Answer:
below
Explanation:
1. B. removing heat.
The process of changing a gas into a liquid is called condensation. It occurs when the gas loses heat energy and its particles slow down and come closer together, eventually forming a liquid. Therefore, by removing heat from a gas, it can be changed into a liquid.
2. D. Smashing an object into many pieces is a physical change.
Smashing an object into many pieces does not change the chemical composition of the object. It only changes its physical appearance or state. A physical change is a change in the state or appearance of matter without any change in its chemical composition. Therefore, smashing an object into many pieces is a physical change.
3. No fixed volume or shape: gas
Fixed volume and shape: solid
Fixed volume but no fixed shape : liquid
4. C. Melting is a physical change.
Melting is the process of changing a solid substance into a liquid by heating it to its melting point. During this process, there is no change in the chemical composition of the substance, only a change in its physical state from solid to liquid. Therefore, melting is a physical change.Option A is incorrect because melting does not involve any biological process.
Option B is incorrect because melting does not result in any chemical reaction that alters the composition of the substance.
Option D is incorrect because melting is a natural physical phenomenon that occurs due to changes in temperature or pressure.
5. B. The new substance is different from the beginning substance.
In a chemical change, a chemical reaction occurs, which involves the breaking and formation of chemical bonds between atoms or molecules. This results in the formation of one or more new substances with different chemical properties than the original substances.
During a chemical change, the original substances are converted into new substances that have different physical and chemical properties, such as color, texture, odor, melting and boiling points, solubility, reactivity, etc. Therefore, the new substance is different from the beginning substance.
6. A. Temperature.
Temperature is the primary factor responsible for the form of matter. At different temperatures, matter exists in different states:
- At low temperatures, matter exists as a solid because the particles are tightly packed and have low energy, which keeps them in a fixed position.
- At higher temperatures, matter exists as a liquid because the particles have enough energy to move past each other but are still close together.
- At even higher temperatures, matter exists as a gas because the particles have enough energy to overcome the attractive forces between them and move independently.
Pressure can also influence the form of matter, but temperature is the primary factor that determines the state of matter. Weather and time are not factors that directly influence the form of matter.
7. B. All solid substances require the same temperature to melt them.
This statement is false. Different solid substances have different melting points, which is the temperature at which they change from a solid to a liquid. The melting point depends on the chemical composition and structure of the substance. Therefore, different solid substances require different temperatures to melt them.
Option A is a true statement because different solid substances have different melting points.
Option C is a true statement because heat can be used to change the physical property of an object, such as melting or boiling it.
8. C. Paper burning into ash.
This is a chemical change because burning paper involves a chemical reaction in which the cellulose fibers in paper combine with oxygen in the air to form new substances, such as water vapor, carbon dioxide, and ash. The chemical composition of the paper changes, and it cannot be reversed.
Option A is a physical change because melting ice into water involves only a change in physical state, not a change in chemical composition.
Option B is a physical change because breaking an object into pieces only changes its physical appearance, not its chemical composition.
Option D is a physical change because water changing to steam involves only a change in physical state, not a change in chemical composition.
9. C. When heat changes the chemical composition of an object.
Heat can produce a chemical change when it is used to break or form chemical bonds between atoms or molecules, resulting in a change in the chemical composition of the substance. This can lead to the formation of new substances with different chemical properties than the original substance. Therefore, option C is the correct statement.
Option A is incorrect because heat energy transfer can produce a physical change, such as melting or boiling, but not necessarily a chemical change.
Option B is incorrect because heat changing ice into liquid water is a physical change, not a chemical change.
Option D is incorrect because observing heat in an experiment does not necessarily produce a chemical change.
A small sample of lead 5g (c=0.138 J/g°C) is placed into 50g of water at 25°C. What is the system’s final temperature if lead started at 50°C?
The system's final temperature is 25.825°C.
