Question 4
2 pts
669.0 mL of oxygen are collected over water at 17.0 °C and a total
pressure of 785.0 mm of mercury. What is the volume (in mL) of dry
oxygen at 60.0 °C and 847.0 mmHg pressure?
Question 5
2 pts
Answer:
711.96 mL
Explanation:
Using the combined gas law equation;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (mmHg)
P2 = final pressure (mmHg)
V1 = initial volume (mL)
V2 = final volume (mL)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
P1 = 785.0 mmHg
P2 = 847.0 mmHg
V1 = 669.0 mL
V2 = ?
T1 = 17.0 °C = 17 + 273 = 290K
T2 = 60.0 °C = 60 + 273 = 333K
Using P1V1/T1 = P2V2/T2
785 × 669/290 = 847 × V2/333
525165/290 = 847 V2/333
1810.91 = 2.54 V2
V2 = 1810.91 ÷ 2.54
V2 = 711.96 mL
Scientists recently discovered that firing low-energy particles at potatoes keeps the potatoes
from developing unwanted sprouts. They observed that these energy particles prevent cell
division in the sprouts. This stops the potatoes from sprouting for up to 120 days. How will this
development most likely affect the potato industry?
Answer:
By allowing the potatoes to be stored longer so they can be sold during winter months.
Explanation:
Since low energy particles are fired at the potatoes to prevent them from developing unwanted sprouts, it means that it prevents sprouts from growing on the potatoes.
Now, winter is wet period which encourages more growth of the sprouts. Thus, the way this development will affect the industry is that the potatoes will be stored for longer period and then sold in the winter.
Increasing which factor will not increase the rate of a chemical reaction?
A: concentration of reactants
B: heat
C: product
D: surface area
Answer:
c. product
i had the test
When sodium chloride is dissolved in water, the freezing point of water _________. A. increases B. first increases, then decreases C. does not change D. decreases
The presence of a non-volatile salt will decrease the freezing point of water and this process is called depression in freezing point. Thus option D is correct.
What is freezing point?Freezing point of a substance is the temperature at which it converts from its liquid state to solid state where, both the states are in equilibrium. Freezing point of water is zero degree celsius.
The freezing point of a solvent depends on some parameters such as the bond type, molecular weight, temperature, pressure etc.
When a non-volatile solute is added to the solvent its freezing point decreases from its initial value. Because presence of non-volatile salts will affect the intermolecular attraction and thereby the energy that must be applied to freeze the compound.
Therefore, the freezing point of water decreases, when sodium chloride is added into it. Thus option D is correct.
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The addition of dimethylglycoxime, H2C4H6O2N2, to a solution containing nickel(II) ion gives rise to a precipitate: Ni2 2H2C4H6O2N2 Ni(H2C4H6O2N2)2 2H If 0.15 g nickel alloy is treated with dimethylglycoxime and .175 mg nickel dimethylglycoxime is collected. Determine the mass and percent of nickel in the alloy.
Solution :
The balanced equation is :
[tex]$Ni^{2+}+2H_2C_4H_6O_2N_2 \rightarrow Ni(H_2C_4H_6O_2N_2)_2+2H^+$[/tex]
Molar mass 56.7 116 290.7
From the balanced equation,
2 mole
= 2 x 116 g of [tex]$H_2C_4H_6O_2N_2$[/tex] produces 1 mole = 290.7 g of nickel dimethylglycoxime
or 2 x 116 mg of [tex]$H_2C_4H_6O_2N_2$[/tex] produces 1 mole = 290.7 g of nickel dimethylglycoxime
0.175 mg of [tex]$H_2C_4H_6O_2N_2$[/tex] produces [tex]$\frac{0.175 \times 290.7}{2 \times 116}$[/tex] = 0.219 mg of nickel dimethylglycoxime
290.7 g of [tex]$Ni(H_2C_4H_6O_2N_2)_2$[/tex] contains 58.7 mg of Ni
0.219 mg of [tex]$Ni(H_2C_4H_6O_2N_2)_2$[/tex] contains [tex]$\frac{0.219 \times 58.7}{290.7} = 0.0443$[/tex] mg of Ni
So mass of nickel, m = 0.0443 mg = [tex]$0.0443 \times 10^{-3}$[/tex] g
Percent of Nickel in the alloy = [tex]$\frac{\text{mass of nickel}}{\text{mass of alloy}} \times 100$[/tex]
[tex]$=\frac{0.0443 \times 10^{-3}}{0.159}\times 100$[/tex]
= 0.03%
The Properties of Liquids
Answer:
Properties of Liquids
Capillary Action. ...
