Pls help me answer the questions in the picture below the picture below has the question and table to fill out
Answers
Recall that to be able to add two quantities, they must have the same units.
We know that:
[tex]1\operatorname{km}=1000m\text{.}[/tex]Therefore:
1)
[tex]\begin{gathered} 15000\operatorname{km}+41000m=15000\times1000m+41000m \\ =15000000m+41000m=15041000m\text{.} \end{gathered}[/tex]2) We cannot convert from kilograms to meters, therefore we cannot add them.
3)
[tex]22m+27m=49m\text{.}[/tex]Answer:
1) 15000 km+4100m=15041000m,
2) No.
3)22m+27m=49m.
Related Questions
9.5t + 8 = 11.5t + 15
Answers
We are given the following equation
[tex]9.5t+8=11.5t+15[/tex]Let us solve the above equation for t.
Step 1:
Combine the like terms together
[tex]9.5t-11.5t=15-8[/tex]Step 2:
Simplify the equation
[tex]\begin{gathered} -2t=7 \\ t=-\frac{7}{2} \end{gathered}[/tex]Therefore, the solution of the equation is -7/2
You invested $4000 between two accounts paying 2% and 4% annual interest. If the total interest earned for the year was $140, how much was invested at each rate?
Answers
Given:
$4000 is invested in two accounts paying 2% and 4% annual interest.
The total interest earned for the year was $140.
To find:
The amount invested at each rate.
Explanation:
Let us frame the equation as follows,
[tex]\begin{gathered} 2\text{ \% }of\text{ }x+4\text{ \% }of\text{ }(4000-x)=140 \\ \frac{2}{100}x+\frac{4}{100}(4000-x)=140 \\ 2x+16000-4x=14000 \\ -2x=-2000 \\ x=\text{ \$}1000 \end{gathered}[/tex]Thus,
The amount invested at 2% interest is $1000.
The amount invested at 4% interest is $3000.
Final answer:
The amount invested at 2% interest is $1000.
The amount invested at 4% interest is $3000.
Chelsea and Aubree are selling cheesecakes for a school fundraiser. Customers can buy pecan cheesecakes and chocolate marble cheesecakes. Chelsea sold 5 pecan cheesecakes, , and 3 chocolate marble cheesecakes, , for a total of $160. Aubree sold 5 pecan cheesecakes and 10 chocolate marble cheesecakes for a total of $300. Write equations to represent the scenario. Then, find the cost each of one pecan cheesecake and one chocolate marble cheesecake.
Answers
Chelsea sold:
[tex]5p+3c=160[/tex]Aubree sold:
[tex]5p+10c=300[/tex]Subtracting the first equation from the second equation, it follows that:
[tex]\begin{gathered} 7c=140 \\ c=20 \end{gathered}[/tex]Substitute x=20 into the first equation:
[tex]\begin{gathered} 5p+3(20)=160 \\ 5p=100 \\ p=20^{\circ} \end{gathered}[/tex]Cheese: 5p + 3c = 160
Aubree: 5p + 10c = 300
Pecan Cheesecake: $ 20
Chocolate Marble Cheesecake: $ 20
Hello can someone please try to explain this to me as simply as possible
Answers
The easiest way to solve this problem is to substract 2π from the angle until we get an angle that is less than 2π.
[tex]\frac{19}{3}\pi-2\pi=\frac{19-6}{3}\pi=\frac{13}{3}\pi[/tex]13/3π is not less than 2π, so we have to substract 2π once more:
[tex]\frac{13}{3}\pi-2\pi=\frac{13-6}{3}\pi=\frac{7}{3}\pi[/tex]7/3π is still not less than 2π, substract 2π once more:
[tex]\frac{7}{3}\pi-2\pi=\frac{7-6}{3}\pi=\frac{1}{3}\pi[/tex]1/3π is less than 2π. It means that the positive angle less than 2π that is coterminal with 19/3π is 1/3π.
Pls help I need an answer fast!!
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The domain of this relation is {-5, -3, 0} which is option c.
From the graph:
The points marked are:
(-5, -4) , (-3, 4) , (0, -4) ,(0, 4).
Domain is nothing but the all the x-values or inputs to the function with no repetition.
Here from the points the set of x-values is {-5, -3, 0, 0}.
Domain = {-5, -3, 0} because 0 is repeated here so it is considered only once.
Hence the domain of the given relation is {-5, -3, 0}.
