(PLS help I’ll give brainliest to whoever can answer right nobody has been able to. )

A company makes piñatas for special events such as birthday parties. One of their piñatas is in the form of a cone-shaped hat. How much space do they have inside the piñata for candy if the piñata is 2 feet tall and 1.5 feet wide? Round to the nearest hundredth.

Answer:

6

Step-by-step explanation:

2 x 3

Answer:

V(sphere) =

[tex] \frac{4 }{3} \pi \:{r}^{3} = 195.43 \\ [/tex]

V(hemisphere) = V(sphere)/2 = 97.715 = 97.7

Answer:

45n+12mm

Step-by-step explanation:

I hope this is right if it is right pls mark me as brainliest and learn well

the value of a and b will be 45 and 0 for the given expression.

the property of having suitable proportions in terms of size, number, degree, harshness, etc.: If a defensive action against an unfair attack results in the destruction that contravenes the proportionality criterion, it may even go far beyond a justifiable defense.

Given, the shapes are a circle with a radius of 21mm and a quarter circle of 6mm.

Since Radius = 21 cm

the radius of the circle/ radius of the quarter circle = 7/2

Total length = Sum of the circumference of both the circle

Since the formula for the circumference of a circle:

C = 2 * pi * radius

Total length = 2* pi* r + 1/4 * (2 * pi * r')

Total length = 2 *pi * 21 + pi * 3

Total length = π(42 + 3)

total length = 45π + 0

therefore, the value of a and b will be 45 and 0 for the given expression.

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#SPJ2

Answer:

give me 2 minutes and I will

Answer:

-1/4

Step-by-step explanation:

14x - 2x + 3 = 0
12x + 3 = 0
12x = -3
12x/12 = -3/12
x = -1/4

Answer: 10.62 irrational

Step-by-step explanation: You can divide 69.15 by 5.25 which equals 74.4 then divide by 7 which equals 10.62

Answer:

Step-by-step explanation:

Because a square has 4 equal sides:

P = 4x

A = [tex]x^{2}[/tex]

[tex]P=\frac{4x^2+4}{x^2-2x+1}[/tex]                              (original P equation)

[tex]4x=\frac{4x^2+4}{x^2-2x+1}[/tex]                             (substitute P = 4x)

[tex]4x(x^2-2x+1)={4x^2+4}[/tex]         (multiply denominator on both sides)

[tex]4x^3-8x^2+4x={4x^2+4}[/tex]          (distribute 4x)

[tex]4x^3-12x^2+4x-4=0[/tex]            (combine like terms, set = to 0)

[tex]4(x^3-3x^2+x-1)=0[/tex]             (factor)

Continue using quadratic formula to find x

Hope this helps! Cannot finish answer right now, so sorry

side=Perimeter/4

side:-

[tex]\\ \rm\Rrightarrow \dfrac{4(x^2+1)}{4(x^2-2x+19}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{x^2+1}{x^2-2x+19)}✓/tex]

Area=side ²

[tex]\\ \rm\Rrightarrow \left(\dfrac{x^2+1}{x^2-2x+19}\right)^2[/tex]

Answer:

2 students do Chemistry, but not Mathematics

Step-by-step explanation:

2 students do Chemistry, but not Mathematics

*View attached table*

Hope this helps!

Using proportions, it is found that it would take 1 hour for the pedestrian to travel the same distance.

A proportion is a fraction of a total amount.

In this problem, the cyclist takes 25 minutes, while the pedestrian's time is [tex]2\frac{2}{5} = \frac{12}{5}[/tex] slower(greater), hence his time is given by:

[tex]t = \frac{12}{5} \times 25 = 12 \times 5 = 60[/tex]

It would take 1 hour for the pedestrian to travel the same distance.

More can be learned about proportions at https://brainly.com/question/24372153

Answer:

a cone with a radius of 4 units

Step-by-step explanation:

when rotating something, this involves a circle. so, the result will always be round and never edgy. therefrom the first option is wrong.

and we are rotating a triangle. the result will have a wide base and a pointed tip. so, the third option is wrong.

the rotation does not make the basic shape smaller. so, the second option is wrong.

yes, the fourth option is correct.