Cohesive and Adhesive Forces. ...
Contact Angles. ...
Surface Tension. ...
Unusual Properties of Water. ...
Vapor Pressure. ...
Viscosity Viscosity is another type of bulk property defined as a liquid's resistance to flow. ...
Wetting Agents
2x²=8.pls help me i really need it
Explanation:
2x²=8
x²=8/2
x=√4
x=2
hope it helps.
Answer:
[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]
[tex] {2x}^{2} = 8 \\ {x}^{2} = \frac{8}{2} \\ {x}^{2} = 4 \\ x = \sqrt{4} \\ x = 2[/tex]
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
[tex] \huge\purple{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}[/tex]
3. At 34.0°C, the pressure inside a nitrogen-filled tennis ball with a volume of 148 cm3 is 212
kPa. How many moles of N2 are in the tennis ball?
Answer:
0.0123 mol
Explanation:
Step 1: Convert 34.0 °C to Kelvin
We will use the following expression.
K = °C + 273.15 = 34.0 + 273.15 = 307.2 K
Step 2: Convert 148 cm³ to L
We will use the conversion factors:
1 cm³ = 1 mL1 L = 1000 mL[tex]148cm^{3} \times \frac{1mL}{1cm^{3}} \times \frac{1L}{1000mL} = 0.148L[/tex]
Step 3: Convert 212 kPa to atm
We will use the conversion factor 1 atm = 101.325 kPa.
212 kPa × 1 atm / 101.325 kPa = 2.09 atm
Step 4: Calculate the moles of nitrogen gas
We will use the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 2.09 atm × 0.148 L / (0.0821 atm.L/mol.K) × 307.2 K = 0.0123 mol
Question 23 (1 point)
Which of these bonds would have greatest ionic character
O-F
P.S
NE
Answer:
P.S
Explanation:
Because sulphur has low electronegative magnitude, hence low polarity potential.
The sulphur atom doesn't not get distorted hence increase in ionic degree character.
The volume of a sample of carbon dioxide gas is 26.42 L at 73.0°C. What will its volume be at 92.0°C at constant pressure?
Answer:
[tex]V_2=27.87L[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the Charles' law a directly proportional relationship to understand the volume-temperature behavior:
[tex]\frac{V_2}{T_2} =\frac{V_1}{T_1}[/tex]
Thus, we solve for the final volume, V2, and make sure the temperature are in Kelvin as shown below:
[tex]V_2 =\frac{V_1T_2}{T_1} \\\\V_2=\frac{26.42L(92+273.15)K}{(73+273.15)K} \\\\V_2=27.87L[/tex]
Regards!
The air we breathe contains different individual gases (mostly nitrogen and oxygen). Which of the following correctly describes the air we breathe? A. mixture B. liquid C. compound D. element
Answer:
A. Mixture
Explanation:
Our air has a group of gases. For example, you said nitrogen & oxygen, Which is significantly a mixture.
Name: ___________________________ Date: __________ Period: ______ Solubility Rules Practice Worksheet Name or give the chemical formula for each of the following compounds. State whether they are soluble (will dissolve) or insoluble (will not dissolve) in solution. Use solubility rules. Chemical Formula Name Solubility NH4OH Ra(OH)2 Nickel (III) Acetate CsOH RbCl Potassium Phosphate MgS CaI2 Gold (II) Hydroxide Li3PO4 Platinum (II) Carbonate Barium Nitrate
What is the pOH of an aqueous solution with a pH of 10.6?
Answer:
pOH=3.4
Explanation:
pH + pOH = 14
So if you have the pH, rearrange the equation:
14-10.6=3.4
Ethanol is a common laboratory solvent and has a density of 0.789 g/mL. What is the mass, in grams, of 131 mL of ethanol?
Answer:
m=103g
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to say that this problem is solved by considering the concept of density, as the degree of compactness of a substance and mathematically defined as the mass divided by the volume (d=m/V). In such a way, for this problem, we solve for the mass as follows:
m=d*V
And we plug in the density and volume to obtain:
m=0.789g/mL*131mL
m=103g
Regards!
