}[/tex]

[tex]\\ \rm\dashrightarrow V2=12.978mL[/tex]

[tex]\\ \rm\dashrightarrow V2=12.98mL[/tex]

Answer:

D

Explanation:

Answer:The answer is B and CCC

Explanation:

Out of the given chemical changes, the two reactions which are faster are those mentioned in B and C as formation of rust and tarnishing of silver are slow reactions.

Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.

There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical changes:

1) inorganic changes

2)organic changes

3) biochemical changes

During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.

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The volume and temperature changes in according to Charles' law will be:

The relationship between the volume and temperature of a given mass of gas is given by Charles' Iaw which states that volume is directly proportional to temperature if a gas in Kelvin.

To complete the tables volume and temperature changes:

Therefore, volume and temperature are directly proportional.

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Answer:

Partial pressure of carbon dioxide is high in the pulmonary capillaries.

Explanation:

Answer:

If you have a periodic table of the elements, you should be able to do this easily. The best periodic table, in my opinion, is the interactive periodic table at ptable(.com).

I will attach a formula sheet with everything you might need to know in chemistry.

Explanation:

You should be able to do this, but if you need more help let me know! :)

Answer:

-30°C = -22°F

-30°C = 243.15K

Explanation:

For converting Celsius to Fahrenheit, this is the equation-

(-30°C × 9/5) + 32 = -22°F

For converting Celsius to Kelvin, this is the equation-

-30°C + 273.15 = 243.15K

765

Explanation:

C1V1=C2V2

10×85=1×V2

V2=850

V'=V2-V2

V'=850-85

V'=765ml

a. For the given combination of reactants, the limiting reagents is F₂

b. The mass of HF that would be made is 106.65 g

From the question, we are to identify the limiting reagent and calculate the mass of HF made

First, we will write the balanced chemical equation for the reaction

3F₂ + NH₃ → 3HF + NF₃

This means 3 moles of F₂ reacts with 1 mole of NH₃ to produce 3 moles of HF and 1 mole of NF₃

From the given information,

We have 5.33 moles of F₂ and 2.22 moles of NH₃

Since,

3 moles of F₂ reacts with 1 mole of NH₃

Then,

5.33 moles of F₂ will react with 1.78 moles of NH₃

Therefore, NH₃ is in excess and F₂ is the limiting reagent

Hence, for the given combination of reactants, the limiting reagents is F₂

b. For the mass of HF that would be made

From the balanced chemical equation,

3 moles of F₂ reacts with 1 mole of NH₃ to produce 3 moles of HF

Then,

5.33 moles of F₂ will react with 1.78 moles of NH₃ to produce 5.33 moles of HF

Number of moles of HF produced = 5.33 moles

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of HF = 20.01 g/mol

∴ Mass of HF produced = 5.33 × 20.01

Mass of HF produced = 106.65 g

Hence, the mass of HF that would be made is 106.65 g

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Answer:

23936.5 N/m² or 23936.5 Pa

Explanation:

Unit conversion

Our dimensions

Solving

Answer:

1.46 M

Explanation:

[A]t=−(0.0416 M/min) x (20.0 min)+2.29 M

[A]t=1.46 M

Sodium hydroxide is a soluble strong base. The pOH of a 3.0 × 10⁻³ M-sodium hydroxide solution is 2.5.

According to Arrhenius, a base is a species that releases OH⁻ ions in an aqueous medium.

Let's consider the basic reaction of NaOH.

NaOH(s) ⇒ Na⁺(aq) + OH⁻(aq)

NaOH is a strong base. This means that the concentration of OH⁻ will be equal to the initial concentration of NaOH, i.e. 3.0 × 10⁻³ M.

Then, we can calculate the pOH of the NaOH solution using the following expression.

pOH = -log [OH⁻] = -log 3.0 × 10⁻³ = 2.5

Sodium hydroxide is a soluble strong base. The pOH of a 3.0 × 10⁻³ M-sodium hydroxide solution is 2.5.

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Answer:2.5

Explanation:

Answer:

Here all the given options are examples of complex carbohydrates.

Explanation:

As all these contains sugar, starch and fibre.

Answer:

Keep the tap closed when not using it, and to not use it every day, like washing a car, you can clean it with a sponge and a bucket of water.

Explanation:

I don't know if this helps though.

Answer:

10 L

Explanation:

Boyle's Law

Our values

Using the equation

Answer:

0.25L

Explanation:

Explanation:

The difference between addition polymerization and condensation polymerization is that in addition polymerization the polymers are formed by the addition of monomers without any by-products whereas in condensation polymerization, the polymers are formed due to the condensation of more than one different monomers resulting in the formation of small molecules such as HCl, water, etc., as by-products.

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a. the mole of substance

b.a standard solution

in analytical chemistry standard solution is a solution containing a precisely known concentration of an element or a substance.

A known mass of solute is dissolved to make a specific volume. it is prepared using a standard solution,such as a primary standard.

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