On factoring, the value of t is 1. This shows that the car will land on the ground after 1 sec.

Quadratic functions are functions having a leading degree of 2.

Given the function height in feet of the car after t seconds expressed as

h = -16t^2 +10t +6

The height of the car on the ground is zero, hence:

16t^2 -10t -6 = 0

8t^2 - 5t - 3 = 0

Factorize the quadratic function

8t^2 - 5t - 3 = 0

On factoring, the value of t is 1. This shows that the car will land on the ground after 1 sec.

Leearn more on functions here: https://brainly.com/question/10439235

Answer:

For the outside square, the diagonal is 7√2, or about 9.9 units.

For the inside square, the diagonal is 5√2, or about 7.1 units.

The solutions to the equation [tex]\rm (x + 2)^{2} - 2(x + 2) - 15 = 0[/tex] are 3 and -5.

To solve any equation is to find the solution of the given equation which satisfied the equation.

The given expression is [tex]\rm (x + 2)^{2} - 2(x + 2) - 15 = 0[/tex]

let u = (x +2)

then the equation becomes

[tex]\rm u^{2} - 2u - 15 = 0[/tex]

by factorizing, we get

(u + 3)(u - 5) = 0

u + 3 = 0, u = -3

u - 5 = 0, u = 5

Since, u = x + 2

So, x + 2 = 5, x = 3

x + 2 = -3, x = -5

Therefore, the solutions to the equation are 3 and -5.

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Answer:

12×8/2=48

10×10=100

2(48)+3(100)

96+300= 396ft²

Answer:

[tex] 1 \frac{2}{3}\: liters [/tex]

Step-by-step explanation:

[tex]V_{soda}[/tex] in one bottle = 5/9 liters

No of bottles = 3

Total volume of soda

[tex] = \frac{5}{9} \times 3 \\ \\ = \frac{5}{3} \\ \\ = 1 \frac{2}{3} \: liters[/tex]

[tex]\mathsf\blue{♧ANSWER♧}[/tex]

[tex] \mathsf \orange{ \frac{x \times y}{2}} [/tex]

[tex] \mathsf \green{ \frac{8 \times 12}{2} }[/tex]

[tex] \mathsf \orange{ \frac{96}{2} }[/tex]

[tex] \mathsf \green{48 \: square \: units}[/tex]

[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]

[tex]\qquad\qquad\qquad \large\underline{ \boxed{ \sf{✰\: Information }}}[/tex]

[tex]{ \boxed{ ✟ \: \underline{ \boxed{ \sf \: Area \: of \: kite = \frac{ d_1 \times d_2}{2} \: or \blue{ \: \frac{1}{2} \times d_1 \times d_2}}}✟ }}[/tex]

[tex]\rule{80mm}{2.5pt}[/tex]

[tex] \qquad \rm{➛Area \: of \: kite = \frac{BD×AC}{2} }[/tex]

[tex]\qquad \rm{➛Area \: of \: kite = \frac{8×12}{2} } \\ \qquad \rm{➛Area \: of \: kite = \frac{ \cancel{96}}{ \cancel2} } \\ \qquad \rm{➛Area \: of \: kite = 48 {units}^{2} }[/tex]

[tex]\rule{80mm}{2.5pt}[/tex]

★Hence area of kite with diagonals BD = 8 units and AC = 12 units is

[tex]\qquad\qquad\qquad{ \boxed{↪ \underline{ \boxed{ \sf{\: 48 {units}^{2} \green✓ }}}↩}}[/tex]

[tex]\rule{80mm}{2.5pt}[/tex]

★ More info regarding this topic ★

[tex]\rule{80mm}{2.5pt}[/tex]

Hope it helps !

Answer:

B = (5, 1).

Step-by-step explanation:

From the formula for the midpoint of  a line :-

(-1 + x)/2 , (5 + y)/2 = (6/2, 6/2)    where x and y are the coordinates of B.

so (-1 + x)/2 = 6/2

-1 + x = 6

x = 5.

and (5 + y)/2 = 6/2

5 +  y = 6

y =  1.

