Plz help! correct answer will get another brainliest!

Answer:

B. Tanisha sold the CDs for $2 each.

Step-by-step explanation:

Answer:

Its 69.1 cm

Step-by-step explanation:

To find circumstance of any circle main formula is 2*pie*r .

Here pie is equal to 3.14 approx and r =11 cm

so

2*3.14*11 = 69.08 cm

This little difference is just because of pie's approximately value used

Answer:

Height of the building is 40 feet

Step-by-step explanation:

From the figure attached,

Height of the person DE = 5 feet

Let height of the building BC = h feet

Since, ΔABC ~ ΔADE,

Their corresponding sides will be proportional,

[tex]\frac{DE}{BC}=\frac{AD}{AB}[/tex]

[tex]\frac{5}{h}=\frac{13}{104}[/tex]

h = [tex]\frac{104\times 5}{13}[/tex]

h = 40 feet

Therefore, height of the building is 40 feet.

Answer:

a) P(X∩Y) = 0.2

b) [tex]P_1[/tex] = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability [tex]P_1[/tex] that he must stop at the first signal but not at the second one can be calculated as:

[tex]P_1[/tex] = P(X) - P(X∩Y)

[tex]P_1[/tex] = 0.36 - 0.2 = 0.16

At the same way, the probability [tex]P_2[/tex] that he must stop at the second signal but not at the first one can be calculated as:

[tex]P_2[/tex] = P(Y) - P(X∩Y)

[tex]P_2[/tex] = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

[tex]P = P_1+P_2\\P=0.16+0.31\\P=0.47[/tex]

Answer: D, 6

Step-by-step explanation:

Match each side from XYZ to ABC (you are trying to find the scale factor of triangle 1 to triangle 2)  into a fraction then simplify

Ex 30/5= 6 or  24/6= 6 or 18/3

Answer:

8.) $7325.98

9.) $8218.10

Step-by-step explanation:

Compounded Interest Rate Formula: A = P(1 + r/n)^nt

Simply plug in our known variables into the formula:

A = 6000(1 + 0.04/12)^60 = 7325.98

A = 5000(1 + 0.05/4)^40 = 8218.10

Answer:

We accept H₀

Step-by-step explanation:

Population mean  μ₀ = 47500

Population standard deviation unknown

Sample size    n = 86   degree of freedom  df = 86 - 1  df = 85

Sample mean    μ = 48061

Sample standard deviation 2,351

The claim implies a two tail test with t-studend distributon

Null  Hypothesis                 H₀               μ  =  μ₀

Alternative Hypothesis      Hₐ               μ  ≠  μ₀      

Confidence Interval  mean α = 0,02     and   α/2  =  0,01

With α/2 and df = 85, from t-table we find  t(c)  critical value

t(c) = 2,3710

We compute t(s) as

t(s)  =  ( μ - μ₀ ) / s /√n

t(s)  = ( 48061 - 47500 )/ 2351/√86

t(s)  = 561 * 9,273 / 2351

t(s) = 2,212

Now we compare t(s) and t(c)

t(s) < t(c)       2,212  < 2,371

Then we are in the acceptance region. We accept H₀

Answer:

everywhere except between 2 and 5

(between -inf and 2 and between 5 and inf)

Step-by-step explanation:

Answer:

14%

Step-by-step explanation:

On edge 2020

Answer:

1. 77520

2. [tex]P_1[/tex] = 0.0017

3. [tex]P_2[/tex] = 0.0019

4. [tex]P_3[/tex] = 0.9981

5. [tex]P_4[/tex] = 0.2036

Step-by-step explanation:

The number of ways or combinations in which we can select x elements from a group of n can be calculated as:

[tex]nCx = \frac{n!}{x!(n-x)!}[/tex]

So, there are 77520 selections that result in all 7 workers coming from the day shift. It is calculated as:

[tex]20C7 = \frac{20!}{7!(20-7)!}=77520[/tex]

At the same way, the total number of selections of 7 workers from the 45 is 45C7, so the probability that all 7 selected workers will be from the day shift is:

[tex]P_1=\frac{20C7}{45C7} =0.0017[/tex]

The probability that all 7 selected workers will be from the same shift is calculated as:

[tex]P_2=\frac{20C7+15C7+10C7}{45C7} =0.0019[/tex]

Because the consultant can select all workers from the day shift (20C7) or can select all workers from the swing shift (15C7) or can select all workers from the graveyard shift (10C7).

On the other hand, the probability that at least two different shifts will be represented among the selected workers is the complement of the probability that all 7 selected workers will be from the same shift. So it is calculated as:

[tex]P_3 = 1- P_2=1 - 0.0019 = 0.9981[/tex]

Finally, the probability that at least one of the shifts will be un-represented in that sample of workers is:

[tex]P_4=\frac{25C7+30C7+35C7}{45C7} =0.2036[/tex]

Where 25C7 is the number of ways to select all 7 workers from swing or graveyard shift, 30C7 is the number of ways to select all 7 workers from day or graveyard shift and 35C7 is the number of ways to selects all 7 workers from day shift and swing shift.