To solve this problem, we need to use the equation:
q = m × c × ΔT
where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
In this case, the lead is losing heat to the water, so q will be negative. The water is gaining heat from the lead, so q will be positive.
First, let's calculate the amount of heat lost by the lead:
q_lead = -m_lead × c_lead × ΔT_lead
= -5 g × 0.138 J/g°C × (50°C - 25°C)
= -172.5 J
Next, let's calculate the amount of heat gained by the water :
[tex]q_{water}[/tex] = [tex]m_{water}[/tex] × [tex]c_{water}[/tex] × Δ[tex]T_{water}[/tex]
= 50 g × 4.184 J/g°C × ([tex]T_{f}[/tex] - 25°C)
where [tex]T_{f}[/tex] is the final temperature of the water
Since the total amount of heat lost by the lead is equal to the total amount of heat gained by the water (assuming no heat is lost to the surroundings), we can set [tex]q_{lead}[/tex] equal to [tex]q_{water}[/tex] and solve for [tex]T_{f}[/tex]:
- [tex]q_{lead}[/tex] = [tex]q_{water}[/tex]
172.5 J = 50 g * 4.184 J/g°C * ([tex]T_{f}[/tex] - 25°C)
[tex]T_{f}[/tex]- 25°C = 0.825
[tex]T_{f}[/tex] = 25°C + 0.825
[tex]T_{f}[/tex] = 25.825°C
Therefore, the system's final temperature is 25.825°C.
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What is the amount (in mole) of sodium trioxocarbonate (IV) in 5.3g of the compound? (Na2CO3 = 106)
Answer:
To calculate the amount (in mole) of sodium trioxocarbonate (IV) in 5.3g of the compound , you can use the formula:
Amount (in moles) = Mass of substance / Molecular mass
The molecular mass of sodium trioxocarbonate (IV) (Na2CO3) is 106 g/mol, as given in the question. Substituting the values in the formula, we get:
Amount (in moles) = 5.3 g / 106 g/mol = 0.05 mol
Therefore, the amount (in mole) of sodium trioxocarbonate (IV) in 5.3g of the compound is 0.05 mol.
Note that the given molecular mass of Na2CO3 must be used to obtain the correct answe12 .
Explanation:
This weather map showed the temperature (in °F) in the United States on a winter day. It also includes two pressure systems, labeled "H" and "L." Explain where weather fronts are most likely located, and predict the weather at each pressure system. edmentum science
Answer:
"H"is in California (High pressure cell brings cool conditions )it would be cool and the fronts are located on the coast of California."L"is in Utah (Low pressure cell brings warm conditions) it would be warmer. you let me know. I answeredit all the way.
Hydrazine, N2H4, reacts with oxygen to form nitrogen gas and water.
N2H4(aq)+O2(g)⟶N2(g)+2H2O(l)
If 3.45 g of N2H4 reacts with excess oxygen and produces 0.650 L of N2, at 295 K
and 1.00 atm, what is the percent yield of the reaction?
Four peripheral hydrogen atoms and two singly-bonded nitrogen atoms make up the molecule of hydrazine.
Thus, It is a colourless, poisonous irritant and sensitizer in its anhydrous form, which harms the central nervous system and causes symptoms as severe as tumours and convulsions.
In addition to having a strong reducing agent that makes it highly explosive, hydrazine has a strong smell that is similar to that of ammonia.
Given this, it appears odd that over 100,000 metric tonnes of the substance are produced annually throughout the world. But hydrazine does have an impact on our daily activities. It can save our lives, give us food and clothing, keep us warm, and even transport us to the moon. It even has the ability to go back in time.
Thus, Four peripheral hydrogen atoms and two singly-bonded nitrogen atoms make up the molecule of hydrazine.
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Question 3 of 10
How can the effect of heat on a reaction be determined?
