PLS HELP! Worth 15 Points and Will give brainlest​

Combine the fractions on the left with a common denominator:

[tex]\dfrac a{x+1} + \dfrac b{x-1} + \dfrac c{(x+1)^2} = \dfrac{a(x+1)(x-1) + b(x+1)^2 + c(x-1)}{(x-1)(x+1)^2}[/tex]

It follows that

[tex]3x^2+3x-2 = a(x+1)(x-1) + b(x+1)^2 + c(x-1)[/tex]

Expand the right side and collect like powers of x :

[tex]3x^2+3x-2 = a(x^2-1) + b(x^2+2x+1) + c(x-1)[/tex]

[tex]3x^2+3x-2 = (a+b)x^2 + (2b + c)x -a +b - c[/tex]

Then we have the system of equations

[tex]\begin{cases}a+b=3\\2b+c=3\\-a+b-c=-2\end{cases}[/tex]

or in matrix form,

[tex]\begin{bmatrix}1&1&0\\0&2&1\\-1&1&-1\end{bmatrix} \begin{bmatrix}a\\b\\c\end{bmatrix} = \begin{bmatrix}3\\3\\-2\end{bmatrix}[/tex]

Compute the determinant of the coefficient matrix:

[tex]\det\begin{bmatrix}1&1&0\\0&2&1\\-1&1&-1\end{bmatrix} = -4[/tex]

Then the inverse of the coefficient matrix is equal 1/det times the adjugate of the coefficient matrix (a.k.a the transpose of the cofactor matrix):

[tex]\begin{bmatrix}1&1&0\\0&2&1\\-1&1&-1\end{bmatrix}^{-1} = \dfrac1{-4} \begin{bmatrix}-3 & -1 & 2 \\ 1 & -1 & -2 \\ 1 & -1 & 2\end{bmatrix}^\top = -\dfrac14 \begin{bmatrix}3&-1&-1\\1&1&1\\-2&2&-2\end{bmatrix}[/tex]

Multiply both sides of the equation by the inverse :

[tex]\begin{bmatrix}a\\b\\c\end{bmatrix} = -\dfrac14 \begin{bmatrix}3&-1&-1\\1&1&1\\-2&2&-2\end{bmatrix} \begin{bmatrix}3\\3\\-2\end{bmatrix} = \begin{bmatrix}2\\1\\1\end{bmatrix}[/tex]

So, we have a = 2 and b = c = 1, and the partial fraction decomposition is

[tex]\dfrac{3x^2+3x-2}{(x+1)^2(x-1)} = \dfrac 2{x+1} + \dfrac 1{x-1} + \dfrac 1{(x+1)^2}[/tex]

Answer:

Step-by-step explanation:

One can solve for a, b, c a little more directly than using a system of 3 equations.

If we multiply the rational expression by (x+1)², we get ...

  (3x² +3x -2)/(x -1) = (x+1)²(a/(x+1) +b/(x-1)) +c

Evaluating this for x = -1 gives ...

  (3(-1)² +3(-1) -2)/(-1 -1) = c

  -2/-2 = 1 = c

Similarly, multiplying by (x -1) gives ...

  (3x² +3x -2)/(x +1)² = (x -1)(a/(x +1) +c/(x +1)²) + b

Evaluating this for x = 1 gives ...

  (3·1² +3·1 -2)/(1 +1)² = b

  4/4 = 1 = b

Now, we need to find the value of 'a'. The identity will hold true for any value of x, so we can see what happens when we substitute x=0. We can use the values of 'b' and 'c' that we found above.

  (3·0² +3·0 -2)/((0 +1)²(0 -1)) = a/(0 +1) +1/(0 -1) +1/(0 +1)²

  -2/-1 = a -1 +1   ⇒   a = 2

_____

System of equations solution

When the terms of the right-side expansion are combined, the numerator of the result is ...

  a(x +1)(x -1) +b(x +1)^2 +c(x -1) = (a+b)x² +(2b+c)x +(-a+b-c) ≡ 3x² +3x -2

Equating the coefficients gives the system of equations whose augmented matrix is:

  [tex]\left[\begin{array}{ccc|c}1&1&0&3\\0&2&1&3\\-1&1&-1&-2\end{array}\right][/tex]

Transforming this to reduced row-echelon form using any of a variety of available tools gives ...