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Which expression is equivalent to O xy √xy² X Ox/² 20 Which expression is equivalent to O xy √xy² X Ox / ² 20
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Answer:
[tex]x(\sqrt[9]{y^2})[/tex]Explanation:
Given that:
[tex]xy^{\frac{2}{9}}[/tex]Simplifying, we have:
[tex]\begin{gathered} xy^{\frac{2}{9}} \\ =x*y^{\frac{2}{9}} \\ =x*\sqrt[9]{y^2} \\ =x(\sqrt[9]{y^2}) \\ \\ xy^{\frac{2}{9}}=x(\sqrt[9]{y^2}) \end{gathered}[/tex]Therefore, the last option is the correct answer
Input a number that has a 6 with 10 times the value of the 6 in 36,421
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Step-by-step explanation:
the 6 in 36,421 has the value 6,000.
10 times that value is 60,000.
so, the new number must have a 6 in the 5th place (the tenthousands place), like
65,535
write the equation of the line passing through the points (-4,-1) and (2,8). Show all of your work.
Answers
the general equation of the lines is
[tex]y=mx+b[/tex]where m is the slope and b the y-intercept
• calculating the slope
[tex]\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ \end{gathered}[/tex]where (x2,y2) is a right point from (x1,y1)
on this case (x2,y2) is (2,8) and (x1,y1) the other point
replacing
[tex]\begin{gathered} m=\frac{8-(-1)}{2-(-4)} \\ \\ m=\frac{9}{6}=\frac{3}{2} \end{gathered}[/tex]the slope is 3/2
• Calculating b
replace m and a point to solve b from the general equation. I will use the point (2,8)
[tex]\begin{gathered} (8)=(\frac{3}{2})(2)+b \\ 8=3+b \\ b=8-3 \\ b=5 \end{gathered}[/tex]• rewriting the equation
replace m and b on the general equation
[tex]y=\frac{3}{2}x+5[/tex]1. What is the circumference of the circle? Use 3.14for 7. Round to the nearest tenth.A. 31.2 ydC. 88.2 ydB. 44.1 ydD. 176.5 yd28.1 yd
Answers
1.-
Circumference = 2 pi r
= 2 * 3.14 * 28.1/2
= 44.1 yd letter B
2.- Circumference = 2*pi* r
= = 2*3.14*11
= 69.08 in letter H
3.- Area = pi*r^2
= 3.14*(9)^2
= 254.34 mm^2 Letter B
I got the majority of the questions but I’m struggling on number 3, letters d, e, f, g, and h.
Answers
Given: The image shown in the question
To Determine: 3 collinearpoints
Solution
Collinear points are the points that lie on the same straight line or in a single line. If two or more than two points lie on a line close to or far from each other, then they are said to be collinear
d. Therefore Points D, G, and F are collinear
Coplanar points are three or more points which lie in the same plane. Recall that a plane is a flat surface which extends without end in all directions.
e. Therefore, the points A, D, G, and F are coplanar points
If two planes intersect each other, the intersection will always be a line
f. Thereffore, the intersection of plane ABC and plane ABE is the line AB
g. The intersection of planes BCH and DEF.
From the image, there is no intersection between the planes BCH and DEF
h. The intersection of line AD and line DF is point D
What is the probability of either event occurring when you roll adie?Event A: Rolling a prime numberEvent B: Rolling a 4Express your answer as a simplified fraction.
Answers
Given:
Roll a die.
Required:
We need to find the probability of rolling a prime number and a number 4.
Explanation:
A)
A die has sic sides and is numbered from 1 to 6.
The sample space, S ={1,2,3,4,5,6}
Let A be the event of rolling a prime number.
Recall that a prime number is a whole number greater than 1 whose only factors are 1 and itself.
[tex]A=\lbrace2,3,5\rbrace[/tex][tex]n(A)=3[/tex]The probability of rolling a prime number is P(A).
[tex]P(A)=\frac{n(A)}{n(S)}[/tex][tex]P(A)=\frac{3}{6}[/tex][tex]P(A)=\frac{1}{2}[/tex]B)
Let B be the event of rolling a number 4.
[tex]B=\lbrace4\rbrace[/tex][tex]n(B)=1[/tex]The probability of rolling a number 4 is P(B).
[tex]P(B)=\frac{n(B)}{n(S)}[/tex][tex]P(B)=\frac{1}{6}[/tex]Final answer:
The probability of rolling a prime number is 1/2.
