Question 1 of 10
Based only on the information given in the diagram, it is guaranteed that
AABC-AXYZ
B.
43
43°
А
A. True
B. False
SUBMIT

Answer:

Situation B is a function.

Step-by-step explanation:

We know that,

A function is a relation in which every element in the domain i mapped to a unique element in the co-domain.

That is, every element in the domain must have a unique image.

So, we see that,

Situation A = {student's name, all the colors that the student likes}

Here, the students can have more than one color which they like.

Thus, this relation is not a function.

Situation B = {student's name, the student's favorite math teacher}

Here, the students can have only one favorite math teacher.

So, this relation is a function.

Answer:

D

Step-by-step explanation:

Answer:

option A) Agree, because the solutions are the same is correct.

Step-by-step explanation:

FIRST SYSTEM

[tex]6x + y= 2[/tex]

[tex]-x-y=-3[/tex]

solving the system

[tex]\begin{bmatrix}6x+y=2\\ -x-y=-3\end{bmatrix}[/tex]

[tex]\mathrm{Multiply\:}-x-y=-3\mathrm{\:by\:}6\:\mathrm{:}\:\quad \:-6x-6y=-18[/tex]

[tex]\begin{bmatrix}6x+y=2\\ -6x-6y=-18\end{bmatrix}[/tex]

adding the equation

[tex]-6x-6y=-18[/tex]

[tex]+[/tex]

[tex]\underline{6x+y=2}[/tex]

[tex]-5y=-16[/tex]

so the system becomes

[tex]\begin{bmatrix}6x+y=2\\ -5y=-16\end{bmatrix}[/tex]

solve -5y for y

[tex]-5y=-16[/tex]

Divide both sides by -5

[tex]\frac{-5y}{-5}=\frac{-16}{-5}[/tex]

simplify

[tex]y=\frac{16}{5}[/tex]

[tex]\mathrm{For\:}6x+y=2\mathrm{\:plug\:in\:}y=\frac{16}{5}[/tex]

[tex]6x+\frac{16}{5}=2[/tex]

subtract 16/5 from both sides

[tex]6x+\frac{16}{5}-\frac{16}{5}=2-\frac{16}{5}[/tex]

[tex]6x=-\frac{6}{5}[/tex]

Divide both sides by 6

[tex]\frac{6x}{6}=\frac{-\frac{6}{5}}{6}[/tex]

[tex]x=-\frac{1}{5}[/tex]

Therefore, the solution to the FIRST SYSTEM is:

[tex]x=-\frac{1}{5},\:y=\frac{16}{5}[/tex]

SECOND SYSTEM

[tex]2x-3y = -10[/tex]

[tex]-x-y=-3[/tex]

solving the system

[tex]\begin{bmatrix}2x-3y=-10\\ -x-y=-3\end{bmatrix}[/tex]

[tex]\mathrm{Multiply\:}-x-y=-3\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-2x-2y=-6[/tex]

[tex]\begin{bmatrix}2x-3y=-10\\ -2x-2y=-6\end{bmatrix}[/tex]

[tex]-2x-2y=-6[/tex]

[tex]+[/tex]

[tex]\underline{2x-3y=-10}[/tex]

[tex]-5y=-16[/tex]

so the system of equations becomes

[tex]\begin{bmatrix}2x-3y=-10\\ -5y=-16\end{bmatrix}[/tex]

solve -5y for y

[tex]-5y=-16[/tex]

Divide both sides by -5

[tex]\frac{-5y}{-5}=\frac{-16}{-5}[/tex]

Simplify

[tex]y=\frac{16}{5}[/tex]

[tex]\mathrm{For\:}2x-3y=-10\mathrm{\:plug\:in\:}y=\frac{16}{5}[/tex]

[tex]2x-3\cdot \frac{16}{5}=-10[/tex]

[tex]2x=-\frac{2}{5}[/tex]

Divide both sides by 2

[tex]\frac{2x}{2}=\frac{-\frac{2}{5}}{2}[/tex]

Simplify

[tex]x=-\frac{1}{5}[/tex]

Therefore, the solution to the SECOND SYSTEM is:

[tex]x=-\frac{1}{5},\:y=\frac{16}{5}[/tex]

Conclusion:

As both systems of equations have the same solution.

Therefore, we conclude that Albert is right when says that the two systems of equations shown have the same solutions.

Hence, option A) Agree, because the solutions are the same is correct.

Answer:

This simple formula: area = 1/2 x perimeter x apothem.

It means: Perimeter × the sum of the lengths of all the sides.

Hope it helps!<3

Answer:

The surface of the polygon is the total space or area that is limited by the borders of the polygon.

Step-by-step explanation:

This area is the amount of space limited by the borderlines and occupied by a polygon. By definition, the sides of the polygon are the same in size. The area of any polygon can be defined by dividing the polygon into triangles.

