Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10). Match each quadrilateral, described by its vertices, to the sequence of transformations that will show it is congruent to quadrilateral JKLM. W(5,1), X(1,7), Y(9,9), and Z(11,7) O(10,1), P(6,7), Q(14,9), and R(16,7) S(4, 16), T(10, 20), U(12, 12), and V(10, 10) A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10) E(5,6), F(1,12), G(9,14), and H(11,12) a translation 2 units right and 3 units down arrowRight a translation 3 units left and 2 units up arrowRight a translation 3 units down and 3 units left arrowRight a sequence of reflections across the x- and y-axes, in any order arrowRight

Answers

Answer 1

Answer:

See Explanation

Step-by-step explanation:

Given:

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).

(a)If we translate  quadrilateral JKLM 3 units down and 3 units left:

(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)

Therefore, we match it with: A translation 3 units down and 3 units left

(b)If we translate  quadrilateral JKLM 2 units right and 3 units down:

(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)

Therefore, we match it with:A translation 2 units right and 3 units down

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:

A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)

(d)If we translate  quadrilateral JKLM 3 units left and 2 units up:

(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)

Therefore, we match it with: A translation 3 units left and 2 units up

(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

No suitable transformation is found from JKLM to STUV.

Answer 2

Answer:

a translation 3 units down and 3 units left

W(5,1), X(1,7), Y(9,9), and Z(11,7)

a translation 2 units right and 3 units down

O(10,1), P(6,7), Q(14,9), and R(16,7)

a sequence of reflections across the

x- and y-axes, in any order

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

a translation 3 units left and 2 units up

E(5,6), F(1,12), G(9,14), and H(11,12)


Related Questions

A data set includes 104body temperatures of healthy adult humans having a mean of 98.7degreesFand a standard deviation of 0.66degreesF.Construct a 99​%confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6degreesFas the mean body​ temperature?

Answers

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body​ temperature is correct.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 104 - 1 = 103

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 103 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.624

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.624\frac{0.66}{\sqrt{104}} = 0.17[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.7 - 0.17 = 98.53ºF.

The upper end of the interval is the sample mean added to M. So it is 98.7 + 0.17 = 98.87 ºF.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body​ temperature is correct.

A 37 bag sample had a mean of 421 grams. Assume the population standard deviation is known to be 29. A level of significance of 0.05 will be used. State the null and alternative hypothesis.

Answers

Answer:  [tex]H_0:\mu=421[/tex]

[tex]H_a : \mu\neq421[/tex]

Step-by-step explanation:

A null hypothesis is a type of hypothesis that is used in statistics that assumes there is no difference between particular characteristics of a population wheres the alternative hypothesis shows that there is a difference.

Given: A 37 bag sample had a mean of 421 grams.

Let [tex]\mu[/tex] be the population mean.

Then, the null hypothesis would be:

[tex]H_0:\mu=421[/tex]

whereas the alternative hypothesis would be:

[tex]H_a : \mu\neq421[/tex]

A triangular plot of land has one side along a straight road measuring 147147 feet. A second side makes a 2323degrees° angle with the​ road, and the third side makes a 2222degrees° angle with the road. How long are the other two​ sides?

Answers

Answer:

81.23 ft and 77.88 ft long

Step-by-step explanation:

The sum of the internal angles of a triangle is 180 degrees, the missing angle is:

[tex]a+b+c=180\\a+23+22=180\\a=135^o[/tex]

According to the Law of Sines:

[tex]\frac{A}{sin(a)}= \frac{B}{sin(b)}= \frac{C}{sin(c)}[/tex]

Let A be the side that is 147 feet long, the length of the other two sides are:

[tex]\frac{A}{sin(a)}= \frac{B}{sin(b)}\\B=\frac{sin(23)*147}{sin(135)}\\B=81.23\ ft\\\\\frac{A}{sin(a)}= \frac{C}{sin(c)}\\C=\frac{sin(22)*147}{sin(135)}\\C=77.88\ ft[/tex]