  [tex]\left[\begin{array}{ccc|c}1&0&0&2\\0&1&0&1\\0&0&1&1\end{array}\right][/tex]

which tells you the solution is (A, B, C) = (2, 1, 1).

Answer:

(8x^9 x y^4) : (1/2x^3)=16x^6y^4

Step-by-step explanation:

8 : 1/2 = 16

x^9 : x^3 = x^6

Equation - [tex]8x^3y^4[/tex] divided by (1/2x^3)=16x^6y^4.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign. A mathematical equation is a formula that uses the equals sign to express the equality of two expressions. The meanings of the word equation as well as its cognates in other languages can vary slightly. For instance, in French, an equation is defined as having one or more variables, whereas in English, an equation is any well-formed formula that consists of two expressions linked by the equals sign.

Finding the values of the variables that result in the equality is the first step in solving an equation with variables. The unknown variables are also known as the variables for which the equation must be solved, and the unknown variable values that satisfy the equality are known as the equation's solutions.

Let the required term be z.

[tex]z/ (1/2x^3)=16x^6y^4[/tex]

[tex]z=(16x^6y^4) }{(1/2x^3)}[/tex]

[tex]z = 8x^3y^4[/tex]

Hence, [tex]8x^3y^4[/tex]

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Steps are in the attachment.

Note :-

=》2 is taken as negative & also taken out of the square root as it's the common factor.

______

⚜ Hope it helps :))

Answer:

both are c

Step-by-step explanation:

Answer:

Y=76x

Step-by-step explanation:

if you divide 3 and 228 it is 76. if you divide 5 and 380 it is 76.if you divide 532 and 7 it is 76. and if you divide 11 and 836 it is 76.

Answer:

Step-by-step explanation:

The trick is to get rid of b in y = mx + b. The way to do that is to take 2 values and subtract them

(380 - 228) / (5 - 3) = 152/2 = 76

Not all problems work out this nicely.

The answer is

y = 76x

In this case you can be a little more direct. m = 380 ÷ 5 = 76, but not all equations are this well behaved and doing it the long way is the best way.

Answer:

21000,14000,and14000

Step-by-step explanation:

3x+2x+2x=49000

7x=49000

x=7000

3×7000=21000

2×7000=14000

2×7000=14000

[tex]4^4(4^7)4\implies 4^4\cdot 4^7\cdot 4^1\implies 4^{4+7+1}\implies 4^{12}[/tex]

Answer:

real answer 4^-2

Step-by-step explanation:

just did on edge

[tex]Hiya![/tex]

Sokka is here to help!!

Here's a explanation!

[tex]-8-(-6)[/tex]

[tex]=-8-(-6)[/tex]

[tex]=-8+6[/tex]

[tex]=-2[/tex]

The answer is B.

Here's a graph photo!

Hopefully, this helps you!!

[tex]Sokka[/tex]

his average speed as he ran: V = S/t = 100/12 = 25/3 (m/s)

ok done. Thank to me :>

Speed is the time rate at which an object is moving along a path. 25/3 is the average speed as he ran

Speed is the time rate at which an object is moving along a path.

Speed =Distance/Time

His average speed as he ran:

V = S/t

Hundred by twelve.

= 100/12

Divide numerator and denominator by four.

Twenty five by three.

Average speed= 25/3 (m/s)

Hence if Andre ran a 100 meter race in 12 seconds. 25/3 is the average speed as he ran

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Answer:

i dont have a premium

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

15, 4, 11, 4

Step-by-step explanation:

x=8

so 7+x, 7+8= 15

12-8 = 4

x+3 , 8+3=11

32/8 = 4

Answer:

Correct choice: B

Step-by-step explanation:

Equation Solving

The area of a trapezoid with height h and bases b1 and b2 is given by:

We must solve this formula for h.