Answer:

I think the answer is 124 though I'm in 8th grade . I have completed algebra 1.

Step-by-step explanation:

The other side of the circle has four minor arcs since they each measure less than  180 .

Answer:

Step-by-step explanation:

There are total cadies in the bag:

Probability of pulling a coffee candy is:

So each 5th candy should be coffee candy

Then you need to pull at least:

Note:

To ensure 3 coffee candies you would need to pull 25 - 2 = 23 candies

Answer:

[tex]\boxed{\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}}[/tex]

Step-by-step explanation:

Given equation to us is :-

[tex]\implies y = 6 - 4x [/tex]

So , here we can put different values of x in order to get different values of y .

Initial table given to us is ,

[tex]\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & & & 2&&-6 \\\cline{1-6}\end{tabular}[/tex]

Put x = (-1) :-

[tex]\implies y = 6 - 4x \\\\\implies y = 6 -4(-1) \\\\\implies y = 6 + 4 \\\\\red{\bf\implies y = 10} [/tex]

Put x = 0 :-

[tex]\implies y = 6 - 4x \\\\\implies y = 6-4(0) \\\\\implies y = 6 - 0 \\\\\pink{\bf\implies y = 6 }[/tex]

Put x = 2 :-

[tex]\implies y = 6-4x \\\\\implies y = 6 - 4(2) \\\\\implies y = 6 - 8 \\\\\blue{\bf\implies y = (-2)} [/tex]

Hence the final table would be :-

[tex]\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}[/tex]

Answer:

150

Step-by-step explanation:

Because I looked it up

Answer:

r = 64

Step-by-step explanation:

r = (k*t*u)/s

Where,

k = constant of proportionality

t = -12,

u= -7,

s= -4,

r= -126.

r = (k*t*u)/s

-126 = (k*-12*-7)/-4

-126 * -4 = 84k

504 = 84k

k = 504/84

k = 6

Find r when t= -8, u= 8, and s= -6.

r = (k*t*u)/s

= (6*-8*8) / -6

= -384 / -6

= 64

r = 64

Answer:

Step-by-step explanation:

You answer goes to minus infinity. There is no answer and you are correct.

Answer:

17/24

Step-by-step explanation:

Change the denominators to match

8/24 + 9/24 = 17/24

Answer:

It's pretty simple. For example, if it says there is a percentage increase on something like there is a jacket for $25 and there was a 15% increase, you multiply 25 by 1.15 to see what the new price is. But say if the same $25 jacket is on sale for 15%, then you can multiply 25 by .15, then subtract that from 25 or originally subtract the 15% from 100 which is 85 and multiply 25x.85 and get the answer directly.

Hope this helps! But this would be easier to explain with an example

Answer:

Slope= 30

Step-by-step explanation:

What does the slope tell me?

It tells me that every time I try to find the slope with different points I get 30 for slope.

0.21333333333

answer:

Answer:

0.213

Step-by-step explanation:

I used a calculator :)

Answer:

y = 2x +4

Step-by-step explanation:

m = [tex]\frac{y_{2} -y_{1} }{x_{2} - x_{1} }[/tex]

