Polarizing windows, filters, etc. are often used to reduce the amount of light that enters the lens of a camera or into a room or a car. A library atrium has an overhead skylight that lets in too much light during the day which heats up the interior of the library far too much. The building engineer installs new double paned polarizing sky lights to reduce the intensity. If sunlight, which is unpolarized, has an average intensity of 1366 W/m2 what angle should the polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 33% of the original value

Answers

Answer 1

Answer:

 θ = 35.7º

Explanation:

For this exercise we must use the law of Malus

          I = I₀ cos² θ

where the angle is between the two polarizers.

When the unpolarized light from the sun reaches the first polarizer, only the light polarized in the direction manages to be transmitted, which is why

          I₁ = I₀ /2

this light reaches the second polarizer

           I₂ = I₁ cos² θ

           I₂ = I₀/2    cos² θ

           cos² θ = 2 I₂ / Io

indicate that the transmitted light is 33% = 0.33 I₀

          cos² θ = 2 0.33

          cos θ = √0.66

          θ = cos⁻¹ 0.8124

          θ = 35.7º


Related Questions

When a narrow laser beam passes through a fine wire mesh before arriving at the wall, it forms a complicated pattern of bright spots on the wall. This pattern of spots would not occur if you sent a flashlight beam through the mesh because light from the flashlight is not a single electromagnetic wave. cannot be sent through a single opening of the mesh. is horizontally polarized, while laser light is vertically polarized. is vertically polarized, while laser light is horizontally polarized.

Answers

Answer:

this pattern to occur there must be coherence in the light beams.

you use a flashlight, the rays are incoherent so diffraction patterns cannot occur.

Explanation:

The point pattern that appears in the wall is the result of the interference and diffraction processes through each space of the mesh, for this pattern to occur there must be coherence in the light beams.

The coherence process is that all the rays have the same constant and phase, before the appearance of the lasers, the light is stopped by a small opening and this ray is the one that passes through the slits, with the appearance of the laser this it is consistent from its production process, so opening is not necessary, with this there is much greater intensity and the measurement process is simplified.

When you use a flashlight, the rays are incoherent so diffraction patterns cannot occur.

Polarization has no effect on diffraction patterns so it does not matter if it is vertical or horizontal.

what type of signal is utilized by the GP's satellite ?

Answers

Answer:

Hi how are you doing today Jasmine

Answer:

The answer is B

Explanation:

I did the USA test prep

Bobby Joe is having a fit and throws his backpack up in the air with an initial velocity of 26.2 m/s. Determine the height it will rise to before coming down and hitting Bobby Joe up the head.

A)2m
B)15m
C)25m
D)35m​

Answers

Answer:

D) 35m"

Explanation:

(and any subsequent words) was ignored because we limit queries to 32 words.

180 J of work is done when lifting a box up to a shelf that is 3 m high. What is the mass of the box?

Answers

Explanation:

Work done= MGH

180=m×10×3

180/30=m

m=6kg

True or False? 13. All living things are made of cells 14. All cells have DNA within their nucleus 15. The cell is the basic unit of life in all organisms 16. All cells in a living thing are similar in structure or function 17. Cells must develop from other cells

Answers

Answer:

1: True

2: False

3: True

4: False

5: True

The shape of the orbit for most comets is a(n):

circle
parabola
ellipse
oval

Answers

Answer:

Ellipse

Explanation:

Most comets have an elliptical path of orbit.

Answer: The shape of the orbit for most comets is: ellipse

A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 25.0 m/s. Then the vehicle travels for 39.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s.
(a) How long is the self-driving car in motion (in s)?
(b) What is the average velocity of the self-driving car for the motion described? (Enter the magnitude in m/s.) m/s

Answers

Answer:

[tex]56.5\ \text{s}[/tex]

[tex]21.13\ \text{m/s}[/tex]

Explanation:

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

s = Displacement

Here the kinematic equations of motion are used

[tex]v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{25-0}{2}\\\Rightarrow t=12.5\ \text{s}[/tex]

Time the car is at constant velocity is 39 s

Time the car is decelerating is 5 s

Total time the car is in motion is [tex]12.5+39+5=56.5\ \text{s}[/tex]

Distance traveled

[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{25^2-0}{2\times 2}\\\Rightarrow s=156.25\ \text{m}[/tex]

[tex]s=vt\\\Rightarrow s=25\times 39\\\Rightarrow s=975\ \text{m}[/tex]

[tex]v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{5}\\\Rightarrow a=-5\ \text{m/s}^2[/tex]

[tex]s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-25^2}{2\times -5}\\\Rightarrow s=62.5\ \text{m}[/tex]

The total displacement of the car is [tex]156.25+975+62.5=1193.75\ \text{m}[/tex]

Average velocity is given by

[tex]\dfrac{\text{Total displacement}}{\text{Total time}}=\dfrac{1193.75}{56.5}=21.13\ \text{m/s}[/tex]

The average velocity of the car is [tex]21.13\ \text{m/s}[/tex].

The bean of light is incident from a light source is: i.covergent
ii.divergent
iii.parallel
iv.both i and ii​

Answers

Answer:

I think the answer is II.divergent

because parralel beams are convergent to the light source

and in the question it says incident from the light source

Answer:

The correct answer is (i) Convergent.

During a football game player A (mass 120kg velocity 5.5m/s [L]) tackles and grabs player B (mass 105kg velocity 7.9m/s [R]). What is the final speed of the two players immediately after the collision?

Answers

Answer:

6.62m/s

Explanation:

Given data

M1= 120kg

U1= 5.5m/s

M2= 105kg

U2= 7.9m/s

The system experiences an inelastic collision, the expression for inelastic collision is

M1U1+ M2U1= (M1+M2)V

Subsitute

120*5.5+ 105*7.9= (120+105)*V

660+ 829.5= (225)*V

1489.5= (225)*V

Divide both sides by 225

V= 1489.5/225

V= 6.62m/s

Hence the common velocity is 6.62m/s

what do electrons and holes make when they are moving

Answers

Answer:

Holes are formed when electrons in atoms move out of the valence band (the outermost shell of the atom that is completely filled with electrons) into the conduction band. (the area in an atom where electrons can escape easily) which happens everywhere in a semiconductor. When an electron and a hole interact and recombine the energy is not transferred into heat energy or thermal vibrations. instead the energy is transferred into an electron within the conduction band which is then promoted to an energy higher in condition band.

Explanation:

So considering that information, electrons and holes make a semiconductor when moving.

an electric train moving at 5m/s accelerates to a speed of 8m/s in 20 seconds. Fine the distance travelled in meters during the period of acceleration

Answers

Answer:  130 meters

===================================================

Explanation:

vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.

So,

x = 0.5*(vi + vf)*t

x = 0.5*(5+8)*20

x = 130 meters

represents the distance traveled. The first equation shown above is one of the four kinematics equations.

would have to be about 130 meters

HELPPP PLEASEEEEE, BRIANLEST WILL BE GIVEN ON CORRECT!​

Answers

work done =force /area

=500/50

power =work done * time taken

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