The probability of rolling a 4 is 1/6.
Assuming it is a normal 6-sided die.
We have 6 possible possibilities : 1,2,3,4,5,6.
In these 6 numbers, only 2,3 and 5 are prime numbers.
Therefore, the probability of event A = 3/6 = 1/2.
There is only one 4 in this sample -> The probability of event B = 1/6.
Please help ! The number of people contacted at each level of a phone tree can be represented by f(x)=3x^
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Solution:
Given:
[tex]\begin{gathered} f(x)=3^x \\ \\ f(x)\text{ is the number of people that will be contacted} \\ x\text{ is the level of the phone tree} \end{gathered}[/tex][tex]\begin{gathered} when\text{ }f(x)=27 \\ 27=3^x \\ \\ Making\text{ the equation have the same base;} \\ 3^3=3^x \\ \\ Since\text{ the bases are equal, equate the exponents.} \\ Hence, \\ 3=x \\ x=3 \end{gathered}[/tex]This means at level 3, 27 people will be contacted.
Therefore, OPTION A is the correct answer.
25 POINTS!!!! PLEASE HELP ITS IXL TRANSFORMATION OF ABSOLUTE VALUE FUNCTIONS
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The graph of f (x) = | x | is
We observe that the graph of g (x) has only one transformation: it moves one unit to the right, therefore
[tex]\begin{gathered} g(x)=a|x-h|+k \\ g(x)=|x-1| \end{gathered}[/tex]a=1, k=0 and h=1 because the graph does not stretch horizontally or vertically, and only moves along the x-axis.
Find the domain and the range of the given relation.
{(-9,-7), (9,3), (0, -6), (-6,0)}
The domain is. (Use a comma to separate answers as needed.)
Answers
Answer:
Domain: -9, -6, 0, 9 I put them in ascending order
Range: -7, -6, 0, 3 I put them in ascending order.
Step-by-step explanation:
The domain is the inputs or the x values.
The range is the outputs or the y values.
Find this function after differentiating it 68 times:f(x) = sin (3x)
Answers
Given the function:
[tex]f(x)=\sin (3x)[/tex]Let's find the function after differentiating it 68 times.
To differentiate, let's take the derivative.
First derivative:
[tex]\begin{gathered} f\text{'(x)= cos(}3x)\frac{d}{dx}(3x)_{} \\ \\ f^{\prime}(x)=3\cos (3x) \end{gathered}[/tex]Second derivative:
Since 3 is the constant with respect to x, the derivative of 3cos(3x) with respect to x will be:
[tex]\begin{gathered} f^{\doubleprime}(x)=3\frac{d}{dx}(\cos (3x)) \\ \\ f^{\doubleprime}(x)=3(-\sin (3x)\frac{d}{dx}(3x)) \\ \\ f^{\doubleprime}(x)=-3\sin (3x)(3\frac{d}{dx}(x)) \\ \\ f^{\doubleprime}(x)=-9\sin (3x)\frac{d}{dx}(x) \\ \\ f^{\doubleprime}(x)=-3^2\sin (3x) \end{gathered}[/tex]After the second differentiation, we have -sin, , the same will be applicable to the 68th time.
Therefore, for the 68th differentiation the exponent for the constant -3 will be 68.
[tex]f(x)=-3^{68}\sin (3x)[/tex]Therefore, after differentiating the function 68 times, we have:
[tex]f(x)=-3^{68}\sin (3x)[/tex]ANSWER:
[tex]f(x)=-3^{68}\sin (3x)[/tex]can you help me with this one it has trhyree parts
Answers
Given: A graph showing point A, B, and C
To Determine: The nature at f, f', and f''
Solution
[tex]f=negative[/tex]At turning point, the first derivative is zero. Therefore
[tex]f^{\prime}=Zero[/tex]The minimum point is the test for the second derivative. Hence, the second derivative is
[tex]f^{\prime\prime}=Positive[/tex]In Summary
f = negative
f' = zero
f'' = positive
Use Cramer's rule to solve the system or to determine that the system is inconsistent or contains dependent equations.
