Pls help with my math! It’s the end of the year and I’m having a hard time trying to finish on time!

Answer:

2

Step-by-step explanation:

18+16+4=36

40-38=2

Answer:

2 cupcakes left

Step-by-step explanation:

40 - (18 + 16 + 1 + 1 + 1 + 1) = 2

Answer:

[tex]tom = \frac{85}{100} \times 20 \\ = 17 \: questions[/tex]

Melissa had a greater mark.

Answer:

Melissa

Step-by-step explanation:

Melissa: 18/20

Tom: 85/100

You need a common denomenater so multiply 18 and 20 by 5:

90/100>85/100

Melissa has the greater mark by 5%

Answer:The value of log base 3 log base 2 log base √3 81 is -a)1 b) 2 c)3 d) 0

Answer:

4

Step-by-step explanation:

Define [tex]\log_a b=c\implies a^c=b[/tex].

Let

[tex]\log_3 81=x[/tex].

Using our definition [tex]\log_a b=c\implies a^c=b[/tex], we have:

[tex]3^x=81[/tex]

Solving for [tex]x[/tex]:

[tex]x=\boxed{4}\text{ from simply knowing that }3^4=81[/tex]

Or

Algebraically solve step-by-step by taking the log of both sides:

[tex]\log 3^x=\log 81[/tex]

Using log property [tex]\log a^b=b\log a[/tex], rewrite:

[tex]x\log 3=\log81[/tex]

Divide both sides by log(3):

[tex]x=\frac{\log 81}{\log 3}=\boxed{4}[/tex]

Answer:

A box plot is drawn with end points at 24 and 49.The box extends from 28 to 44 and a vertical line is drawn inside the box at 34.

Step-by-step explanation:

Ordering the data given :

24,28,32,34,40,44,49

We can calculate the 5 number summary required to give the appropriate boxplot that can be produced :

Minimum = 24

Maximum = 49

Median = 1/2(n+1)th term

n = 7

Median = 1/2(8) = 4th term

Median = 34

Lower quartile, Q1 = 1/4(n+1)th term

n = 7

1/4(8) = 2nd term

Q1 = 28

Upper quartile : 3/4(n+1)th term

n = 7

Q3 = 3/4(8) = 6th term

Q3= 44

Answer:

34

Step-by-step explanation:

Pythagoras theorem states that for a right angle triangle the measure of the  square of the hypotenuse side is equal to the sum of the square of the other two sides.The ladder has to be kept at 13.3( round to the nearest tenth) feet away from the bottom of the wall.

Given information-

The length of the ladder is 24 foot.

The height of the wall is 20 foot.

Suppose the ladder has to kept at x feet away from the bottom of the wall

Here a right angle is formed in which the ladder is hypotenuse side shown in the diagram attached below.

Pythagoras theorem states that for a right angle triangle the measure of the  square of the hypotenuse side is equal to the sum of the square of the other two sides.

As the ladder has to be kept at x feet away from the bottom of the wall. Thus,

[tex]24^2=20^2+x^2\\ 576=400+x^2[/tex]

Solve for the x,

[tex]x=\sqrt{576-400}\\ x=\sqrt{176}\\ x=13.266[/tex]

hence the ladder ladder has to be kept at 13.3( round to the nearest tenth) feet away from the bottom of the wall.

Learn more about the Pythagoras theorem here;

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Answer:

This question would be answered by doing devision because you are splitting  the amount of cookies that should be delivered amongst 13 girls.

1,000/13

76.92307692

That is what came out in my calculator. I don't know if you need it in decimal or in a solid integer but if you were to round 76.9 you would get 77, it is always good to check your work so,

77 times 13

1001

That equals 1001 so that would help at least reach their goal of 1,000 boxes of cookies.

Step-by-step explanation:

I really hope this helps!

Answer:

[tex]\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c[/tex]

Step-by-step explanation:

The question is not properly formatted. However, the integral of [tex]\int {7 \sec(\theta) } \, d\theta[/tex] is as follows:

[tex]\int {7 \sec(\theta) } \, d\theta[/tex]

Remove constant 7 out of the integrand

[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) } \, d\theta[/tex]

Multiply by 1

[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * 1} \, d\theta[/tex]

Express 1 as: [tex]\frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}[/tex]

[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * \frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta[/tex]

Expand

[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta[/tex]

Let

[tex]u = \sec(\theta) + \tan(\theta)[/tex]

Differentiate

[tex]\frac{du}{d\theta} = \sec(\theta)\tan(\theta) + sec^2(\theta)[/tex]

Make [tex]d\theta[/tex] the subject

[tex]d\theta = \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}[/tex]

So, we have:

[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{u}} \,* \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}[/tex]

Cancel out [tex]\sec(\theta)\tan(\theta) + sec^2(\theta)[/tex]

