Answer:
The answer is the last one: Atom X is in a column to the right of Atom Y on the periodic table.
Explanation:
First, let's see the following formula:
[tex]#\text{ neutrons=atomic mass-atomic number.}[/tex]As we have the number of neutrons and the atomic mass, let's find the atomic number of each atom by solving for 'atomic number'. The new formula is:
[tex]atomic\text{ number=atomic mass-\# neutrons.}[/tex]Let's replace the given values:
[tex]\begin{gathered} atomi\text{c number of X=19-10=9,} \\ atomic\text{ number of Y=16-8=8.} \end{gathered}[/tex]Remember that isotopes are atoms that have the same atomic number, but different mass numbers due to a change in the number of neutrons. In this case, they have different atomic numbers, so we discard this option.
If you go to see the periodic table, you can realize that based on the atomic number, atom X correspond to the element fluorine (F), and atom Y correspond to the element oxygen (O).
You can note that O is in the VIA family, and F is in the VIIA family, so they are not in the same family of the periodic table. O (Y atom) is on the left side of F (X atom) and F is on the right side of O (Y atom).
Based on this logic, the answer would be the last one: Atom X is in a column to the right of Atom Y on the periodic table.
A gas sample has 0.49 moles and occupies 1.20 L. How many moles of gas are added to increase the volume to 4.30 L?
1.76moles
Explanations:The number of moles of gas "n" is directly proportional to its volume "v". This can be expressed as:
[tex]\begin{gathered} n\alpha v \\ n=kv \\ k=\frac{n_1}{v_1}=\frac{n_2}{v_2} \end{gathered}[/tex]where:
n1 and n2 are initial and final moles respectively
v1 and v2 are the initial and final volumes
Given the following parameters
[tex]\begin{gathered} n_1=0.49mole \\ v_1=1.20L \\ v_2=4.30L \end{gathered}[/tex]Required
Final number of moles "n2"
Substitute the given parameters into the formula
[tex]\begin{gathered} n_2=\frac{n_1v_2}{v_1} \\ n_2=\frac{0.49\times4.30}{1.20} \\ n_2=\frac{2.107}{1.20} \\ n_2=1.76moles \end{gathered}[/tex]Hence the moles of gas added to increase the volume to 4.30L is 1.76moles
How many and what types of bonds are shown here? I know some, but not all. I need to know so I can calculate the enthalpy change.
Here in all the compounds we see covalent bonds, that is to say that the atoms are sharing electrons with each other. Now, covalent bonds are divided into single, double or triple according to the number of electrons they share.
When they share a pair of electrons, a line is drawn that represents a bond. If it has only one it will be a simple bond, if it has two it will be a double bond and if it has 3 it will be a triple bond.
Here we see simple covalent bonds and double covalent bonds.
Now, to calculate the enthalpy change we can do it starting from the bond energies, applying the following formula:
[tex]\Delta H_r=PotentialEnergyofProductBonds-PotentialEnergyofReactantBonds[/tex]The bonds to take into account for the calculation of enthalpy will be:
Ethanol:
5 bonds C-H
1 bond C-O
1 bond O-H
Oxygen:
1 bond O=O, but there are 3 moles of O2, so it will be 3 bonds O=O
Carbon dioxide:
2 bonds O=C, there are 2 moles of CO2, so it will be 2x2= 4 bonds O=C
Water:
2 bonds O-H, there are 3 moles of H2O, so it will be 2x3=6 bonds O-H
Classify each reaction as synthesis, decomposition, single displacement, or double displacement (a) H2 + O2 = H2O (b) N2H4(l)—> NH3(g)+N2(g) (c) H2SO4 + NaOH —> H2O+Na2SO4 (d) Al2 (CO3) -^-> Al2O3 + CO2 (e) NH4I+ Cl2 —-> NH4Cl+I2
a) H2 + O2 = H2O -----> Synthesis
b) N2H4(l)—> NH3(g)+N2(g) ----> Decomposition
c) H2SO4 + NaOH —> H2O+Na2SO4 ----> Double-displacement
d)Al2 (CO3) -^-> Al2O3 + CO2----> Decomposition
e) NH4I+ Cl2 —-> NH4Cl+I2 ----> Single displacement
This is a fill in the blank type of question I’m really confused and somehow very much appreciated.