A. Heat will increase reaction rate, but not equilibrium position.
B. Heat always shifts a reaction toward reactant formation.
C. Heat always shifts a reaction toward product formation.
D. Heat is treated as a reactant or a product.
SUBMIT
Given the following equations and H° values, determine the heat of reaction at 298 K for the reaction: C(s) + 2 H2(g) -> CH4(g)
H2 (g) + 1/2 02 (g) -> H20 (l)
CO2 (g) + 2 H20 (l) -> CH4 (g) + 2 02 (g)
C(s) + O2(g) -›CO2(g)
H kJ = - 393.5
H kJ = -285.8
H kJ = +890.3
The heat of reaction for the reaction C(s) + 2 H2(g) -> CH4(g) at 298 K can be calculated by using the following equation: ΔH = (ΔHf products - ΔHf reactants).
Applying this equation to the given reaction, we get ΔH = (-890.3 + 393.5 + 285.8) kJ = -210.0 kJ.
This is the heat of reaction at 298 K for the reaction C(s) + 2 H2(g) -> CH4(g).
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A soft drink contains 33g of sugar in 349g of H2O. What is the concentration of sugar in the soft drink in mass percent?
.
A soft drink contains 33g of sugar in 349g of H[tex]_2[/tex]O. 14.3% is the concentration of sugar in the soft drink in mass percent.
One approach to indicate the concentration of any dissolved component in a solution is by mass percentage. Mass percentage is the ratio of the total weight of a compound in a solution to the overall mass of the solution, expressed in percentages.
In order to express the mass percent of a solution, the grammes of solute are divided by the grammes of solution, and the result is multiplied by 100. As long as you use a comparable number for both the component and solute mass.
Mass percent = (mass of solute/mass of solute+ mass of solvent)×100
= ( 33/ 33+ 349)×100
=14.3%
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Can someone please help? And quickly if you can thank you!
The concept ideal gas equation is used here to determine the number of moles. The ideal gas law is the equation of state of a hypothetical ideal gas. Here the number of moles of gas is 0.17.
The equation which is formed by the combination of Boyle's law, Charles's law and Avogadro's law is called the ideal gas equation. An ideal gas is a theoretical gas composed of a set of randomly moving point particles which interact through elastic collisions.
The ideal gas equation is:
PV = nRT
n = PV / RT
10°C = 283 K
Number of moles is:
n = 1.2 × 3.4 / 0.0821 × 283 = 0.17
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1. (16 points) Shown below are IR and MS data for a compound with a molecular formula of C3H₂O
a) Identify the functional groups
responsible for the labeled
absorptions in the IR spectrum.
i) 1601 cm¹
ii) 1691 cm¹
Relative Intensity
100-
80-
m/z
rel. Intensity
22.6
73.1
105 100.0
120
26.2
$1.0
77.0
50 60
TRATT
100 110 120
1601 cm
1691 cm³
iii) From the parent,
what mass is lost to form
the base peak at m/z =
105?
iv) What is the likely
structure of that
fragment that is lost
to form m/z 105?
70
m/z
v) From the parent, what mass is lost to form the m/z = 77 peak?
Answer:
i) 1601 cm¹ - This absorption is likely from a C=O stretching vibration indicative of an aldehyde or ketone functional group.
ii) 1691 cm¹ - This absorption is likely from an O-H stretching vibration indicative of an alcohol functional group.
iii) From the parent, the mass lost to form the base peak at m/z = 105 is 17 amu.
iv) The likely structure of the fragment that is lost to form m/z 105 is C2H2O.
v) From the parent, the mass lost to form the m/z = 77 peak is 28 amu.
vi) The likely structure of the fragment that is lost to form m/z 77 is C2H3O.
Explanation:
Please name this compound.
Answer:
The chemical name for this compound is 4-ethyl-2-methylhex-2-ene.
if this helps, please mark my answer as brainliest
N₂ +
H₂O →>>
NH, -
+
0₂
The balanced chemical equation for the reaction is:
N₂ + 3H₂O → 2NH₃ + O₂
The equation shows that nitrogen gas (N₂) and water (H₂O) react to form ammonia (NH₃) and oxygen gas (O₂). The coefficients in the balanced equation indicate that one molecule of N₂ reacts with three molecules of H₂O to produce two molecules of NH₃ and one molecule of O₂.
