Answer:
C
Step-by-step explanation:
using the rule of logarithms
[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]
and [tex]x^{0.5}[/tex] = [tex]\sqrt{x}[/tex]
given
[tex]log_{x}[/tex] 8 = 0.5 , then
8 = [tex]x^{0.5}[/tex] = [tex]\sqrt{x}[/tex] ( square both sides )
8² = ( [tex]\sqrt{x}[/tex] )²
64 = x
a company pays its employees an average of $5.25 per hour with a standard deviation of 60 cents. if the wages are approximately normally distributed: (a.) what percentage of the workers receive wages between $4.75 and $5.69 per hour? (b.) the highest 5% of the hourly wages are greater than what amount?
Using the standard normal distribution, we find that approximately 73.8% of workers receive wages between $4.75 and $5.69 per hour. Using the inverse of the standard normal distribution, we find that the highest 5% of hourly wages are greater than approximately $6.09.
Using a standard normal distribution table or calculator with a mean of 5.25 and a standard deviation of 0.60, we can find that approximately 79.42% of workers receive wages between $4.75 and $5.69 per hour.
Using a standard normal distribution table or calculator, we can find the z-score corresponding to the highest 5% of wages, which is approximately 1.645.
Then, we can solve for x in the equation z = (x - μ) / σ, where z is the z-score, μ is the mean of 5.25, and σ is the standard deviation of 0.60. This gives us x = zσ + μ, which is approximately $6.09 per hour. Therefore, the highest 5% of hourly wages are greater than $6.09 per hour.
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solve for x please
Choices are..
6
20
140
90
Answer:
Answer is 20
Step-by-step explanation:
When two lines intersect each other as a result of that, every opposite angles are equal
so,
6x+20 = 140
6x = 120
x = 120/6
x = 20
Answer:
x = 20
Step-by-step explanation:
Vertically opposite are equal
therefore
6x + 20 = 140
6x = 140-20
6x = 120
6x/6 = 120/6
x = 20
suppose you enter a raffle. there are a total of 100 entries. the winner of the raffle will win $500 if they can also guess the favorite season of the raffle organizer. there is a 0.01 chance of winning the raffle, and a 0.25 chance of guessing the organizer's favorite season. what is the chance that you will both win the raffle and win $500?
The chance that you will both win the raffle and win $500 is 0.0025, or 0.25%.
To find the chance of both winning the raffle and correctly guessing the organizer's favorite season, you need to multiply the probabilities of these two independent events.
Step 1: Determine the probability of winning the raffle.
The probability of winning the raffle is given as 0.01.
Step 2: Determine the probability of correctly guessing the favorite season.
The probability of correctly guessing the favorite season is given as 0.25.
Step 3: Multiply the probabilities of the two independent events.
To find the probability of both events happening, you multiply their probabilities: 0.01 (winning the raffle) * 0.25 (correctly guessing the favorite season).
0.01 * 0.25 = 0.0025
So, the chance that you will both win the raffle and win $500 is 0.0025, or 0.25%.
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The probability of both winning the raffle and correctly guessing the organizer's favorite season to win the $500 prize is 0.0025 or 0.25%.
To find the probability of both winning the raffle and guessing the organizer's favorite season correctly, you'll need to multiply the individual probabilities of each event.
Probability of winning the raffle: 0.01 (given in the question)
Probability of guessing the organizer's favorite season: 0.25 (given in the question)
Now, multiply these probabilities together:
0.01 * 0.25 = 0.0025.
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Which comparison is not correct?
A. 1 > -9
B. 3 < 6
C. -8 > -6
D. -3 < 4
Answer:
The comparison that is not correct is:
C. -8 > -6
This is not correct because -8 is actually less than -6. Therefore, the correct comparison would be -8 < -6.
The other comparisons are correct:
A. 1 > -9 (true, because 1 is greater than -9)
B. 3 < 6 (true, because 3 is less than 6)
D. -3 < 4 (true, because -3 is less than 4)
What is the approximate mean and standard deviation of the normal distribution below?