First, multiply by 2 to eliminate denominators:

Now, divide by b1+b2:

Swapping sides:

Correct choice: B

Answer:

y = 5x - 16

Step-by-step explanation:

1. To solve this question, we must convert 5x - y = 16 into slope-intercept form (y = mx + b).

2. (Solving for y)

Step 1: Subtract 5x from both sides.

Step 2: Divide both sides by -1.

Therefore, the answer is y = 5x - 16.

Part A

The given angle is 4pi/3. Multiply it by the factor 180/pi to convert from radians to degree mode.

Note how the given angle has pi in the numerator, while the conversion factor has pi in the denominator. The two pi terms will cancel.

(4pi/3)*(180/pi)

(4/3)*(180/1)

(4*180)/(3*1)

720/3

240

The angle 4pi/3 radians is equivalent to 240 degrees. This 240 degree angle is in quadrant 3. Any angle in this quadrant is between 180 degrees and 270 degrees, excluding both endpoints. This is the bottom left quadrant, aka the southwest quadrant.

===========================================================

Part B

To find the reference angle, we'll subtract off pi. This only works for angles in quadrant 3. This is because the first pi radians, aka 180 degrees, is taken up by the first two upper quadrants. The remaining bit in the third quadrant is all we care about to find the reference angle.

reference angle = (given angle in quadrant 3) - pi

reference angle = (4pi/3) - pi

reference angle = (4pi/3) - (3pi/3)

reference angle = (4pi - 3pi)/3

reference angle = pi/3

===========================================================

Part C

Use a calculator or a reference table to find that

tan(4pi/3) = tan(pi/3) = sqrt(3)

Alternatively, you can compute the sine and cosine values first

Dividing the two items in the order mentioned will get us the tangent value

tan = sin/cos

tan(pi/3) = sin(pi/3) divide cos(pi/3)

tan(pi/3) = sqrt(3)/2 divide 1/2

tan(pi/3) = sqrt(3)

In the jump from the second to last step, to the last step, the denominators '2' cancel out when dividing.

Answer:

tag archives and records and counting the days

Answer:

1st number is 6

2nd number is 30

3rd number is 33

Step-by-step explanation:

Let x be the first number.

The second of three numbers is 5 times the first = 5x

The third number is 3 more than the second = 5x + 3

If the second is decreased by twice the third, the result is -21.

Multiply the third number by 2.

2(5x + 3)

= 10x + 6

Subtract the second number to it.

(5x)-(10x + 6) = -21

-5x - 6 = -21

Use APE or Addition Property of Equality

-5x = -21 + 6

-5x = -15

Use DPE or Division Property of Equality to get the value of x

[tex]\frac{-5x}{-5} = \frac{-15}{-5}[/tex]

x = 3

Now put the value of x in the equation

first number(x) = 6

second number(5x) = 5(6) = 30

third number(5x + 3)

5(6) + 3

30 + 3 = 33

15 days

Step-by-step explanation:

The half-life equation is given as

[tex]m(t) = m(0)e^{-0.073t}[/tex] (1)

where m(0) is the initial mass of radioactive iodine at t = 0. To solve for the time t, let's put the exponential part on the left-hand side:

[tex]e^{-0.073t} = \dfrac{m(t)}{m(0)}[/tex]

Taking the natural logarithm of both sides to get

[tex]\ln{e^{-0.073t}} = \ln\left[\dfrac{m(t)}{m(0)}\right][/tex] (2)

Recall the following properties of logarithms:

[tex]\ln{A}^b = b\ln{A}[/tex]

[tex]\ln{e} = 1[/tex]

We can rewrite Eqn(2) as

[tex]-0.073t = \ln\left[\dfrac{m(t)}{m(0)}\right][/tex]

Solving for t, we get

[tex]t = -\dfrac{1}{0.073}\ln\left[\dfrac{m(t)}{m(0)}\right][/tex]

Since m(0) = 15 gm and m(t) = 5 gm, then the amount of time that elapses to reduce the mass down to 5 gm is

[tex]t = -\dfrac{1}{0.073}\ln\left(\dfrac{5\:\text{g}}{15\:\text{g}}\right)[/tex]

[tex]\:\:\:\:\:= 15\:\text{days}[/tex]

Answer:

B.O.D.M.A.S

Step-by-step explanation:

B: Bracket

O: Operation

D: Division

M: Multiplication

A: Addition

S: Subtraction

Follow these steps.