The image shows a Lithium Atom. The atom is composed by three subatomic particles: electron, proton and neutron.
The number of protons in an atom gives the type of atom it is. The Lithium atom has an atomic number of 3, which means that this atom always has 3 protons.
The protons and the neutrons are in the nucleus of the atom, which are , in this case, the blue and red particles. We can see that we have 4 blue ones, and since we know that we can only have 3 protons on Lithium, the blue ones have to be the neutrons, which males the red ones the protons.
The electrons are located around the atom, on the orbital, so they are the green ones.
Thus, we have:
1 - electron
2 - proton
3 - neutron
The solubility product constant (Ksp) for zinc sulfide is 3.0 x 10^-23 at 25 C. What is the concentration of zinc ions in a saturated zinc sulfide solution? Answer choices: 4.1 x 10^-3 M 5.5 x 10^-12 M 1.5 x 10^-23 M 1.5 x 10^-12 M
The dissociation of zinc sulfide is expressed as:
[tex]ZnS\rightarrow[Zn^{2+}][S^{2-}][/tex]The Ksp value is expressed as:
[tex]\begin{gathered} Ksp=(x)(x) \\ Ksp=x^2 \end{gathered}[/tex]Substitute the given Ksp value to have:
[tex]3.0\times10^{-23}=x^2[/tex]Take the square root of both sides
[tex]\begin{gathered} x=\sqrt{3.0\times10^{-23}} \\ x=5.47\times10^{-12}M \\ [Zn^{2+}]\approx5.5\times10^{-12}M \end{gathered}[/tex]Hence the concentration of zinc ions in a saturated zinc sulfide solution is 5.5 * 10^-12M
It’s finding the reaction. It needs to be completed and balanced
answer
balanced equation
Fe(s) + Na₃PO ₄ -> FePO₄ + 3Na
a) Read the graphs is energy absorbed or release as a reaction progresses from the reactants to the activation complex?b) compare how are the graphs for the reactions 1 and 2 different?
A) The graph that shows energy changes in reaction 2 is showing an endothermic reaction. This graph shows that the reaction is absorbing energy. On the other hand, the graph that shows the energy changes in reaction 1 is showing an exothermic reaction meaning energy is being released.
B) The graph for reaction 2 shows that the reactants are lower than the products whilst on reaction 1 the reactants are higher than the products. For reaction 2 the activation energy is greater than that of reaction 1.
A solution has a hydroxide ion concentration of 0.001 M. What is the pH of the solution?Group of answer choices37111314
pOH = - log10[OH-]
pOH= −log10(1×10−3)
pOH = 3
we know that :
pH+ pOH=14
pH =14 - pOH
therefore pH=14−3
= 11
The pH of the solution is 11
What size does see the letters au they know it means gold what is Au?
• Gold chemical symbol is Au, denoted from the word aurum
• Gold is element number 79 and its symbol is Au.