HELP PLEASE!! DUE IN A FEW MINUTES!!
1) Aluminum and indium are in the same group
2) Barium is in group 2 and period 6
What is the periodic table?The names of the compounds are;
Triphosphorous tetrachloride
Calcium bromide
Nitrogen hexasulfur
The molecules that balance the charges are;
K3P, Al2O3, CaS
The elements in group 17 are chlorine and fluorine
The elements in period 3 are sodium and magnesium.
The balanced equations are from the data given;
SnO2 + 2H2 → Sn + 2H2O
4Al + 3O2 → 2Al2O3
Au2S3 + 3H2 → 2Au + 3H2S
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Which compound represents fe+3 o-2
Answer:
The compound that represents Fe+3 O-2 is Fe2O3 (iron oxide or rust)
a 70 piece of metal at 120 C is dropped into a kilometer with 150 g of 30C water the final temperature of the water and little changes 35c what is the specific heat of the metal
A 70 piece of metal at 120 C is dropped into a kilometer with 150 g of 30C water the final temperature of the water and little changes 35c, 0.385 J/g°c is the specific heat of the metal.
The amount of heat needed to raise a substance's temperature by one degree Celsius in one gramme, also known as specific heat. Typically, calories and joules per gramme per degree Celsius are used as a measure of specific heat.
In the 18th century, the Scottish researcher Joseph Black found that equivalent masses of various substances required varying quantities of heat to bring them across the same temperature range. Based on this finding.
cm = (0.15 kg x 4.18 J/gCx (35C - 30C)) / (70 pieces x 0.1 kg/piece x (120C - 35C))
cm = 0.385 J/g°c
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Reversible reactions allow products to create the reactants after a chemical reaction has gone from reactants to products. Which of the following is an example of a reversible reaction?
A) Oxygen combining with hemoglobin in red blood cells in our body, and then the red blood cells delivering the oxygen to needed locations\
B) Ammonium chloride separating into ammonia and hydrogen chloride gas
C)Hydrogen and oxygen combining to form water, and then water being broken down by a cell to be used in cellular respiration
D)All of the above
Saccharin (HNC7H4SO3) is a weak acid with pKa = 2.32 at 298 K.
a. Write a hydrolysis equation for the reaction of saccharin with water.
b. Calculate the pH of 0.10 M solution of saccharin.
c. Calculate the %ionization of the acid in this solution.
The pka or molarity of a solution may be used to calculate its pH. The saccharin solution in this area has a pH of 1.65.
The pH for a solution determines how acidic or basic it is. It refers to the opposite of the positive logarithm of the H+ ion concentration in maths. A solution that is acidic has a pH below 7, while a basic solution has a pH above 7.
Ka of an acid = [A-] [H+] / [HA]
ka = antilog (-pka)
= antilog (- 2.32)
= 0.0047
Ka = [H+]²/[HA]
[H+]² = Ka × [HA]
= 0.0047 × 0.11
= 0.00051
[H+] = 0.022.
pH = -log [H+]
= -log (0.022)
= 1.65
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Calculate the final temperature (in Celsius) of HCI gas if 0.500 L at 42°C and 0.950 atm is heated
until the volume reaches 1.81 L at 0.950 atm. (deg C)
You have 400,000 atoms of a radioactive substance. After 2 half-lives have past, how many atoms remain?
Remember that you cannot have a fraction of an atom, so round the answer to the nearest whole number.
After 2 half-lives, 100,000 atoms of the radioactive substance will remain.
If two half-lives have passed, the number of remaining atoms will be one-fourth (1/2 x 1/2 = 1/4) of the original number of atoms.