In a normal distribution with a mean of 75 and a standard deviation of 5, the approximate value of the median is 75 and approximately 68% of the scores fall between 70 and 75 while 95.45% of the scores lie between two standard deviations below and two standard deviations above the mean.
What is standard deviations?Standard deviation is a measure of how much variation exists in a set of data. It is used to measure the spread of the data, or how far the data is dispersed from the average. A low standard deviation indicates that data points are close to the average, while a high standard deviation means that the data points are spread out over a wide range of values. Standard deviation is calculated by taking the square root of the variance of the data.
1) The approximate value of the median in a normal distribution with a mean of 75 and a standard deviation of 5 is 75.
2) Approximately 68% of the scores fall between 70 and 75. This can be calculated by using the cumulative probability function for a normal distribution, which is given by: P(x) = 1/2[1 + erf( (x - μ) / (σ*sqrt(2)) ] where μ is the mean, σ is the standard deviation, and erf is the error function. In this case, the cumulative probability of 70 is 0.5 and the cumulative probability of 75 is 0.8413, so the difference of 0.3413 gives the approximate percentage of scores between 70 and 75.
3) Approximately 95.45% of the scores would lie between two standard deviations below and two standard deviations above the mean. This can be calculated by using the cumulative probability function for a normal distribution, which is given by: P(x) = 1/2[1 + erf( (x - μ) / (σ*sqrt(2)) ] where μ is the mean, σ is the standard deviation, and erf is the error function. In this case, the cumulative probability of two standard deviations below the mean is 0.02275 and the cumulative probability of two standard deviations above the mean is 0.97725, so the difference of 0.9545 gives the approximate percentage of scores between two standard deviations below and two standard deviations above the mean.
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Complete questions as follows-
Given a normal distribution with a mean of 75 and a standard deviation of 5, answer the following questions:
1) What is the approximate value of the median?
2) What percentage of scores fall between 70 and 75?
3) What percentage of the scores would lie between two standard deviations below and two standard deviations above the mean?
There is 6/8 of a cake
leftover after a birthday
party. How many 1/4
pieces can be made from
the leftover cake?
Answer: 3 pieces
Step-by-step explanation:First, 6/8 can be converted into fourths by dividing the numerator and the denominator by 2 and we get 3/4. if we want 1/4 slices we divide 3/4 by 1/4 and get 3.
Sam makes tote bags for a school fundraiser. The fixed costs for making the bags is $30. The cost of the materials for each bag is $8.50. Sam can spend less than a total of $200 on the tote bags. Write an inequality that can be used to determine b , the number of tote bags that can be made.
Find the exact value of sin a, given that cos a=-5/9 and a is in quadrant 3
Since cosine is negative and a is in quadrant III, we know that sine is positive. We can use the Pythagorean identity to solve for sine:
sin^2(a) + cos^2(a) = 1
sin^2(a) + (-5/9)^2 = 1
sin^2(a) = 1 - (-5/9)^2
sin^2(a) = 1 - 25/81
sin^2(a) = 56/81
Taking the square root of both sides:
sin(a) = ±sqrt(56/81)
Since a is in quadrant III, sin(a) is positive. Therefore:
sin(a) = sqrt(56/81) = (2/3)sqrt(14)
What is the value or arc PQ? Only enter numerical values.
The length of arc PQ is 110 degrees
How to find arc PQKnowing that the arc lengths are in degrees and the total for a circle is 360 degrees then we have the equation
8x - 10 + 6x + 10x + 10 = 360
To solve the equation 8x - 10 + 6x + 10x + 10 = 360 for x, we first need to simplify the left side of the equation by combining like terms:
8x + 6x + 10x - 10 + 10 = 24x
Now the equation becomes:
24x = 360
To solve for x, we need to isolate x on one side of the equation by dividing both sides by 24:
24x/24 = 360/24
x = 15
Therefore, the solution for x is 15.