Ethanol is a common laboratory solvent and has a density of 0.789 g/ml. 103.359 g is the mass of 131 mL of ethanol.
Mass is a physical property of matter that measures the amount of substance in an object. It is typically measured in grams (g) or kilograms (kg).
To calculate the mass of 131 mL of ethanol, we need to use the density of ethanol.
Density of ethanol = 0.789 g/mL
Mass = Volume x Density
Substituting the given values, we get:
Mass = 131 mL x 0.789 g/ml
= 103.359 g
Therefore, the mass of 131 mL of ethanol is 103.359 g.
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When considering free energy change, biochemists usually define a standard state, the biochemical standard state, which is modified from the chemical standard state to fit biochemical applications. Determine which of the phrases describe the biochemical standard state, the chemical standard state, or both.
a. Temperature is 25C
b. Initial concentration of reactants and products is 1M
Answer:
Chemical standard state
a. Temperature is 25C
b. Initial concentration of reactants and products is 1M
Biochemical standard state
a. Temperature is 25C
b. Initial concentration of reactants and products is 1M
Explanation:
The standard state is the reference state of a material which can be used to calculate its properties under other nonstandard conditions.
The biochemical standard state include;
a. Temperature is 25C
b. Initial concentration of reactants and products is 1M
Similarly, the chemical standard state include;
a. Temperature is 25C
b. Initial concentration of reactants and products is 1M
Hence the answer.
For the following, you will complete an atom count, but you will first need to make the list of atoms. After the count is complete, determine whether the equation is balanced.
N2H4 + N2O4 → 3 N2 + 4 H2O
please help
Answer: The equation [tex]N_{2}H_{4} + N_{2}O_{4} \rightarrow 3N_{2} + 4H_{2}O[/tex] is not a balanced equation.
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]N_{2}H_{4} + N_{2}O_{4} \rightarrow 3N_{2} + 4H_{2}O[/tex]
Here, number of atoms on reactant side are as follows.
N = 4H = 4O = 4Number of atoms on product side are as follows.
N = 6H = 8O = 1Since, the number of atoms present on reactant side are not equal in number as compared to the atoms present on product side. Hence, this equation is not balanced.
Thus, we can conclude that the equation [tex]N_{2}H_{4} + N_{2}O_{4} \rightarrow 3N_{2} + 4H_{2}O[/tex] is not a balanced equation.
n today's experiment, Solutions A and B are prepared as follows. Solution A: Solution B: 2.0 mL of 3.00 x 10-4 M bromcresol green 2.0 mL of 3.00 x 10-4 M bromcresol green 5.0 mL of 1.60 M acetic acid (HAc) 2.0 mL of 0.160 M sodium acetate (NaAc) 2.0 mL of 0.200 M KCl diluted to a total volume of 50 mL diluted to a total volume of 50 mL How many mL of Solution A must be added to Solution B to give a buffer that is equimolar in HAc and Ac-
Answer:
2 mL of Solution A must be added to Solution B to give a buffer that is equimolar.
Explanation:
Given the data in the question;
First we determine the number of sodium acetate;
⇒ molarity × volume ( L )
⇒ 0.16 × 2.0 mL
⇒ 0.16 × 0.002 L
⇒ 0.00032
Now, Molarity of sodium acetate = moles / Volume(L)
⇒ ( 0.00032 / 50 ) × 1000
⇒ 0.0064
Since number of moles of acetic acid that should be added tp make equimolar solution is 0.00032
and Molarity of acetic acid is 0.16 molL⁻¹
Let X represent the volume that should be added.
so;
Molarity = Moles / Volume (L)
we substitute
0.16 = (0.00032 / X) × 1000
0.16 = 32 / X
X = 0.32 / 0.16
X = 2 mL
Therefore, 2 mL of Solution A must be added to Solution B to give a buffer that is equimolar.
Which of these are an important part of a scientific process?
1. Watch how the solubility of a gas changes as pressure is increased and then decreased during the run. Which of the following statements correctly explain the relationship between the solubility of a gas and its pressure?