Therefore, the number of remaining atoms will be:
400,000 x (1/4) = 100,000 atoms
Rounding this to the nearest whole number, we get:
100,000 atoms
Therefore after 2 half-lives, 100,000 atoms of the radioactive substance will remain.
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shapes of simple polyatomic molecules
Answer:
Polyatomic molecules that are linear in shape are known as linear polyatomic molecules. The atoms in these linear molecules are arranged in a straight line (at an angle of 180 degrees). At the central atom of linear geometry polyatomic molecules, the electron pair has sp hybridization.
How many moles of KF are contained in 180.0 mL of a 0.250 M solution?
Answer:
To calculate the number of moles of KF in a solution, we can use the formula:
moles = concentration x volume
where concentration is in units of moles per liter (M), and volume is in liters (L).
First, we need to convert the volume from milliliters (mL) to liters (L):
180.0 mL = 0.1800 L
Next, we can plug in the values we have:
moles = 0.250 M x 0.1800 L = 0.0450 moles
Therefore, there are 0.0450 moles of KF in 180.0 mL of a 0.250 M solution.
Explanation:
How much energy is required to heat 192 grams of lead from 18 degrees Celsius to 44
degrees Celsius?
The amount of energy required to heat the given amount of lead from 18°C to 44°C is 638.976 J.
The specific heat capacity of lead is 0.128 J/g°C.
To calculate the amount of heat energy required to heat 192 grams of lead from 18°C to 44°C, we can use the formula:
Q = m × c × ΔT
where:
Q = heat energy (in Joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
Plugging in the given values:
m = 192 g
c = 0.128 J/g°C
ΔT = (44°C - 18°C) = 26°C
Q = 192 g × 0.128 J/g°C × 26°C
Q = 638.976 J
So, the amount of heat energy required to heat 192 grams of lead from 18°C to 44°C is 638.976 Joules.
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precipitation of carbonate ion with barium ion
Answer:
When barium ions are added to a solution containing carbonate ions, barium carbonate precipitate is formed, which serves as an additional confirmation for the presence of carbonate ions in the medium. According to Table 1, silver salts of chloride ions are insoluble.
concept of hybridization in chemistry
Answer:
Hybridization is the process in which two complementary single-stranded DNA and/or RNA molecules bond together to form a double-stranded molecule.
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The nitrogen pressure at the Venusian surface is 2050 torr and the atmosphere of Venus is 3.0 mole% N2. What is the surface pressure on Venus in atm?
At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. You may want to reference (pages 641 - 644) section 15.6 while completing this problem. Part a if the initial concentration of no is 0.175 m, what is the equilibrium concentration of no? how is the quadratic equation set up i cannot get the right values
Substance A decomposes at a rate proportional to the amount of A present.
Write an equation relating A to the amount left of an initial amount Ao after time t.
It is found that 8 g of A will reduce to 4 g in 3 hr. After how long will there be only 1 g left?
It will take approximately 2.079 hours for there to be only 1 g of substance A left.
The rate of decomposition of substance A is proportional to the amount of A present, which means that we can use the following differential equation to describe the decay;
dA/dt = -kA
where A is the amount of substance A at time t, k is the rate constant of the reaction, and the negative sign indicates that A is decreasing over time.
To solve differential equation, we separate the variables and integrate;
[tex]d_{A}[/tex]/A = -k [tex]d_{t}[/tex]
Integrating both sides gives;
ln(A) = [tex]-k_{t}[/tex] + C
where C is the constant of integration. To find the value of C, we can use the initial condition that 8 g of A reduces to 4 g in 3 hours. At t=0, A=Ao=8 g, and at t=3, A=4 g. Substituting values into the equation above, we have;
ln(8) = -3k + C
ln(4) = -6k + C
Subtracting first equation from second, we get;
ln(4/8) = -3k
Simplifying, we get;
k = ln(2)/3
Now, we can use the equation we derived earlier to find how long it will take for there to be only 1 g of A left;
ln(A) =[tex]-k_{t}[/tex] + C
ln(1) = -(ln(2)/3)t + C
Simplifying, we get:
t = 3 ln(2)
t ≈ 2.079 hours
Therefore, it will take 2.079 hours.