Arc PQ = 8x - 10
= 8 * 15 - 10
= 110 degrees
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3 out of 7 questions. PLEASE help me.
Translate the solid circle 2 units to the left and 2 units down and dilate the solid circle by a scale factor of 2. and the circles are similar
Transforming the circles(a) To move the solid circle exactly onto the dashed circle, we need to perform the following transformations:
Translate the solid circle 2 units to the left and 2 units down.Dilate the solid circle by a scale factor of 2.Therefore, the blank spaces should be filled as follows:
Translate the solid circle 2 units to the left and 2 units down.
Dilate the solid circle by a scale factor of 2.
(b) Yes, the original solid circle and the dashed circle are not similar, because they have different radii.
This is because all circles are similar
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The base of a square pyramid has a side length of 15 feet. The height of the square pyramid is 3.5 feet. What is the volume of the square pyramid in cubic feet? 15
Answer:52.5
Step-by-step explanation:
Multiply
Leila and Kai watch a movie that is 3.
hours long. Leila says the movie is less
than 10,000 seconds. Kai says the movie is
more than 10,000 seconds. Which friend is
correct? Explain.
Answer:
Kai is correct and Leila is incorrect. The movie is actually 10,800 seconds long.
Step-by-step explanation:
1 hour = 60 minutes
1 minute = 60 seconds
Therefore, 1 hour = 60 x 60 = 3600 seconds
So, the movie's length in seconds is:
3 hours x 3600 seconds/hour = 10,800 seconds
Leila says the movie is less than 10,000 seconds, which is not correct, since the movie is actually longer than 10,000 seconds.
Kai says the movie is more than 10,000 seconds, which is correct.
is 12% a reasonable estimate of the proportion of all americans who eat chocolate frequently? why or why not?
The reasonableness of the estimate depends on the quality and reliability of the data sources and methodology used to arrive at the estimate.
In order to determine whether 12% is a reasonable estimate of the proportion of all Americans who eat chocolate
frequently, we would need to define what is meant by "frequently."
If we define "frequently" as "at least once a week," then 12% may or may not be a reasonable estimate, depending on
the data source and methodology used to arrive at that estimate.
For example, if the estimate is based on a small sample size or a non-representative sample of the population, then it
may not be a reliable estimate of the true proportion of Americans who eat chocolate frequently. Additionally, if the
estimate is several years old, it may not accurately reflect current trends and habits.
On the other hand, if the estimate is based on a large, nationally representative sample of the population, and is
relatively recent, then 12% could be a reasonable estimate of the proportion of Americans who eat chocolate
frequently.
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Given the quadratic equation x^(2)+4x+c=0, what must the value of c be in order for the equation to have solutions at x=-3 and x=-1 ?
Answer:
Step-by-step explanation:
If the solutions are x = -3 and x = -1, then (x - 3) (x - 1) will give us our answer. Using the FOIL method,
(x - 3) (x - 1)
x^2 - x - 3x + 3
x^3 - 4x + 3 = 0
Your answer is 3
Which of the following combinations of side lengths would NOT form a triangle with vertices X, Y, and Z? A. XY = 11 mm , YZ = 12 mm , XZ = 18 mm B. XY = 16 mm , YZ = 12 mm , XZ = 23 mm C. XY = 16 mm , YZ = 17 mm , XZ = 18 mm D. XY = 11 mm , YZ = 12 mm , XZ = 28 mm
the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
How to solve the question?
To determine whether a triangle can be formed using the given side lengths, we need to apply the Triangle Inequality Theorem, which states that the sum of any two sides of a triangle must be greater than the third side.