Answers
In order to solve the system using Cramer's rule, first let's put the system in matrix form:
[tex]\begin{gathered} \begin{bmatrix}{1} & {1} \\ {1} & {-1}\end{bmatrix}\begin{bmatrix} & {x} \\ & {y}\end{bmatrix}=\begin{bmatrix} & {7} \\ & {1}\end{bmatrix}\\ \\ D\cdot X=B \end{gathered}[/tex]The matrix D is the matrix with the coefficients of x and y from each equation.
The determinant of a 2x2 matrix is given by the product of the terms in the main diagonal minus the product of terms in the secondary diagonal:
[tex]|D|=1\cdot(-1)-1\cdot1=-1-1=-2[/tex]The matrix Dx is given by the matrix D after switching the first column with the coefficient matrix B:
[tex]\begin{gathered} Dx=\begin{bmatrix}{7} & {1} \\ {1} & {-1}\end{bmatrix}\\ \\ |Dx|=7\cdot(-1)-1\cdot1=-7-1=-8 \end{gathered}[/tex]And the matrix Dy is given by the matrix D after switching the second column with the coefficient matrix B:
[tex]\begin{gathered} Dy=\begin{bmatrix}{1} & {7} \\ {1} & {1}\end{bmatrix}\\ \\ |Dy|=1\cdot1-7\operatorname{\cdot}1=1-7=-6 \end{gathered}[/tex]Now, solving the system, we have:
[tex]\begin{gathered} x=\frac{|Dx|}{|D|}=\frac{-8}{-2}=4\\ \\ y=\frac{|Dy|}{|D|}=\frac{-6}{-2}=3 \end{gathered}[/tex]I want to purchase a third of a cupcake for myself, a third for and sister, and 4 thirds for our cousin.
Answers
Based on the above, we need a little less than two cupcakes (1.99) to have the amount of cupcakes everyone wants.
How to identify the amount of cupcakes that each one wants?To identify the amount of cupcake that each one wants, we must make the divisions of the fractions as shown below:
1/3 = 0.33
1/3 = 0.33
4/3 = 1.33
Based on the above, me and my sister require 0.33 from a cupcake, while our cousin requires 1.33. To know how many cupcakes we need to meet everyone's need, we must add these values as shown below:
0.33 + 0.33 + 1.33 = 1.99
So 1.99 cupcakes would be needed so it would be better to buy 2 cupcakes to give everyone the portion they need.
Note: This question is incomplete because there is some information missing. Here is the complete information:
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Factor the following polynomial using the greatest common factor. If the expression cannot be factored, enter the expression as is. 3y+18
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Given the following polynomial,
[tex]3y+18[/tex]We can factor it as follows;
[tex]\begin{gathered} 3y+18 \\ \text{The greatest common factor is 3} \\ We\text{ factor out 3 and we have;} \\ 3(y+6) \end{gathered}[/tex]ANSWER:
[tex]3(y+6)[/tex]Simplify the expression (6.8 x 106) +
(3.4 × 106). Express your answer in
scientific notation.
+
) × 10
x 10
x 10
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(I'll use ^ for the index stuff)
First, we put 10^6 out as the common term
=> 10^6(6.8+3.4)
=> 10^6 (a) x 10.2 (b)
Though, because b has to be less than 10, we divide b by 10 and multiply a by 10
=> 10^7 x 1.02
Suppose the population of a certain clty is 3775 thousand it is expected to decrease to 2911 thousand in 50 years. Find the percent decreaseThe percent decrease is approximately %(Round to the nearest tenth )
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The current population of the city is 3775000. Since it is expected to decrease to 2911000, the percent decrease would be
[tex]undefined[/tex]The volume of this triangular prism is 1,690 cubic feet. What is the value of t?
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The volume of a triangular prism is given by:
[tex]\begin{gathered} V=\frac{1}{2}bhl \\ where: \\ V=1690ft \\ b=t \\ h=13ft \\ l=20ft \end{gathered}[/tex]Solve for t:
[tex][/tex]Answer:
13 feet
Step-by-step explanation:
See attached worksheet
B) Write an equation of the line passing through the point (3,-2) that is parallel to the line y = [tex] \frac{2}{3} x - 1[/tex]
Answers
TO solve this problem, We might think "how can I use that parallel line to find my expression?". Well, if it is a parallel line it means our expression represents a line that has the same slope. That is the information we need from the parallel line and once the slope intercept for is y = mx - b where m represents the slope, it means our slope in
[tex]y=\frac{2}{3}x-1[/tex]is m = 2/3. Now we can look for our expression. So we use a point slope formula as bellow:
[tex](y-y_1)=m(x-x_1)[/tex]Where:
So, Now we can substitute the slope and the values of the point and solve as follows:
And above we can see circled in green our final answer, the expression we were looking for.