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A rubber balloon containing 1.0 L of gas is carried from the top of a mountain to the bottom of the mountain, where it’s volume is measured as .85 L at standard pressure. Assuming that there was no temperature change during the trip, what was the pressure in atmospheres at the top of the mountain?
Show steps pls
Answer:
the pressure at the top of the mountain was 0.85 atm.
Explanation:
We can use the combined gas law to solve this problem:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.
Assuming that the temperature remains constant, we can simplify the combined gas law to:
P1 * V1 = P2 * V2
where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Substituting the given values, we get:
P1 * 1.0 L = 1 atm * 0.85 L
P1 = (1 atm * 0.85 L) / 1.0 L
P1 = 0.85 atm
A substance with a pH of 2 would be considered a strong what?
Answer:
A substance with pH 2 should be considered a strong acid.
Explanation
ph is a measure of how acidic or basic water is. The range goes from 0-14, with 7 being neutral.
pH of less than 7 indicate acidity and pH greater than 7 indicates base. So , the intensity of the acidic products increase as the pH decrease from 6 to 0 ,i.e. lower the value of pH higher will be the acidity.
With pH 2 given in the question it is considered as a strong acid.However , pH 2 acids are less acidic than acids having pH 0 and 1 but more acidic in compare to pH 3-6.
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Heat absorbed or released by a substance can be calculated with the equation _____________.
q = m × Cs × ∆T
q = m × Cs ÷ ∆T
q = m + Cs + ∆T
q = m + Cs
how mony moles of each ion present in 100mL of0.12M Ca3(Po4)2 solution.
In 100 mL of 0.12 M Ca3(PO4)2 solution, there are 0.036 moles of calcium ions and 0.024 moles of phosphate ions.
To find the number of moles of each ion present in 100 mL of 0.12 M Ca3(PO4)2 solution, we first need to determine the formula weight of Ca3(PO4)2.
Ca3(PO4)2 contains three calcium ions (Ca2+) and two phosphate ions (PO43-).
The atomic weight of calcium (Ca) is 40.08 g/mol, and there are three calcium ions in Ca3(PO4)2, so the total weight of calcium in Ca3(PO4)2 is 3 x 40.08 = 120.24 g/mol.
The atomic weight of phosphorus (P) is 30.97 g/mol, and the atomic weight of oxygen (O) is 16.00 g/mol.
The molecular weight of the phosphate ion (PO43-) is therefore 30.97 + (4 x 16.00) = 94.97 g/mol. Since there are two phosphate ions in Ca3(PO4)2, the total weight of phosphate in Ca3(PO4)2 is 2 x 94.97 = 189.94 g/mol.
The total formula weight of Ca3(PO4)2 is therefore 120.24 + 189.94 = 310.18 g/mol.
To find the number of moles of each ion present in 100 mL of 0.12 M Ca3(PO4)2 solution, we can use the formula:
moles = concentration x volume
For calcium ions:
moles of Ca2+ = concentration of Ca3(PO4)2 x (3 moles of Ca2+ / 1 mole of Ca3(PO4)2) x volume
moles of Ca2+ = 0.12 M x (3 / 1) x 0.1 L
moles of Ca2+ = 0.036 mol
For phosphate ions:
moles of PO43- = concentration of Ca3(PO4)2 x (2 moles of PO43- / 1 mole of Ca3(PO4)2) x volume
moles of PO43- = 0.12 M x (2 / 1) x 0.1 L
moles of PO43- = 0.024 mol
Therefore, in 100 mL of 0.12 M Ca3(PO4)2 solution, there are 0.036 moles of calcium ions and 0.024 moles of phosphate ions.
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