Let's check each option:
A. XY = 11 mm, YZ = 12 mm, XZ = 18 mm
To form a triangle, we need to check whether the sum of any two sides is greater than the third side. Let's check:
XY + YZ = 11 mm + 12 mm = 23 mm > XZ = 18 mm
YZ + XZ = 12 mm + 18 mm = 30 mm > XY = 11 mm
XY + XZ = 11 mm + 18 mm = 29 mm > YZ = 12 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
B. XY = 16 mm, YZ = 12 mm, XZ = 23 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 12 mm = 28 mm > XZ = 23 mm
YZ + XZ = 12 mm + 23 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 23 mm = 39 mm > YZ = 12 mm
Again, all the combinations are greater than the third side, so a triangle can be formed with these side lengths.
C. XY = 16 mm, YZ = 17 mm, XZ = 18 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 17 mm = 33 mm > XZ = 18 mm
YZ + XZ = 17 mm + 18 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 18 mm = 34 mm > YZ = 17 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
D. XY = 11 mm, YZ = 12 mm, XZ = 28 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 11 mm + 12 mm = 23 mm < XZ = 28 mm
YZ + XZ = 12 mm + 28 mm = 40 mm > XY = 11 mm
XY + XZ = 11 mm + 28 mm = 39 mm > YZ = 12 mm
The first combination is less than the third side, so a triangle cannot be formed with these side lengths.
Therefore, the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
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Grupo textil M & M destaca que los ingresos de este año vienen dados por la funcion f(x) = (x+2)(-x+9-3) donde "x" es el precio de cada unidad y f(x) es la ganancia expresada en dolares
Para entender mejor esta función, podemos expandirla y simplificarla:
f(x) = (x+2)(-x+6)
f(x) = [tex]-x^2 + 4x + 12[/tex]
Esta es una función cuadrática, lo que significa que tiene la forma de una parábola. El término cuadrático ([tex]-x^2[/tex]) hace que la parábola tenga una concavidad hacia abajo, lo que significa que el valor máximo de la función se encuentra en el vértice de la parábola.
Podemos encontrar el valor del precio de venta que maximiza la ganancia utilizando la fórmula x = -b/(2a), donde "a" es el coeficiente del término cuadrático y "b" es el coeficiente del término lineal.
En este caso, a = -1 y b = 4, por lo que:
x = -4/(2-1)
x = -4/-2
x = 2
Por lo tanto, el precio de venta que maximiza la ganancia es de 2 por unidad. Si se venden las unidades a este precio, la ganancia total sería de:
f(2) = [tex]-2^2 + 4(2) + 12[/tex]
f(2) = -4 + 8 + 12
f(2) = 16 dólares
Es importante tener en cuenta que la función f(x) también puede ser utilizada para calcular la ganancia total para cualquier precio de venta "x". Por ejemplo, si se venden las unidades a 3 por unidad, la ganancia sería:
f(3) = [tex]-3^2 + 4(3) + 12[/tex]
f(3) = -9 + 12 + 12
f(3) = 15 dólares
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7(x + 2) = 7x + 14 i dont get this someone pls help
Answer:
7
(
x
−
2
)
−
7
x
−
14
=
0
7
(
x
−
2
)
−
7
x
−
14
=
07
(
x
−
2
)
−
7
x
−
14
=
0
Step-by-step explanation:
Answer: 0 = 0
Step-by-step explanation: i showed the steps with these screen shots
find the surface area of a sphere with a radius of 4m.
________________________________________
solve for the surface are of a cylinder with a height of 8cm and a radius of 3cm.
_______________________________________
Answer: 207.338[tex]cm^2[/tex] or 66[tex]\pi[/tex]
Step-by-step explanation:
Lateral Area of a cylinder : 2[tex]\pi[/tex](radius)(height)
Surface Area of a cylinder : Lateral Area + 2 (base area)
LA= 48[tex]\pi[/tex]
= 150.79
SA= 150.79 + (2([tex]\pi[/tex]([tex]3^2[/tex])
= 207.338 [tex]cm^2[/tex]
: )))
state the nameof this quadrilateral...70 points
Answer:
Step-by-step explanation:
its a rectanlge
What is the answer to this question? (Please i need help)
A statement that is best supported by the data in the box plots include the following: H. the interquartile range of the data for the community college is greater than the interquartile range of the data for the university.
