Answer:
[tex][I_2]=[Br]=0.31M[/tex]
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:
[tex]I_2+Br_2\rightleftharpoons 2IBr[/tex]
Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:
[tex]K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}[/tex]
Thus, we solve for x as show below:
[tex]\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M[/tex]
Therefore, the concentrations of both bromine and iodine are:
[tex][I_2]=[Br]=2.0M-1.69M=0.31M[/tex]
Regards!
What happens in radioactive decay?
O A. An electron is lost to form a negatively charged particle.
O B. An unstable nucleus breaks down into smaller parts.
O C. Two smaller nuclei are joined to form one larger nucleus.
O D. A large nucleus breaks apart to form smaller nuclei.
SHIRME
A radioactive atom will spontaneously release radiation in the shape of energy rather than particles in order to transition into a more steady state.
Why is something radioactive?Radioactivity, as its name suggests, seems to be the act of generating radiation without any external cause. This is carried out by an unstable atomic nucleus that "wants" to abandon certain power in order to change to a more stable form.
Are people radioactive at all?Absolutely, since humans consume radioactive materials from the environment through food, drink, and air, our bodies are inherently radioactive. Our bodies take these substances in and store them in our bones, tissues, and organs. We also breathe them in and consume them.
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Pls help I will give brainliest
Answer:
paki sagot naman pls para my isagot ako sa module ko ty
When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II) sulfate PbSO4 is reduced to lead at the cathode and oxidized to solid lead(II) oxide PbO at the anode.Suppose a current of 62.0 is fed into a car battery for 23.0 seconds. Calculate the mass of lead deposited on the cathode of the battery. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.
Answer: The mass of lead deposited on the cathode of the battery is 1.523 g.
Explanation:
Given: Current = 62.0 A
Time = 23.0 sec
Formula used to calculate charge is as follows.
[tex]Q = I \times t[/tex]
where,
Q = charge
I = current
t = time
Substitute the values into above formula as follows.
[tex]Q = I \times t\\= 62.0 A \times 23.0 sec\\= 1426 C[/tex]
It is known that 1 mole of a substance tends to deposit a charge of 96500 C. Therefore, number of moles obtained by 1426 C of charge is as follows.
[tex]Moles = \frac{1426 C}{96500 C/mol}\\= 0.0147 mol[/tex]
The oxidation state of Pb in [tex]PbSO_{4}[/tex] is 2. So, moles deposited by Pb is as follows.
[tex]Moles of Pb = \frac{0.0147}{2}\\= 0.00735 mol[/tex]
It is known that molar mass of lead (Pb) is 207.2 g/mol. Now, mass of lead is calculated as follows.
[tex]No. of moles = \frac{mass}{molar mass}\\ 0.00735 = \frac{mass}{207.2 g/mol}\\mass = 1.523 g[/tex]
Thus, we can conclude that the mass of lead deposited on the cathode of the battery is 1.523 g.
Plz help me well mark brainliest if correct
Answer:
D) biodiversity
Explanation:
the answer is D) biodiversity
Once the concentration of the common ion is increased______.
a. the solubility of the ionic solid increases.
b. the solubility of the ionic solid decreases.
c. the solubility of the common ion increases.
d. the solubility of the common ion decreases.
Answer:
B
Explanation:
PPLLLLLZZZZZ HELPPPPPPPPP ME WITH THIS QUESTION BRAINLIEST ANY ANSWERS WOULD BE GREATLY APPRECIATED :) chemical reaction will stop when the limiting reactant is used up.
Question 1 options:
True
False
sodium is an inactive metal why
Answer:
Inactive metals are inert metals that doesn’t react with most of the chemicals.They are highly resistant to oxidation and corrosion when exposed to moisture.
Explanation:
Astronauts must be protected from extreme heat while
reentering the Earth's atmosphere. Scientists can use the
engineering design process to help make reentry safer.
You have defined the problem as a need for heat shields to be stronger. What
should be your next step in using the engineering design process to solve the
problem?
O A. Communicate your solution to your team members.
O B. Update your initial design for the heat shield.
O C. Identify the criteria and constraints of the project.
O D. Build a prototype of a possible new type of heat shield.
The next engineering step to be taken is to update your initial design for the heat shield.
What is a heat sheild?The term heat sheild refers to a device that can be used to shield an from astronaut extreme heat especially as they re-enter the earth's atmosphere.