The other two sides are 81.23 ft and 77.88 ft long

Two cities whose longitudes are 10E and 20W on the equator are apart

Answers

Step-by-step explanation:

to be honest I'm not sure how to do

A tank contains 3,000 L of brine with 16 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate. (a) How much salt is in the tank after t minutes

Answers

Answer:

The amount of salt in the tank after t minutes is

y= 16e^(t/100)kg

Step- by-step Explanation

The tank contain 3000L of the brine

The rate is 30L/ min

The solution is mixed thoroughly, therefore, the rate in= rate out

dy/dt= rate in to the tank= rate out of the tank

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

Suppose you were given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2). What is the value of a?

Answers

Answer:

Hope it helps..........

The given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2). Hence, the value of x is 7.5.

What is a function?

Function is a type of relation, or rule, that maps one input to specific single output.

The given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2).

here x = 2

Substitute in the function;

F(x)=x^4-2x^3+3x^2 - ax+3

F(2) = 2^4-2(2)^3+3(2)^2 - a(2) +3

F(2) = 16 - 16 + 12 - 2a +3

F(2) = 15 - 2a

15 - 2a = 0

15 = 2a

a = 7.5

Hence, the value of x is 7.5

Learn more about function here:

https://brainly.com/question/2253924

#SPJ2

The initial population of a town in the year 2010 was 20 000. By 2014, the population had grown exponentially to 32 500 people. Write an equation to represent the population of the town (P) over time in years (n).

Answers

Answer:

  P = 20000×1.625^(n/4)

Step-by-step explanation:

An exponential equation can be written using the given data:

  value = (initial value)×(growth factor in period)^(n/(period))

Here, the growth is by a factor of 32500/20000 = 1.625, and the period is 4 years. Then your exponential equation is ...

  P = 20000×1.625^(n/4)

A person has a bag containing dimes and nickels. There are a total of 120 coins in the bag, and the total value of the coins is $9.25. Determine how many dimes and nickels are in the bag. There are _____dimes. There are _____ nickels.

Answers

Answer:

There are 65 dimes. There are 55 nickels.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

x is the number of dimes

y is the number of nickels.

There are a total of 120 coins in the bag

This means that x + y = 120.

The total value of the coins is $9.25.

The dime is worth $0.10 and the nickel is worth $0.05. So

0.1x + 0.05y = 9.25

System:

[tex]x + y = 120[/tex]

[tex]0.1x + 0.05y = 9.25[/tex]

From the first equation:

[tex]y = 120 - x[/tex]

Replacing in the second:

[tex]0.1x + 0.05y = 9.25[/tex]

[tex]0.1x + 0.05(120 - x) = 9.25[/tex]

[tex]0.1x + 6 - 0.05x = 9.25[/tex]

[tex]0.05x = 3.25[/tex]

[tex]x = \frac{3.25}{0.05}[/tex]

[tex]x = 65[/tex]

[tex]y = 120 - x = 120 - 65 = 55[/tex]

There are 65 dimes. There are 55 nickels.

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Three hundred feet of fencing is used

dimensions of the playground that maximize the total enclosed area. What is the maximum area?

The smaller dimension is

feet

Answers

Answer:

50 ft by 75 ft3750 square feet

Step-by-step explanation:

Let x represent the length of the side not parallel to the partition. Then the length of the side parallel to the partition is ...

  y = (300 -2x)/3

And the enclosed area is ...

  A = xy = x(300 -2x)/3 = (2/3)(x)(150 -x)

This is the equation of a parabola with x-intercepts at x=0 and x=150. The line of symmetry, hence the vertex, is located halfway between these values, at x=75.

The maximum area is enclosed when the dimensions are ...

  50 ft by 75 ft

That maximum area is 3750 square feet.