Option B is correct .Given the reaction: N2(g) +2O2(g) ⇌ 2NO2(g) The forward reaction is endothermic. Determine which of the following changes would result in more product being produced. I. Increase NO2II. Decrease O2III. Add a catalystIV. Increase the temperatureV. Increase the pressureA. IV and VB. I and IIC. II, III, and VD. II and IV
In this question, we have to determine which are the factors that will cause the forward reaction to be favored, causing more products to be produced, the possibilities are:
I. Increase NO2
This option would cause more reactants to be produced, since we are raising the number of products, therefore the reaction will produce more reactants to balance
II. Decrease O2
Same case as option I
Since I and II are wrong, the only option left is letter A, if you increase the temperature the endothermic reaction will be favored, and increasing the pressure, the reaction with less moles of gas will be favored, both are the case in our question
Letter A is correct
What is the correct balance of the equation for the combustion of ethanol (CH3CH2OH - drinking alcohol)?- CH3CH2OH + 3O2 → 2CO2 + 3H2O- 3CH3CH2OH + 9O2 → 6CO2 + 12H2O- CH3CH2OH + O2 → CO2 + H2O- 2CH3CH2OH + 13O2 → 4CO2 + 6H2O
Answer:
[tex]A[/tex]Explanation:
Here, we want to write the correct equation for the combustion of ethanol
When organic compound burns in an unlimited supply of oxygen, what is produced is carbon (iv) oxide and water
We have the balaced chemical reaction as shown below:
[tex]CH_3CH_2OH\text{ + 3O}_2\text{ }\rightarrow\text{ 2CO}_2\text{ + 3H}_2O[/tex]How many moles of nitrogen gas (N2) are needed in order to produce 5 moles of an NH3?N2+3H2–> 2 NH3
Step 1 - Reading a chemical equation
In order to properly 'read' a chemical equation, we must know that the bigger numbers, those that come before the formulas of each susbtance, represent a quantity in moles.
The given chemical equation could be read thus as:
[tex]N_2+3H_2\to2NH_3[/tex]one mole of N2 react with 3 moles of H2 producing 2 moles of NH3
Step 2 - Finding how many moles of N2 are needed
Reading a chemical equation is like obtaining its recipe: we discover the proportion between the substances, and we can use it to predict how much we wll need if we 'change' the recipe.
Since we want to produce 5 moles of NH3, we can use this proportion:
one mole of N2 produces 2 moles of NH3
Therefore:
[tex]\begin{gathered} 1\text{ mole of N2 produces ---- 2 moles of NH3} \\ x\text{ moles of N2 would produce -- 5 moles of NH3} \\ \\ x=\frac{5}{2}=2.5\text{ moles of N2} \end{gathered}[/tex]We would need thus 2.5 moles of N2.
Use the chart to answer the question. Given the bond energy below which bond is the weakest? Which bond is most stable?
Answer
C-Cl is the weakest bond in the chart.
H-F is the most stable bond in the chart
Explanation
As bond strength increases, the atoms in the bond are pulled more tightly together. Therefore, generally, as the bond energy increases, the bond length decreases. The strength of a bond between two atoms increases as the number of electron pairs in the bond increases.
So, the bond energy is directly related to the strength of a chemical bond. High bond energy means that a bond is strong and the molecule that contains that bond is likely to be stable and less reactive.
Hence, C-Cl is the weakest bond in the chart because it has the least bond energy (339 kJ/mol) and H-F is the most stable bond in the chart because it has the highest bond energy (565 kJ/mol).
Not a timed or graded assignment. I need:The givenConversion factor used Orientation of conversion factor in the dimensional analysis setupNumerical answer Units used throughout Significant figures Quick answer = amazing review thank you so much In advance :)
Calculations:
1 mole of O2 gas occupie 22.4 L
So x moles of O2 gas occupies 53 L .....do a cross multiply,
[tex]\begin{gathered} xmolesofO_2\text{ = }\frac{53L\cdot moleO_2}{22.4\text{ L}} \\ \text{ =2.366 moles } \\ \approx2.4moles_{} \end{gathered}[/tex]This means that 2.4 moles of Oxygen gas will occupy 53 L
9.Which statement is true of an ice tea solution?Select one:a. The tea and water particles can be separated out by filtering.b. The tea and water particles look the same throughout the solution.c. Individual tea and water particles are easily seen.d. The tea and water particles are bonded chemically.
Answer
b. The tea and water particles look the same throughout the solution.
Explanation
The water and tea are not chemically bonded together, the tea dissolved in water and they can be easily separated by distillation. Since tea is dissolved in water, the mixture is homogenous, you cannot differentiate between the tea and water, so the particles look the same throughout the solution.