y - [tex]y_{1}[/tex] = m ( x - [tex]x_{1}[/tex] )

~~~~~~~

(1, 6)

(- 3, - 2)

m = 2

y - 6 = 2 ( x - 1 ) <------ ( point-slope form )

y = 2x + 4  <------- ( slope-intercept form )

2x - y = - 4  <------ ( standard form )

Answer:

I believe answer is 0.041

Answer:

Step-by-step explanation:

Answer:

=10

Step-by-step explanation:

Answer:

4 8 12 16

3 6 9  12

Step-by-step explanation:

Answer:

[tex]x = - \frac{25}{3} [/tex]

Step-by-step explanation:

[tex] \frac{10}{3} = \frac{x}{( - \frac{5}{2}) } [/tex]

[tex] \frac{10}{3} = - \frac{2x}{5} [/tex]

[tex]5(10) = - 2x(3)[/tex]

[tex]50 = - 6x[/tex]

[tex] - 6x = 50[/tex]

[tex] \frac{ - 6x}{ - 6} = \frac{50}{ - 6} [/tex]

[tex]x = - \frac{50}{6} [/tex]

[tex]x = - \frac{25}{3} [/tex]

Answer:

2.) 0.10 (3.) 0.10 (4.) 2.43

Step-by-step explanation:

Given that:

x p(x)

0 0.12

1 0.18

2 0.30

3 0.15

4

5 0.10

6 0.05

X : __0__ 1 ___ 2 ___ 3 _____ 4 ____ 5 ____ 6

p(x):0.12_0.18_0.30_0.15__0.10___0.10 ___0.05

Σ of p(x) = 1

(0.12 + 0.18 + 0.30 + 0.15 + x + 0.10 + 0.05) = 1

0.9 + x = 1

x = 1 - 0.9

x = 0.1

2.)

P(x = 4) = 0.10

3.)

P(x = 5) = 0.10

4.)

Σ(x * p(x)) :

(0*0.12) + (1*0.18) + (2*0.3) + (3*0.15) + (4*0.1) + (5*0.1) + (6*0.05) = 2.43

Answer:

.06

Step-by-step explanation:

edg

Answer:

.06

Step-by-step explanation:

test on edg e

Answer:

60.72

Step-by-step explanation:

you multiply 25.3 by 2.4

Step-by-step explanation:

Let the given ratio be pk : qk .

So , here the quadratic equation is lx² + nx + n = 0. With respect to Standard form ax² + bx + c = 0.

We have ,

→ Sum of roots = -b/a = -n/l = qk + pk

→ Product of roots = c/a = n/l = k²pq .

[tex]=> \dfrac{n}{l} = \dfrac{k^2}{pq} \\\\=> k^2 =\dfrac{n}{pql} [/tex]

And here pk and qk is a root of the quadratic equation ,

[tex]=> lx^2 + nx + n = 0 \\\\=> l(pk)^2 + n(pk) + n = 0\\\\=> lp^2k^2+npk + n = 0 \\\\=> lp^2\bigg( \dfrac{n}{pql} \bigg) + np\bigg(\sqrt{\dfrac{n}{pql}} \bigg) + n = 0 \\\\ => n\bigg\{\dfrac{p}{q}+\sqrt{\dfrac{np}{lq}}+1\bigg\} = 0 \\\\=> \dfrac{p}{q}+\sqrt{\dfrac{np}{lq}}+1 =0\\\\=>\sqrt{\dfrac{p}{q}} \bigg( \dfrac{q}{p}+\sqrt{\dfrac{np}{lq}}+1\bigg) = 0 \\\\=> \sqrt{\dfrac{p}{q}}+ \sqrt{\dfrac{q}{p}}+ \sqrt{\dfrac{n}{l}}=0 \\\\\boxed{\red{\bf\longmapsto \sqrt{\dfrac{p}{q}}+ \sqrt{\dfrac{q}{p}} = - \sqrt{\dfrac{n}{l}}}} [/tex]

Answer:

A) The point( -1 , 5)  is satisfies the  given graph  [tex]g(x) = (\frac{1}{5} )^{x}[/tex]

B) The point( 3 , 1/125)  is satisfies the  given graph  [tex]g(x) = (\frac{1}{5} )^{x}[/tex]

Step-by-step explanation:

Explanation:-

Given graph  

               y =      [tex]g(x) = (\frac{1}{5} )^{x}[/tex]

Put the point ( -1 , 5)

Put y =5 and x =-1

            [tex]5 = (\frac{1}{5} )^{-1} = 5[/tex]

The point( -1 , 5)  is satisfies the  given graph

ii)

Given graph  

               y =      [tex]g(x) = (\frac{1}{5} )^{x}[/tex]

             [tex]\frac{1}{125} = (\frac{1}{5} )^{3} = \frac{1}{125}[/tex]

The point( 3 , 1/125)  is satisfies the  given graph  [tex]g(x) = (\frac{1}{5} )^{x}[/tex]

Answer:

Step-by-step explanation:

yes

if you solve the equation,

5x+15=7x-11

26=2x

x=26/2=13

Answer:

4

Step-by-step explanation:

y = mx + b

m represents the slope, and as we can see in the equation, the number 4 is there instead of m, so therefore 4 is the slope

Answer:

x = 37

y = 79

Step-by-step explanation:

Remark

We are going to go through an extensive discussion of the value of x. The value for y is found exactly the same way.

Top diagram.

The top diagram establishes the fact that if any two points are on the major arc of the circle whose center is 0, then the vertex of the of the two angles so formed are equal. The end points of these two angles must be established by the endpoints of the chord A and B.

Put in much simpler language.

<ACB = <AC'B

The end points of the angles are A and B of the Chord AB.

The Vertex of the angles are both on the major arc of the circle. These two are C and C'

Bottom Diagram

The idea here is to find the value of C. If we do that, then we know what x is in the diagram you provided.

Draw diameter COA       Construction

< CAB = 90                      Any vertex (C) on circumference with diameter endpoints (A & C) = 90

<CAT_1 = 90                   A diameter always meets a tangent at 90o

<BAT_1 = 37                   Given

<CAB = 90-37                  <CAB and <BAT_1 are complementary

<ACB = 37                       A right triangle's acute angles are complementary.

<ACB = x = 37o              See top diagram