_____

Comment on the solution

The generic solution to problems of this sort is that half the fence (cost) is used in each of the orthogonal directions. Here, half the fence is 150 ft, so the long side measures 150'/2 = 75', and the short side measures 150'/3 = 50'. This remains true regardless of the number of partitions, and regardless if part or all of one side is missing (e.g. bounded by a barn or river).

At a DBE lecture of 100 students, there are 29 women and 23 men. Out of these students, 4 are teachers and 24 are either men nor teachers. Find the number of women teachers attending the lecture

Answers

Answer:

20 teachers

Step-by-step explanation:

Because if you take 100 and minus it by 29, 23, 4 and 24 you get 20.

What is the solution to the system of linear equations below?
x+4y=22
2x+y=9

Answers

Answer:

[tex]\boxed{\sf \ \ \ x = 2 \ \ and \ \ y = 5 \ \ \ }[/tex]

Step-by-step explanation:

hello, we have two equation

(1) x + 4y = 22

(2) 2x + y = 9

let's multiply (1) by 2 and subtract (2)

2x + 8y - (2x + y) = 2*22 - 9 = 44 - 9 = 35

<=> 2x + 8y -2x -y = 35

<=> 7y = 35

<=> y = 35/7 = 5

we replace this value in (1) and it comes

x + 4*5 = 22

<=> x = 22 - 20 = 2

so the solution is

x = 2 and y = 5

hope this helps

A student writes an incorrect step while checking if the sum of the measures of the two remote interior angles of triangle ABC below is equal to the measure of the exterior angle. A triangle ABC is shown. The base of the triangle extends into a straight line. The angle formed between this straight line and the edge of the triangle is marked as p. The angle adjacent to p is marked as o, and the other two angles inside the triangle are marked as m and n. Step 1: m∠m + m∠n + m∠p = 180 degrees (sum of angles of a triangle) Step 2: m∠p + m∠o = 180 degrees (adjacent supplementary angles) Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p Step 4: So, m∠m + m∠n = m∠p In which step did the student first make a mistake and how can it be corrected? Step 1; it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle) Step 1; it should be m∠m + m∠n + m∠o = 90 degrees (adjacent angles) Step 2; it should be m∠o + m∠p = 180 degrees (alternate exterior angles) Step 2; m∠p − m∠o = 90 degrees (alternate interior angles)

Answers

Answer:

(A)Step 1; it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle)

Step-by-step explanation:

In the triangle, the exterior angle = pThe adjacent interior angle =oThe two opposite angles are marked m and n

The steps followed by the student are:

Step 1: m∠m + m∠n + m∠p = 180 degrees (sum of angles of a triangle)

Step 2: m∠p + m∠o = 180 degrees (adjacent supplementary angles)

Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p

Step 4: So, m∠m + m∠n = m∠p

We observe that the student made a mistake in Step 1, it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle).

p is outside the triangle, therefore it cannot form one of the angles in the triangle.

The first steps in writing f(x) = 4x2 + 48x + 10 in vertex form are shown. f(x) = 4(x2 + 12x) + 10 (twelve-halves) squared = 36 What is the function written in vertex form?

Answers

Answer:

[tex]f(x)=4(x+6)^2-134[/tex]

Step-by-step explanation:

We are required to write the function[tex]f(x) = 4x^2 + 48x + 10[/tex] in vertex form.

First, bring the constant to the left-hand side.

[tex]f(x) -10= 4x^2 + 48x[/tex]

Factorize the right hand side.

[tex]f(x) -10= 4(x^2 + 12x)[/tex]

Take note of the factored term(4) and write it in the form below.

[tex]f(x) -10+4\Box= 4(x^2 + 12x+\Box)[/tex]

[tex]\Box = (\frac{\text{Coefficient of x}}{2} )^2\\\\\text{Coefficient of x}=12\\\\\Box = (\frac{12}{2} )^2 =6^2=36[/tex]

Substitute 36 for the boxes.