Write the molecular formulas for the alkenes with 7,8,9 and 10 carbons
Step 1 - Understanding the general molecular formula for an alkane
All akanes can be reduced to a general formula that relates the number of H atoms to the number of C atoms. This general formula is:
[tex]C_nH_{2n+2}[/tex]What this formula means is that, if the number of C atoms in the alkane is n, then the number of H atoms will be 2n+2. This is a fixed relation and we can use it to discover the molecular formula for any alkane.
Step 2 - Applying the formula for 7, 8, 9 and 10 C
Since we have a formula relating the number of H to the number of C, we just need to substitute n for the number of C in each case:
[tex]\begin{gathered} n=7,2n+2=16\rightarrow C_7H_{16} \\ \\ n=8,2n+2=18\rightarrow C_8H_{18} \\ \\ n=9,2n+2=20\rightarrow C_9H_{20} \\ \\ n=10,2n+2=22\rightarrow C_{10}H_{22} \end{gathered}[/tex]1. If the reaction of 80 grams of Pb(NO3)2 produces 21.3 grams of NO2, what is thepercent yield?2Pb(NO3)22PbO + 4NO₂ + 02
ANSWER
The percentage yield of the reaction is 95.7%
EXPLANATION
Given that;
The mass of Pb(NO3)2 is 80 grams
The mass of NO2 produced is 21.3 grams
Follow the steps below to find the percentage yield of the reaction
Step 1; Write a balanced equation of the reaction
[tex]\text{ 2Pb\lparen NO}_3)_2\text{ }\rightarrow\text{ 2PbO + 4NO}_2\text{ + O}_2[/tex]Step 2; Find the number of moles of Pb(NO3)2 using the formula below
[tex]\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}[/tex]Recall, that the molar mass of Pb(NO3)2 is 331.2 g/mol
[tex]\begin{gathered} \text{mole = }\frac{\text{ 80}}{\text{ 331.2}} \\ \text{ mole = 0.242 mol} \end{gathered}[/tex]Step 3; Find the number of moles of NO2 using a stoichiometry ratio
In the equation above, 2 moles Pb(NO3)2 give 4 moles NO2
Let x represents the number of moles of NO2
[tex]\begin{gathered} \text{ 2 moles Pb\lparen NO}_3)_2\text{ }\rightarrow\text{ 4 moles NO}_2 \\ \text{ 0.242 mol Pb\lparen NO}_3)_2\text{ }\rightarrow\text{ x moles NO}_2 \\ \text{ cross multiply} \\ \text{ 2 moles Pb\lparen NO}_3)_2\times\text{ x moles NO}_2\text{ = 4 moles NO}_2\text{ }\times\text{ 0.242 mol Pb\lparen NO}_3)_2 \\ \text{ Isolate x} \\ \text{ x moles NO}_2\text{ = }\frac{4\text{ moles NO}_{2\text{ }}\times0.242mol\cancel{Pb(NO_3})_2}{2moles\cancel{Pb(NO_3})_2} \\ \text{ } \\ \text{ x moles NO}_2\text{ = }\frac{4\text{ }\times\text{ 0.242}}{2\text{ }} \\ \text{ } \\ \text{ x moles NO}_2\text{ = }\frac{0.968}{2} \\ \text{ x moles NO}_2\text{ = 0.484 mole} \end{gathered}[/tex]The number of moles of NO2 is 0.484 mole
Step 4; Find the mass of NO2
[tex]\text{ Mole = }\frac{\text{ mass}}{\text{ molar mass}}[/tex]Recall, that the molar mass of NO2 is 46 g/mol
[tex]\begin{gathered} \text{ mass = mole }\times\text{ molar mass} \\ \text{ mass = 0.484 }\times\text{ 46} \\ \text{ mass = 22.264 grams} \end{gathered}[/tex]Since the calculated mass of NO2 is 22.264 grams, hence, the theoretical yield is 22.264 grams
Step 5; Find the percentage yield of NO2
[tex]\text{ Percentage yield = }\frac{\text{ Actual yield }}{\text{ theoretical yield}}\times\text{ 100\%}[/tex][tex]\begin{gathered} \text{ Percentage yield = }\frac{\text{ 21.3}}{\text{ 22.264}}\text{ }\times\text{ 100} \\ \\ \text{ Percentage yield = 0.956 }\times\text{ 100} \\ \text{ Percentage yield = 95.7\%} \end{gathered}[/tex]Therefore, the percentage yield of the reaction is 95.7%
Question 24 of 30Which of the following is a fossil fuel in solid-rock form that is obtainedthrough mining?OA. BauxiteB. GypsumC. PetroleumD. Coal
Answer:
[tex]D\text{ : Coal}[/tex]Explanation:
Fossil fuels are remains of dead organic materials (plants and animals) buried inside the earth's crust for a long number of years.