After you have identified the problem, the next engineering step to be taken is to update your initial design for the heat shield.
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A chemistry student needs 30.0 g of acetic acid for an experiment. He has available 1.2 kg of a 7.58% w/w solution of acetic acid in acetone.
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Round your answer to 3 significant digits.
Answer:
The mass of solution will be "395.78 g".
Explanation:
Given:
Mass of acetic acid,
= 30 g
Percentage,
= 7.58% w/w
Now,
⇒ % [tex]=\frac{Mass \ of \ acetic \ acid}{Mass \ of \ solution}\times 100[/tex]
By putting the values, we get
⇒ [tex]7.58=\frac{30}{Mass \ of \ solution}\times 100[/tex]
⇒ [tex]Mass \ of \ solution=\frac{30\times 100}{7.58}[/tex]
⇒ [tex]=\frac{3000}{7.58}[/tex]
⇒ [tex]=395.78 \ g[/tex]
For the reaction 2Na + Cl2 2NaCl, calculate the percent yield if
155.0 g of chlorine (Cl2) should be produced and your experiment
produced 143 g (C12).
Answer:
[tex]Y=92.25\%[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to calculate the percent yield by dividing the actual yield of 143 grams of gaseous chlorine by the theoretical yield of 155 g of this gas. In such a way, we proceed as follows:
[tex]Y=\frac{143g}{155g} *100\%[/tex]
Which has a result of:
[tex]Y=92.25\%[/tex]
Regards!
AgI + KNO3 what type of reaction is this
Answer:
all + kn03
Explanation:
and the reaction is single replacement
Select ALL of the abiotic factors
lesson 5.01
Question 1 options:
air
light
fungi
soil
salinity
Answer:
I think it should be
salinity and
light
Is anyone good at chemistry if so can someone please help me NO LINKS PLEASE
Answer:
I think it's (a) all of the materials will reach the same temperature and heat flow will stop.
1. The density of gasoline is 0.7 g/ml. What is the mass of 400L of gasoline?
Answer:
280,000g
Explanation:
0.7g/mL x 1000mL/1L x 400L = 280,000g
Which is the first step in the fusion process?
Explanation:
The first step of the Hydrogen fusion process: a nucleus of Deuterium (2H) is formed from two protons with the emission of an antielectron and a neutrino. The basic Hydrogen fusion cycle involves four Hydrogen nuclei (protons) and two electrons and yields a Helium nucleus, two neutrinos and six photons.
Answer:
C just took it
Explanation:
How many total ions are there in 5.00 moles of cobalt (II) bromide?
what are the products of this reaction
Cu+AgNO3
Answer:
1 Cu + AgNO3 → Ag + CuNO3
2 Cu + Ag(NO3)2 → Ag + CuNO3
Explanation:
plzzz mark me brainliest
Considering the side chain of each of the amino acids at pH 7.4, is that amino acid classified at neutral, basic, or acidic? You are currently in a sorting module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop. Neutral Basic Acidic
Answer:
Considering the side chain of each of the amino acids at pH 7.4, is that amino acid classified at neutral, basic, or acidic? You are currently in a sorting module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop. Neutral Basic Acidic
The answer is in the the images. I have placed all the structures in the specific boxes. I hope this helps.
A 2.5 M solution of a weak acid is prepared. Using a pH meter, the pH is measured to be 5.1. Calculate the acid ionization constant, [tex]K_{a}[/tex] , of this weak acid.
Show your work
Molarity of acid=2.5M
pH=5.1.
ka=?
Now
We need to write an eqn to show the dissociation of the acid
HA + H2O === H3O+ + A-
Writing The Equilibrium(Or Acid dissociation constant) of this reaction
Ka =[H3O+] {A-]/ {HA].
The concept behind this is
concentration of Products divided by those of reactants. Water is not written because its a pure liquid and does not affect the Equilibrium constant.
Now If you have any Idea on ICE tables..
You'd know that the concentration of acid will decrease by 2.5-x
Whilst the products...will increase by x each
Note: This is when the ratio of their Moles are in 1:1
ka= x.x/2.5-x
Since the Moles of A- and H3O+ are in 1:1... Their concentrations at equilibrium will be the same
so
Ka= x²/2.5-x
Now what is x??
x is the Hydrozonium ion concentration.
we can get it from the pH formula
pH= -log (H3O+)
Making H3O+ subject by applying Logarithm Rules
H3O+ = 10^-ph
x=10^-5.1
=7.94x10^-6.