[tex]f(x) -10+4\boxed{36}= 4(x^2 + 12x+\boxed{36})[/tex]

[tex]f(x) -10+144= 4(x^2 + 12x+6^2)[/tex]

[tex]f(x) +134= 4(x+6)^2\\f(x)=4(x+6)^2-134[/tex]

The function written in vertex form is [tex]f(x)=4(x+6)^2-134[/tex]

Answer:

C

Step-by-step explanation:

I just finished the unit test on Edge. and got a 100% and I selected "c" as my answer.

A contractor is setting up new accounts for the local cable company. She earns $75 for each customer account she sets up. Which expression models this situation, and how much will she profit if she sets up 8 customers? (The variable c represents the number of customers.) Question 4 options: A) c – 75; $9.78 B) 75c; $600 C) c + 75; $600 D) 75/c; $9.78

Answers

Answer:

B

Step-by-step explanation:

The contractor gets $75 for every single customer she sets up. Okay, so if she sets up 1 customer, she gets $75, if she sets up 2, she gets $150 and so on.

This is a multiplication expression since multiplication is just repeated addition, which is what is happening in this case, where the contractor gets $75 added to her account every time she sets another person up.

At this point you can just eliminate the other answer options except for B, so it is B.

But to double check... if you multiply 75 by 8, you would get $600, which is B.

Answer:

d

Step-by-step explanation:

75/c; $9.78

Legal descriptions tend to prefer neat straight lines from point to point, regardless of describing a square, rectangle, triangle or even a smooth circle. When might a property boundary end up being a squiggly line?

Answers

Answer:

When describing a property line drawn down the center of a creek bed

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a that makes the following probability statements true.

a. P(X <= a) =0.95
b. P(X < a)= 0.49
c. P(X >= a)= 0.85
d. P(X >a )= 0.89
e. P(1.83 <= x <=a)= 0.31

Answers

Answer:

(a) The value of a is 53.35.

(b) The value of a is 38.17.

(c) The value of a is 26.95.

(d) The value of a is 25.63.

(e) The value of a is 12.06.

Step-by-step explanation:

The probability density function of X is:

[tex]f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}[/tex]

Here, 22 < X < 55.

(a)

Compute the value of a as follows:

[tex]P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35[/tex]

Thus, the value of a is 53.35.

(b)

Compute the value of a as follows:

[tex]P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17[/tex]

Thus, the value of a is 38.17.

(c)

Compute the value of a as follows:

[tex]P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95[/tex]

Thus, the value of a is 26.95.

(d)

Compute the value of a as follows:

[tex]P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63[/tex]

Thus, the value of a is 25.63.

(e)

Compute the value of a as follows:

[tex]P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06[/tex]

Thus, the value of a is 12.06.

Want Brainliest? Get this correct Which of the following is the quotient of the rational expressions shown below?

Answers

Answer:

  [tex]\dfrac{4x^2+12x+5}{6x^2-3x}[/tex]

Step-by-step explanation:

Invert the denominator and multiply.

  [tex]\dfrac{2x+5}{3x}\div\dfrac{2x-1}{2x+1}=\dfrac{2x+5}{3x}\cdot\dfrac{2x+1}{2x-1}\\\\=\dfrac{(2x+5)(2x+1)}{(3x)(2x-1)}=\boxed{\dfrac{4x^2+12x+5}{6x^2-3x}}\qquad\text{matches choice A}[/tex]

Answer:

[tex]\frac{4x^2+12x+5}{6x^2-3x}[/tex]

Step-by-step explanation:

After using the reciprocal of the second term, the denominator will multiply out to be [tex]6x^2-3x[/tex]. There is only one option with that as the denominator so it must be the correct answer.