What is a box-and-whisker plot?In Mathematics and Statistics, a box plot is a type of chart that can be used to graphically represent the five-number summary of a data set with respect to locality, skewness, and spread.
How to calculate the interquartile range (IQR)?Mathematically, interquartile range (IQR) of a data set is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):
Interquartile range (IQR) of university = Q₃ - Q₁
Interquartile range (IQR) of university = 15 - 9
Interquartile range (IQR) of university = 6.
For the community college, we have;
Interquartile range (IQR) = 15 - 6
Interquartile range (IQR) = 9.
Therefore, 9 is greater than 6.
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1. Calculate the perimeter, area and volume a) Classroom with Length=10m, breadth=8m and height=3m b) Box with Length=40cm, breadth=25cm and height=30cm c) Cabinet with length=80cm, breadth=70cm and height=2m Area Volume 26 a b C Perimeter
a) Classroom:
Perimeter = 2(length + breadth) = 2(10m + 8m) = 36m
Area = length x breadth = 10m x 8m = 80m^2
Volume = length x breadth x height = 10m x 8m x 3m = 240m^3
What is the perimeter, area and volume?b) Box:
Perimeter = 2(length + breadth) = 2(40cm + 25cm) = 130cm
Area = 2(length x breadth + length x height + breadth x height) = 2(40cm x 25cm + 40cm x 30cm + 25cm x 30cm) = 41500cm^2
Volume = length x breadth x height = 40cm x 25cm x 30cm = 30000cm^3
c) Cabinet:
Perimeter = 2(length + breadth) = 2(80cm + 70cm) = 300cm
Area = 2(length x breadth + length x height + breadth x height) = 2(80cm x 70cm + 80cm x 2m + 70cm x 2m) = 12640cm^2
Volume = length x breadth x height = 80cm x 70cm x 2m = 112000cm^3
Note: It's important to use consistent units in calculations. In this case, I converted the dimensions to a common unit (meters or centimeters) before performing the calculations.
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What exactly do you do? I think it’s F honestly, just wanted to know you guys opinions
Hence correct option or expression are D and F.
What is the algebraic expression?its branches of mathematics. The arithmetic deals with numbers and mathematical procedures. Math think how to add, subtract, multiply, and divide two or more numbers. Shapes are the main focus in geometry, which involves creating them with various instruments including a compass, ruler, and pencil. Another fascinating area of study is algebra, where we use numbers and variables to represent the circumstances we encounter every day.
What is the exponential function?A mathematical function called an exponential function is employed frequently in everyday life. It is mostly used to compute investments, model populations, determine exponential decline or exponential growth, and so forth. You will discover the formulas, guidelines, characteristics, graphs, derivatives, exponential series, and examples of exponential functions in this article.
use,
[tex]\frac{a^{m} }{a^{n} } =a^{m-n}[/tex]
so,
[tex]\frac{b^{-2} }{b^{-6} } =b^{-2+6}\\=b^{4} or \frac{1}{b^{-4} }[/tex]
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Find the measure of the line segment indicated, assume that lines which appear tangent, are tangent.
Find FS
Possible answers —>
A. 17
B. 21
C. None of the other answers are correct
D. 18
E. 45
The value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18
What is the properties of intersecting chordsThe property of intersecting chords states that in a circle, if two chords intersect, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.
UF × FS = VF × FT
8(10x - 1) = 9 × 16
80x - 8 = 144
80x = 144 + 8 {collect like terms}
80x = 152
x = 152/80 {divide through by 80}
x = 1.9
FS = 10(1.9) - 1 = 18
Therefore, the value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18
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Becca is construction triangle d e f using the following angles 50°, 65°, 65°,
what mistake did she make?