Answer:

18.2 :)

Have a great day!!!

Answer:

1st one =  d y^27

2nd one = b 2x^9

Step-by-step explanation:

1st one: since the power is being raised to the power of 3 you multiply the numbers

2nd one: the powers aren't being raised so you add the powers together.

12x^13y^10/6X^4y^10

then dividing for exponents is subtracting them so

2x^9 since y gets canceled out

Answer:

[tex]\boxed{\sf \ \ \ \text{one possibility is } f(x)=3x \ and \ g(x)=x+2 \ \ \ }[/tex]

Step-by-step explanation:

hello

h(x)=f(g(x))=3(x+2)

if we have f(x)=3x and g(x)=x+2 then

f(g(x))=f(x+2)=3(x+2)

hope this helps

Answer:

Step-by-step explanation:

(a) The linear approximation of g(x) at x=b will be ...

  g(x) ≈ g'(b)(x -b) +g(b)

Using the given relations, this is ...

  g'(3) = 3² +7 = 16

  g(x) ≈ 16(x -3) -1

Then the points of interest are ...

  g(2.95) ≈ 16(2.95 -3) -1 = -1.8

  g(3.05) ≈ 16(3.05 -3) -1 = -0.2

__

(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)

Answer:

The population of four years ago was 100,783 inhabitants

Step-by-step explanation:

The population of the city after t years is given by the following equation:

[tex]P(t) = P(0)(1-r)^{t}[/tex]

In which P(0) is the initial population and r is the decrease rate, as a decimal.

2 years later, that is to say two years ago, the population of this same city was 81,000 inhabitants and today it is 65,610.

This means that:

[tex]P(2) = 81000, P(4) = 65610[/tex]

We are going to use this to build a system, and find P(0), which is the initial population(four years ago).

P(2) = 81000

[tex]P(t) = P(0)(1-r)^{t}[/tex]

[tex]81000 = P(0)(1-r)^{2}[/tex]

[tex](1-r)^{2} = \frac{81000}{P(0)}[/tex]

P(4) = 65610

[tex]P(t) = P(0)(1-r)^{t}[/tex]

[tex]65100 = P(0)(1-r)^{4}[/tex]

[tex]65100 = P(0)((1-r)^{2})^{2}[/tex]

Since [tex](1-r)^{2} = \frac{81000}{P(0)}[/tex]

[tex]65100 = P(0)(\frac{81000}{P(0)})^{2}[/tex]

Using P(0) = x

[tex]65100 = x(\frac{81000}{x})^{2}[/tex]

[tex]65100 = \frac{6561000000x}{x^{2}}[/tex]

[tex]65100x^{2} = 6561000000x[/tex]

[tex]65100x^{2} - 6561000000x[/tex]

[tex]x(65100x - 6561000000) = 0[/tex]

x = 0, which does not interest us, or:

[tex]65100x - 6561000000 = 0[/tex]

[tex]65100x = 6561000000[/tex]

[tex]x = \frac{6561000000}{65100}[/tex]

[tex]x = 100,783[/tex]

The population of four years ago was 100,783 inhabitants

Answer:

a) [tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

b) [tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

c) [tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

[tex]\hat p=\frac{823}{1000}=0.823[/tex]

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by [tex]\alpha=1-0.95=0.05[/tex] and [tex]\alpha/2 =0.025[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96[/tex]

The confidence interval for the mean is given by the following formula:  

[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

If we replace the values obtained we got:

[tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]    (a)  

And on this case we have that [tex]ME =\pm 0.03[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex]   (b)  

And replacing into equation (b) the values from part a we got:

[tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

Part c

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Explanation:

The notation [tex]T_{-3,5}(x,y)[/tex]  or means to move any point (x,y) along the vector <-3,5>. Put another way, it says to shift (x,y) three units to the left and five units up. The x portion deals with left or right shifting, the y portion deals with up or down shifting. Since the x portion is negative, we go in the negative direction on the x axis. Y being positive means we move up rather than down.

This all means we end up with the translation rule [tex](x,y) \to (x-3,y+5)[/tex]

Answer:    20,736

Step-by-step explanation:

Math and History and Chemistry and Biology and Subjects

  3!     x        4!        x          3!          x        1!          x        4!       = 20,736

Answer:

h = - [tex]\frac{3}{2}[/tex]

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = 2x² + 6x + 11 ( factor out 2 from the first 2 terms )

   = 2(x² + 3x) + 11

Using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² + 3x

y = 2(x² + 2([tex]\frac{3}{2}[/tex] )x + [tex]\frac{9}{4}[/tex] - [tex]\frac{9}{4}[/tex] ) + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² - [tex]\frac{9}{2}[/tex] + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² + [tex]\frac{13}{2}[/tex] ← in vertex form

with h = - [tex]\frac{3}{2}[/tex]

Answer:

3/13

Step-by-step explanation:

There are a total of 13 fish (6+ 7 = 13). There are 3 small, red fish. (1/2 · 6 = 3). Put the number of small, red fish over the total number of fish because the small, red fish is being selected from the entire tank of fish. 3/13 cannot be simplified any further.