A. As pressure decreases, the concentration of gas molecules in the solution increases.
B. The concentration of gas particles in the solution is higher at 4.25 atm than at 1.00 atm.
C. The solubility of a gas decreases with a decrease in pressure.
D. The solubility of nitrogen gas at 2.00 atm is twice the solubility of the gas at 1.00 atm.
E. Fewer gas molecules are soluble at higher pressures.
F. More gas molecules are soluble as pressure is increased.
G. As pressure is increased, the rate at which gas molecules enter the solution decreases.
2. At a certain temperature, the solubility of N2 gas in water at 3.08 atm is72.5mg of N2 gas/100 g water. Calculate the solubility of N2 gas in water, at the same temperature, if the partial pressure of N2 gas over the solution is increased from 3.08 atm to 8.00 atm .
Answer:
A. As pressure decreases, the concentration of gas molecules in the solution increases.
D. The solubility of nitrogen gas at 2.00 atm is twice the solubility of the gas at 1.00 atm.
F. More gas molecules are soluble as pressure is increased.
The solubility is 188.3 mg of N2 gas/100 g water.
Explanation:
As the pressure on the gas decreases, the volume of gas molecules in the solution increases due to having distance from each other. The solubility of nitrogen gas at 2.00 atm is twice the solubility of the gas at 1.00 atm because there is more pressure on the gas molecules so due to more compression, the gas becomes more soluble. More gas molecules are soluble as pressure is increased. The solubility is 188.3 mg of N2 gas/100 g water if the atmospheric pressure is increases from 3.08 atm to 8.00 atm. This value is calculated with the help of formula i.e. P2/P1 = S2/S1.
Write in exponential form: 34⋅34⋅34⋅34⋅34⋅34⋅34⋅34.
Answer:
34^8
Explanation:
Which of the following pairs of elements could NOT react to
form an ionic compound? Check all that apply.
Answer:
Carbon and Oxygen cannot react to form an ionic compound because the two elements are non-metals. To form an ionic bond, a metal combines with a non-metal through electrostatic attraction of oppositely charged ions.
Answer:
Explanation:
The two that won't are C and O. They will react, but not ionically. O is on the left of the Periodic table and C is more or less in the middle. They form CO carbon Monoxide and CO2 which is Carbon Dioxide. They are just not ionic.
What Energy transformation occurs when gasoline burns in an automobile
Answer:
The release of energy from fuels is used to make other forms of energy. When gasoline burns in a car engine, some of the chemical energy in the gasoline is converted into heat. The heat is converted into mechanical energy. The mechanical energy moves the car.I hope this helped!
Explanation:
Which of the following is true?
The imaginary one subscript does not have a Greek prefix
The name of C6 H10 F6 is hexacarbide decahydrogen hexafluorine.
The name for the N2 molecule would have no Greek prefixes in it.
To name a covalent molecule you always change the ending on the metal atom.
Answer:
The name for the N2 molecule would have no Greek prefixes in it.
Explanation:
Prefixes and suffixes are used to name compounds that have many component parts.
The molecule N2 is just a simple molecule that consists of only two atoms of nitrogen. It is a diatomic molecule hence there are no Greek prefixes in the name of the molecule.
The molecule is simply identified as nitrogen gas.
What is the limiting reactant when 1.50 g of lithium and 1.50 g of nitrogen combine to form lithium nitride, a
component of advanced batteries, according to the following unbalanced equation?
Li + N2 ⟶ Li3 N
Answer:
Li is limiting reactant
Explanation:
Based on the reaction:
6Li + N2 → 2Li3N
Where 6 moles of Li reacts per mole of N2
To solve this question we must convert the mass of each reactant to moles and using the chemical equation we can find limiting reactant
Moles Li -6.941g/mol-
1.50g * (1mol / 6.941g) = 0.2161 moles Li
Moles N2 -Molar mass:28g/mol-
1.50g * (1mol / 28g) = 0.0536 moles N2
For a complete reaction of 0.536 moles N2 are needed:
0.536 moles N2 * (6mol Li / 1mol N2) = 0.3214 moles Li
As there are just 0.2161 moles of Li
Li is limiting reactantWhich of the following is true about the suns radiation?
40 percent is reflected by the atmosphere
It is long-wave
60 percent reaches the earths surface
It is short-wave
None of the rays are harmful
How do scientists design a system?
