Answer:
The correct answer is -
1. a) The bubbles will shrink, some may vanish.
2. a) Can A will make a louder and stronger fizz than can B.
Explanation:
In the first question, it is given that the bottle is not opened and therefore, squeezing the bottle filled with a carbonated drink will increase the pressure on the carbonated liquid which forces the bubbles to dissolve or displace or vanish as it moves to empty space.
Thus, the correct answer would be - The bubbles will shrink, some may vanish
In the second question, there are two different conditions for two different unopened cans of carbonated water that are different temperatures one at the garage with higher temperature and one in the fridge at low temperature. As it is known that higher the temperature less will be solubility of gas in liquid so gas in can A will be less soluble which means it has more gas and it will make louder and stronger fizz than B which was stored at low temperature.
thus, the correct answer would be - Can A will make a louder and stronger fizz than can B.
Is it possible for a reaction with + ΔG° to still be spontaneous in the forward direction? Explain.
Answer:
See explanation.
Explanation:
Hello!
In this case, according to the thermodynamic definition of the Gibbs free energy:
[tex]\Delta G=\Delta H-T\Delta S[/tex]
In the scenario by which G>0 (nonspontaneous) it would be possible for reaction to have a G<0 (spontaneous) if:
- If H>0 and S>0, then the temperature should be increased until the process was entropy-driven for it to be possible.
- If H> and S<0, then it'd be impossible to have an spontaneous process.
- If H<0 and S>0 then the process was not spontaneous.
- If H<0 and S<0 it is possible if the temperature is not high enough to ensure the process is enthalpy-driven.
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Hydrogen peroxide with a concentration of 3.0 percent (3.0 g of H2O2 in 100 mL of solution) is sold in drugstores for use as an antiseptic. For a 10.0-mL 3.0 percent H2O2 solution, calculate (a) the oxygen gas produced (in liters) at STP when the compound undergoes complete decomposition and (b) the ratio of the volume of O2 collected to the initial volume of the H2O2 solution.
Answer:
a) 0.099 L
b) 9.9
Explanation:
Now, given the equation for the decomposition of H2O2;
2H2O2(l) ------> 2H2O(l) + O2(g)
Mass of H2O2;
percent w/v concentration = mass/volume * 100
volume = 10.0-mL
percent w/v concentration = 3.0 percent
mass of H2O2 = x
3 = x/ 10 * 100
30 = 100x
x = 30/100
x = 0.3 g of H2O2
Number of moles in 0.3 g of H2O2 = mass/ molar mass
Molar mass of H2O2 = 34.0147 g/mol
Number of moles in 0.3 g of H2O2 = 0.3g/34.0147 g/mol
= 0.0088 moles
From the reaction equation;
2 moles of H2O2 yields 1 mole of oxygen
0.0088 moles of H2O2 = 0.0088 * 1/2 = 0.0044 moles of oxygen
If 1 mole of oxygen occupies 22.4 L
0.0044 moles of oxygen occupies 0.0044 * 22.4/1
= 0.099 L
b) initial volume of the H2O2 solution = 10 * 10-3 L
Hence, ratio of the volume of O2 collected to the initial volume of the H2O2 solution = 0.099 L/10 * 10-3 L = 9.9
21 POINTS TO WHO EVER CAN ANSWER THIS
Explain why water is considered the "universal solvent".
Answer:
Explanation:
Water is capable of dissolving a variety of different substances, which is why it is such a good solvent. And, water is called the "universal solvent" because it dissolves more substances than any other liquid. This allows the water molecule to become attracted to many other different types of molecules.
Set of degenerate orbital in germanium
Answer:
Which set of orbitals are degenerate?
Degenerate is used in quantum mechanics to mean 'of equal energy. ' It usually refers to electron energy levels or sublevels. For example, orbitals in the 2p sublevel are degenerate - in other words the 2px, 2py, and 2pz orbitals are equal in energy, as shown in the diagram.
Explanation:
Answer:
Electron orbitals having the same energy levels are called degenerate orbitals, For example, orbitals in the 2p sublevel are degenerate - in other words the 2px, 2py, and 2pz orbitals are equal in energy.
Polar bears are well adapted to the Arctic environment due to their white
fur coats. Which statement BEST explains why white coat color was
possibly favored by natural selection over other coat colors?
answer: white fur works as a camouflage against the white snow, allowing polar bears an advantage when hunting for food and hiding from predators
Which one is not an ore of copper
1 Azurite
2 Malachite
3 Haematite
4 Chalcopyrite
Hydrochloric acid reacts with sodium hydroxide to form water and sodium chloride. Hydrochloric acid is an extremely acidic, clear, corrosive liquid. Sodium hydroxide is a very basic white solid.
What can be known about the reactants of this reaction?
They will be clear.
They will not have the properties of sodium hydroxide or hydrochloric acid.
They will be corrosive.
They will have the properties of sodium hydroxide or hydrochloric acid.
The answer is C.
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A sealed 1.0L flask is filled with 0.500 mols of I_2 and 0.500 mols of Br_2. When the container achieves equilibrium the equilibrium constant is 1.10x10^{-2}. What is the equilibrium concentration of the product, IBr?
Answer:
[IBr] = 0.049 M.
Explanation:
Hello there!
In this case, according to the balanced chemical reaction:
[tex]I_2+Br_2\rightarrow 2IBr[/tex]
It is possible to set up the following equilibrium expression:
[tex]K=\frac{[IBr]^2}{[I_2][Br_2]} =0.0110[/tex]
Whereas the the initial concentrations of both iodine and bromine are 0.50 M; and in terms of [tex]x[/tex] (reaction extent) would be:
[tex]0.0110=\frac{(2x)^2}{(0.50-x)^2}[/tex]
Which can be solved for [tex]x[/tex] to obtain two possible results:
[tex]x_1=-0.0277M\\\\x_2=0.0245M[/tex]
Whereas the correct result is 0.0245 M since negative results does not make any sense. Thus, the concentration of the product turns out:
[tex][IBr]=2x=2*0.0249M=0.049M[/tex]
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Which answer would represent 0.001 moles?
Answer:
Which answer would represent 0.001 moles?
How does air flow when a low-pressure center occurs in the
atmosphere?
Answer:
A
Explanation:
It is so because the low air pressure create vacuum and the air from high pressure area move toward the low air pressure.