CAN SOMEONEHELP PLS ASAP

Answers

Answer:

a ≈ 2.2

Step-by-step explanation:

Using the Cosine rule in Δ ABC

a² = b² + c² - 2bc cos A

Here b = 3, c = 4 and A = 32° , thus

a² = 3² + 4² - (2 × 3 × 4 × cos32° )

    = 9 + 16 - 24cos32°

    = 25 - 24cos32° ( take the square root of both sides )

a = [tex]\sqrt{25-24cos32}[/tex] ≈ 2.2

What is the standard form for 80000 + 200+ 2

Answers

Answer:

80202

Step-by-step explanation:

Simply add according to number value:

200 - 2 goes into hundreds place

2 - 2 goes into ones place

80000 - 8 goes into ten-thousands place

The total number of hamburgers sold by a national fast-food chain is growing exponentially. If 3 billion had been sold by 2003 and 9 billion had been sold by 2010, how many will have been sold by 2013

Answers

Answer:

F(10) = 14.41 Billion

The total number of hamburgers that will have been sold by 2013 is 14.41 billion.

Step-by-step explanation:

The exponential function representing the total number of hamburgers sold by a national fast-food chain which grows exponentially can be expressed as;

f(t) = p(a)^t

In 2003, t = 0 and f(0) = 3 Billion

f(0) = p = 3 billion

The initial value p = 3 billion

In 2010, t = (2010-2003) = 7

f(7) = p(a)^7 = 9 billion

3(a)^7 = 9

a^7 = 9/3 = 3

a = 3^(1/7)

Therefore, the function f(t) is;

f(t) = 3(3)^(t/7) .......2

In 2013, t = (2013 - 2003) = 10

Substituting t = 10 into equation 2;

f(10) = 3(3)^(10/7)

F(10) = 14.41195997001 Billion

F(10) = 14.41 Billion

The total number of hamburgers that will have been sold by 2013 is 14.41 billion.

which of the following equations is equal to 2x^2+8 A. (2x-4i)(x-2i) B. (2x+4i)(x+2i) C. (2x-2i)(x+6i) D. (2x-4i)(x+2i)

Answers

Answer:

(2x-4i) (x+2i)

Step-by-step explanation:

2x^2+8

Factor out 2

2 ( x^2+4)

Writing as the difference of squares  a^2 -b^2 = (a-b) (a+b)

2 ( x^2 -(2i)^2)

2 ( x-2i) (x+2i)

Multiplying the 2 into the first term

(2x-4i) (x+2i)

solve the proportion for y 11/8=y/13

Answers

Answer:

We can use the cross products property.

11/8 = y / 13

8y = 11 * 13

y = 11 * 13 / 8 = 17.875

Answer:

y=17.875

Step-by-step explanation:

[tex]\frac{11}{8} = \frac{y}{13}[/tex]

11(13)=8y

143=8y

y=17.875

Find the value of s(t(-3)):
s(x) = - 3x-2
t(x) = 5x - 4
Please helppp!

Answers

Step-by-step explanation:

(-3x-2/x) multiply by (-15x+12/x)

Let S be a sample space and E and F be events associated with S. Suppose that Pr (Upper E )equals 0.6​, Pr (Upper F )equals 0.2 and Pr (Upper E intersect Upper F )equals 0.1. Calculate the following probabilities. ​(a) Pr (E|F )​(b) Pr (F|E )​(c) Pr (E| Upper F prime )​(d) Pr (Upper E prime | Upper F prime )

Answers

Answer:

(a)0.5

(b)0.17

(c)0.625

(b)0.375

Step-by-step explanation:

Pr(E)=0.6​

Pr(F)=0.2

[tex]Pr(E\cap F)=0.1.[/tex]

(a)Pr (E|F )

[tex]Pr (E|F )=\dfrac{Pr(E \cap F)}{Pr(F)} \\=\dfrac{0.1}{0.2}\\\\=0.5[/tex]

(b)Pr (F|E )