[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{1}{u}} \,du}}[/tex]

Integrate

[tex]\int {7 \sec(\theta) } \, d\theta = 7\ln(u) + c[/tex]

Recall that: [tex]u = \sec(\theta) + \tan(\theta)[/tex]

[tex]\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c[/tex]

Answer:

(-infinity, 4]

Step-by-step explanation:

The range is the possible y values

The smallest that (x+3)^2 can be is zero

f(x) = 4 − 2(x + 3)^2

f(x) = 4 -2(0) = 4

This is the maximum value

As the square term gets bigger we are subtracting a larger amount and it will get more negative

Let x = infinity, x+3 = infinity and infinity ^2 = infinity  and 2* infinity = infinity

f(x) = 4 - infinity

     = -infinity

The range is -infinity to 4

9514 1404 393

Answer:

  5.5

Step-by-step explanation:

The rate of change is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (16.5 -11)/(3 -2) = 5.5/1

  m = 5.5

The rate of change of this function is 5.5.

Answer:

9.43

Step-by-step explanation:

Given

See attachment for illustration

Required

Distance AE

The actual path taken by the taxicab are in bold lines.

To calculate the distance AE, we simply consider the triangle AOE where

[tex]AE^2 = OE^2 + AO^2[/tex]

[tex]AE^2 = 5^2 + (5+3)^2[/tex]

[tex]AE^2 = 5^2 + 8^2[/tex]

[tex]AE^2 = 25 + 64[/tex]

[tex]AE^2 = 89[/tex]

Take square roots

[tex]AE = \sqrt{89[/tex]

[tex]AE = 9.43[/tex]

Given:

Price of 12 shirts = Rs. [tex]3600\dfrac{3}{5}[/tex]

Price of 6 pants = Rs. [tex]3000\dfrac{1}{5}[/tex]

To find:

The price of 4 shirts and 4 pants​.

Solution:

It is given that,

Price of 12 shirts = Rs. [tex]3600\dfrac{3}{5}[/tex]

Price of 1 shirt = Rs. [tex]\dfrac{1}{12}\times 3600\dfrac{3}{5}[/tex]

Price of 4 shirts = Rs. [tex]\dfrac{4}{12}\times 3600\dfrac{3}{5}[/tex]

                          = Rs. [tex]\dfrac{1}{3}\times \dfrac{18003}{5}[/tex]

                          = Rs. [tex]\dfrac{18003}{15}[/tex]

Price of 6 pants = Rs. [tex]3000\dfrac{1}{5}[/tex]

Price of 1 pant = Rs. [tex]\dfrac{1}{6}\times 3000\dfrac{1}{5}[/tex]

Price of 4 pants = Rs. [tex]\dfrac{4}{6}\times 3000\dfrac{1}{5}[/tex]

                          = Rs. [tex]\dfrac{2}{3}\times \dfrac{15001}{5}[/tex]

                          = Rs. [tex]\dfrac{30002}{15}[/tex]

Now, the price of 4 shirts and 4 pants​ is:

[tex]\text{Required price}=\dfrac{18003}{15}+\dfrac{30002}{15}[/tex]

[tex]\text{Required price}=\dfrac{48005}{15}[/tex]

[tex]\text{Required price}=\dfrac{9601}{3}[/tex]

[tex]\text{Required price}=3200\dfrac{1}{3}[/tex]

Therefore, the price of 4 shirts and 4 pants​ is Rs. [tex]3200\dfrac{1}{3}[/tex].

Answer:

Step-by-step explanation:

surface area of cuboid=2(l*b+b*h+h*l)

=2(15*15+15*7+7*15)

=2(225+105+105)

=2*435

=870

Answer:

Mia would have a 55$ interest  :)

Step-by-step explanation:

The g(x) is equal to (2/3)x.To find g(x) in the composite function h(x) = f(g(x)), we need to substitute f(x) = 2x - 1 into the equation and solve for g(x

Given that h(x) = (4/3)x - 1 and f(x) = 2x - 1, we can set up the composite unction:

h(x) = f(g(x))

Substituting f(x) into the equation:

(4/3)x - 1 = 2(g(x)) - 1

Simplifying the equation:

(4/3)x - 1 = 2g(x) - 1

We can now solve for g(x):

2g(x) = (4/3)x

Dividing both sides by 2:

g(x) = (2/3)x

For more such questions on function

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Answer: $2.46

Step-by-step explanation:

First, let's find the unit price for both buckets!

A 1 gallon bucket of paint is $21.95. But how much will a 1 gallon bucket of paint cost if it had origianlly been 97.45 for 5 gallons of paint?

We need to divide 97.45 by 5, and the answer will be the unit price.

97.45 ÷ 5 = 19.49.