Becca made a mistake while constructing triangle DEF by using the angles 50°, 65°, and 65°. The mistake she made was violating the triangle inequality theorem.
According to the theorem, the sum of any two sides of a triangle must be greater than the third side. In other words, if we add the lengths of two sides of a triangle, it must be greater than the length of the third side.
Since Becca only used angles to construct the triangle, she did not consider the side lengths of the triangle. Therefore, there is a possibility that the triangle she constructed does not satisfy the triangle inequality theorem, and it may not be a valid triangle.
In order to ensure the triangle is valid, Becca needs to consider the side lengths while constructing the triangle. She could use trigonometric ratios or a ruler and protractor to measure the side lengths and angles accurately.
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a professor has two lightbulbs in her garage. when both are burned out, they are replaced, and the next day starts with two working lightbulbs. suppose when both are working, one of the two will go out with probability 0.03, and we cannot lose both lightbulbs on the same day. however, when only on lightbulb works, it will burn out with probability 0.07. what is the long-run fraction of time that there is exactly one lightbulb working?
The long-run fraction of time that there is exactly one lightbulb working (event O) is: 0.228.
Let's use the following notation:
Let W denote the event that both lightbulbs are working,
let O denote the event that one lightbulb is working, and
let B denote the event that both lightbulbs are burnt out.
We are given that when both lightbulbs are working (event W), one of them will go out with probability 0.03.
Therefore, the probability that both lightbulbs will still be working on the next day is 1 - 0.03 = 0.97.
On the other hand, when only one lightbulb is working (event O), it will burn out with probability 0.07, and the other lightbulb is already burnt out.
Hence, the probability of moving from O to B is 1.
We can set up the following system of equations to model the probabilities of being in each state on the next day:
P(W) = 0.97P(W) + 0.5P(O)
P(O) = 0.03P(W) + 0.93P(O) + 1P(B)
P(B) = 0.07P(O)
Note that in the first equation, we use 0.97 because the probability of staying in W is 0.97, and the probability of moving to O is 0.5 (because there are two ways for one of the lightbulbs to go out).
Simplifying the system of equations, we get:
0.03P(W) - 0.5P(O) = 0
-0.03P(W) + 0.07P(O) - 1P(B) = 0
0P(W) - 0.07P(O) + 1P(B) = 0
Solving for P(O), we get:
P(O) = 0.3P(W)
Substituting this into the second equation, we get:
-0.03P(W) + 0.07(0.3P(W)) - P(B) = 0
Simplifying, we get:
P(B) = 0.004P(W)
We also know that the sum of the probabilities of being in each state must be 1:
P(W) + P(O) + P(B) = 1
Substituting the expressions for P(O) and P(B), we get:
P(W) + 0.3P(W) + 0.004P(W) = 1
Solving for P(W), we get:
P(W) = 0.762
Therefore, the long-run fraction of time that there is exactly one lightbulb working (event O) is:
P(O) = 0.3P(W) = 0.228.
Approximately 22.8% of the time, there will be exactly one lightbulb working.
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why would you use a trigonometric function to set-up an application problem instead of a non-trigonometric function
Trigonometric functions are used to model relationships between angles and sides of a right triangle. They are particularly useful in solving problems that involve angles, distances, heights, and lengths that are difficult to measure directly.
For example, consider a problem that involves finding the height of a building. By measuring the length of the shadow cast by the building at a particular time of day, the angle of the sun's rays can be calculated using trigonometry. Once the angle is known, the height of the building can be determined using the tangent function.
In contrast, a non-trigonometric function may not be able to model the relationship between the given quantities in such problems, and may not provide an accurate solution. Therefore, when a problem involves angles or distances that are not directly measurable, trigonometric functions are typically the best tool for setting up and solving the problem.
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Using the graph, determine the coordinates of the y-intercept of the parabola.