Answer:

Equilateral

Acute

Step-by-step explanation:

The sides are all equal as indicated by the lines on each side - Equilateral

The angles are all equal by the angle marks  180/3 = 60 which is less than 90 degrees.  This makes the angles acute

Hey there!

To solve this, we need to plug each of our answer options into the inequality and see if it is true. Which ever one doesn't make the inequality true when plugged in is the answer.

OPTION A

(x,y)=(-3,0)

We plug our values into the inequality.

0≥ I-3I+3

You may have noticed the bars surrounding the negative three.. If you didn't know, this is called absolute value. Absolute value is how far the number is from 0 on the number line. -7 is 7 away from 0 on a number line, so the absolute value of -7 is 7. The absolute value of 7 is 7. The absolute value of 0 is 0. Absolute value is signified by these bars. Le'ts finish evaluating.

0≥6

As you can see, zero is not greater than or equal to six. So, option A is false.

Since A is not a solution, we already know that that is the answer, so we don't even need to check B and C. But, we can still evaluate them if you want.

OPTION B

6≥I-3I+3

6≥6

This is true.

OPTION C

4≥I0I+3

4≥3

This is also true.

Therefore, the answer is A. (-3,0)

Have a wonderful day!

Answer:

The answer is b=0 or b=9.085603

The equation is solved and the perfect squares are removed from the square root and A = b²√( 30b )

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

A = √( 30b⁵ )

On simplifying the equation , we get

We can simplify the given expression by breaking down the number inside the square root into its prime factors:

30b⁵ = 2 x 3 x 5 x b⁵

Since we are looking to remove all perfect squares, we can remove the factors of 2 and 3, which are the only perfect squares present in the prime factorization of 30. This leaves us with:

30b⁵ = 2 x 3 x 5 x b⁵

= 2 x 3 x 5 x b⁴ x b

= 30b⁴ x b

Therefore, we can simplify the original expression as:

√(30b⁵) = √(30b⁴ x b) = √(30b⁴) x √b

A = b²√30 x √b

Hence , the expression √(30b⁵) simplifies to A = b²√30 x √b

To learn more about equations click :

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Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

Simply replace X with 4

Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

Answer:

  (5x +4y)^2

Step-by-step explanation:

The first and last terms are both perfect squares, and the middle term is twice the product of their roots. That means the trinomial is the perfect square trinomial ...

  25x^2 +40xy +16y^2 = (5x +4y)^2

_____

It matches the pattern ...

  a^2 +2ab +b^2 = (a +b)^2

Answer:

(5x +4y)^2

Step-by-step explanation:

Answer:

x^2 -2x+1

Step-by-step explanation:

(x - 1)^2

(x-1) * (x-1)

FOIL

first: x^2

outer: -1x

inner: -1x

last: 1

Add together

x^2 -1x-1x+1

Combine like terms

x^2 -2x+1

Answer:

[tex] \boxed{\sf D. \ {x}^{2} - 2x + 1} [/tex]

Step-by-step explanation:

[tex] \sf Expand \: the \: following: \\ \sf \implies {(x - 1)}^{2} \\ \\ \sf \implies (x - 1)(x - 1) \\ \\ \sf \implies x(x - 1) - 1(x - 1) \\ \\ \sf \implies (x)(x) - (1)(x) - (1)(x) - (1)( - 1) \\ \\ \sf \implies {x}^{2} - x - x - ( - 1) \\ \\ \sf \implies {x}^{2} - 2x - ( - 1) \\ \\ \sf \implies {x}^{2} - 2x + 1[/tex]

Answer:

180-130 = 50 degrees because its same side angle

m<2 = 50

Step-by-step explanation:

the second one m<1 is 105 for the same reason

Answer:

20) -43

21) 25

22)-9

Step-by-step explanation:

20) -6 (-6 + 49)/6 = -43

21) 10 - (-10 - (-1 + 6)) = 25

22) 1 - 10/2 - 5 = -9

Step-by-step explanation:

Let's calculate the expression khowing that m= 1 and n = 5

Let's calculate the expression khowing that n= -7 and p= - 6

Let's calculate the expression khowing that n = -6 and m = -1 and p = -10

Answer:

6

Step-by-step explanation:

Arrange the data from smallest to largest

1,3,6,7,9

The median is the middle number

1,3   ,6,   7, 9

The middle number is 6