A 1 gallon bucket of paint that was originally priced as $97.45 for 5 gallons of paint si now $19.49 per bucket.

But we're not done! We still need to find the difference in unit prince between a 5 gallon bucket of paint for $97.45 and a 1 gallon bucket of paint for $21.95.

21.95 - 19.49 = 2.46.

Therefore, the difference in unit price between a 5 gallon bucket of paint for $97.45 and a 1 gallon bucket of paint for $21.95 is $2.46.

Answer:

it would get 6 zeros

Step-by-step explanation:

hope it helps :)

Step-by-step explanation:

The given expression is:

[tex]r=\dfrac{2p^2}{q-3}[/tex]

We need to solve it to make q the subject of the formula.

Cross multiplying both sides,

[tex]rq-3r=2p^2[/tex]

Adding 3r to both sides,

[tex]rq-3r+3r=2p^2+3r\\\\rq=2p^2+3r[/tex]

Now, dividing both sides by r,

[tex]q=\dfrac{2p^2+3r}{r}[/tex]

Hence, this is the required solution.

Answer:

The volume is increasing at a rate of 25,133 mm/s.

Step-by-step explanation:

Diameter is 40mm

Radius is half the diameter, so [tex]r = \frac{40}{2} = 20[/tex]

How fast is the volume increasing when the diameter is 40mm?

We have to apply implicit differentiation, of V and r in function of t. So

[tex]V = \frac{4}{3} \pi r^3[/tex]

[tex]\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}[/tex]

The radius of a sphere is increasing at a rate of 5 mm/s.

This means that [tex]\frac{dr}{dt} = 5[/tex]

Then

[tex]\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}[/tex]

[tex]\frac{dV}{dt} = 4\pi (20)^2(5)[/tex]

[tex]\frac{dV}{dt} = 25133[/tex]

The volume is increasing at a rate of 25,133 mm/s.

Answer:

Answer:

Step-by-step explanation:

take 60 degree as reference angle

using tan rule

tan 60=opposite/adjacent

[tex]\sqrt{3[/tex]=x/5

5*[tex]\sqrt{3[/tex] =x

5[tex]\sqrt{3[/tex]=x

Answer:

A. 15

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 37°

Opposite Leg = x

Hypotenuse = 25

Step 2: Solve for x

Answer:

1 / 6

Step-by-step explanation:

If the probability distribution has the probabilities :

5/12, 1/6, 1/4 and x

Then ;

The total sum of all the probabilities should be equal to 1 ;

That is ;

5/12 + 1/6 + 1/4 + x = 1

Lcm of 4, 6, 12 = 12

(5 + 2 + 3)/12 + x = 1

10/12 + x = 1

x = 1 - 10/12

x = 2 / 12

x = 1/6

Answer:

1, 2, 3, 4

Step-by-step explanation:

x+(x+1)+(X+2)+(X+3)+2 = 3(X+3)

4X+8=3x+9

x=1

Answer:

5,6,7,8

Step-by-step explanation:

5+6+7+8=26

8*3=24

26-24=2

Answer:

Step-by-step explanation:

Answer:

-2/7

Step-by-step explanation:

Answer:

c=13.6km, B=47.9⁰, A=22.8⁰,

Using the cosine rule, the missing parts of the triangle are:

c = 13.6 km; B = 47.9°; C = 22.8°

Cosine rule is given as, c² = a² + b² ﹣ 2ab(cosC)

Given the following:

Find c using the cosine rule:

c² = 5.6² + 10.7² ﹣ 2(5.6)(10.7)(cos 109.3)

c² = 185.5

c = √185.5

c = 13.6 km.

Use the cosine rule to find A:

5.6² = 10.7² + 13.6² ﹣ 2(10.7)(13.6)(cosA)

31.36 = 299.45 ﹣ 291.04(cosA)

31.36 - 299.45 = ﹣ 291.04(cosA)

-268.09 = ﹣ 291.04(cosA)

0.9211 = (cosA)

C = cos^(-1)(0.9211)

C = 22.8°

Find B:

B = 180 - 22.8 - 109.3

B = 47.9°

Therefore, using the cosine rule, the missing parts of the triangle are:

c = 13.6 km; B = 47.9°; C = 22.8°

Learn more about the cosine rule on:

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Answer:

The null hypothesis is [tex]H_0: p \geq 0.32[/tex]

The alternative hypothesis is [tex]H_1: p < 0.32[/tex]

Step-by-step explanation:

State the null and alternative hypotheses to test that less than 32% of mall visitors make a purchase

At the null hypothesis, we test if the proportion is of at least 32%, that is:

[tex]H_0: p \geq 0.32[/tex]

We are testing if less than 32% of visitors make a purchase, so, at the alternative hypothesis, we test if the proportion is less than 32%, that is:

[tex]H_1: p < 0.32[/tex]