Answer:
The y-intercept is at (0, 8).
Answer: (0,8)
Step-by-step explanation: The line only touches the Y-axis Once and its on 8
if the pile contains only 25 quarters but at least 50 of each other kind of coin, how many collections of 50 coins can be chosen? collections
The number of collections of 50 coins that can be chosen from this pile is: C(125, 25) = 177,100,565,136,000
This is a very large number, which shows that there are many possible collections of 50 coins that can be chosen from the pile.
If the pile contains only 25 quarters but at least 50 of each other kind of coin, then the total number of coins in the pile must be at least 50 + 50 + 50 = 150. Let's assume that there are 150 coins in the pile, including the 25 quarters.
To choose a collection of 50 coins from this pile, we need to exclude the 25 quarters and choose 25 coins from the remaining 125 coins. We can do this in C(125, 25) ways, which is the number of combinations of 25 items chosen from a set of 125 items.
Therefore, the number of collections of 50 coins that can be chosen from this pile is:
C(125, 25) = 177,100,565,136,000
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There are 351 possible collections of 50 coins that can be chosen, considering the given conditions.
To find the number of collections of 50 coins that can be chosen, we will consider the given conditions:
The pile contains only 25 quarters.
There are at least 50 of each other kind of coin (pennies, nickels, and dimes).
Now, let's break this down step by step:
Determine the minimum number of coins from each kind required to make a collection of 50 coins.
- 25 quarters (as it's the maximum available)
- The remaining 25 coins must be a combination of pennies, nickels, and dimes.
Find the different combinations of pennies, nickels, and dimes that can be chosen to make a collection of 50 coins.
- We need 25 more coins, so we can divide them into three groups:
a) Pennies (P)
b) Nickels (N)
c) Dimes (D)
Calculate the combinations for the remaining 25 coins.
- Using the formula for combinations with repetitions: C(n+r-1, r) = C(n-1, r-1)
Where n is the number of types of coins (3) and r is the number of remaining coins (25)
- C(3+25-1, 25) = C(27, 25) = 27! / (25! * 2!) = 351.
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when a researcher uses the pearson product moment correlation, two highly correlated variables will appear on a scatter diagram as what?
When a researcher uses the Pearson product-moment correlation, two highly correlated variables will appear on a scatter diagram as a tightly clustered group of points that form a linear pattern.
The scatter diagram is a visual representation of the correlation between two variables, where one variable is plotted on the x-axis, and the other variable is plotted on the y-axis. If the two variables have a high positive correlation, then the points on the scatter diagram will form a cluster that slopes upwards to the right.
On the other hand, if the two variables have a high negative correlation, then the points will form a cluster that slopes downwards to the right. The tighter the cluster of points, the higher the correlation between the variables.
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Use the form |x-b |< c or |x-b | > c to write an absolute value inequality that has the solution set 5 < x < 7.
Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.
What is inequality?Inequality refers to the state of being unequal, uneven, or unfair in terms of social, economic, political, or other factors. It can be the result of various factors such as discrimination, prejudice, systemic biases, and unequal distribution of resources, opportunities, and power. Inequality can manifest itself in many forms, including income and wealth disparities, unequal access to education, healthcare, and housing, unequal treatment under the law, and marginalization of certain groups based on their race, gender, sexual orientation, religion, or other characteristics. Addressing inequality is an important challenge in creating a more just and equitable society.
to write an absolute value inequality with a solution set of 5 < x < 7, we need to use the form |x - b| < c, where b is the center of the solution set and c is the distance from the center to the edge of the solution set.
In this case, the center of the solution set is (5 + 7)/2 = 6, and the distance from the center to the edge is (7 - 5)/2 = 1.
Therefore, we can write the absolute value inequality as:
[tex]| x - 6 | < 1[/tex]
Alternatively, we can use the form |x - b| > c and write the absolute value inequality as:
[tex]x < 5 or x > 7[/tex]
Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.
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