They are reliable energy sources
Coal is a form of fossil fuel, petroleum is a form of fossil fuel too. However, petroleum is drilled to bring it out of the earth while coal is mined
The correct answer choice here is thus coal
If the hydrogen ion concentration [H*] is 1.00 x 10-10 the solution isacidic basic (alkaline)neutral or none of the above
Answer
basic (alkaline)
Explanation
To know if the solution is acidic, basic or neutral, you need to determine the pH of the solution.
[tex]pH=-log[OH^+][/tex]Putting [OH⁺] = 1.00 x 10⁻¹⁰ into the pH formula, we have
[tex]\begin{gathered} pH=-log(1.00\times10^{-10}) \\ \\ pH=-(-10) \\ \\ pH=10 \end{gathered}[/tex]Note that the pH scale ranges from 0 to 14, with 7 being neutral. pHs less than 7 are acidic while pHs greater than 7 are alkaline (basic).
Therefore, the solution is basic (alkaline)
Not a timed or graded assignment. Quick answer = amazing review :) Prompt : “which of the following allows us to make mathematical predictions using Charles’ law”
Answer:
[tex]\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}[/tex]Explanation:
Here, we want to select the option that represent the mathematical equation of the Charles' law
According to the law, the volume of a given mass of gas at a constant temperature is directly proportional to the absolute temperature (temperature in Kelvin) of the given mass of gas
Mathematically:
[tex]\begin{gathered} V\text{ }\propto\text{ T} \\ Which\text{ means :} \\ V\text{ = KT} \\ or\text{ } \\ \frac{V}{T\text{ }}\text{ = K} \end{gathered}[/tex]Writing the above in terms of the final and initial state, we have it that:
[tex]\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}[/tex]Where:
V1 is initial volume
T1 is the initial temperature
V2 is the final volume
T2 is the final temperature
the electronegativity of the halogens changes down group 7.Explain how electronegativity changes down group 7. (3 marks)
STEP-BY-STEP EXPLANATION:
Firstly, we need to define electronegativity
Electronegativity is defined as the tendency of an atom in a covalent bond to attract the bonding electrons.
The electronegativity of the halogen decreases down the group due to an increase in the radius of the atom resulting in the addition of outermost shells to the shell of the atom. As the number of shells increases, the force attraction between the nucleus and the electron moving around the shell decreases.
A chemist determines by measurement that 0.0900 moles of iodine solid participate in a chemical reaction. Calculate the mass of iodine solid that participates. Be sure your answer has the correct number of significant digits
We have 0.0900 moles of iodine solid which formula is I2
------------------------------------------------------------------------------------
Molecular weight = 253.8089 g/mol
------------------------------------------------------------------------------------
We are going to use this:
[tex]\begin{gathered} \text{Moles = }\frac{\text{grams}}{\text{molecular weight}} \\ \text{Moles x Molecular weight = grams} \\ 0.0900\text{ moles x 253.8089 }\frac{g}{\text{mol}}=22.8428g_{} \end{gathered}[/tex]Answer: Mass of iodine solid = 22.8428 g
Using the equationCaCO3 (s) + 2 HCl (aq) arrow CaCl2 + CO2 (g) + H2O (l)calculate the molarity of a hydrochloric acid solution if an initial mass of 5.238 g of CaCO3 was reacted with 25.0 mL of the of the acid and 3.77 g of CACO3 remain after the reaction is complete.