O A. They use a system that has already been designed.
O B. They ignore influences from sources outside of the experiment.
C. They include all possible influences in their model.
D. They isolate their experiment from unwanted influences.
Answer: D
Explanation:
The scientists design a system by isolate their experiment from unwanted influences. Therefore, option D is correct.
What is system ?Chemistry's field of systems chemistry strives to understand intricate webs of interdependent molecules and their system-level characteristics. These characteristics cannot be attributed to the individual components working independently, but rather to the aggregate behavior of the system's components.
A system is a well-organized group of components that work closely together to achieve a single objective. The system receives a variety of inputs, processes those inputs through certain steps to produce specific outputs, and then combines those outputs to achieve its overall objective.
The two main categories are natural systems and designed systems. Subatomic systems, various types of biological systems, our planet, the solar system, the galactic system, and the universe are all examples of natural systems.
Thus, option D is correct.
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The chemical reaction between water and magnesium is?
Answer: hydrogen gas
Explanation: When magnesium interacts with water, it will form a hydrogen gas that ignites violently due to the excessive heat and oxygen supply.
21. A piece of metal with a a mass of 15.2 g is heated from 17°C to 42°C. In the process it absorbs 1362 J of
energy as heat. What is the specific heat of the metal?
TO
Answer:
3.58J/g°C is the specific heat of the metal
Explanation:
The specific heat of a material is defined as the energy that 1g of the material absorbs and produce the increasing in temperature in 1°C. The equation is:
Q = S*ΔT*m
Where Q is energy = 1362J
S is specific heat of the material
ΔT is change in temperature = 42°C - 17°C = 25°C
And m is the mass of the material = 15.2g
Replacing:
S = Q / ΔT*m
S = 1362J / 25°C*15.2g
3.58J/g°C is the specific heat of the metalch3-co-ch2-ch2-ch3 IUpAC name
Answer:
2-pentanone.
Explanation:
Hello there!
In this case, for the given compound and, in agreement with the octet rule, it is possible to realize that the CO is actually C=O as shown below:
CH3 - C - CH2 - CH2 - CH3
||
O
Thus, since the C=O stands for the carbonyl group within the parent chain, we infer this is a ketone and more specifically 2-pentanone as it has five carbon atoms.
Regards!
A student experimentally determines the density of a plastic cube using the caliper method, liquid displacement method, and suspension method. The cube's true density is 0.9822 g/cm3. Use the student's collected data below to answer the following questions.
Student's Collected Data
Cube's Mass 0.66g
Caliper Method
Edge Length 0.85 cm
Liquid Displacement Method
Volume of Liquid 5.5 mL
Volume of Liquid + Object 6.2 mL
Required:
Determine the density of the cube for each method.
Answer:
- density of the cube for Caliper Method is 1.08 g/mL
- density of the cube for Liquid Displacement Method is 0.94 g/mL
Explanation:
Given the data in the question;
The cube's true density = 0.9822 g/cm³
Student's Collected Data;
Cube's Mass = 0.66g
Caliper Method
Edge Length = 0.85 cm
Liquid Displacement Method
Volume of Liquid = 5.5 mL
Volume of Liquid + Object = 6.2 mL
For Caliper Method;
Edge Length = 0.85 cm
so the volume of the cube will be ( 0.85 cm )³ OR 0.614125 cm³ ≈ 0.61 cm³ = 0.61 mL
so Density will be;
Density[tex]_{caliper[/tex] = mass of cube / volume of cube
we substitute
Density[tex]_{caliper[/tex] = 0.66g / 0.61 mL
Density[tex]_{caliper[/tex] = 1.08 g/mL
Therefore, density of the cube for Caliper Method is 1.08 g/mL
For Liquid Displacement Method;
Volume of object = total volume - volume of liquid
= 6.2 mL - 5.5 mL = 0.7 mL
now, Density of object will be;
Density[tex]_{Liquid-Displacement[/tex] = mass / volume
we substitute
Density[tex]_{Liquid-Displacement[/tex] = 0.66 g / 0.7 mL
Density[tex]_{Liquid-Displacement[/tex] = 0.942857 ≈ 0.94 g/mL
Therefore, density of the cube for Liquid Displacement Method is 0.94 g/mL