Now back to Ka
Ka= x²/2.5-x
Ka= (7.94x10^-6)²/2.5-(7.94x10^-6)
Ka= (7.94x10^-6)²/2.4999
Ka= 2.52x10^-11.
Was a Fun One
The ionization constant of this weak acid is [tex]2.52*10^{-11}[/tex]. The values can be substituted in dissociation formula.
What information do we have?
Molarity of acid=2.5M
pH=5.1
To find:
ka=?
Calculation of ionization constant:[tex]HA + H_2O < === > H_3O^+ + A^-[/tex]
The value of dissociation constant will be:
[tex]Ka =[H_3O^+] [A^-]/ {HA][/tex]
The Moles of A- and H3O+ are in 1:1.Their concentrations at equilibrium will be the same.
[tex]Ka= x.x/2.5-x\\\\Ka= x^2/2.5-x\\\\pH= -log (H_3O^+)\\\\H_3O^+ = 10^{-pH}\\\\x=10^{-5.1}\\\\x=7.94*10^{-6}[/tex]
[tex]Ka= x^2/2.5-x\\\\Ka= (7.94*10^{-6})^2/2.5-(7.94*10^{-6})\\\\Ka= (7.94*10^{-6})^2/2.4999\\\\Ka= 2.52*10^{-11}\\\\[/tex]
Thus, ionization constant of this weak acid is [tex]2.52*10^{-11}[/tex].
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"When your heart was an open book" is an example of of
A. simile
B. metaphor
C. alliteration
D. all of the above
B. metaphor
The answer is metaphor, because it can't possibly be other thing.
what is solubility? .
what volume of h2 can be produced at stp from 2 mol cah2 and excess water if the reaction goes 100% to completion?
Answer:
89.6 L of H₂ will be produced at STP from 2 moles of CaH₂ and excess water if the reaction goes to 100% completion.
Explanation:
The balanced chemical equation of the reaction between calcium hydride, CaH₂ and excess water to produce calcium hydroxide and hydrogen gas is given below:
CaH₂ (s) + 2H₂O (l) ----> Ca(OH)₂ (aq) + 2H₂ (g)
From the equation of the chemical reaction above, 1 mole of calcium hydride reacts with 2 moles of water to produce 2 moles of hydrogen gas.
Then, 2 moles calcium hydride will react with excess water to produce 2 × 2 -moles of hydrogen gas = 4 moles of hydrogen gas.
One mas a gas at STP has a volume of 22.4 L
4 moles of hydrogen gas will have a volume of 4 × 22.4 L = 89.6 L
Therefore, 89.6 L of H₂ will be produced at STP from 2 moles of CaH₂ and excess water if the reaction goes to 100% completion.
What is the lowest whole number ratio between the aluminum ion and carbonate ion in the compound, aluminum carbonate?
A. 2 :1
B. 1: 1
C. 3 : 2
D. 1 : 2
E. 2 : 3
Answer:
E. 2 : 3
Explanation:
Aluminium carbonate is a neutral compound made by aluminium ion, Al³⁺ and carbonate ion, CO₃²⁻. As is neutral, the formula must be:
Al₂(CO₃)₃.
2 Al₃⁺ = 6 positives charges
3 CO₃²⁻ = 6 negative charges
Thus, the simplest whole number ratio between Al³⁺ and CO₃²⁻ must be:
2:3
And right answer is:
E. 2 : 3how can miscible liquids that different boiling points be separated
Answer:
By boiling and further condensing the liquid with the lowest boiling point.
Explanation:
Hello there!
In this case, according to the attached diagram, it turns out possible for us to infer that the mechanism whereby miscible liquids with different boiling points are separated is distillation, because the flask is heated until the boiling point of the liquid with the lowest value, in order to boil it and subsequently condense it, whereas the liquid with the highest boiling point remains in the flask; and therefore, the two liquids are separated.
Regards!
identify two conjugate base for each compound HCN and HBr
The conjugate base of HCN is CN^-
The conjugate base of HBr is Br^-
In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: g
The question is incomplete. The complete question is :
In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: The color change will occur when [some amount] of NaOH is added because the color change occurs when [some condition]. The goal for your explanation is that it describes the outcome of this example, but can also be used to predict the outcome of other examples of this phenomenon. Here's an example explanation: The color of the solution will change when 40 ml of NaOH is added to a beaker of HCl because the color always changes when 40ml of base is added. Although this explanation works for this example, it probably won't work in examples where the flask contains a different amount of HCl, such as 30ml. Try to make an explanation that accurately predicts the outcome of other versions of this phenomenon.