Answer:
1.17 M HCl.
Explanation:
What is given?
Mass of CaCO3 = 5.238 g.
Excess of CaCO3 = 3.77 g.
Mass of CaCO3 consumed in the reaction = 5.238 g - 3.77g = 1.468 g.
Molar mass of CaCO3 = 100 g/mol.
Volume of HCl solution = 25.0 mL.
Step-by-step solution:
As you can see, we have an excess of CaCO3 because we have 3.77g of CaCO3 remaining and initially we used 5.238 g of this compound that actually was consumed 1.468 g in the reaction. So, let's see how many moles there are in 1.468 g of CaCO3 using its molar mass:
[tex]1.468\text{ g CaCO}_3\cdot\frac{1\text{ mol CaCO}_3}{100\text{ g CaCO}_3}=0.01468\text{ moles CaCO}_3.[/tex]And now, based on this, you can see that in the chemical equation, we have 1 mol of CaCO3 reacting with 2 moles of HCl, so let's find how many moles of HCl we need to react with 0.01468 moles of CaCO3:
[tex]0.01468\text{ moles CaCO}_3\cdot\frac{2\text{ moles HCl}}{1\text{ mol CaCO}_3}=0.02936\text{ moles HCl.}[/tex]Now that we have the number of moles of HCl and its volume (25.0 mL), we can calculate its molarity using the following formula:
[tex]Molarity=\frac{mole\text{s of solute}}{liter\text{s of solution}}=\frac{mol}{L}.[/tex]But we need to have the volume in liters. Remember that 1 L equals 1000 mL, so:
[tex]25.0\text{ mL}\cdot\frac{1\text{ L}}{1000\text{ mL}}=0.025\text{ L.}[/tex]And finally, we can replace our data with the molarity formula:
[tex]Molarity\text{ of HCl=}\frac{0.02936\text{ moles}}{0.025\text{ L}}=1.174\text{ M.}[/tex]The molarity of the hydrochloric acid solution would be 1.17 M.
Use the activity series below to predict the products of each of the following reactions. You do not need tobalance the equations.Li > K > Ba> Sr > Ca> Na > Mg > Al> Mn > Zn > Cr > Fe > Cd>Co> Ni> Sn> Pb > H> Sb> Bi > Cu > Ag > Pd > Hg > Pt > AuF2 > Cl₂> Br2 > 12FeSO4 + Na - ?CCl4 + Br₂ ?1Ono reactionno reactionNa₂SO4 + FeBrCl + CO FeNa+ SO4CB4 + Cl₂DONECOMPLETE
Answer:
[tex]B[/tex]Explanation:
Using the activity series, we want to predict the products of the reaction
From the series, we know that sodium is higher than iron. This means that sodium can displace iron from its salt
Thus, we have the equation of reaction as:
[tex]FeSO_4\text{ + 2Na }\rightarrow\text{ Na}_2SO_4\text{ + Fe}[/tex]The empirical formula for C6H12O6 is?Group of answer choicesC3H4O3C2H4O2C1H2O1C6H12O6
The empirical formula shows the smallest integer numbers of the atoms of the elements that make up a substance. Therefore, we need to find the number that is divisible by the index of each element of the molecular formula.
The molecular formula is C6H12O6 We can divide each index by 6:
6/6 = 1
12/6 = 2
6/6 = 1
So the empirical formula is CH2O.
Answer: C1H2O1
A chemist prepares a sample of hydrogen bro-mide and finds that it occupies 238 mL at 66°C and 513 Torr.What volume would it occupy at O°C at the same pressure?Answer in units of mL.