Hope you understand ^^

Answer:

Step-by-step explanation:

Answer:

A. 1.56

Step-by-step explanation:

[0(3) + 1(9) + 2(10) + 3(2) + 4(1)] / [3 + 9 + 10 + 2 + 1]

Answer: The answer would be 3.91666666667

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{4 \dfrac{2}{3} - \dfrac{3}{4}}[/tex]

[tex]\mathsf{= \dfrac{4\times3+2}{3} - \dfrac{3}{4}}[/tex]

[tex]\mathsf{= \dfrac{12 + 2}{3} - \dfrac{3}{4}}[/tex]

[tex]\mathsf{= \dfrac{14}{3} - \dfrac{3}{4}}[/tex]

[tex]\mathsf{= \dfrac{56}{11} - \dfrac{9}{12}}[/tex]

[tex]\mathsf{= \dfrac{14\times4}{12 - 0}}[/tex]

[tex]\mathsf{= \dfrac{56 - 9}{12}}[/tex]

[tex]\mathsf{= \dfrac{47}{12}}[/tex]

[tex]\mathsf{= 3 \dfrac{11}{12}}[/tex]

[tex]\huge\textsf{Therefore, your answer should be: }\huge\boxed{\\\mathsf{\dfrac{47}{12} \ or\ 3 \dfrac{11}{12}}}\huge\checkmark[/tex]

[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

  a[1] = 80; a[n] = -a[n-1]/4

Step-by-step explanation:

The given sequence has a first term of 80 and a common ratio of -20/80 = -1/4. That is, each term is -1/4 times the previous one. The recursive formula is ...

  [tex]A_1=80\\A_{n}=-\dfrac{1}{4}\times A_{n-1}[/tex]

Answer:

The formula y = mx + b is said to be a linear function

Step-by-step explanation:

Answer:

D. is a linear function

Step-by-step explanation:

A. rational function

B. quadratic function

C. cube root function

Answer:

5 seconds

Step-by-step explanation:

hope it helps

correct me if i'm wrong

Answer:

C

Step-by-step explanation:

if you don't know it choose C

Answer:

a) y = 0.10(16) + 100

y = $ 101.60

b) y = 0.10(150) + 100

y = $115

c) y = 0.10(200) + 100

y = $120

d) y = 0.10(250) + 100

y = $125

Step-by-step explanation:

Answer: its a

Step-by-step explanation: its the same answer

Answer: the answer is 3(p - 5) + 2s

Step-by-step explanation:

its the only answer there that makes since and hope this helps im kinda bad at algebra but this was easy

[tex]0.18[/tex]

is the decimal point

Linear equations can represent parallel lines, perpendicular lines and lines with no relationship at all.

The equation of the line in form of y =mx + b is [tex]\mathbf{y = 2x + 17}[/tex]

The equation is given as:

[tex]\mathbf{y =-\frac x2 - 6}[/tex]

For a linear equation y = mx + b, the slope of the equation is m

So, by comparison:

[tex]\mathbf{m =-\frac 12}[/tex]

The relationship between the slopes of perpendicular lines is:

[tex]\mathbf{m_2 =-\frac 1{m_1}}[/tex]

So, we have:

[tex]\mathbf{m_2 =-\frac 1{-1/2}}[/tex]

[tex]\mathbf{m_2 =2 }[/tex]

This means that, the slope of the line that passes through point (-8,1) is 2

The line equation is then calculated as:

[tex]\mathbf{y = m(x - x_1) + y_1}[/tex]

This gives

[tex]\mathbf{y = 2(x + 8) + 1}[/tex]

Open brackets

[tex]\mathbf{y = 2x + 16 + 1}[/tex]

Simplify

[tex]\mathbf{y = 2x + 17}[/tex]

Hence, the equation of the line in form of y =mx + b is [tex]\mathbf{y = 2x + 17}[/tex]

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