Identify the point and slope in the equation y - 1 = -2(x -2)
Answers
The equation
[tex]y-1=-2(x-2)[/tex]Is in point intercept form
The general equation of point intercept form is given as
[tex]y-y_1=m(x-x_1)_{}[/tex]Comparing the two equations
This implies
[tex]m=-2[/tex]Hence, the slope in the equation is -2
Also, by comparing the equations
[tex]x_1=2,y_1=1[/tex]Thus the point in the equation is (2, 1)
what is the value if g
Answers
We know that
49º + g = 79º
we have to find a number that added with 49º is 79º
This number is
79º - 49º = 30º
Since
49º + 30º = 79º
Then
g = 30º
Answer: g = 30ºwhat is 9k - 2K + 5 + 7
Answers
Question 2:
[tex]9K-2K+5+7=[/tex]Let us simplify the above expression
The terms are already combined so we just need to simplify them
[tex]\begin{gathered} 9K-2K+5+7 \\ 7K+5+7 \\ 7K+12 \end{gathered}[/tex]Question 3:
[tex]3-5y+6=[/tex]Let us simplify the above expression
Combine the like terms together and simplify
[tex]\begin{gathered} 3-5y+6 \\ 3+6-5y \\ 9-5y \end{gathered}[/tex]Question 4:
[tex]7r-r=[/tex]Let us simplify the above expression
Simply subtract r from 7r
[tex]\begin{gathered} 7r-r \\ 6r \end{gathered}[/tex]Therefore, the simplified expressions are
[tex]\begin{gathered} 2.\: \: 9K-2K+5+7=7K+12 \\ 3.\: \: 3-5y+6=9-5y \\ 4.\: \: 7r-r=6r \end{gathered}[/tex]Find the missing probability.P(A∩B)=3/100,P(B|A)=3/20,P(A)=?A. 3/10B. 13/40C. 1/5D. 39/400
Answers
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given probabilities
[tex]\begin{gathered} p(A\cap B)=\frac{3}{100} \\ p(B|A)=\frac{3}{20} \\ p(A)=? \end{gathered}[/tex]STEP 2: Write the formula for conditional probability
[tex]p(B|A)=\frac{p(A\cap B)}{p(A)}[/tex]STEP 3: Get the value of the requried probability
By Substitution,
[tex]\begin{gathered} \frac{3}{20}=\frac{\frac{3}{100}}{p(A)} \\ \\ \frac{3}{20}=\frac{3}{100\times p(A)} \\ Cross\text{ Multiply} \\ 3(100p(A))=3\times20 \\ 300\times p(A)=60 \\ p(A)=\frac{60}{300}=\frac{1}{5} \end{gathered}[/tex]Hencce, p(A) = 1/5
Write an additional expression for the situation. Then find the sum.A roller coaster drops 112 feet before going back up 52 feet.
Answers
Given:-
A roller coaster drops 112 feet before going back up 52 feet.
To find an additional expression for the situation. Then find the sum.
So here dropping down is considered as negative and back up is considered as positive.
So we get,
[tex]-112+52[/tex]So the sum is,
[tex]-112+52=-60[/tex]So the required solution is -60.
What is the equation for the lines that passes through the coordinates (0,0) and (3.5,3.5)
Answers
The equation of the line which passes through the coordinates (0,0) and (3.5,3.5) is y = x.
The slope intercept form of a line is given by:-
y = mx + c
Where,
m represents the slope of the line
c represents the y -intercept
(x,y) represents the coordinates of each point on the line.
We also know the slope of the line will be:-
(3.5-0)/(3.5-0) = 3.5/3.5 = 1
Hence, m = 1
Putting (0,0) in y = mx + c, we get,
0 = m*0 + c
0 = 0 + c
c = 0
Hence, the equation of the line is given by:-
y = x
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Find the discount and the sale price. Original Price $20Discount Sale Price Discount Rate 30% The discount is $ The sale price is $
Answers
We will find the values as follows:
*Discount:
[tex]x=\frac{20\cdot30}{100}\Rightarrow x=6[/tex]So, the discount is $6.
*Sale price:
[tex]SP=20-6\Rightarrow SP=14[/tex]So, the sale price is $14.