Solution :
Consider the equation of the reaction between NaOH and [tex]$HCl$[/tex]
NaOH (aq) + HCl (aq) → NaCl(aq) + [tex]$H_2O (l)$[/tex]
The above equation tells us that [tex]$1 \text{mole}$[/tex] of [tex]$NaOH$[/tex] reacts with [tex]$1 \text{mole}$[/tex] of [tex]$HCl$[/tex].
So at the equivalence point, the moles of NaOH added = moles of [tex]$HCl$[/tex]present.
If the volume of the [tex]$HCl$[/tex] taken = [tex]$V_1$[/tex] mL and the conc. of [tex]$HCl$[/tex] = [tex]$M_1$[/tex] mole/L
The volume of NaOH added up to the color change = [tex]$V_2 \text{ and conc of NaOH = M}_2$[/tex] mole/L
Moles of [tex]$HCl$[/tex] taken = [tex]$V_1 \ mL \times M_1 \ mol/100 \ mL = V_2M_2 \times 10^{-3}$[/tex] moles.
The color change will occur when the moles of NaOH added is equal to the moles of [tex]$HCl$[/tex] taken.
Thus when [tex]$V_1 M_1 \times 10^{-3} = V_2M_2 \times 10^{-3}$[/tex]
or when [tex]$V_1M_1 = V_2M_2$[/tex]
or [tex]$V_2=\frac{V_1M_1}{M_2}$[/tex] mL of NaOH added, we observe the color change.
Where [tex]$V_1, M_1$[/tex] are the volume and molarity of the [tex]$HCl$[/tex] taken.
[tex]$M_2$[/tex] is the molarity of NaOH added.
When both the NaOH and [tex]$HCl$[/tex] are of the same concentrations, i.e. if [tex]$M_1=M_2$[/tex], then [tex]$V_2=V_1$[/tex]
Or the 40 mL of [tex]$HCl$[/tex] will need 40 mL of NaOH for a color change and
30 mL of [tex]$HCl$[/tex] would need 30 mL of NaOH for the color change (provided the concentration [tex]$M_1=M_2$[/tex])
What is the the heat of reaction, delta, in kJ/mol?
a) -26kJ/mol
b) -25kJ/mol
c) -10kJ/mol
d)-35kJ/mol
Answer:
b) -25 kJ/mol.
Explanation:
Hello there!
In this case, since the general definition of the enthalpy of reaction involves the subtraction of the energy of the products and the energy of the reactants:
[tex]\Delta H=H_{prod}-H_{react}[/tex]
Thus, since the graph shows that the energy of the products is 20 kJ/mol and that of reactants 45 kJ/mol, we will obtain:
[tex]\Delta H=20kJ/mol-45kJ/mol\\\\\Delta H=-25kJ/mol[/tex]
Which means it is exothermic.
Regards!
A “happy” atom is one that has a _________ valence orbital. octet rule
Answer:
Hello There!!
Explanation:
I believe the answer is 8.
hope this helps,have a great day!!
~Pinky~
Calculate the molar mass of Ca3(PO4)2
934.32 g Ca3(PO4)2 =______
moles Ca3(PO4)2
Answer:
Molar mass of Ca₃(PO₄)₂ = 310.18 g/mol934.32 g Ca₃(PO₄)₂ = 3.01 moles Ca₃(PO₄)₂Explanation:
The molar mass (MM) of Ca₃(PO₄)₂ can be calculated as follows:
MM of Ca₃(PO₄)₂ = (MM of Ca)*3 + [(MM of P) +(MM of O)*4]*2MM of Ca₃(PO₄)₂ = 310.18 g/molNow we can convert 934.32 g of Ca₃(PO₄)₂ into moles:
934.32 g ÷ 310.18 g/mol = 3.01 molesQuestions
Determine the primary and secondary valencies of the following complexes and calculate their spin only magnetic
moment.
iii. [Cu(OH2)6]504
i. K[TI(CN).]
ii. [V(NH3)4Br2]
iv. K3 [Cr(CN)6]
Answer:
yes
Explanation:
yes