Proving the Single Opposite Side Pair Theorem Given: AD=BC and AD BC prove:ABCD is a parallelogram

Answers

Answer 1

Answer:

8 parts

Step-by-step explanation:

1. AD≅BC                                                                Given

2. AD║BC                                                                Given

3. ∠DAC and ∠BCA                                                Def. of alt.

are alt. interior  angles                                          interior angle

4. ∠DAC ≅ ∠BCA                                           alternate interior angle theorem

5. AC ≅ AC                                                       reflexive property

6. ΔDAC ≅ ΔBCA                                                     SAS

7. AB ≅ CD                                                              CPCTC

8. ABCD is a parallelogram                                parallelogram side theorem

Answer 2

The proof of ABCD is a parallelogram is given in the solution.

What is a parallelogram?

In geometry, a parallelogram is a simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.

The proof is as follows :-

AD≅BC (Given)

AD║BC (Given)

∠DAC and ∠BCA (alternate angles)

∠DAC ≅ ∠BCA (alternate angle)

AC ≅ AC (common)

ΔDAC ≅ ΔBCA (SAS rule)

AB ≅ CD (CPCT)

Hence,

ABCD is a parallelogram (by the definition of parallelogram)

Hence, proved.

Learn more about parallelogram, click;

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Proving The Single Opposite Side Pair Theorem Given: AD=BC And AD BC Prove:ABCD Is A Parallelogram

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