Answer:
[tex]191.68\text{ mL}[/tex]Explanation:
Here, we want to get the final volume
From the general gas equation, we have it that:
[tex]\frac{P_1V_1}{T_1}\text{ = }\frac{P_2V_2}{T_2}[/tex]From the question, we have it that:
P1 is the initial pressure which is 513 torr
V1 is the initial volume which is 238 mL
T1 is the initial temperature which we have to convert to absolute value by adding 273.15 K ( 66 + 273.15 = 339.15 K)
P2 is the final pressure that is the same as the initial which is 513 torr
V2 is the final volume that we want to calculate
T2 is the final temperature which is 273.15 K (0 degrees Celsius is 273.15 K)
Substituting the values, we have:
[tex]\begin{gathered} \frac{513\times238}{339.15}\text{ = }\frac{513\times V_2}{273.15} \\ \\ V_2\text{ = }\frac{513\times238\times273.15}{339.15\text{ }\times\text{ 513}}\text{ = 191.68 mL} \end{gathered}[/tex]We could have solved this by using Charles' law that relates temperature to volume (volume is directly proportional to temperature)
Pop at room temperature will have less carbon dioxide dissolved in it than cold popTrue False
In relation to temperature, gases dissolved in liquids behave inversely to solids. The solubility of a gas in water/liquid decreases with increasing temperature; this means that solubility and temperature are inversely proportional.
Let's compare these 2 cases.
Pop at room temperature is hotter than cold pop. So, the answer is True because of the explanation up.
Answer: True
Show how by calculation how you will prepare 1.0x10-2 M NaOH from 0.1 M NaoHstock solution
To prepare 1.0x10^-2M NaOH from 0.1M NaOH stock solution, you have to take a volume of the stock solution and dilute it using 9 times that volume of water. We conclude it from the equation for dilutions:
[tex]\begin{gathered} V1C1=V2C2 \\ 0.1V1=0.01V2 \\ \frac{0.1}{0.01}V1=V2 \\ 10V1=V2 \\ V1=\frac{1}{10}V2 \end{gathered}[/tex]It means that to prepare the 1.0x10^-2 solution, dilute 1 mL (for instance) of stock solution in 9mL of water.
Why are solids not included in the Ksp formula?
Explanation:
When calculating the equilibrium constant expression we don't include pure solids or liquids because their concentrations stay constant during the reaction. Since their concentrations don't change significantly throughout the reaction (if enough is present) they don't affect the equilibrium so we don't include them in the ksp formula.
Answer: because the concentration of a purid solid remains constant during the reaction.
How do I find the rate of reaction in terms of how it’s written?
Answer:
Explanation:
The Reaction Rate for a given chemical reaction is the measure of the change in concentration of the reactants or the change in concentration of the products per unit time. Let's see the following reaction:
[tex]aA+bB\rightarrow cC+dD.[/tex]The rate can be measured in terms of either reactant (A or B) or either product (C or D), like this:
[tex]rate=-\frac{1}{a}\cdot\frac{\Delta\lbrack A]}{\Delta t}=-\frac{1}{b}\cdot\frac{\Delta\lbrack B]}{\Delta t}=\frac{1}{c}\cdot\frac{\Delta\lbrack C]}{\Delta t}=\frac{1}{d}\cdot\frac{\Delta\lbrack D]}{\Delta t}.[/tex]The problem is asking for the rate of the reaction in terms of the change of nitrogen dioxide (NO2) concentration, so we can apply the formula of rate.
As NO2 are in the reactants, the rate is negative because it is consuming and the coefficient which is 14 is in the denominator:
[tex]rate=-\frac{1}{14}\cdot\frac{\Delta\lbrack NO_2]}{\Delta t}.[/tex]The answer would be that the rate of NO2 concentration in the reaction is -1/14*(Δ[NO2])/Δt).