John paid $75 for a pair of shoe that cost $100 at a discount of 25 percent.

An equation is an expression that shows the relationship between two or more numbers and variables.

Let us assume that the shoe cost $100, he spins the spinner and gets a discount of 25%, hence:

Money paid = 100 - 25% of 100

Money paid = 100 - 25 = $75

John paid $75 for a pair of shoe that cost $100 at a discount of 25 percent.

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The rotation of point G to point H is an illustration of a circular movement

The rotation that maps point G to point H is 72 degrees clockwise

From the figure, we have the following parameters:

Number of sections (n) = 5

Angle at the center = 360

The angle of rotation is then calculated as:

Rotation = 360/5

Evaluate

Rotation = 72

Point H is to the left of point G.

This represents a clockwise direction

Hence, the rotation that maps point G to point H is 72 degrees clockwise

Read more about rotation at:

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Answer:

72° clockwise

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

3^2 = 9

Answer:

Step-by-step explanation:

slope is -3/1

Slope is Rise/Run

meaning 3 down and 1 right

so in this case the down means the Y-axis

and the right means the x-axis

so lets put out some points.

(2,-1)

Then 1 right and down 3

(3, -4)

(4,-7)

and soo on, but we want to fin the point where x is zero.

Why?

Because that is where the y-Intercept is at.

Slope Intercept form is y=mx+b

Where m is the slope

And b is the y- Intercept

Soooo

Let's work backwards

Instead of Right 1 and Down 3 lets do

Left 1 and Up 3

And we will be starting with our original point

(2,-1)

then left 1, Up 3

2-1=1

-1+3=2

soo...

(1,2)

then again

(0,5)

That is our Y-intercept.

Now lets put all of it together.

Y=Mx+B

M=Slope

B=Y-Intercept

Y=-3x+5

You're welcome...

SonicIsCoool, if you need more help im at your service.

[tex](x - 3)(2x {}^{2} - 5x + 1)[/tex]

[tex]2x {}^{3} - 5x {}^{2} + x - 6x {}^{2} + 15x - 3 [/tex]

[tex]2x {}^{3} - 11x {}^{2} + 16x - 3[/tex]

Answer:

B. 2 3/4 lbs

Step-by-step explanation:

there ar 16 ticks on a scale, the pointer is on 12, meaning it is 12/16, whihc is answer b

Answer:

its b

Step-by-step explanation:

looked it up

Answer: 42.0

Step-by-step explanation:

Answer:

23, 25, 27, 29

Step-by-step explanation:

14*2 = 28, 28-5=23

15*2=30, 30-5=25

16*2=32, 32-4=27

17*2=34, 34-5=29

[tex]14 \times 2 - 5[/tex]

[tex]28 - 5[/tex]

[tex]23[/tex]

[tex]15 \times 2 - 5[/tex]

[tex]30 - 5[/tex]

[tex]25[/tex]

[tex]16 \times 2 - 5[/tex]

[tex]32 - 5[/tex]

[tex]27[/tex]

[tex]17 \times 2 - 5[/tex]

[tex]34 - 5[/tex]

[tex]29[/tex]

The standard form of a polynomial is: ax^n+ bx^n-1 + cx^n-2  + ......... + d

The standard form of the polynomial is 4x^3 + 2x^2  + 3x - 6

The polynomial is given as:

(4x^3 - 2x - 9) + (2x^2 + 5x + 3)

Remove the bracket

4x^3 - 2x - 9 + 2x^2 + 5x + 3

Collect like terms

4x^3 + 2x^2 - 2x + 5x - 9 + 3

Evaluate the like terms

4x^3 + 2x^2  + 3x - 6

Hence, the standard form of the polynomial is 4x^3 + 2x^2  + 3x - 6

Read more about polynomials at:

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[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}[/tex]

Let's use distance formula ~

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{(2 - ( - 4)) {}^{2} + (0 - 1) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{(2 + 4) {}^{2} + ( - 1) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{ {}^{} 36+ 1{}^{} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{ {}^{} 37{}^{} } [/tex]

Therefore, the required distance is [tex]\sf \sqrt{37}[/tex] units