[tex]Pr (F|E )=\dfrac{Pr(E \cap F)}{Pr(E)} \\=\dfrac{0.1}{0.6}\\\\=0.17[/tex]

(c)Pr (E|F')​

Pr(F')=1-P(F)

=1-0.2=0.8

[tex]Pr(E \cap F')=P(E)-P(E\cap F)\\=0.6-0.1\\=0.5[/tex]

Therefore:

[tex]Pr (E|F' )=\dfrac{Pr(E \cap F')}{Pr(F')} \\=\dfrac{0.5}{0.8}\\\\=0.625[/tex]

(d)Pr(E'|F')​

[tex]P(E'\cap F')=P(E \cup F)'\\=1-P(E \cup F)\\=1-[P(E)+P(F)-P(E\cap F)]\\=1-[0.6+0.2-0.1]\\=1-0.7\\=0.3[/tex]

Therefore:

[tex]Pr (E'|F' )=\dfrac{Pr(E' \cap F')}{Pr(F')} \\=\dfrac{0.3}{0.8}\\\\=0.375[/tex]

Which proportion would convert 18 ounces into pounds?

Answers

Answer:

16 ounces = 1 pound

Step-by-step explanation:

You would just do 18/16 = 1.125 pounds. There are always 16 ounces in a pound, so it always works like this

16 ounces to 1 pound

Which of the following relations is a function?
A{(3,-1), (2, 3), (3, 4), (1,7)}

B{(1, 2), (2, 3), (3, 4), (4, 5)}.

C{(3, 0), (4, -3), (6, 7), (4,4)}

D{(1, 2), (1, 3), (2, 8), (3, 9)}​

Answers

Answer:

B

Step-by-step explanation:

A is not a function because the same x value is repeated twice with different y values. The same goes for C and D so the answer is C.

Answer:

B.

Step-by-step explanation:

Well a relation is a set of points and a function is a relation where every x value corresponds to only 1 y value.

So lets see which x values in these relations have only 1 y value.

A. Well a isn’t a function because the number 3 which is a x value had two y values which are -1 and 4.

B. This relation is a function because there are no similar x values.

C. This is not a function because the x value 4 has two y values which are 4 and -3.

D. This is not a function because the number 1 has 2 and 3 as y values.

Consider the statement, "Confidence intervals are underutilized" and explain what the implications might be of using or not using confidence intervals.

Answers

Answer:

Step-by-step explanation:

Confidence intervals have been underutilized prior to this time.

The implications of not using confidence intervals include:

- The under-representation or over-representation of research results that amounts from the use of a single figure to represent a statistic.

- In Market Research analysis, neglecting the use of confidence intervals will increase the risk of your portfolio.

Implications/Importance of using confidence intervals include:

- Calculation of confidence interval gives additional information about the likely values of the statistic you are estimating.

- In the presentation and comprehension of results, confidence intervals give more accuracy from the data or metrics captured.

- Given a sample mean, confidence intervals show the likely range of values of the population mean.

Please need help Please

Answers

Answer: 14/11

Step-by-step explanation:

When 14/11 is multiplied by 1/4, you get a repeating decimal.  All repeating decimals are rational.

Hope it helps <3

Can Someone help me!!! I need this ASAP! What number? Increased by 130% is 69? FYI: the answer is less than 69

Answers

Answer:

Hey there!

There are a few ways you could solve this problem, but the easiest would to be writing an equation.

You could say-

2.3x=69

Divide by 2.3

x=30

Hope this helps :)

Answer:

30

Step-by-step explanation:

the answer is 30 bc increasing something by 130% is multiplying it by 2.3 so technically you have to divide 69 by 2.3 which equals to 30

A half marathon is 13.1 miles long. Leah is running a half marathon and has completed 7.75 miles. How many miles to
the finish line?

Answers

Answer:

5.35 more miles

Answer:

5.35 miles to the finish line

Step-by-step explanation:

Step one

13.1-7.75=

5.35

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